140398 The angular velocity and the amplitude of a simple pendulum is $\omega$ and $A$ respectively. At a displacement $x$ from the mean position, if its kinetic energy is $T$ and potential energy is $U$, then the ratio of $T$ to $U$ is

140399 In $\mathrm{SHM}$ restoring force is $\mathrm{F}=-\mathrm{kx}$, where $\mathrm{k}$ is force constant, $x$ is displacement and $A$ is amplitude of motion, then total energy depends upon

140400 The oscillation of a body on a smooth horizontal surface is represented by the equation,
$X=A \cos (\omega t)$
Where, $X=$ displacement at time $t$
$\omega=\text { frequency of oscillation }$
Which one of the following graphs shows correctly the variation a with $t$ ?

1

2

3

4
Here, $\mathbf{a}=$ acceleration at time $t$
$\mathbf{T}=$ Time period

140401 The total mechanical energy of a harmonic oscillator of $A=1 \mathrm{~m}$ and force constant 200 $\mathrm{Nm}^{-1}$ is $150 \mathrm{~J}$. Then

140404 A body is executing S.H.M. Its potential energy is $E_{1}$ and $E_{2}$ at displacement $x$ and $y$ respectively. The potential energy at displacement $(x+y)$ is

140398 The angular velocity and the amplitude of a simple pendulum is $\omega$ and $A$ respectively. At a displacement $x$ from the mean position, if its kinetic energy is $T$ and potential energy is $U$, then the ratio of $T$ to $U$ is

140399 In $\mathrm{SHM}$ restoring force is $\mathrm{F}=-\mathrm{kx}$, where $\mathrm{k}$ is force constant, $x$ is displacement and $A$ is amplitude of motion, then total energy depends upon

140400 The oscillation of a body on a smooth horizontal surface is represented by the equation,
$X=A \cos (\omega t)$
Where, $X=$ displacement at time $t$
$\omega=\text { frequency of oscillation }$
Which one of the following graphs shows correctly the variation a with $t$ ?

1

2

3

4
Here, $\mathbf{a}=$ acceleration at time $t$
$\mathbf{T}=$ Time period

140401 The total mechanical energy of a harmonic oscillator of $A=1 \mathrm{~m}$ and force constant 200 $\mathrm{Nm}^{-1}$ is $150 \mathrm{~J}$. Then

140404 A body is executing S.H.M. Its potential energy is $E_{1}$ and $E_{2}$ at displacement $x$ and $y$ respectively. The potential energy at displacement $(x+y)$ is

140398 The angular velocity and the amplitude of a simple pendulum is $\omega$ and $A$ respectively. At a displacement $x$ from the mean position, if its kinetic energy is $T$ and potential energy is $U$, then the ratio of $T$ to $U$ is

140399 In $\mathrm{SHM}$ restoring force is $\mathrm{F}=-\mathrm{kx}$, where $\mathrm{k}$ is force constant, $x$ is displacement and $A$ is amplitude of motion, then total energy depends upon

140400 The oscillation of a body on a smooth horizontal surface is represented by the equation,
$X=A \cos (\omega t)$
Where, $X=$ displacement at time $t$
$\omega=\text { frequency of oscillation }$
Which one of the following graphs shows correctly the variation a with $t$ ?

1

2

3

4
Here, $\mathbf{a}=$ acceleration at time $t$
$\mathbf{T}=$ Time period

140401 The total mechanical energy of a harmonic oscillator of $A=1 \mathrm{~m}$ and force constant 200 $\mathrm{Nm}^{-1}$ is $150 \mathrm{~J}$. Then

140404 A body is executing S.H.M. Its potential energy is $E_{1}$ and $E_{2}$ at displacement $x$ and $y$ respectively. The potential energy at displacement $(x+y)$ is

140398 The angular velocity and the amplitude of a simple pendulum is $\omega$ and $A$ respectively. At a displacement $x$ from the mean position, if its kinetic energy is $T$ and potential energy is $U$, then the ratio of $T$ to $U$ is

140399 In $\mathrm{SHM}$ restoring force is $\mathrm{F}=-\mathrm{kx}$, where $\mathrm{k}$ is force constant, $x$ is displacement and $A$ is amplitude of motion, then total energy depends upon

140400 The oscillation of a body on a smooth horizontal surface is represented by the equation,
$X=A \cos (\omega t)$
Where, $X=$ displacement at time $t$
$\omega=\text { frequency of oscillation }$
Which one of the following graphs shows correctly the variation a with $t$ ?

1

2

3

4
Here, $\mathbf{a}=$ acceleration at time $t$
$\mathbf{T}=$ Time period

140401 The total mechanical energy of a harmonic oscillator of $A=1 \mathrm{~m}$ and force constant 200 $\mathrm{Nm}^{-1}$ is $150 \mathrm{~J}$. Then

140404 A body is executing S.H.M. Its potential energy is $E_{1}$ and $E_{2}$ at displacement $x$ and $y$ respectively. The potential energy at displacement $(x+y)$ is

140398 The angular velocity and the amplitude of a simple pendulum is $\omega$ and $A$ respectively. At a displacement $x$ from the mean position, if its kinetic energy is $T$ and potential energy is $U$, then the ratio of $T$ to $U$ is

140399 In $\mathrm{SHM}$ restoring force is $\mathrm{F}=-\mathrm{kx}$, where $\mathrm{k}$ is force constant, $x$ is displacement and $A$ is amplitude of motion, then total energy depends upon

140400 The oscillation of a body on a smooth horizontal surface is represented by the equation,
$X=A \cos (\omega t)$
Where, $X=$ displacement at time $t$
$\omega=\text { frequency of oscillation }$
Which one of the following graphs shows correctly the variation a with $t$ ?

1

2

3

4
Here, $\mathbf{a}=$ acceleration at time $t$
$\mathbf{T}=$ Time period

140401 The total mechanical energy of a harmonic oscillator of $A=1 \mathrm{~m}$ and force constant 200 $\mathrm{Nm}^{-1}$ is $150 \mathrm{~J}$. Then

140404 A body is executing S.H.M. Its potential energy is $E_{1}$ and $E_{2}$ at displacement $x$ and $y$ respectively. The potential energy at displacement $(x+y)$ is