Semiconductor Electronics Material Devices and Simple Circuits
151277
For the combination of gates shown here, which of the following truth table part is not true?
1 \(\mathrm{A}=0, \mathrm{~B}=1, \mathrm{C}=1\)
2 \(\mathrm{A}=0, \mathrm{~B}=0, \mathrm{C}=0\)
3 \(\mathrm{A}=1, \mathrm{~B}=1, \mathrm{C}=1\)
4 \(\mathrm{A}=1, \mathrm{~B}=0, \mathrm{C}=1\)
Explanation:
B Equivalent truth table can be written as {|c|c|c|c|} | A B A.B A+A.B=C\)| |---| \( 0 1 0 0\) \( 1 0 0 1\) \( 0 0 0 0\) \( 1 1 1 1\) \( Option (a) can't justify the above truth table.
UPSEE - 2016
Semiconductor Electronics Material Devices and Simple Circuits
151282
A logic gate and its truth table are shown below {|l|l|l|} | \(\) \(\) \(\)\)| |---| \( 0 0 0\) \(0 1 1\) \(1 0 1\) \(1 1 1\) \( The gate is :
1 NOR
2 AND
3 OR
4 NOT
Explanation:
C Truth table of given circuit is, {|c|c|c|} | { Input } output\)| |---| \( \(\) \(\) \(=+\)\) \( 0 0 0\) \( 0 1 1\) \( 1 0 1\) \( 1 1 1\) \(
UPSEE - 2005
Semiconductor Electronics Material Devices and Simple Circuits
151283
A gate in which all inputs must be low to get a high output is called :
1 a NAND gate
2 an inverter
3 a NOR gate
4 an AND gate
Explanation:
C A logic gate in which all inputs must be low to get a high output is called NOR gate. {|c|c|c|} | { Input } output\)| |---| \( \(\) \(\) \(=+\)\) \( 0 0 1\) \( 0 1 0\) \( 1 0 0\) \( 1 1 0\) \(
UPSEE - 2004
Semiconductor Electronics Material Devices and Simple Circuits
151285
Three variable Boolean expression \(P Q+P Q R\) \(+\overline{\mathrm{P}} \mathrm{Q}+\mathrm{P} \overline{\mathrm{Q}} \mathrm{R}\) can be written as
Semiconductor Electronics Material Devices and Simple Circuits
151286
The circuit gives the output as that of
1 AND gate
2 OR gate
3 NAND gate
4 NOR gate
5 NOT gate
Explanation:
B From given circuit the output is \(\mathrm{Y} =\overline{\overline{\mathrm{A} \cdot \mathrm{B}}+\overline{\mathrm{C}}}=\overline{\overline{\mathrm{A} \cdot \mathrm{B}}} \overline{\overline{\mathrm{C}}}\) \(=\mathrm{A} \cdot \mathrm{B} \cdot \mathrm{C}=\text { AND gate }\)Output is high only when all inputs are high as that of AND gate.
Semiconductor Electronics Material Devices and Simple Circuits
151277
For the combination of gates shown here, which of the following truth table part is not true?
1 \(\mathrm{A}=0, \mathrm{~B}=1, \mathrm{C}=1\)
2 \(\mathrm{A}=0, \mathrm{~B}=0, \mathrm{C}=0\)
3 \(\mathrm{A}=1, \mathrm{~B}=1, \mathrm{C}=1\)
4 \(\mathrm{A}=1, \mathrm{~B}=0, \mathrm{C}=1\)
Explanation:
B Equivalent truth table can be written as {|c|c|c|c|} | A B A.B A+A.B=C\)| |---| \( 0 1 0 0\) \( 1 0 0 1\) \( 0 0 0 0\) \( 1 1 1 1\) \( Option (a) can't justify the above truth table.
UPSEE - 2016
Semiconductor Electronics Material Devices and Simple Circuits
151282
A logic gate and its truth table are shown below {|l|l|l|} | \(\) \(\) \(\)\)| |---| \( 0 0 0\) \(0 1 1\) \(1 0 1\) \(1 1 1\) \( The gate is :
1 NOR
2 AND
3 OR
4 NOT
Explanation:
C Truth table of given circuit is, {|c|c|c|} | { Input } output\)| |---| \( \(\) \(\) \(=+\)\) \( 0 0 0\) \( 0 1 1\) \( 1 0 1\) \( 1 1 1\) \(
UPSEE - 2005
Semiconductor Electronics Material Devices and Simple Circuits
151283
A gate in which all inputs must be low to get a high output is called :
1 a NAND gate
2 an inverter
3 a NOR gate
4 an AND gate
Explanation:
C A logic gate in which all inputs must be low to get a high output is called NOR gate. {|c|c|c|} | { Input } output\)| |---| \( \(\) \(\) \(=+\)\) \( 0 0 1\) \( 0 1 0\) \( 1 0 0\) \( 1 1 0\) \(
UPSEE - 2004
Semiconductor Electronics Material Devices and Simple Circuits
151285
Three variable Boolean expression \(P Q+P Q R\) \(+\overline{\mathrm{P}} \mathrm{Q}+\mathrm{P} \overline{\mathrm{Q}} \mathrm{R}\) can be written as
Semiconductor Electronics Material Devices and Simple Circuits
151286
The circuit gives the output as that of
1 AND gate
2 OR gate
3 NAND gate
4 NOR gate
5 NOT gate
Explanation:
B From given circuit the output is \(\mathrm{Y} =\overline{\overline{\mathrm{A} \cdot \mathrm{B}}+\overline{\mathrm{C}}}=\overline{\overline{\mathrm{A} \cdot \mathrm{B}}} \overline{\overline{\mathrm{C}}}\) \(=\mathrm{A} \cdot \mathrm{B} \cdot \mathrm{C}=\text { AND gate }\)Output is high only when all inputs are high as that of AND gate.
