QBManager

Semiconductor Electronics Material Devices and Simple Circuits

151312 Assertion: The logic gate NOT can be built using diode.
Reason: The output voltage and the input voltage of the diode have $180^{\circ}$ phase difference.

1 If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.

2 If both Assertion and Reason are correct but Reason in not a correct explanation of the Assertion.

3 If the Assertion is correct but Reason is incorrect.

4 If both the Assertion and Reason are incorrect.

5 If the Assertion is incorrect but the Reason is correct.

AIIMS-2005

Semiconductor Electronics Material Devices and Simple Circuits

151319 The diagram of a logic circuit is given below. The output \
(A\) of the circuit is represented by-
original image

1 P. (R+Q)

2 P. (R.Q)

3

P +

(R.Q)

4

P + (R + Q)

Explanation:

C Given circuit diagram,
original image
The Boolean expression,
$A = (P + R) \cdot (P + Q)$
$A = PP + PQ + RP + RQ$
$A = P + PQ + RP + RQ$
$= P (1 + Q) + RP + RQ$
$∵ P + Q = 1 and PP = P$
$A = P + RP + RQ$
$= P (1 + R) + RQ$
$= P + (RQ)$

BCECE-2016

Semiconductor Electronics Material Devices and Simple Circuits

151320 The corresponding truth table for the function $Z$ of $X$ and $Y$ represented by given figure is-
original image

1 {|l|l|l|}
|

\)|
|---|

000

010

101

111

\(

2 {|l|l|l|}
|

\)|
|---|

001

011

100

110

\(

3 {|c|c|c|}
|

\)|
|---|

001

010

101

110

\(

4 None of these

Explanation:

B Given circuit diagram,
original image
Then Boolean expression
$Z = X \cdot (X + Y)$
$Z = X X + X Y$
Truth table,
{|l|l|l|}
| \)|
|---|
$000$
$010$
$101$
$111$
\(

BCECE-2014

Semiconductor Electronics Material Devices and Simple Circuits

151322 Output $Y$ is given by :
original image

1

(\bar{X} + \bar{Y}) \cdot Z

2

(X + Y) Z

3

(X + Y) \overset{―}{Z}

4

\bar{X} \cdot \bar{Y} + Z

Explanation:

B Given circuit combination,
original image
Then Boolean expression
$W = (\overset{―}{X} + \overset{―}{Y}) \cdot Z$

BCECE-2007

Semiconductor Electronics Material Devices and Simple Circuits

151323 Sum of the two binary numbers $(100010)_{2}$ and $(11011)_{2}$ is-

1

(111111)_{2}

2

(101111)_{2}

3

(111001)_{2}

4

(111101)_{2}

Explanation:

D Sum of given two binary number
$Missing \end{array}$
$+ (11011)_{2}$
$Misplaced \hline$
Rule
$Missing \end{array}$
$\begin{matrix} r e x t r a \end{matrix}$

BCECE-2007

Semiconductor Electronics Material Devices and Simple Circuits

151312 Assertion: The logic gate NOT can be built using diode.
Reason: The output voltage and the input voltage of the diode have $180^{\circ}$ phase difference.

1 If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.

2 If both Assertion and Reason are correct but Reason in not a correct explanation of the Assertion.

3 If the Assertion is correct but Reason is incorrect.

4 If both the Assertion and Reason are incorrect.

5 If the Assertion is incorrect but the Reason is correct.

AIIMS-2005

Semiconductor Electronics Material Devices and Simple Circuits

151319 The diagram of a logic circuit is given below. The output \
(A\) of the circuit is represented by-
original image

1 P. (R+Q)

2 P. (R.Q)

3

P +

(R.Q)

4

P + (R + Q)

Explanation:

C Given circuit diagram,
original image
The Boolean expression,
$A = (P + R) \cdot (P + Q)$
$A = PP + PQ + RP + RQ$
$A = P + PQ + RP + RQ$
$= P (1 + Q) + RP + RQ$
$∵ P + Q = 1 and PP = P$
$A = P + RP + RQ$
$= P (1 + R) + RQ$
$= P + (RQ)$

BCECE-2016

Semiconductor Electronics Material Devices and Simple Circuits

151320 The corresponding truth table for the function $Z$ of $X$ and $Y$ represented by given figure is-
original image

1 {|l|l|l|}
|

\)|
|---|

000

010

101

111

\(

2 {|l|l|l|}
|

\)|
|---|

001

011

100

110

\(

3 {|c|c|c|}
|

\)|
|---|

001

010

101

110

\(

4 None of these

Explanation:

B Given circuit diagram,
original image
Then Boolean expression
$Z = X \cdot (X + Y)$
$Z = X X + X Y$
Truth table,
{|l|l|l|}
| \)|
|---|
$000$
$010$
$101$
$111$
\(

