Semiconductor Electronics Material Devices and Simple Circuits
151312
Assertion: The logic gate NOT can be built using diode. Reason: The output voltage and the input voltage of the diode have \(180^{\circ}\) phase difference.
1 If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
2 If both Assertion and Reason are correct but Reason in not a correct explanation of the Assertion.
3 If the Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
5 If the Assertion is incorrect but the Reason is correct.
Explanation:
D NOT gate can not be built using diode and output voltage and input voltage of the diode have same phase difference. So both assertion and reason are incorrect.
AIIMS-2005
Semiconductor Electronics Material Devices and Simple Circuits
151319
The diagram of a logic circuit is given below. The output \ (A\) of the circuit is represented by-
1 P. (R+Q)
2 P. (R.Q)
3 \(\mathrm{P}+\) (R.Q)
4 \(\mathrm{P}+(\mathrm{R}+\mathrm{Q})\)
Explanation:
C Given circuit diagram, The Boolean expression, \(\mathrm{A} =(\mathrm{P}+\mathrm{R}) \cdot(\mathrm{P}+\mathrm{Q})\) \(\mathrm{A} =\mathrm{PP}+\mathrm{PQ}+\mathrm{RP}+\mathrm{RQ}\) \(\mathrm{A} =\mathrm{P}+\mathrm{PQ}+\mathrm{RP}+\mathrm{RQ}\) \(=\mathrm{P}(1+\mathrm{Q})+\mathrm{RP}+\mathrm{RQ}\) \(\because \quad \mathrm{P} +\mathrm{Q}=1 \text { and } \mathrm{PP}=\mathrm{P}\) \(\mathrm{A} =\mathrm{P}+\mathrm{RP}+\mathrm{RQ}\) \(=\mathrm{P}(1+\mathrm{R})+\mathrm{RQ}\) \(=\mathrm{P}+(\mathrm{RQ})\)
BCECE-2016
Semiconductor Electronics Material Devices and Simple Circuits
151320
The corresponding truth table for the function \(Z\) of \(X\) and \(Y\) represented by given figure is-
B Given circuit combination, Then Boolean expression \(\mathrm{W}=(\overline{\mathrm{X}}+\overline{\mathrm{Y}}) \cdot \mathrm{Z}\)
BCECE-2007
Semiconductor Electronics Material Devices and Simple Circuits
151323
Sum of the two binary numbers \((100010)_2\) and \((11011)_2\) is-
1 \((111111)_2\)
2 \((101111)_2\)
3 \((111001)_2\)
4 \((111101)_2\)
Explanation:
D Sum of given two binary number \(\begin{array}{r} (100010)_2\) \(+(11011)_2\) \(\hline(111101)_2 \end{array}\) Rule \(\left\{\begin{array}{l} 0+1=1\) \(1+1=10 \end{array}\right\}\)
Semiconductor Electronics Material Devices and Simple Circuits
151312
Assertion: The logic gate NOT can be built using diode. Reason: The output voltage and the input voltage of the diode have \(180^{\circ}\) phase difference.
1 If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
2 If both Assertion and Reason are correct but Reason in not a correct explanation of the Assertion.
3 If the Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
5 If the Assertion is incorrect but the Reason is correct.
Explanation:
D NOT gate can not be built using diode and output voltage and input voltage of the diode have same phase difference. So both assertion and reason are incorrect.
AIIMS-2005
Semiconductor Electronics Material Devices and Simple Circuits
151319
The diagram of a logic circuit is given below. The output \ (A\) of the circuit is represented by-
1 P. (R+Q)
2 P. (R.Q)
3 \(\mathrm{P}+\) (R.Q)
4 \(\mathrm{P}+(\mathrm{R}+\mathrm{Q})\)
Explanation:
C Given circuit diagram, The Boolean expression, \(\mathrm{A} =(\mathrm{P}+\mathrm{R}) \cdot(\mathrm{P}+\mathrm{Q})\) \(\mathrm{A} =\mathrm{PP}+\mathrm{PQ}+\mathrm{RP}+\mathrm{RQ}\) \(\mathrm{A} =\mathrm{P}+\mathrm{PQ}+\mathrm{RP}+\mathrm{RQ}\) \(=\mathrm{P}(1+\mathrm{Q})+\mathrm{RP}+\mathrm{RQ}\) \(\because \quad \mathrm{P} +\mathrm{Q}=1 \text { and } \mathrm{PP}=\mathrm{P}\) \(\mathrm{A} =\mathrm{P}+\mathrm{RP}+\mathrm{RQ}\) \(=\mathrm{P}(1+\mathrm{R})+\mathrm{RQ}\) \(=\mathrm{P}+(\mathrm{RQ})\)
BCECE-2016
Semiconductor Electronics Material Devices and Simple Circuits
151320
The corresponding truth table for the function \(Z\) of \(X\) and \(Y\) represented by given figure is-
B Given circuit combination, Then Boolean expression \(\mathrm{W}=(\overline{\mathrm{X}}+\overline{\mathrm{Y}}) \cdot \mathrm{Z}\)
BCECE-2007
Semiconductor Electronics Material Devices and Simple Circuits
151323
Sum of the two binary numbers \((100010)_2\) and \((11011)_2\) is-
1 \((111111)_2\)
2 \((101111)_2\)
3 \((111001)_2\)
4 \((111101)_2\)
Explanation:
D Sum of given two binary number \(\begin{array}{r} (100010)_2\) \(+(11011)_2\) \(\hline(111101)_2 \end{array}\) Rule \(\left\{\begin{array}{l} 0+1=1\) \(1+1=10 \end{array}\right\}\)
Semiconductor Electronics Material Devices and Simple Circuits
151312
Assertion: The logic gate NOT can be built using diode. Reason: The output voltage and the input voltage of the diode have \(180^{\circ}\) phase difference.
