Close Packed Structures
CHXII01:THE SOLID STATE

318752 The total number of tetrahedral voids in the face centred unit cell is

1 6
2 8
3 10
4 12
CHXII01:THE SOLID STATE

318753 In a cubic close packed structure of mixed oxides, the lattice is made up of oxides ions, \(20 \%\) of tetrahedral voids are occupied by divalent \(\mathrm{X}^{2+}\) ions and \(50 \%\) of the octahedral voids are occupied by trivalent \(\mathrm{Y}^{3+}\) ions. The formula of the oxide is

1 \(\mathrm{XY}_{2} \mathrm{O}_{4}\)
2 \(\mathrm{X}_{4} \mathrm{Y}_{5} \mathrm{O}_{10}\)
3 \(\mathrm{X}_{5} \mathrm{Y}_{4} \mathrm{O}_{10}\)
4 \(\mathrm{X}_{2} \mathrm{YO}_{4}\)
CHXII01:THE SOLID STATE

318754 In a solid, oxide ions are arranged in CCP, cations A occupy one-sixth of the tetrahedral voids and cations B occupy one-third of the octahedral voids. The formula of the compound is

1 \(\mathrm{AB}_{2} \mathrm{O}_{3}\)
2 \(\mathrm{A}_{2} \mathrm{BO}_{3}\)
3 \(\mathrm{ABO}_{3}\)
4 \(\mathrm{A}_{2} \mathrm{~B}_{2} \mathrm{O}_{3}\)
CHXII01:THE SOLID STATE

318755 If ' \(\mathrm{Z}\) ' is the number of atoms in the unit cell that represents the closest packing sequence --\(\mathrm{ABC} \mathrm{ABC}---\), the number of octahedral voids in the unit cell is equal to

1 \(\mathrm{Z} / 4\)
2 \(\mathrm{Z} / 2\)
3 \(2 \mathrm{Z}\)
4 \(\mathrm{Z}\)
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CHXII01:THE SOLID STATE

318752 The total number of tetrahedral voids in the face centred unit cell is

1 6
2 8
3 10
4 12
CHXII01:THE SOLID STATE

318753 In a cubic close packed structure of mixed oxides, the lattice is made up of oxides ions, \(20 \%\) of tetrahedral voids are occupied by divalent \(\mathrm{X}^{2+}\) ions and \(50 \%\) of the octahedral voids are occupied by trivalent \(\mathrm{Y}^{3+}\) ions. The formula of the oxide is

1 \(\mathrm{XY}_{2} \mathrm{O}_{4}\)
2 \(\mathrm{X}_{4} \mathrm{Y}_{5} \mathrm{O}_{10}\)
3 \(\mathrm{X}_{5} \mathrm{Y}_{4} \mathrm{O}_{10}\)
4 \(\mathrm{X}_{2} \mathrm{YO}_{4}\)
CHXII01:THE SOLID STATE

318754 In a solid, oxide ions are arranged in CCP, cations A occupy one-sixth of the tetrahedral voids and cations B occupy one-third of the octahedral voids. The formula of the compound is

1 \(\mathrm{AB}_{2} \mathrm{O}_{3}\)
2 \(\mathrm{A}_{2} \mathrm{BO}_{3}\)
3 \(\mathrm{ABO}_{3}\)
4 \(\mathrm{A}_{2} \mathrm{~B}_{2} \mathrm{O}_{3}\)
CHXII01:THE SOLID STATE

318755 If ' \(\mathrm{Z}\) ' is the number of atoms in the unit cell that represents the closest packing sequence --\(\mathrm{ABC} \mathrm{ABC}---\), the number of octahedral voids in the unit cell is equal to

1 \(\mathrm{Z} / 4\)
2 \(\mathrm{Z} / 2\)
3 \(2 \mathrm{Z}\)
4 \(\mathrm{Z}\)
CHXII01:THE SOLID STATE

318752 The total number of tetrahedral voids in the face centred unit cell is

1 6
2 8
3 10
4 12
CHXII01:THE SOLID STATE

318753 In a cubic close packed structure of mixed oxides, the lattice is made up of oxides ions, \(20 \%\) of tetrahedral voids are occupied by divalent \(\mathrm{X}^{2+}\) ions and \(50 \%\) of the octahedral voids are occupied by trivalent \(\mathrm{Y}^{3+}\) ions. The formula of the oxide is

1 \(\mathrm{XY}_{2} \mathrm{O}_{4}\)
2 \(\mathrm{X}_{4} \mathrm{Y}_{5} \mathrm{O}_{10}\)
3 \(\mathrm{X}_{5} \mathrm{Y}_{4} \mathrm{O}_{10}\)
4 \(\mathrm{X}_{2} \mathrm{YO}_{4}\)
CHXII01:THE SOLID STATE

318754 In a solid, oxide ions are arranged in CCP, cations A occupy one-sixth of the tetrahedral voids and cations B occupy one-third of the octahedral voids. The formula of the compound is

1 \(\mathrm{AB}_{2} \mathrm{O}_{3}\)
2 \(\mathrm{A}_{2} \mathrm{BO}_{3}\)
3 \(\mathrm{ABO}_{3}\)
4 \(\mathrm{A}_{2} \mathrm{~B}_{2} \mathrm{O}_{3}\)
CHXII01:THE SOLID STATE

318755 If ' \(\mathrm{Z}\) ' is the number of atoms in the unit cell that represents the closest packing sequence --\(\mathrm{ABC} \mathrm{ABC}---\), the number of octahedral voids in the unit cell is equal to

1 \(\mathrm{Z} / 4\)
2 \(\mathrm{Z} / 2\)
3 \(2 \mathrm{Z}\)
4 \(\mathrm{Z}\)
CHXII01:THE SOLID STATE

318752 The total number of tetrahedral voids in the face centred unit cell is

1 6
2 8
3 10
4 12
CHXII01:THE SOLID STATE

318753 In a cubic close packed structure of mixed oxides, the lattice is made up of oxides ions, \(20 \%\) of tetrahedral voids are occupied by divalent \(\mathrm{X}^{2+}\) ions and \(50 \%\) of the octahedral voids are occupied by trivalent \(\mathrm{Y}^{3+}\) ions. The formula of the oxide is

1 \(\mathrm{XY}_{2} \mathrm{O}_{4}\)
2 \(\mathrm{X}_{4} \mathrm{Y}_{5} \mathrm{O}_{10}\)
3 \(\mathrm{X}_{5} \mathrm{Y}_{4} \mathrm{O}_{10}\)
4 \(\mathrm{X}_{2} \mathrm{YO}_{4}\)
CHXII01:THE SOLID STATE

318754 In a solid, oxide ions are arranged in CCP, cations A occupy one-sixth of the tetrahedral voids and cations B occupy one-third of the octahedral voids. The formula of the compound is

1 \(\mathrm{AB}_{2} \mathrm{O}_{3}\)
2 \(\mathrm{A}_{2} \mathrm{BO}_{3}\)
3 \(\mathrm{ABO}_{3}\)
4 \(\mathrm{A}_{2} \mathrm{~B}_{2} \mathrm{O}_{3}\)
CHXII01:THE SOLID STATE

318755 If ' \(\mathrm{Z}\) ' is the number of atoms in the unit cell that represents the closest packing sequence --\(\mathrm{ABC} \mathrm{ABC}---\), the number of octahedral voids in the unit cell is equal to

1 \(\mathrm{Z} / 4\)
2 \(\mathrm{Z} / 2\)
3 \(2 \mathrm{Z}\)
4 \(\mathrm{Z}\)
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