NEET Test Series from KOTA - 10 Papers In MS WORD
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Moving Charges & Magnetism
153373
The lines of force of a uniform magnetic field:
1 must be convergent.
2 must be divergent.
3 must be parallel to each other.
4 intersect.
Explanation:
C The lines of force, which are represented by arrow, are parallel in a uniform magnetic field planes. - A uniform magnetic must be parallel to each other.
NDA (I) 2011
Moving Charges & Magnetism
153374
A positively charged particle projected towards west is deflected towards north by a magnetic field. The direction of the magnetic field is
1 towards South
2 towards east
3 in downward direction
4 in upward direction
Explanation:
D The direction of the magnetic field can be determined using the Flemings left hand rule. When a positively charged particle projected towards west is deflected towards north by a magnetic field then the direction of current will be the same towards west and direction of magnetic force is towards north. Hence, according to Fleming left hand rule, the direction of magnetic field will be upwards.
NDA (I) 2013
Moving Charges & Magnetism
153377
If we double the radius of a coil keeping the current through it unchanged, then the magnetic field at any point at a large distance from the centre becomes approximately
1 double
2 three times
3 four times
4 one-fourth
Explanation:
C Magnetic field at an axial point $d>>R$ is $B=\frac{\mu_{0} I R^{2}}{2\left(d^{2}+R^{2}\right)^{3 / 2}}$ $B=\left(\frac{\mu_{0} I}{2 d^{3}}\right) R^{2}$ Where $I$ and $d$ is constant, we get $B \propto R^{2}$ Thus, when radius is doubled, the magnetic field becomes four times hence option (c) is correct.
AIIMS-2014
Moving Charges & Magnetism
153380
What is the magnetic field at a distance $\mathbf{R}$ from a coil of radius $r$ carrying current $I$ ?
B This can be resolved into two component, one along the axis OP and other PS, which is perpendicular to OP. So, the total magnetic field at a point which is at a distance $\mathrm{x}$ away from the axis of a circular coil of radius $r$ is given by. $\mathrm{B}_{\mathrm{x}}=\frac{\mu_{0} \mathrm{Ir}^{2}}{2\left(\mathrm{R}^{2}+\mathrm{r}^{2}\right)^{3 / 2}}$
153373
The lines of force of a uniform magnetic field:
1 must be convergent.
2 must be divergent.
3 must be parallel to each other.
4 intersect.
Explanation:
C The lines of force, which are represented by arrow, are parallel in a uniform magnetic field planes. - A uniform magnetic must be parallel to each other.
NDA (I) 2011
Moving Charges & Magnetism
153374
A positively charged particle projected towards west is deflected towards north by a magnetic field. The direction of the magnetic field is
1 towards South
2 towards east
3 in downward direction
4 in upward direction
Explanation:
D The direction of the magnetic field can be determined using the Flemings left hand rule. When a positively charged particle projected towards west is deflected towards north by a magnetic field then the direction of current will be the same towards west and direction of magnetic force is towards north. Hence, according to Fleming left hand rule, the direction of magnetic field will be upwards.
NDA (I) 2013
Moving Charges & Magnetism
153377
If we double the radius of a coil keeping the current through it unchanged, then the magnetic field at any point at a large distance from the centre becomes approximately
1 double
2 three times
3 four times
4 one-fourth
Explanation:
C Magnetic field at an axial point $d>>R$ is $B=\frac{\mu_{0} I R^{2}}{2\left(d^{2}+R^{2}\right)^{3 / 2}}$ $B=\left(\frac{\mu_{0} I}{2 d^{3}}\right) R^{2}$ Where $I$ and $d$ is constant, we get $B \propto R^{2}$ Thus, when radius is doubled, the magnetic field becomes four times hence option (c) is correct.
AIIMS-2014
Moving Charges & Magnetism
153380
What is the magnetic field at a distance $\mathbf{R}$ from a coil of radius $r$ carrying current $I$ ?
B This can be resolved into two component, one along the axis OP and other PS, which is perpendicular to OP. So, the total magnetic field at a point which is at a distance $\mathrm{x}$ away from the axis of a circular coil of radius $r$ is given by. $\mathrm{B}_{\mathrm{x}}=\frac{\mu_{0} \mathrm{Ir}^{2}}{2\left(\mathrm{R}^{2}+\mathrm{r}^{2}\right)^{3 / 2}}$
153373
The lines of force of a uniform magnetic field:
1 must be convergent.