Semiconductor Electronics Material Devices and Simple Circuits
151277
For the combination of gates shown here, which of the following truth table part is not true?
1 \(\mathrm{A}=0, \mathrm{~B}=1, \mathrm{C}=1\)
2 \(\mathrm{A}=0, \mathrm{~B}=0, \mathrm{C}=0\)
3 \(\mathrm{A}=1, \mathrm{~B}=1, \mathrm{C}=1\)
4 \(\mathrm{A}=1, \mathrm{~B}=0, \mathrm{C}=1\)
Explanation:
B Equivalent truth table can be written as {|c|c|c|c|} | A B A.B A+A.B=C\)| |---| \( 0 1 0 0\) \( 1 0 0 1\) \( 0 0 0 0\) \( 1 1 1 1\) \( Option (a) can't justify the above truth table.
UPSEE - 2016
Semiconductor Electronics Material Devices and Simple Circuits
151282
A logic gate and its truth table are shown below {|l|l|l|} | \(\) \(\) \(\)\)| |---| \( 0 0 0\) \(0 1 1\) \(1 0 1\) \(1 1 1\) \( The gate is :
1 NOR
2 AND
3 OR
4 NOT
Explanation:
C Truth table of given circuit is, {|c|c|c|} | { Input } output\)| |---| \( \(\) \(\) \(=+\)\) \( 0 0 0\) \( 0 1 1\) \( 1 0 1\) \( 1 1 1\) \(
UPSEE - 2005
Semiconductor Electronics Material Devices and Simple Circuits
151283
A gate in which all inputs must be low to get a high output is called :
1 a NAND gate
2 an inverter
3 a NOR gate
4 an AND gate
Explanation:
C A logic gate in which all inputs must be low to get a high output is called NOR gate. {|c|c|c|} | { Input } output\)| |---| \( \(\) \(\) \(=+\)\) \( 0 0 1\) \( 0 1 0\) \( 1 0 0\) \( 1 1 0\) \(
UPSEE - 2004
Semiconductor Electronics Material Devices and Simple Circuits
151285
Three variable Boolean expression \(P Q+P Q R\) \(+\overline{\mathrm{P}} \mathrm{Q}+\mathrm{P} \overline{\mathrm{Q}} \mathrm{R}\) can be written as
Semiconductor Electronics Material Devices and Simple Circuits
151286
The circuit gives the output as that of
1 AND gate
2 OR gate
3 NAND gate
4 NOR gate
5 NOT gate
Explanation:
B From given circuit the output is \(\mathrm{Y} =\overline{\overline{\mathrm{A} \cdot \mathrm{B}}+\overline{\mathrm{C}}}=\overline{\overline{\mathrm{A} \cdot \mathrm{B}}} \overline{\overline{\mathrm{C}}}\) \(=\mathrm{A} \cdot \mathrm{B} \cdot \mathrm{C}=\text { AND gate }\)Output is high only when all inputs are high as that of AND gate.
Semiconductor Electronics Material Devices and Simple Circuits
151277
For the combination of gates shown here, which of the following truth table part is not true?
1 \(\mathrm{A}=0, \mathrm{~B}=1, \mathrm{C}=1\)
2 \(\mathrm{A}=0, \mathrm{~B}=0, \mathrm{C}=0\)
3 \(\mathrm{A}=1, \mathrm{~B}=1, \mathrm{C}=1\)
4 \(\mathrm{A}=1, \mathrm{~B}=0, \mathrm{C}=1\)
Explanation:
B Equivalent truth table can be written as {|c|c|c|c|} | A B A.B A+A.B=C\)| |---| \( 0 1 0 0\) \( 1 0 0 1\) \( 0 0 0 0\) \( 1 1 1 1\) \( Option (a) can't justify the above truth table.
