1 Ampere's law is : f $\overrightarrow{\mathrm{B}} \cdot \mathrm{d} \overrightarrow{\mathrm{S}}=\mu_{\mathrm{o}} \mathrm{i}_{\text {enc }}$
2 Faraday's law is : $\mathrm{e}=-\mathrm{e}_{\mathrm{o}} \frac{\mathrm{d} \phi_{\mathrm{B}}}{\mathrm{dt}}$
3 Biot-Savart law is : $\mathrm{d} \overrightarrow{\mathrm{B}}=\frac{\mu_{\mathrm{o}} \mathrm{i}}{4 \pi} \frac{\mathrm{d} \overrightarrow{\mathrm{s}} \times \overrightarrow{\mathrm{r}}}{\mathrm{r}^{3}}$
4 Gauss's law is : $\varepsilon_{\mathrm{o}} f \overrightarrow{\mathrm{E}} \cdot \mathrm{d} \overrightarrow{\mathrm{A}}=\mathrm{q}$
Explanation:
B Faraday's law basic law of electromagnetism which help us predict how a magnetic field would interact with an electric circuit to produce an electromotive force (EMF) $\mathrm{e}=-\mathrm{N} \frac{\mathrm{d} \phi}{\mathrm{dt}}$ Where -ve sign indicates the direction of induced emf.
AMU-2007
Moving Charges & Magnetism
153351
A charged particle moves through a magnetic field in a direction perpendicular to it. Then, the
1 acceleration remains unchanged
2 velocity remains unchanged
3 speed of the particle remains uncahnged
4 direction of the particle remains unchanged
Explanation:
C Given, $\theta=90^{\circ}$ $\mathrm{F}=\mathrm{qVB} \sin \theta$ $\mathrm{F}=\mathrm{qVB} \sin 90^{\circ}$ $\mathrm{F}=\mathrm{qVB}$ Thus, speed will not be changed only direction will be changed.
CBSE AIPMT 2003
Moving Charges & Magnetism
153354
A uniform electric field and a uniform magnetic field are acting along the same direction in a certain region. If an electron is projected in the region such that its velocity is pointed along the direction of fields, then the electron
1 Speed will decrease
2 Speed will increase
3 will turn towards left of direction of motion
4 Will turn towards right of direction of motion
Explanation:
A From question, the electric field and magnetic field are acting along the same direction. $\mathrm{F}_{\mathrm{m}}=0$ Thus, the speed of electron will decrease.
AIPMT-2011
Moving Charges & Magnetism
153360
An electron moving in a circular orbit of radius $r$ makes $n$ rotations per second. The magnetic field produced at the centre has magnitude
1 $\frac{\mu_{0} \mathrm{ne}}{2 \pi \mathrm{r}}$
2 Zero
3 $\frac{\mu_{0} n^{2} \mathrm{e}}{\mathrm{r}}$
4 $\frac{\mu_{0} \mathrm{ne}}{2 \mathrm{r}}$
Explanation:
D Current due to the electron (e) rotation, $\mathrm{I}=$ ne Magnetic field at center of circular coil is $\vec{B}=\frac{\mu_{o} I}{2 r}$ $\vec{B}=\frac{\mu_{o} n e}{2 r}$
AIPMT-2015
Moving Charges & Magnetism
153371
A bar magnet is placed inside a uniform magnetic field. What does it experience?
1 A force
2 A torque
3 Both a force and a torque
4 Neither a force nor a torque
Explanation:
B A bar magnet placed inside a uniform magnetic field experience a torque. In a uniform magnetic field the two poles of the bar magnet experience equal and opposite forces. The force at one end nullifies the force at the other end. Hence, the bar magnet experience only the torque due to uniform magnetic field and thus the net force is zero. If bar magnet is placed in a non uniform magnetic field then it will experiences both torque as well as force.
1 Ampere's law is : f $\overrightarrow{\mathrm{B}} \cdot \mathrm{d} \overrightarrow{\mathrm{S}}=\mu_{\mathrm{o}} \mathrm{i}_{\text {enc }}$
2 Faraday's law is : $\mathrm{e}=-\mathrm{e}_{\mathrm{o}} \frac{\mathrm{d} \phi_{\mathrm{B}}}{\mathrm{dt}}$
3 Biot-Savart law is : $\mathrm{d} \overrightarrow{\mathrm{B}}=\frac{\mu_{\mathrm{o}} \mathrm{i}}{4 \pi} \frac{\mathrm{d} \overrightarrow{\mathrm{s}} \times \overrightarrow{\mathrm{r}}}{\mathrm{r}^{3}}$
4 Gauss's law is : $\varepsilon_{\mathrm{o}} f \overrightarrow{\mathrm{E}} \cdot \mathrm{d} \overrightarrow{\mathrm{A}}=\mathrm{q}$
Explanation:
B Faraday's law basic law of electromagnetism which help us predict how a magnetic field would interact with an electric circuit to produce an electromotive force (EMF) $\mathrm{e}=-\mathrm{N} \frac{\mathrm{d} \phi}{\mathrm{dt}}$ Where -ve sign indicates the direction of induced emf.
