QBManager

PHXI07:SYSTEMS OF PARTICLES AND ROTATIONAL MOTION

366067 A solid cylinder is in pure rolling on a horizontal surface, then the relation between $v$ and $ω$ is
supporting img

1

v = R ω

2

ω = R v

3

v > R ω

4

v = \frac{ω}{R}

PHXI07:SYSTEMS OF PARTICLES AND ROTATIONAL MOTION

366068 Assertion :
In rolling, all points of a rigid body have the same linear speed.
Reason :
The rotational motion may affect the linear velocity of rigid body.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

PHXI07:SYSTEMS OF PARTICLES AND ROTATIONAL MOTION

366069 A rigid body is in motion along the path shown. Two points $P & O$ are considered on the body. $α$ is the angle made by the axis (that joins $P$ and $O$ ). w.r.to horizontal direction. If body has to be only in translational motion then.
supporting img

1

α_{1} = α_{2} = α_{3}

2

α_{1} = α_{2} \neq α_{3}

3

α_{1} \neq α_{2} = α_{3}

4

α_{1} \neq α_{2} \neq α_{3}

Explanation:

For the body to be in translational motion the velocity vectors of the points $P$ and $O$ must be same in magnitude and direction at every instant. The value of $α$ also should be constant throughout the motion.

PHXI07:SYSTEMS OF PARTICLES AND ROTATIONAL MOTION

366070 In bicycle the radius of rear wheel is twice the radius of front wheel. If $r_{F}$ and $r_{r}$ are the radii, $v_{F}$ and $v_{r}$ are speeds of topmost points of wheel, then

1

v_{F} = 2 v_{r}

2

v_{r} = 2 v_{F}

3

v_{F} > v_{r}

4

v_{F} = v_{r}

Explanation:

As the wheels are in pure rolling the velocity of the top point of the wheel is twice that of centre of mass and the speed of centre of mass is same for both the wheels (Angular speeds are different).
$So v_{F} = v_{r}$

PHXI07:SYSTEMS OF PARTICLES AND ROTATIONAL MOTION

366067 A solid cylinder is in pure rolling on a horizontal surface, then the relation between $v$ and $ω$ is
supporting img

1

v = R ω

2

ω = R v

3

v > R ω

4

v = \frac{ω}{R}

PHXI07:SYSTEMS OF PARTICLES AND ROTATIONAL MOTION

366068 Assertion :
In rolling, all points of a rigid body have the same linear speed.
Reason :
The rotational motion may affect the linear velocity of rigid body.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

PHXI07:SYSTEMS OF PARTICLES AND ROTATIONAL MOTION

366069 A rigid body is in motion along the path shown. Two points $P & O$ are considered on the body. $α$ is the angle made by the axis (that joins $P$ and $O$ ). w.r.to horizontal direction. If body has to be only in translational motion then.
supporting img

1

α_{1} = α_{2} = α_{3}

2

α_{1} = α_{2} \neq α_{3}

3

α_{1} \neq α_{2} = α_{3}

4

α_{1} \neq α_{2} \neq α_{3}

Explanation:

For the body to be in translational motion the velocity vectors of the points $P$ and $O$ must be same in magnitude and direction at every instant. The value of $α$ also should be constant throughout the motion.

PHXI07:SYSTEMS OF PARTICLES AND ROTATIONAL MOTION

366070 In bicycle the radius of rear wheel is twice the radius of front wheel. If $r_{F}$ and $r_{r}$ are the radii, $v_{F}$ and $v_{r}$ are speeds of topmost points of wheel, then

1

v_{F} = 2 v_{r}

2

v_{r} = 2 v_{F}

3

v_{F} > v_{r}

4

v_{F} = v_{r}

Explanation:

As the wheels are in pure rolling the velocity of the top point of the wheel is twice that of centre of mass and the speed of centre of mass is same for both the wheels (Angular speeds are different).
$So v_{F} = v_{r}$

