322993
Distinction between primary, secondary, and tertiary alcohol is done by
1 Oxidation method
2 Lucas test
3 Victor Meyer method
4 All of these
Explanation:
All the methods used to distinguish alcohols.
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
322994
Oxidation of an alcohol \(\left(\mathrm{C}_{5} \mathrm{H}_{12} \mathrm{O}\right)\) with acid dichromate gives a mixture of dimethyl ketone and acetic acid. The alcohol could be
1 2 -methyl-3-butanol
2 2-methylbutanol
3 2-methylbutan-2-ol
4 3-methylbutan-2-ol.
Explanation:
Tertiary alcohols are oxidised in acidic \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\) to give a mixture of ketone and an acid.
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
322995
Which of the following compound can not be used in preparation of iodoform?
1 \(\mathrm{CH}_{3} \mathrm{CHO}\)
2 \(\mathrm{CH}_{3} \mathrm{COCH}_{3}\)
3 \(\mathrm{HCHO}\)
4 2- propanol
Explanation:
Formaldehyde can not produce iodoform, as only those compound which contains either potassium iodide and sod. hypochlorite yield iodoform.
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
322996
A compound that gives positive iodoform test is
1 1-pentanol
2 2-pentanol
3 3-pentanol
4 pentanal.
Explanation:
Alcohols having group and aldehydes and ketones having group give positive iodoform test.
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
322997
Which of the following will not form a yellow precipitate on heating with an alkaline solution of iodine?
\({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{OH}}\) does not have \({\rm{ - CH(OH)C}}{{\rm{H}}_{\rm{3}}}\) group hence it will not form yellow precipitate with an alkaline solution of iodine (haloform reaction).
322993
Distinction between primary, secondary, and tertiary alcohol is done by
1 Oxidation method
2 Lucas test
3 Victor Meyer method
4 All of these
Explanation:
All the methods used to distinguish alcohols.
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
322994
Oxidation of an alcohol \(\left(\mathrm{C}_{5} \mathrm{H}_{12} \mathrm{O}\right)\) with acid dichromate gives a mixture of dimethyl ketone and acetic acid. The alcohol could be
1 2 -methyl-3-butanol
2 2-methylbutanol
3 2-methylbutan-2-ol
4 3-methylbutan-2-ol.
Explanation:
Tertiary alcohols are oxidised in acidic \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\) to give a mixture of ketone and an acid.
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
322995
Which of the following compound can not be used in preparation of iodoform?
1 \(\mathrm{CH}_{3} \mathrm{CHO}\)
2 \(\mathrm{CH}_{3} \mathrm{COCH}_{3}\)
3 \(\mathrm{HCHO}\)
4 2- propanol
Explanation:
Formaldehyde can not produce iodoform, as only those compound which contains either potassium iodide and sod. hypochlorite yield iodoform.
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
322996
A compound that gives positive iodoform test is
1 1-pentanol
2 2-pentanol
3 3-pentanol
4 pentanal.
Explanation:
Alcohols having group and aldehydes and ketones having group give positive iodoform test.
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
322997
Which of the following will not form a yellow precipitate on heating with an alkaline solution of iodine?
\({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{OH}}\) does not have \({\rm{ - CH(OH)C}}{{\rm{H}}_{\rm{3}}}\) group hence it will not form yellow precipitate with an alkaline solution of iodine (haloform reaction).
322993
Distinction between primary, secondary, and tertiary alcohol is done by
1 Oxidation method
2 Lucas test
3 Victor Meyer method
4 All of these
Explanation:
All the methods used to distinguish alcohols.
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
322994
Oxidation of an alcohol \(\left(\mathrm{C}_{5} \mathrm{H}_{12} \mathrm{O}\right)\) with acid dichromate gives a mixture of dimethyl ketone and acetic acid. The alcohol could be
1 2 -methyl-3-butanol
2 2-methylbutanol
3 2-methylbutan-2-ol
4 3-methylbutan-2-ol.
Explanation:
Tertiary alcohols are oxidised in acidic \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\) to give a mixture of ketone and an acid.
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
322995
Which of the following compound can not be used in preparation of iodoform?