1 If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
2 If both Assertion and Reason are correct but Reason in not a correct explanation of the Assertion.
3 If the Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
5 If the Assertion is incorrect but the Reason is correct.
Explanation:
D NOT gate can not be built using diode and output voltage and input voltage of the diode have same phase difference. So both assertion and reason are incorrect.
AIIMS-2005
Semiconductor Electronics Material Devices and Simple Circuits
151319
The diagram of a logic circuit is given below. The output \ (A\) of the circuit is represented by-
1 P. (R+Q)
2 P. (R.Q)
3 \(\mathrm{P}+\) (R.Q)
4 \(\mathrm{P}+(\mathrm{R}+\mathrm{Q})\)
Explanation:
C Given circuit diagram, The Boolean expression, \(\mathrm{A} =(\mathrm{P}+\mathrm{R}) \cdot(\mathrm{P}+\mathrm{Q})\) \(\mathrm{A} =\mathrm{PP}+\mathrm{PQ}+\mathrm{RP}+\mathrm{RQ}\) \(\mathrm{A} =\mathrm{P}+\mathrm{PQ}+\mathrm{RP}+\mathrm{RQ}\) \(=\mathrm{P}(1+\mathrm{Q})+\mathrm{RP}+\mathrm{RQ}\) \(\because \quad \mathrm{P} +\mathrm{Q}=1 \text { and } \mathrm{PP}=\mathrm{P}\) \(\mathrm{A} =\mathrm{P}+\mathrm{RP}+\mathrm{RQ}\) \(=\mathrm{P}(1+\mathrm{R})+\mathrm{RQ}\) \(=\mathrm{P}+(\mathrm{RQ})\)
BCECE-2016
Semiconductor Electronics Material Devices and Simple Circuits
151320
The corresponding truth table for the function \(Z\) of \(X\) and \(Y\) represented by given figure is-
B Given circuit combination, Then Boolean expression \(\mathrm{W}=(\overline{\mathrm{X}}+\overline{\mathrm{Y}}) \cdot \mathrm{Z}\)
BCECE-2007
Semiconductor Electronics Material Devices and Simple Circuits
151323
Sum of the two binary numbers \((100010)_2\) and \((11011)_2\) is-
1 \((111111)_2\)
2 \((101111)_2\)
3 \((111001)_2\)
4 \((111101)_2\)
Explanation:
D Sum of given two binary number \(\begin{array}{r} (100010)_2\) \(+(11011)_2\) \(\hline(111101)_2 \end{array}\) Rule \(\left\{\begin{array}{l} 0+1=1\) \(1+1=10 \end{array}\right\}\)
NEET Test Series from KOTA - 10 Papers In MS WORD
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Semiconductor Electronics Material Devices and Simple Circuits
151312
Assertion: The logic gate NOT can be built using diode. Reason: The output voltage and the input voltage of the diode have \(180^{\circ}\) phase difference.
1 If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
2 If both Assertion and Reason are correct but Reason in not a correct explanation of the Assertion.
3 If the Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
5 If the Assertion is incorrect but the Reason is correct.
Explanation:
D NOT gate can not be built using diode and output voltage and input voltage of the diode have same phase difference. So both assertion and reason are incorrect.
