Close Packed Structures
CHXII01:THE SOLID STATE

318748 In a crystalline solid, having formula \({\text{X}}{{\text{Y}}_{\text{2}}}{{\text{O}}_{\text{4}}}\), oxide ions are arranged in cubic close packed lattice while, cations \({\text{X}}\) are present in tetrahedral voids and cations \({\text{Y}}\) are present in octahedral voids. The percentage of tetrahedral voids occupied by \({\text{X}}\) is

1 \(12.5 \%\)
2 \(25 \%\)
3 \(50 \%\)
4 \(75 \%\)
CHXII01:THE SOLID STATE

318749 Total number of voids in 0.5 mole of a compound forming hexagonal closed packed structure are

1 \(6.022 \times 10^{23}\)
2 \(3.011 \times 10^{23}\)
3 \(9.033 \times 10^{23}\)
4 \(4.516 \times 10^{23}\)
CHXII01:THE SOLID STATE

318750 In chrysoberyl, a compound containing Beryllium, Aluminium and Oxygen, oxide ions form cubic close packed structure. Aluminium ions occupy \(\dfrac{1}{4}\) th of octahedral voids. The formula of the compound is:

1 \(\mathrm{BeAlO}_{4}\)
2 \(\mathrm{BeAl}_{2} \mathrm{O}_{4}\)
3 \(\mathrm{Be}_{2} \mathrm{AlO}_{2}\)
4 \(\mathrm{BeAlO}\)
CHXII01:THE SOLID STATE

318751 Titanium crystallises in a face centred cubic lattice. It reacts with carbon or hydrogen interstitially by allowing atoms of these elements to occupy holes in the host lattice. Hydrogen occupies tetrahedral holes but carbon occupies octahedral holes the formula of titanium carbide and hydride are

1 \(\mathrm{TiC}_{2}, \mathrm{TiH}\)
2 \(\mathrm{TiC}_{2}, \mathrm{TiH}_{4}\)
3 \(\mathrm{TiC}, \mathrm{TiH}_{2}\)
4 \(\mathrm{TiC}_{3}, \mathrm{TiH}_{2}\)
CHXII01:THE SOLID STATE

318748 In a crystalline solid, having formula \({\text{X}}{{\text{Y}}_{\text{2}}}{{\text{O}}_{\text{4}}}\), oxide ions are arranged in cubic close packed lattice while, cations \({\text{X}}\) are present in tetrahedral voids and cations \({\text{Y}}\) are present in octahedral voids. The percentage of tetrahedral voids occupied by \({\text{X}}\) is

1 \(12.5 \%\)
2 \(25 \%\)
3 \(50 \%\)
4 \(75 \%\)
CHXII01:THE SOLID STATE

318749 Total number of voids in 0.5 mole of a compound forming hexagonal closed packed structure are

1 \(6.022 \times 10^{23}\)
2 \(3.011 \times 10^{23}\)
3 \(9.033 \times 10^{23}\)
4 \(4.516 \times 10^{23}\)
CHXII01:THE SOLID STATE

318750 In chrysoberyl, a compound containing Beryllium, Aluminium and Oxygen, oxide ions form cubic close packed structure. Aluminium ions occupy \(\dfrac{1}{4}\) th of octahedral voids. The formula of the compound is:

1 \(\mathrm{BeAlO}_{4}\)
2 \(\mathrm{BeAl}_{2} \mathrm{O}_{4}\)
3 \(\mathrm{Be}_{2} \mathrm{AlO}_{2}\)
4 \(\mathrm{BeAlO}\)
CHXII01:THE SOLID STATE

318751 Titanium crystallises in a face centred cubic lattice. It reacts with carbon or hydrogen interstitially by allowing atoms of these elements to occupy holes in the host lattice. Hydrogen occupies tetrahedral holes but carbon occupies octahedral holes the formula of titanium carbide and hydride are

1 \(\mathrm{TiC}_{2}, \mathrm{TiH}\)
2 \(\mathrm{TiC}_{2}, \mathrm{TiH}_{4}\)
3 \(\mathrm{TiC}, \mathrm{TiH}_{2}\)
4 \(\mathrm{TiC}_{3}, \mathrm{TiH}_{2}\)
CHXII01:THE SOLID STATE