PHXI07:SYSTEMS OF PARTICLES AND ROTATIONAL MOTION

366067 A solid cylinder is in pure rolling on a horizontal surface, then the relation between $v$ and $ω$ is
supporting img

1

v = R ω

2

ω = R v

3

v > R ω

4

v = \frac{ω}{R}

PHXI07:SYSTEMS OF PARTICLES AND ROTATIONAL MOTION

366068 Assertion :
In rolling, all points of a rigid body have the same linear speed.
Reason :
The rotational motion may affect the linear velocity of rigid body.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

PHXI07:SYSTEMS OF PARTICLES AND ROTATIONAL MOTION

366069 A rigid body is in motion along the path shown. Two points $P & O$ are considered on the body. $α$ is the angle made by the axis (that joins $P$ and $O$ ). w.r.to horizontal direction. If body has to be only in translational motion then.
supporting img

1

α_{1} = α_{2} = α_{3}

2

α_{1} = α_{2} \neq α_{3}

3

α_{1} \neq α_{2} = α_{3}

4

α_{1} \neq α_{2} \neq α_{3}

Explanation:

For the body to be in translational motion the velocity vectors of the points $P$ and $O$ must be same in magnitude and direction at every instant. The value of $α$ also should be constant throughout the motion.

PHXI07:SYSTEMS OF PARTICLES AND ROTATIONAL MOTION

366070 In bicycle the radius of rear wheel is twice the radius of front wheel. If $r_{F}$ and $r_{r}$ are the radii, $v_{F}$ and $v_{r}$ are speeds of topmost points of wheel, then

1

v_{F} = 2 v_{r}

2

v_{r} = 2 v_{F}

3

v_{F} > v_{r}

4

v_{F} = v_{r}

Explanation:

As the wheels are in pure rolling the velocity of the top point of the wheel is twice that of centre of mass and the speed of centre of mass is same for both the wheels (Angular speeds are different).
$So v_{F} = v_{r}$

PHXI07:SYSTEMS OF PARTICLES AND ROTATIONAL MOTION

366067 A solid cylinder is in pure rolling on a horizontal surface, then the relation between $v$ and $ω$ is
supporting img

1

v = R ω

2

ω = R v

3

v > R ω

4

v = \frac{ω}{R}

PHXI07:SYSTEMS OF PARTICLES AND ROTATIONAL MOTION

366068 Assertion :
In rolling, all points of a rigid body have the same linear speed.
Reason :
The rotational motion may affect the linear velocity of rigid body.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

PHXI07:SYSTEMS OF PARTICLES AND ROTATIONAL MOTION

366069 A rigid body is in motion along the path shown. Two points $P & O$ are considered on the body. $α$ is the angle made by the axis (that joins $P$ and $O$ ). w.r.to horizontal direction. If body has to be only in translational motion then.
supporting img

1

α_{1} = α_{2} = α_{3}

2

α_{1} = α_{2} \neq α_{3}

3

α_{1} \neq α_{2} = α_{3}

4

α_{1} \neq α_{2} \neq α_{3}

Explanation:

For the body to be in translational motion the velocity vectors of the points $P$ and $O$ must be same in magnitude and direction at every instant. The value of $α$ also should be constant throughout the motion.

PHXI07:SYSTEMS OF PARTICLES AND ROTATIONAL MOTION

366070 In bicycle the radius of rear wheel is twice the radius of front wheel. If $r_{F}$ and $r_{r}$ are the radii, $v_{F}$ and $v_{r}$ are speeds of topmost points of wheel, then

1

v_{F} = 2 v_{r}

2

v_{r} = 2 v_{F}

3

v_{F} > v_{r}

4

v_{F} = v_{r}

Explanation:

As the wheels are in pure rolling the velocity of the top point of the wheel is twice that of centre of mass and the speed of centre of mass is same for both the wheels (Angular speeds are different).
$So v_{F} = v_{r}$