AIIMS-2005
Semiconductor Electronics Material Devices and Simple Circuits
151319
The diagram of a logic circuit is given below. The output \ (A\) of the circuit is represented by-
1 P. (R+Q)
2 P. (R.Q)
3 \(\mathrm{P}+\) (R.Q)
4 \(\mathrm{P}+(\mathrm{R}+\mathrm{Q})\)
Explanation:
C Given circuit diagram, The Boolean expression, \(\mathrm{A} =(\mathrm{P}+\mathrm{R}) \cdot(\mathrm{P}+\mathrm{Q})\) \(\mathrm{A} =\mathrm{PP}+\mathrm{PQ}+\mathrm{RP}+\mathrm{RQ}\) \(\mathrm{A} =\mathrm{P}+\mathrm{PQ}+\mathrm{RP}+\mathrm{RQ}\) \(=\mathrm{P}(1+\mathrm{Q})+\mathrm{RP}+\mathrm{RQ}\) \(\because \quad \mathrm{P} +\mathrm{Q}=1 \text { and } \mathrm{PP}=\mathrm{P}\) \(\mathrm{A} =\mathrm{P}+\mathrm{RP}+\mathrm{RQ}\) \(=\mathrm{P}(1+\mathrm{R})+\mathrm{RQ}\) \(=\mathrm{P}+(\mathrm{RQ})\)
BCECE-2016
Semiconductor Electronics Material Devices and Simple Circuits
151320
The corresponding truth table for the function \(Z\) of \(X\) and \(Y\) represented by given figure is-
B Given circuit combination, Then Boolean expression \(\mathrm{W}=(\overline{\mathrm{X}}+\overline{\mathrm{Y}}) \cdot \mathrm{Z}\)
BCECE-2007
Semiconductor Electronics Material Devices and Simple Circuits
151323
Sum of the two binary numbers \((100010)_2\) and \((11011)_2\) is-
1 \((111111)_2\)
2 \((101111)_2\)
3 \((111001)_2\)
4 \((111101)_2\)
Explanation:
D Sum of given two binary number \(\begin{array}{r} (100010)_2\) \(+(11011)_2\) \(\hline(111101)_2 \end{array}\) Rule \(\left\{\begin{array}{l} 0+1=1\) \(1+1=10 \end{array}\right\}\)
Semiconductor Electronics Material Devices and Simple Circuits
151312
Assertion: The logic gate NOT can be built using diode. Reason: The output voltage and the input voltage of the diode have \(180^{\circ}\) phase difference.
1 If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
2 If both Assertion and Reason are correct but Reason in not a correct explanation of the Assertion.
3 If the Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
5 If the Assertion is incorrect but the Reason is correct.
Explanation:
D NOT gate can not be built using diode and output voltage and input voltage of the diode have same phase difference. So both assertion and reason are incorrect.
AIIMS-2005
Semiconductor Electronics Material Devices and Simple Circuits
151319
The diagram of a logic circuit is given below. The output \ (A\) of the circuit is represented by-
1 P. (R+Q)
2 P. (R.Q)
3 \(\mathrm{P}+\) (R.Q)
4 \(\mathrm{P}+(\mathrm{R}+\mathrm{Q})\)
Explanation:
C Given circuit diagram, The Boolean expression, \(\mathrm{A} =(\mathrm{P}+\mathrm{R}) \cdot(\mathrm{P}+\mathrm{Q})\) \(\mathrm{A} =\mathrm{PP}+\mathrm{PQ}+\mathrm{RP}+\mathrm{RQ}\) \(\mathrm{A} =\mathrm{P}+\mathrm{PQ}+\mathrm{RP}+\mathrm{RQ}\) \(=\mathrm{P}(1+\mathrm{Q})+\mathrm{RP}+\mathrm{RQ}\) \(\because \quad \mathrm{P} +\mathrm{Q}=1 \text { and } \mathrm{PP}=\mathrm{P}\) \(\mathrm{A} =\mathrm{P}+\mathrm{RP}+\mathrm{RQ}\) \(=\mathrm{P}(1+\mathrm{R})+\mathrm{RQ}\) \(=\mathrm{P}+(\mathrm{RQ})\)
BCECE-2016
Semiconductor Electronics Material Devices and Simple Circuits
151320
The corresponding truth table for the function \(Z\) of \(X\) and \(Y\) represented by given figure is-
B Given circuit combination, Then Boolean expression \(\mathrm{W}=(\overline{\mathrm{X}}+\overline{\mathrm{Y}}) \cdot \mathrm{Z}\)
BCECE-2007
Semiconductor Electronics Material Devices and Simple Circuits
151323
Sum of the two binary numbers \((100010)_2\) and \((11011)_2\) is-
1 \((111111)_2\)
2 \((101111)_2\)
3 \((111001)_2\)
4 \((111101)_2\)
Explanation:
D Sum of given two binary number \(\begin{array}{r} (100010)_2\) \(+(11011)_2\) \(\hline(111101)_2 \end{array}\) Rule \(\left\{\begin{array}{l} 0+1=1\) \(1+1=10 \end{array}\right\}\)
