Semiconductor Electronics Material Devices and Simple Circuits
151324
A logic gate having two inputs \(A\) and \(B\) and output \(\mathrm{C}\) has the following truth table {c|c|c} | \(\) \(\) \(\)\)| |---| \( 1 1 0\) \( 1 0 1\) \( 0 1 1\) \( 0 0 1\) \( It is :
1 an OR gate
2 an AND gate
3 a NOR gate
4 a NAND gate
Explanation:
D Given truth table {|l|l|l|} | \(\) \(\) \(\)\)| |---| \( 1 1 0\) \(1 0 1\) \(0 1 1\) \(0 0 1\) \( Thus the Boolean expression will be \(\mathrm{Y}=\overline{\mathrm{A} \cdot \mathrm{B}}\)which represents NAND gate.
BCECE-2005
Semiconductor Electronics Material Devices and Simple Circuits
151326
For which logic gate the following statements is true? The output is high if and only if all inputs are high.
1 NAND
2 OR
3 AND
4 NOR
Explanation:
C We know that, for AND gate output is high if and only if all inputs are high. Truth table, {|l|l|l|} | \(\) \(\) \(\)\)| |---| \( 0 0 0\) \(0 1 0\) \(1 0 0\) \(1 1 1\) \( The Boolean expression of AND gate, \(\mathrm{Y}=\mathrm{A} \cdot \mathrm{B}\)
MHT-CET 2020
Semiconductor Electronics Material Devices and Simple Circuits
151327
The gate represented in the given figure is
1 NOR
2 AND
3 NOT
4 \(\mathrm{OR}\)
Explanation:
C Given logic gate Then Boolean expression, \(\mathrm{Y}=\overline{\mathrm{X}}\)Therefore, it is a NOT gate.
MHT-CET 2020
Semiconductor Electronics Material Devices and Simple Circuits
151328
The resultant gate and its Boolean expression for the given circuit is
Semiconductor Electronics Material Devices and Simple Circuits
151324
A logic gate having two inputs \(A\) and \(B\) and output \(\mathrm{C}\) has the following truth table {c|c|c} | \(\) \(\) \(\)\)| |---| \( 1 1 0\) \( 1 0 1\) \( 0 1 1\) \( 0 0 1\) \( It is :
1 an OR gate
2 an AND gate
3 a NOR gate
4 a NAND gate
Explanation:
D Given truth table {|l|l|l|} | \(\) \(\) \(\)\)| |---| \( 1 1 0\) \(1 0 1\) \(0 1 1\) \(0 0 1\) \( Thus the Boolean expression will be \(\mathrm{Y}=\overline{\mathrm{A} \cdot \mathrm{B}}\)which represents NAND gate.
BCECE-2005
Semiconductor Electronics Material Devices and Simple Circuits
151326
For which logic gate the following statements is true? The output is high if and only if all inputs are high.
1 NAND
2 OR
3 AND
4 NOR
Explanation:
C We know that, for AND gate output is high if and only if all inputs are high. Truth table, {|l|l|l|} | \(\) \(\) \(\)\)| |---| \( 0 0 0\) \(0 1 0\) \(1 0 0\) \(1 1 1\) \( The Boolean expression of AND gate, \(\mathrm{Y}=\mathrm{A} \cdot \mathrm{B}\)
MHT-CET 2020
Semiconductor Electronics Material Devices and Simple Circuits
151327
The gate represented in the given figure is
1 NOR
2 AND
3 NOT
4 \(\mathrm{OR}\)
Explanation:
C Given logic gate Then Boolean expression, \(\mathrm{Y}=\overline{\mathrm{X}}\)Therefore, it is a NOT gate.
MHT-CET 2020
Semiconductor Electronics Material Devices and Simple Circuits
151328
The resultant gate and its Boolean expression for the given circuit is
Semiconductor Electronics Material Devices and Simple Circuits
151324
A logic gate having two inputs \(A\) and \(B\) and output \(\mathrm{C}\) has the following truth table {c|c|c} | \(\) \(\) \(\)\)| |---| \( 1 1 0\) \( 1 0 1\) \( 0 1 1\) \( 0 0 1\) \( It is :
1 an OR gate
2 an AND gate
3 a NOR gate
4 a NAND gate
Explanation:
D Given truth table {|l|l|l|} | \(\) \(\) \(\)\)| |---| \( 1 1 0\) \(1 0 1\) \(0 1 1\) \(0 0 1\) \( Thus the Boolean expression will be \(\mathrm{Y}=\overline{\mathrm{A} \cdot \mathrm{B}}\)which represents NAND gate.
BCECE-2005
Semiconductor Electronics Material Devices and Simple Circuits
151326
For which logic gate the following statements is true? The output is high if and only if all inputs are high.
1 NAND
2 OR
3 AND
4 NOR
Explanation:
C We know that, for AND gate output is high if and only if all inputs are high. Truth table, {|l|l|l|} | \(\) \(\) \(\)\)| |---| \( 0 0 0\) \(0 1 0\) \(1 0 0\) \(1 1 1\) \( The Boolean expression of AND gate, \(\mathrm{Y}=\mathrm{A} \cdot \mathrm{B}\)
MHT-CET 2020
Semiconductor Electronics Material Devices and Simple Circuits
151327
The gate represented in the given figure is
1 NOR
2 AND
3 NOT
4 \(\mathrm{OR}\)
Explanation:
C Given logic gate Then Boolean expression, \(\mathrm{Y}=\overline{\mathrm{X}}\)Therefore, it is a NOT gate.
MHT-CET 2020
Semiconductor Electronics Material Devices and Simple Circuits
151328
The resultant gate and its Boolean expression for the given circuit is
Semiconductor Electronics Material Devices and Simple Circuits
151324
A logic gate having two inputs \(A\) and \(B\) and output \(\mathrm{C}\) has the following truth table {c|c|c} | \(\) \(\) \(\)\)| |---| \( 1 1 0\) \( 1 0 1\) \( 0 1 1\) \( 0 0 1\) \( It is :
1 an OR gate
2 an AND gate
3 a NOR gate
4 a NAND gate
Explanation:
D Given truth table {|l|l|l|} | \(\) \(\) \(\)\)| |---| \( 1 1 0\) \(1 0 1\) \(0 1 1\) \(0 0 1\) \( Thus the Boolean expression will be \(\mathrm{Y}=\overline{\mathrm{A} \cdot \mathrm{B}}\)which represents NAND gate.
BCECE-2005
Semiconductor Electronics Material Devices and Simple Circuits
151326
For which logic gate the following statements is true? The output is high if and only if all inputs are high.
1 NAND
2 OR
3 AND
4 NOR
Explanation:
C We know that, for AND gate output is high if and only if all inputs are high. Truth table, {|l|l|l|} | \(\) \(\) \(\)\)| |---| \( 0 0 0\) \(0 1 0\) \(1 0 0\) \(1 1 1\) \( The Boolean expression of AND gate, \(\mathrm{Y}=\mathrm{A} \cdot \mathrm{B}\)
MHT-CET 2020
Semiconductor Electronics Material Devices and Simple Circuits
151327
The gate represented in the given figure is
1 NOR
2 AND
3 NOT
4 \(\mathrm{OR}\)
Explanation:
C Given logic gate Then Boolean expression, \(\mathrm{Y}=\overline{\mathrm{X}}\)Therefore, it is a NOT gate.
MHT-CET 2020
Semiconductor Electronics Material Devices and Simple Circuits
151328
The resultant gate and its Boolean expression for the given circuit is