1 \(\mathrm{CH}_{3} \mathrm{CHO}\)
2 \(\mathrm{CH}_{3} \mathrm{COCH}_{3}\)
3 \(\mathrm{HCHO}\)
4 2- propanol
Explanation:
Formaldehyde can not produce iodoform, as only those compound which contains either potassium iodide and sod. hypochlorite yield iodoform.
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
322996
A compound that gives positive iodoform test is
1 1-pentanol
2 2-pentanol
3 3-pentanol
4 pentanal.
Explanation:
Alcohols having group and aldehydes and ketones having group give positive iodoform test.
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
322997
Which of the following will not form a yellow precipitate on heating with an alkaline solution of iodine?
\({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{OH}}\) does not have \({\rm{ - CH(OH)C}}{{\rm{H}}_{\rm{3}}}\) group hence it will not form yellow precipitate with an alkaline solution of iodine (haloform reaction).
322993
Distinction between primary, secondary, and tertiary alcohol is done by
1 Oxidation method
2 Lucas test
3 Victor Meyer method
4 All of these
Explanation:
All the methods used to distinguish alcohols.
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
322994
Oxidation of an alcohol \(\left(\mathrm{C}_{5} \mathrm{H}_{12} \mathrm{O}\right)\) with acid dichromate gives a mixture of dimethyl ketone and acetic acid. The alcohol could be
1 2 -methyl-3-butanol
2 2-methylbutanol
3 2-methylbutan-2-ol
4 3-methylbutan-2-ol.
Explanation:
Tertiary alcohols are oxidised in acidic \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\) to give a mixture of ketone and an acid.
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
322995
Which of the following compound can not be used in preparation of iodoform?
1 \(\mathrm{CH}_{3} \mathrm{CHO}\)
2 \(\mathrm{CH}_{3} \mathrm{COCH}_{3}\)
3 \(\mathrm{HCHO}\)
4 2- propanol
Explanation:
Formaldehyde can not produce iodoform, as only those compound which contains either potassium iodide and sod. hypochlorite yield iodoform.
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
322996
A compound that gives positive iodoform test is
1 1-pentanol
2 2-pentanol
3 3-pentanol
4 pentanal.
Explanation:
Alcohols having group and aldehydes and ketones having group give positive iodoform test.
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
322997
Which of the following will not form a yellow precipitate on heating with an alkaline solution of iodine?
\({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{OH}}\) does not have \({\rm{ - CH(OH)C}}{{\rm{H}}_{\rm{3}}}\) group hence it will not form yellow precipitate with an alkaline solution of iodine (haloform reaction).
322993
Distinction between primary, secondary, and tertiary alcohol is done by
1 Oxidation method
2 Lucas test
3 Victor Meyer method
4 All of these
Explanation:
All the methods used to distinguish alcohols.
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
322994
Oxidation of an alcohol \(\left(\mathrm{C}_{5} \mathrm{H}_{12} \mathrm{O}\right)\) with acid dichromate gives a mixture of dimethyl ketone and acetic acid. The alcohol could be
1 2 -methyl-3-butanol
2 2-methylbutanol
3 2-methylbutan-2-ol
4 3-methylbutan-2-ol.
Explanation:
Tertiary alcohols are oxidised in acidic \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\) to give a mixture of ketone and an acid.
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
322995
Which of the following compound can not be used in preparation of iodoform?
1 \(\mathrm{CH}_{3} \mathrm{CHO}\)
2 \(\mathrm{CH}_{3} \mathrm{COCH}_{3}\)
3 \(\mathrm{HCHO}\)
4 2- propanol
Explanation:
Formaldehyde can not produce iodoform, as only those compound which contains either potassium iodide and sod. hypochlorite yield iodoform.
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
322996
A compound that gives positive iodoform test is
1 1-pentanol
2 2-pentanol
3 3-pentanol
4 pentanal.
Explanation:
Alcohols having group and aldehydes and ketones having group give positive iodoform test.
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
322997
Which of the following will not form a yellow precipitate on heating with an alkaline solution of iodine?
\({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{OH}}\) does not have \({\rm{ - CH(OH)C}}{{\rm{H}}_{\rm{3}}}\) group hence it will not form yellow precipitate with an alkaline solution of iodine (haloform reaction).
