Close Packed Structures
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
CHXII01:THE SOLID STATE

318744 In a compound, atoms of element \({\mathrm{Y}}\) form ccp lattice and those of element X occupy \({\mathrm{2 / 3 \mathrm{rd}}}\) of tetrahedral voids. How many atoms of X are present in one formula unit of the compound?

1 2
2 1
3 5
4 4
CHXII01:THE SOLID STATE

318745 A solid is formed by two elements \({\text{P}}\) and \({\text{Q}}\). The element \({\text{Q}}\) forms cubic close packing and atoms of \({\text{P}}\) occupy one third of tetrahedral voids. The formula of the compound is

1 \({\text{P}}{{\text{Q}}_{\text{3}}}\)
2 \({{\text{P}}_{\text{3}}}{\text{Q}}\)
3 \({{\text{P}}_{\text{2}}}{{\text{Q}}_{\text{3}}}\)
4 \({{\text{P}}_{\text{3}}}{{\text{Q}}_{\text{2}}}\)
CHXII01:THE SOLID STATE

318746 Assertion :
Total number of octahedral voids present in unit cell of cubic close packing including the one that is present at the body centre, is four.
Reason :
Besides the body centre there is one octahedral void present at the centre of each of six faces of the unit cell and each of which is shared between two adjacent unit cells.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
CHXII01:THE SOLID STATE

318747 If a compound (oxide) have HCP arrangement and the cations M occupy two-third octahedral voids. The formula of the compound is :

1 \(\mathrm{M}_{3} \mathrm{O}\)
2 \(\mathrm{M}_{3} \mathrm{O}_{2}\)
3 \(\mathrm{M}_{2} \mathrm{O}_{3}\)
4 \(\mathrm{M}_{3} \mathrm{O}_{4}\)
CHXII01:THE SOLID STATE

318744 In a compound, atoms of element \({\mathrm{Y}}\) form ccp lattice and those of element X occupy \({\mathrm{2 / 3 \mathrm{rd}}}\) of tetrahedral voids. How many atoms of X are present in one formula unit of the compound?

1 2
2 1
3 5
4 4
CHXII01:THE SOLID STATE

318745 A solid is formed by two elements \({\text{P}}\) and \({\text{Q}}\). The element \({\text{Q}}\) forms cubic close packing and atoms of \({\text{P}}\) occupy one third of tetrahedral voids. The formula of the compound is

1 \({\text{P}}{{\text{Q}}_{\text{3}}}\)
2 \({{\text{P}}_{\text{3}}}{\text{Q}}\)
3 \({{\text{P}}_{\text{2}}}{{\text{Q}}_{\text{3}}}\)
4 \({{\text{P}}_{\text{3}}}{{\text{Q}}_{\text{2}}}\)
CHXII01:THE SOLID STATE

318746 Assertion :
Total number of octahedral voids present in unit cell of cubic close packing including the one that is present at the body centre, is four.
Reason :
Besides the body centre there is one octahedral void present at the centre of each of six faces of the unit cell and each of which is shared between two adjacent unit cells.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
CHXII01:THE SOLID STATE

318747 If a compound (oxide) have HCP arrangement and the cations M occupy two-third octahedral voids. The formula of the compound is :

1 \(\mathrm{M}_{3} \mathrm{O}\)
2 \(\mathrm{M}_{3} \mathrm{O}_{2}\)
3 \(\mathrm{M}_{2} \mathrm{O}_{3}\)
4 \(\mathrm{M}_{3} \mathrm{O}_{4}\)
CHXII01:THE SOLID STATE

318744 In a compound, atoms of element \({\mathrm{Y}}\) form ccp lattice and those of element X occupy \({\mathrm{2 / 3 \mathrm{rd}}}\) of tetrahedral voids. How many atoms of X are present in one formula unit of the compound?

1 2
2 1
3 5
4 4
CHXII01:THE SOLID STATE

318745 A solid is formed by two elements \({\text{P}}\) and \({\text{Q}}\). The element \({\text{Q}}\) forms cubic close packing and atoms of \({\text{P}}\) occupy one third of tetrahedral voids. The formula of the compound is

1 \({\text{P}}{{\text{Q}}_{\text{3}}}\)
2 \({{\text{P}}_{\text{3}}}{\text{Q}}\)
3 \({{\text{P}}_{\text{2}}}{{\text{Q}}_{\text{3}}}\)
4 \({{\text{P}}_{\text{3}}}{{\text{Q}}_{\text{2}}}\)
CHXII01:THE SOLID STATE

318746 Assertion :
Total number of octahedral voids present in unit cell of cubic close packing including the one that is present at the body centre, is four.
Reason :
Besides the body centre there is one octahedral void present at the centre of each of six faces of the unit cell and each of which is shared between two adjacent unit cells.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
CHXII01:THE SOLID STATE

318747 If a compound (oxide) have HCP arrangement and the cations M occupy two-third octahedral voids. The formula of the compound is :

1 \(\mathrm{M}_{3} \mathrm{O}\)
2 \(\mathrm{M}_{3} \mathrm{O}_{2}\)
3 \(\mathrm{M}_{2} \mathrm{O}_{3}\)
4 \(\mathrm{M}_{3} \mathrm{O}_{4}\)
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
CHXII01:THE SOLID STATE

318744 In a compound, atoms of element \({\mathrm{Y}}\) form ccp lattice and those of element X occupy \({\mathrm{2 / 3 \mathrm{rd}}}\) of tetrahedral voids. How many atoms of X are present in one formula unit of the compound?

1 2
2 1
3 5
4 4
CHXII01:THE SOLID STATE

318745 A solid is formed by two elements \({\text{P}}\) and \({\text{Q}}\). The element \({\text{Q}}\) forms cubic close packing and atoms of \({\text{P}}\) occupy one third of tetrahedral voids. The formula of the compound is

1 \({\text{P}}{{\text{Q}}_{\text{3}}}\)
2 \({{\text{P}}_{\text{3}}}{\text{Q}}\)
3 \({{\text{P}}_{\text{2}}}{{\text{Q}}_{\text{3}}}\)
4 \({{\text{P}}_{\text{3}}}{{\text{Q}}_{\text{2}}}\)
CHXII01:THE SOLID STATE

318746 Assertion :
Total number of octahedral voids present in unit cell of cubic close packing including the one that is present at the body centre, is four.
Reason :
Besides the body centre there is one octahedral void present at the centre of each of six faces of the unit cell and each of which is shared between two adjacent unit cells.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
CHXII01:THE SOLID STATE

318747 If a compound (oxide) have HCP arrangement and the cations M occupy two-third octahedral voids. The formula of the compound is :

1 \(\mathrm{M}_{3} \mathrm{O}\)
2 \(\mathrm{M}_{3} \mathrm{O}_{2}\)
3 \(\mathrm{M}_{2} \mathrm{O}_{3}\)
4 \(\mathrm{M}_{3} \mathrm{O}_{4}\)