142494 If $10000 \mathrm{~V}$ is applied across an $\mathrm{X}$-ray tube, what will be the ratio of de-Broglie wavelength of the incident electrons to the shortest wavelength $X$-ray produced?
$\left(\frac{\mathrm{e}}{\mathrm{m}}\right.$ for electron $\left.=1.8 \times 10^{11} \mathrm{C} \mathrm{kg}^{-1}\right)$

142495 When the kinetic energy of an electron is increased, the wavelength of the associated wave will

142498 Monochromatic light of frequency $6.0 \times 10^{14} \mathrm{~Hz}$ is produced by a laser. The power emitted is $2 \times 10^{-3} \mathrm{~W}$. The number of photons emitted, on the average, by the source per second is

142501 An electron and a proton have same de-Broglie wavelength, then kinetic energy of the electron is :

142503 If alpha particle and deuteron move with velocity $v$ and $2 v$ respectively, the ratio of their de-Broglie wave length will be

142494 If $10000 \mathrm{~V}$ is applied across an $\mathrm{X}$-ray tube, what will be the ratio of de-Broglie wavelength of the incident electrons to the shortest wavelength $X$-ray produced?
$\left(\frac{\mathrm{e}}{\mathrm{m}}\right.$ for electron $\left.=1.8 \times 10^{11} \mathrm{C} \mathrm{kg}^{-1}\right)$

142495 When the kinetic energy of an electron is increased, the wavelength of the associated wave will

142498 Monochromatic light of frequency $6.0 \times 10^{14} \mathrm{~Hz}$ is produced by a laser. The power emitted is $2 \times 10^{-3} \mathrm{~W}$. The number of photons emitted, on the average, by the source per second is

142501 An electron and a proton have same de-Broglie wavelength, then kinetic energy of the electron is :

142503 If alpha particle and deuteron move with velocity $v$ and $2 v$ respectively, the ratio of their de-Broglie wave length will be

142494 If $10000 \mathrm{~V}$ is applied across an $\mathrm{X}$-ray tube, what will be the ratio of de-Broglie wavelength of the incident electrons to the shortest wavelength $X$-ray produced?
$\left(\frac{\mathrm{e}}{\mathrm{m}}\right.$ for electron $\left.=1.8 \times 10^{11} \mathrm{C} \mathrm{kg}^{-1}\right)$

142495 When the kinetic energy of an electron is increased, the wavelength of the associated wave will

142498 Monochromatic light of frequency $6.0 \times 10^{14} \mathrm{~Hz}$ is produced by a laser. The power emitted is $2 \times 10^{-3} \mathrm{~W}$. The number of photons emitted, on the average, by the source per second is

142501 An electron and a proton have same de-Broglie wavelength, then kinetic energy of the electron is :

142503 If alpha particle and deuteron move with velocity $v$ and $2 v$ respectively, the ratio of their de-Broglie wave length will be

142494 If $10000 \mathrm{~V}$ is applied across an $\mathrm{X}$-ray tube, what will be the ratio of de-Broglie wavelength of the incident electrons to the shortest wavelength $X$-ray produced?
$\left(\frac{\mathrm{e}}{\mathrm{m}}\right.$ for electron $\left.=1.8 \times 10^{11} \mathrm{C} \mathrm{kg}^{-1}\right)$

142495 When the kinetic energy of an electron is increased, the wavelength of the associated wave will

142498 Monochromatic light of frequency $6.0 \times 10^{14} \mathrm{~Hz}$ is produced by a laser. The power emitted is $2 \times 10^{-3} \mathrm{~W}$. The number of photons emitted, on the average, by the source per second is

142501 An electron and a proton have same de-Broglie wavelength, then kinetic energy of the electron is :

142503 If alpha particle and deuteron move with velocity $v$ and $2 v$ respectively, the ratio of their de-Broglie wave length will be

142494 If $10000 \mathrm{~V}$ is applied across an $\mathrm{X}$-ray tube, what will be the ratio of de-Broglie wavelength of the incident electrons to the shortest wavelength $X$-ray produced?
$\left(\frac{\mathrm{e}}{\mathrm{m}}\right.$ for electron $\left.=1.8 \times 10^{11} \mathrm{C} \mathrm{kg}^{-1}\right)$

142495 When the kinetic energy of an electron is increased, the wavelength of the associated wave will

142498 Monochromatic light of frequency $6.0 \times 10^{14} \mathrm{~Hz}$ is produced by a laser. The power emitted is $2 \times 10^{-3} \mathrm{~W}$. The number of photons emitted, on the average, by the source per second is

142501 An electron and a proton have same de-Broglie wavelength, then kinetic energy of the electron is :

142503 If alpha particle and deuteron move with velocity $v$ and $2 v$ respectively, the ratio of their de-Broglie wave length will be