2 must be divergent.
3 must be parallel to each other.
4 intersect.
Explanation:
C The lines of force, which are represented by arrow, are parallel in a uniform magnetic field planes. - A uniform magnetic must be parallel to each other.
NDA (I) 2011
Moving Charges & Magnetism
153374
A positively charged particle projected towards west is deflected towards north by a magnetic field. The direction of the magnetic field is
1 towards South
2 towards east
3 in downward direction
4 in upward direction
Explanation:
D The direction of the magnetic field can be determined using the Flemings left hand rule. When a positively charged particle projected towards west is deflected towards north by a magnetic field then the direction of current will be the same towards west and direction of magnetic force is towards north. Hence, according to Fleming left hand rule, the direction of magnetic field will be upwards.
NDA (I) 2013
Moving Charges & Magnetism
153377
If we double the radius of a coil keeping the current through it unchanged, then the magnetic field at any point at a large distance from the centre becomes approximately
1 double
2 three times
3 four times
4 one-fourth
Explanation:
C Magnetic field at an axial point $d>>R$ is $B=\frac{\mu_{0} I R^{2}}{2\left(d^{2}+R^{2}\right)^{3 / 2}}$ $B=\left(\frac{\mu_{0} I}{2 d^{3}}\right) R^{2}$ Where $I$ and $d$ is constant, we get $B \propto R^{2}$ Thus, when radius is doubled, the magnetic field becomes four times hence option (c) is correct.
AIIMS-2014
Moving Charges & Magnetism
153380
What is the magnetic field at a distance $\mathbf{R}$ from a coil of radius $r$ carrying current $I$ ?
B This can be resolved into two component, one along the axis OP and other PS, which is perpendicular to OP. So, the total magnetic field at a point which is at a distance $\mathrm{x}$ away from the axis of a circular coil of radius $r$ is given by. $\mathrm{B}_{\mathrm{x}}=\frac{\mu_{0} \mathrm{Ir}^{2}}{2\left(\mathrm{R}^{2}+\mathrm{r}^{2}\right)^{3 / 2}}$
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
Moving Charges & Magnetism
153373
The lines of force of a uniform magnetic field:
1 must be convergent.
2 must be divergent.
3 must be parallel to each other.
4 intersect.
Explanation:
C The lines of force, which are represented by arrow, are parallel in a uniform magnetic field planes. - A uniform magnetic must be parallel to each other.
NDA (I) 2011
Moving Charges & Magnetism
153374
A positively charged particle projected towards west is deflected towards north by a magnetic field. The direction of the magnetic field is
1 towards South
2 towards east
3 in downward direction
4 in upward direction
Explanation:
D The direction of the magnetic field can be determined using the Flemings left hand rule. When a positively charged particle projected towards west is deflected towards north by a magnetic field then the direction of current will be the same towards west and direction of magnetic force is towards north. Hence, according to Fleming left hand rule, the direction of magnetic field will be upwards.
NDA (I) 2013
Moving Charges & Magnetism
153377
If we double the radius of a coil keeping the current through it unchanged, then the magnetic field at any point at a large distance from the centre becomes approximately
1 double
2 three times
3 four times
4 one-fourth
Explanation:
C Magnetic field at an axial point $d>>R$ is $B=\frac{\mu_{0} I R^{2}}{2\left(d^{2}+R^{2}\right)^{3 / 2}}$ $B=\left(\frac{\mu_{0} I}{2 d^{3}}\right) R^{2}$ Where $I$ and $d$ is constant, we get $B \propto R^{2}$ Thus, when radius is doubled, the magnetic field becomes four times hence option (c) is correct.
AIIMS-2014
Moving Charges & Magnetism
153380
What is the magnetic field at a distance $\mathbf{R}$ from a coil of radius $r$ carrying current $I$ ?
B This can be resolved into two component, one along the axis OP and other PS, which is perpendicular to OP. So, the total magnetic field at a point which is at a distance $\mathrm{x}$ away from the axis of a circular coil of radius $r$ is given by. $\mathrm{B}_{\mathrm{x}}=\frac{\mu_{0} \mathrm{Ir}^{2}}{2\left(\mathrm{R}^{2}+\mathrm{r}^{2}\right)^{3 / 2}}$