BCECE-2014

Semiconductor Electronics Material Devices and Simple Circuits

151322 Output $Y$ is given by :
original image

1

(\bar{X} + \bar{Y}) \cdot Z

2

(X + Y) Z

3

(X + Y) \overset{―}{Z}

4

\bar{X} \cdot \bar{Y} + Z

Explanation:

B Given circuit combination,
original image
Then Boolean expression
$W = (\overset{―}{X} + \overset{―}{Y}) \cdot Z$

BCECE-2007

Semiconductor Electronics Material Devices and Simple Circuits

151323 Sum of the two binary numbers $(100010)_{2}$ and $(11011)_{2}$ is-

1

(111111)_{2}

2

(101111)_{2}

3

(111001)_{2}

4

(111101)_{2}

Explanation:

D Sum of given two binary number
$Missing \end{array}$
$+ (11011)_{2}$
$Misplaced \hline$
Rule
$Missing \end{array}$
$\begin{matrix} r e x t r a \end{matrix}$

BCECE-2007

Semiconductor Electronics Material Devices and Simple Circuits

151312 Assertion: The logic gate NOT can be built using diode.
Reason: The output voltage and the input voltage of the diode have $180^{\circ}$ phase difference.

1 If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.

2 If both Assertion and Reason are correct but Reason in not a correct explanation of the Assertion.

3 If the Assertion is correct but Reason is incorrect.

4 If both the Assertion and Reason are incorrect.

5 If the Assertion is incorrect but the Reason is correct.

AIIMS-2005

Semiconductor Electronics Material Devices and Simple Circuits

151319 The diagram of a logic circuit is given below. The output \
(A\) of the circuit is represented by-
original image

1 P. (R+Q)

2 P. (R.Q)

3

P +

(R.Q)

4

P + (R + Q)

Explanation:

C Given circuit diagram,
original image
The Boolean expression,
$A = (P + R) \cdot (P + Q)$
$A = PP + PQ + RP + RQ$
$A = P + PQ + RP + RQ$
$= P (1 + Q) + RP + RQ$
$∵ P + Q = 1 and PP = P$
$A = P + RP + RQ$
$= P (1 + R) + RQ$
$= P + (RQ)$

BCECE-2016

Semiconductor Electronics Material Devices and Simple Circuits

151320 The corresponding truth table for the function $Z$ of $X$ and $Y$ represented by given figure is-
original image

1 {|l|l|l|}
|

\)|
|---|

000

010

101

111

\(

2 {|l|l|l|}
|

\)|
|---|

001

011

100

110

\(

3 {|c|c|c|}
|

\)|
|---|

001

010

101

110

\(

4 None of these

Explanation:

B Given circuit diagram,
original image
Then Boolean expression
$Z = X \cdot (X + Y)$
$Z = X X + X Y$
Truth table,
{|l|l|l|}
| \)|
|---|
$000$
$010$
$101$
$111$
\(

BCECE-2014

Semiconductor Electronics Material Devices and Simple Circuits

151322 Output $Y$ is given by :
original image

1

(\bar{X} + \bar{Y}) \cdot Z

2

(X + Y) Z

3

(X + Y) \overset{―}{Z}

4

\bar{X} \cdot \bar{Y} + Z

Explanation:

B Given circuit combination,
original image
Then Boolean expression
$W = (\overset{―}{X} + \overset{―}{Y}) \cdot Z$

BCECE-2007

Semiconductor Electronics Material Devices and Simple Circuits

151323 Sum of the two binary numbers $(100010)_{2}$ and $(11011)_{2}$ is-

1

(111111)_{2}

2

(101111)_{2}

3

(111001)_{2}

4

(111101)_{2}

Explanation:

D Sum of given two binary number
$Missing \end{array}$
$+ (11011)_{2}$
$Misplaced \hline$
Rule
$Missing \end{array}$
$\begin{matrix} r e x t r a \end{matrix}$

BCECE-2007

Semiconductor Electronics Material Devices and Simple Circuits

151312 Assertion: The logic gate NOT can be built using diode.
Reason: The output voltage and the input voltage of the diode have $180^{\circ}$ phase difference.

1 If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.

2 If both Assertion and Reason are correct but Reason in not a correct explanation of the Assertion.

3 If the Assertion is correct but Reason is incorrect.

4 If both the Assertion and Reason are incorrect.

5 If the Assertion is incorrect but the Reason is correct.

AIIMS-2005

Semiconductor Electronics Material Devices and Simple Circuits

151319 The diagram of a logic circuit is given below. The output \
(A\) of the circuit is represented by-
original image

1 P. (R+Q)

2 P. (R.Q)

3

P +

(R.Q)

4

P + (R + Q)

Explanation:

