PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365286
In the given circuits (\(a\)), (\(b\)) and (\(c\)), the potential drop across the two\(p\)-\(n\) junctions are equal in
1 Circuit (\(b\)) only
2 Circuit (\(c\)) only
3 Both circuits (\(a\)) and (\(c\))
4 Circuit (\(a\)) only
Explanation:
In (\(a\)) & (\(c\)) circuits, both the junctions are in same biasing conditions so offers equal resistances. Since both are in series, therefore equal potential will drop across the junction.
NEET - 2022
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365287
In figure assuming the diodes to be ideal,
1 \({D_2}\) is forward biased and \({D_1}\) is reverse biased and hence no current flows from \(B\) to \(A\) and vice-versa
2 \({D_1}\) is forward biased and \({D_2}\) is reverse biased and hence current flows from \(A\) to \(B\)
3 \({D_1}\) and \({D_2}\) are both reverse biased and hence no current flows from \(A\) to \(B\) and vice-versa
4 \({D_1}\) and \({D_2}\) are both forward biased and hence current flows from \(A\) to \(B\)
Explanation:
In the given circuit, \(p\) side \(p\)-\(n\) junction \({D_1}\) is connected to lower voltage and \(n\)-side of \({D_1}\) to higher voltage. Therefore, \({D_1}\) reverse biased. The \(p\)-side of \(p\)-\(n\) junction \({D_2}\) is at higher potential and \(n\)-side of \({D_2}\) is at lower potential. Therefore, \({D_2}\) is forward biased. Hence, current does not flow through the junction from \(B\) to \(A\) i.e., option (1) is correct.
NCERT Exemplar
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365288
The value of current in the following diagrams is (diode assumed to be ideal one)
1 \(0.1\,amp\)
2 \(0.01\,amp\)
3 \(1\,amp\)
4 \({\text{Zero}}\)
Explanation:
In reverse bias current through ideal diode is zero
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
NEET Test Series from KOTA - 10 Papers In MS WORD
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PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365286
In the given circuits (\(a\)), (\(b\)) and (\(c\)), the potential drop across the two\(p\)-\(n\) junctions are equal in
1 Circuit (\(b\)) only
2 Circuit (\(c\)) only
3 Both circuits (\(a\)) and (\(c\))
4 Circuit (\(a\)) only
Explanation:
In (\(a\)) & (\(c\)) circuits, both the junctions are in same biasing conditions so offers equal resistances. Since both are in series, therefore equal potential will drop across the junction.
NEET - 2022
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365287
In figure assuming the diodes to be ideal,
1 \({D_2}\) is forward biased and \({D_1}\) is reverse biased and hence no current flows from \(B\) to \(A\) and vice-versa
2 \({D_1}\) is forward biased and \({D_2}\) is reverse biased and hence current flows from \(A\) to \(B\)
3 \({D_1}\) and \({D_2}\) are both reverse biased and hence no current flows from \(A\) to \(B\) and vice-versa
4 \({D_1}\) and \({D_2}\) are both forward biased and hence current flows from \(A\) to \(B\)
Explanation:
In the given circuit, \(p\) side \(p\)-\(n\) junction \({D_1}\) is connected to lower voltage and \(n\)-side of \({D_1}\) to higher voltage. Therefore, \({D_1}\) reverse biased. The \(p\)-side of \(p\)-\(n\) junction \({D_2}\) is at higher potential and \(n\)-side of \({D_2}\) is at lower potential. Therefore, \({D_2}\) is forward biased. Hence, current does not flow through the junction from \(B\) to \(A\) i.e., option (1) is correct.
NCERT Exemplar
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365288
The value of current in the following diagrams is (diode assumed to be ideal one)
1 \(0.1\,amp\)
2 \(0.01\,amp\)
3 \(1\,amp\)
4 \({\text{Zero}}\)
Explanation:
In reverse bias current through ideal diode is zero
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365286
In the given circuits (\(a\)), (\(b\)) and (\(c\)), the potential drop across the two\(p\)-\(n\) junctions are equal in
1 Circuit (\(b\)) only
2 Circuit (\(c\)) only
3 Both circuits (\(a\)) and (\(c\))
4 Circuit (\(a\)) only
Explanation:
In (\(a\)) & (\(c\)) circuits, both the junctions are in same biasing conditions so offers equal resistances. Since both are in series, therefore equal potential will drop across the junction.
NEET - 2022
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365287
In figure assuming the diodes to be ideal,
1 \({D_2}\) is forward biased and \({D_1}\) is reverse biased and hence no current flows from \(B\) to \(A\) and vice-versa
2 \({D_1}\) is forward biased and \({D_2}\) is reverse biased and hence current flows from \(A\) to \(B\)
3 \({D_1}\) and \({D_2}\) are both reverse biased and hence no current flows from \(A\) to \(B\) and vice-versa
4 \({D_1}\) and \({D_2}\) are both forward biased and hence current flows from \(A\) to \(B\)
Explanation:
In the given circuit, \(p\) side \(p\)-\(n\) junction \({D_1}\) is connected to lower voltage and \(n\)-side of \({D_1}\) to higher voltage. Therefore, \({D_1}\) reverse biased. The \(p\)-side of \(p\)-\(n\) junction \({D_2}\) is at higher potential and \(n\)-side of \({D_2}\) is at lower potential. Therefore, \({D_2}\) is forward biased. Hence, current does not flow through the junction from \(B\) to \(A\) i.e., option (1) is correct.
NCERT Exemplar
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365288
The value of current in the following diagrams is (diode assumed to be ideal one)
1 \(0.1\,amp\)
2 \(0.01\,amp\)
3 \(1\,amp\)
4 \({\text{Zero}}\)
Explanation:
In reverse bias current through ideal diode is zero
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365286
In the given circuits (\(a\)), (\(b\)) and (\(c\)), the potential drop across the two\(p\)-\(n\) junctions are equal in
1 Circuit (\(b\)) only
2 Circuit (\(c\)) only
3 Both circuits (\(a\)) and (\(c\))
4 Circuit (\(a\)) only
Explanation:
In (\(a\)) & (\(c\)) circuits, both the junctions are in same biasing conditions so offers equal resistances. Since both are in series, therefore equal potential will drop across the junction.
NEET - 2022
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365287
In figure assuming the diodes to be ideal,
1 \({D_2}\) is forward biased and \({D_1}\) is reverse biased and hence no current flows from \(B\) to \(A\) and vice-versa
2 \({D_1}\) is forward biased and \({D_2}\) is reverse biased and hence current flows from \(A\) to \(B\)
3 \({D_1}\) and \({D_2}\) are both reverse biased and hence no current flows from \(A\) to \(B\) and vice-versa
4 \({D_1}\) and \({D_2}\) are both forward biased and hence current flows from \(A\) to \(B\)
Explanation:
In the given circuit, \(p\) side \(p\)-\(n\) junction \({D_1}\) is connected to lower voltage and \(n\)-side of \({D_1}\) to higher voltage. Therefore, \({D_1}\) reverse biased. The \(p\)-side of \(p\)-\(n\) junction \({D_2}\) is at higher potential and \(n\)-side of \({D_2}\) is at lower potential. Therefore, \({D_2}\) is forward biased. Hence, current does not flow through the junction from \(B\) to \(A\) i.e., option (1) is correct.
NCERT Exemplar
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365288
The value of current in the following diagrams is (diode assumed to be ideal one)
1 \(0.1\,amp\)
2 \(0.01\,amp\)
3 \(1\,amp\)
4 \({\text{Zero}}\)
Explanation:
In reverse bias current through ideal diode is zero
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