318748 In a crystalline solid, having formula \({\text{X}}{{\text{Y}}_{\text{2}}}{{\text{O}}_{\text{4}}}\), oxide ions are arranged in cubic close packed lattice while, cations \({\text{X}}\) are present in tetrahedral voids and cations \({\text{Y}}\) are present in octahedral voids. The percentage of tetrahedral voids occupied by \({\text{X}}\) is

1 \(12.5 \%\)
2 \(25 \%\)
3 \(50 \%\)
4 \(75 \%\)
CHXII01:THE SOLID STATE

318749 Total number of voids in 0.5 mole of a compound forming hexagonal closed packed structure are

1 \(6.022 \times 10^{23}\)
2 \(3.011 \times 10^{23}\)
3 \(9.033 \times 10^{23}\)
4 \(4.516 \times 10^{23}\)
CHXII01:THE SOLID STATE

318750 In chrysoberyl, a compound containing Beryllium, Aluminium and Oxygen, oxide ions form cubic close packed structure. Aluminium ions occupy \(\dfrac{1}{4}\) th of octahedral voids. The formula of the compound is:

1 \(\mathrm{BeAlO}_{4}\)
2 \(\mathrm{BeAl}_{2} \mathrm{O}_{4}\)
3 \(\mathrm{Be}_{2} \mathrm{AlO}_{2}\)
4 \(\mathrm{BeAlO}\)
CHXII01:THE SOLID STATE

318751 Titanium crystallises in a face centred cubic lattice. It reacts with carbon or hydrogen interstitially by allowing atoms of these elements to occupy holes in the host lattice. Hydrogen occupies tetrahedral holes but carbon occupies octahedral holes the formula of titanium carbide and hydride are

1 \(\mathrm{TiC}_{2}, \mathrm{TiH}\)
2 \(\mathrm{TiC}_{2}, \mathrm{TiH}_{4}\)
3 \(\mathrm{TiC}, \mathrm{TiH}_{2}\)
4 \(\mathrm{TiC}_{3}, \mathrm{TiH}_{2}\)
CHXII01:THE SOLID STATE

318748 In a crystalline solid, having formula \({\text{X}}{{\text{Y}}_{\text{2}}}{{\text{O}}_{\text{4}}}\), oxide ions are arranged in cubic close packed lattice while, cations \({\text{X}}\) are present in tetrahedral voids and cations \({\text{Y}}\) are present in octahedral voids. The percentage of tetrahedral voids occupied by \({\text{X}}\) is

1 \(12.5 \%\)
2 \(25 \%\)
3 \(50 \%\)
4 \(75 \%\)
CHXII01:THE SOLID STATE

318749 Total number of voids in 0.5 mole of a compound forming hexagonal closed packed structure are

1 \(6.022 \times 10^{23}\)
2 \(3.011 \times 10^{23}\)
3 \(9.033 \times 10^{23}\)
4 \(4.516 \times 10^{23}\)
CHXII01:THE SOLID STATE

318750 In chrysoberyl, a compound containing Beryllium, Aluminium and Oxygen, oxide ions form cubic close packed structure. Aluminium ions occupy \(\dfrac{1}{4}\) th of octahedral voids. The formula of the compound is:

1 \(\mathrm{BeAlO}_{4}\)
2 \(\mathrm{BeAl}_{2} \mathrm{O}_{4}\)
3 \(\mathrm{Be}_{2} \mathrm{AlO}_{2}\)
4 \(\mathrm{BeAlO}\)
CHXII01:THE SOLID STATE

318751 Titanium crystallises in a face centred cubic lattice. It reacts with carbon or hydrogen interstitially by allowing atoms of these elements to occupy holes in the host lattice. Hydrogen occupies tetrahedral holes but carbon occupies octahedral holes the formula of titanium carbide and hydride are

1 \(\mathrm{TiC}_{2}, \mathrm{TiH}\)
2 \(\mathrm{TiC}_{2}, \mathrm{TiH}_{4}\)
3 \(\mathrm{TiC}, \mathrm{TiH}_{2}\)
4 \(\mathrm{TiC}_{3}, \mathrm{TiH}_{2}\)