C Given circuit diagram,
original image
The Boolean expression,
$A = (P + R) \cdot (P + Q)$
$A = PP + PQ + RP + RQ$
$A = P + PQ + RP + RQ$
$= P (1 + Q) + RP + RQ$
$∵ P + Q = 1 and PP = P$
$A = P + RP + RQ$
$= P (1 + R) + RQ$
$= P + (RQ)$

BCECE-2016

Semiconductor Electronics Material Devices and Simple Circuits

151320 The corresponding truth table for the function $Z$ of $X$ and $Y$ represented by given figure is-
original image

1 {|l|l|l|}
|

\)|
|---|

000

010

101

111

\(

2 {|l|l|l|}
|

\)|
|---|

001

011

100

110

\(

3 {|c|c|c|}
|

\)|
|---|

001

010

101

110

\(

4 None of these

Explanation:

B Given circuit diagram,
original image
Then Boolean expression
$Z = X \cdot (X + Y)$
$Z = X X + X Y$
Truth table,
{|l|l|l|}
| \)|
|---|
$000$
$010$
$101$
$111$
\(

BCECE-2014

Semiconductor Electronics Material Devices and Simple Circuits

151322 Output $Y$ is given by :
original image

1

(\bar{X} + \bar{Y}) \cdot Z

2

(X + Y) Z

3

(X + Y) \overset{―}{Z}

4

\bar{X} \cdot \bar{Y} + Z

Explanation:

B Given circuit combination,
original image
Then Boolean expression
$W = (\overset{―}{X} + \overset{―}{Y}) \cdot Z$

BCECE-2007

Semiconductor Electronics Material Devices and Simple Circuits

151323 Sum of the two binary numbers $(100010)_{2}$ and $(11011)_{2}$ is-

1

(111111)_{2}

2

(101111)_{2}

3

(111001)_{2}

4

(111101)_{2}

Explanation:

D Sum of given two binary number
$Missing \end{array}$
$+ (11011)_{2}$
$Misplaced \hline$
Rule
$Missing \end{array}$
$\begin{matrix} r e x t r a \end{matrix}$

BCECE-2007

Semiconductor Electronics Material Devices and Simple Circuits

151312 Assertion: The logic gate NOT can be built using diode.
Reason: The output voltage and the input voltage of the diode have $180^{\circ}$ phase difference.

1 If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.

2 If both Assertion and Reason are correct but Reason in not a correct explanation of the Assertion.

3 If the Assertion is correct but Reason is incorrect.

4 If both the Assertion and Reason are incorrect.

5 If the Assertion is incorrect but the Reason is correct.

AIIMS-2005

Semiconductor Electronics Material Devices and Simple Circuits

151319 The diagram of a logic circuit is given below. The output \
(A\) of the circuit is represented by-
original image

1 P. (R+Q)

2 P. (R.Q)

3

P +

(R.Q)

4

P + (R + Q)

Explanation:

C Given circuit diagram,
original image
The Boolean expression,
$A = (P + R) \cdot (P + Q)$
$A = PP + PQ + RP + RQ$
$A = P + PQ + RP + RQ$
$= P (1 + Q) + RP + RQ$
$∵ P + Q = 1 and PP = P$
$A = P + RP + RQ$
$= P (1 + R) + RQ$
$= P + (RQ)$

BCECE-2016

Semiconductor Electronics Material Devices and Simple Circuits

151320 The corresponding truth table for the function $Z$ of $X$ and $Y$ represented by given figure is-
original image

1 {|l|l|l|}
|

\)|
|---|

000

010

101

111

\(

2 {|l|l|l|}
|

\)|
|---|

001

011

100

110

\(

3 {|c|c|c|}
|

\)|
|---|

001

010

101

110

\(

4 None of these

Explanation:

B Given circuit diagram,
original image
Then Boolean expression
$Z = X \cdot (X + Y)$
$Z = X X + X Y$
Truth table,
{|l|l|l|}
| \)|
|---|
$000$
$010$
$101$
$111$
\(

BCECE-2014

Semiconductor Electronics Material Devices and Simple Circuits

151322 Output $Y$ is given by :
original image

1

(\bar{X} + \bar{Y}) \cdot Z

2

(X + Y) Z

3

(X + Y) \overset{―}{Z}

4

\bar{X} \cdot \bar{Y} + Z

Explanation:

B Given circuit combination,
original image
Then Boolean expression
$W = (\overset{―}{X} + \overset{―}{Y}) \cdot Z$

BCECE-2007

Semiconductor Electronics Material Devices and Simple Circuits

151323 Sum of the two binary numbers $(100010)_{2}$ and $(11011)_{2}$ is-

1

(111111)_{2}

2

(101111)_{2}

3

(111001)_{2}

4

(111101)_{2}

Explanation:

D Sum of given two binary number
$Missing \end{array}$
$+ (11011)_{2}$
$Misplaced \hline$
Rule
$Missing \end{array}$
$\begin{matrix} r e x t r a \end{matrix}$

BCECE-2007

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