UPSEE - 2016
Semiconductor Electronics Material Devices and Simple Circuits
151282
A logic gate and its truth table are shown below {|l|l|l|} | \(\) \(\) \(\)\)| |---| \( 0 0 0\) \(0 1 1\) \(1 0 1\) \(1 1 1\) \( The gate is :
1 NOR
2 AND
3 OR
4 NOT
Explanation:
C Truth table of given circuit is, {|c|c|c|} | { Input } output\)| |---| \( \(\) \(\) \(=+\)\) \( 0 0 0\) \( 0 1 1\) \( 1 0 1\) \( 1 1 1\) \(
UPSEE - 2005
Semiconductor Electronics Material Devices and Simple Circuits
151283
A gate in which all inputs must be low to get a high output is called :
1 a NAND gate
2 an inverter
3 a NOR gate
4 an AND gate
Explanation:
C A logic gate in which all inputs must be low to get a high output is called NOR gate. {|c|c|c|} | { Input } output\)| |---| \( \(\) \(\) \(=+\)\) \( 0 0 1\) \( 0 1 0\) \( 1 0 0\) \( 1 1 0\) \(
UPSEE - 2004
Semiconductor Electronics Material Devices and Simple Circuits
151285
Three variable Boolean expression \(P Q+P Q R\) \(+\overline{\mathrm{P}} \mathrm{Q}+\mathrm{P} \overline{\mathrm{Q}} \mathrm{R}\) can be written as
Semiconductor Electronics Material Devices and Simple Circuits
151286
The circuit gives the output as that of
1 AND gate
2 OR gate
3 NAND gate
4 NOR gate
5 NOT gate
Explanation:
B From given circuit the output is \(\mathrm{Y} =\overline{\overline{\mathrm{A} \cdot \mathrm{B}}+\overline{\mathrm{C}}}=\overline{\overline{\mathrm{A} \cdot \mathrm{B}}} \overline{\overline{\mathrm{C}}}\) \(=\mathrm{A} \cdot \mathrm{B} \cdot \mathrm{C}=\text { AND gate }\)Output is high only when all inputs are high as that of AND gate.
Semiconductor Electronics Material Devices and Simple Circuits
151277
For the combination of gates shown here, which of the following truth table part is not true?
1 \(\mathrm{A}=0, \mathrm{~B}=1, \mathrm{C}=1\)
2 \(\mathrm{A}=0, \mathrm{~B}=0, \mathrm{C}=0\)
3 \(\mathrm{A}=1, \mathrm{~B}=1, \mathrm{C}=1\)
4 \(\mathrm{A}=1, \mathrm{~B}=0, \mathrm{C}=1\)
Explanation:
B Equivalent truth table can be written as {|c|c|c|c|} | A B A.B A+A.B=C\)| |---| \( 0 1 0 0\) \( 1 0 0 1\) \( 0 0 0 0\) \( 1 1 1 1\) \( Option (a) can't justify the above truth table.
UPSEE - 2016
Semiconductor Electronics Material Devices and Simple Circuits
151282
A logic gate and its truth table are shown below {|l|l|l|} | \(\) \(\) \(\)\)| |---| \( 0 0 0\) \(0 1 1\) \(1 0 1\) \(1 1 1\) \( The gate is :
1 NOR
2 AND
3 OR
4 NOT
Explanation:
C Truth table of given circuit is, {|c|c|c|} | { Input } output\)| |---| \( \(\) \(\) \(=+\)\) \( 0 0 0\) \( 0 1 1\) \( 1 0 1\) \( 1 1 1\) \(
UPSEE - 2005
Semiconductor Electronics Material Devices and Simple Circuits
151283
A gate in which all inputs must be low to get a high output is called :
1 a NAND gate
2 an inverter
3 a NOR gate
4 an AND gate
Explanation:
C A logic gate in which all inputs must be low to get a high output is called NOR gate. {|c|c|c|} | { Input } output\)| |---| \( \(\) \(\) \(=+\)\) \( 0 0 1\) \( 0 1 0\) \( 1 0 0\) \( 1 1 0\) \(
UPSEE - 2004
Semiconductor Electronics Material Devices and Simple Circuits
151285
Three variable Boolean expression \(P Q+P Q R\) \(+\overline{\mathrm{P}} \mathrm{Q}+\mathrm{P} \overline{\mathrm{Q}} \mathrm{R}\) can be written as
Semiconductor Electronics Material Devices and Simple Circuits
151286
The circuit gives the output as that of
1 AND gate
2 OR gate
3 NAND gate
4 NOR gate
5 NOT gate
Explanation:
B From given circuit the output is \(\mathrm{Y} =\overline{\overline{\mathrm{A} \cdot \mathrm{B}}+\overline{\mathrm{C}}}=\overline{\overline{\mathrm{A} \cdot \mathrm{B}}} \overline{\overline{\mathrm{C}}}\) \(=\mathrm{A} \cdot \mathrm{B} \cdot \mathrm{C}=\text { AND gate }\)Output is high only when all inputs are high as that of AND gate.