AMU-2007
Moving Charges & Magnetism
153351
A charged particle moves through a magnetic field in a direction perpendicular to it. Then, the
1 acceleration remains unchanged
2 velocity remains unchanged
3 speed of the particle remains uncahnged
4 direction of the particle remains unchanged
Explanation:
C Given, $\theta=90^{\circ}$ $\mathrm{F}=\mathrm{qVB} \sin \theta$ $\mathrm{F}=\mathrm{qVB} \sin 90^{\circ}$ $\mathrm{F}=\mathrm{qVB}$ Thus, speed will not be changed only direction will be changed.
CBSE AIPMT 2003
Moving Charges & Magnetism
153354
A uniform electric field and a uniform magnetic field are acting along the same direction in a certain region. If an electron is projected in the region such that its velocity is pointed along the direction of fields, then the electron
1 Speed will decrease
2 Speed will increase
3 will turn towards left of direction of motion
4 Will turn towards right of direction of motion
Explanation:
A From question, the electric field and magnetic field are acting along the same direction. $\mathrm{F}_{\mathrm{m}}=0$ Thus, the speed of electron will decrease.
AIPMT-2011
Moving Charges & Magnetism
153360
An electron moving in a circular orbit of radius $r$ makes $n$ rotations per second. The magnetic field produced at the centre has magnitude
1 $\frac{\mu_{0} \mathrm{ne}}{2 \pi \mathrm{r}}$
2 Zero
3 $\frac{\mu_{0} n^{2} \mathrm{e}}{\mathrm{r}}$
4 $\frac{\mu_{0} \mathrm{ne}}{2 \mathrm{r}}$
Explanation:
D Current due to the electron (e) rotation, $\mathrm{I}=$ ne Magnetic field at center of circular coil is $\vec{B}=\frac{\mu_{o} I}{2 r}$ $\vec{B}=\frac{\mu_{o} n e}{2 r}$
AIPMT-2015
Moving Charges & Magnetism
153371
A bar magnet is placed inside a uniform magnetic field. What does it experience?
1 A force
2 A torque
3 Both a force and a torque
4 Neither a force nor a torque
Explanation:
B A bar magnet placed inside a uniform magnetic field experience a torque. In a uniform magnetic field the two poles of the bar magnet experience equal and opposite forces. The force at one end nullifies the force at the other end. Hence, the bar magnet experience only the torque due to uniform magnetic field and thus the net force is zero. If bar magnet is placed in a non uniform magnetic field then it will experiences both torque as well as force.
1 Ampere's law is : f $\overrightarrow{\mathrm{B}} \cdot \mathrm{d} \overrightarrow{\mathrm{S}}=\mu_{\mathrm{o}} \mathrm{i}_{\text {enc }}$
2 Faraday's law is : $\mathrm{e}=-\mathrm{e}_{\mathrm{o}} \frac{\mathrm{d} \phi_{\mathrm{B}}}{\mathrm{dt}}$
3 Biot-Savart law is : $\mathrm{d} \overrightarrow{\mathrm{B}}=\frac{\mu_{\mathrm{o}} \mathrm{i}}{4 \pi} \frac{\mathrm{d} \overrightarrow{\mathrm{s}} \times \overrightarrow{\mathrm{r}}}{\mathrm{r}^{3}}$
4 Gauss's law is : $\varepsilon_{\mathrm{o}} f \overrightarrow{\mathrm{E}} \cdot \mathrm{d} \overrightarrow{\mathrm{A}}=\mathrm{q}$
Explanation:
B Faraday's law basic law of electromagnetism which help us predict how a magnetic field would interact with an electric circuit to produce an electromotive force (EMF) $\mathrm{e}=-\mathrm{N} \frac{\mathrm{d} \phi}{\mathrm{dt}}$ Where -ve sign indicates the direction of induced emf.
AMU-2007
Moving Charges & Magnetism
153351
A charged particle moves through a magnetic field in a direction perpendicular to it. Then, the
1 acceleration remains unchanged
2 velocity remains unchanged
3 speed of the particle remains uncahnged
4 direction of the particle remains unchanged
Explanation:
C Given, $\theta=90^{\circ}$ $\mathrm{F}=\mathrm{qVB} \sin \theta$ $\mathrm{F}=\mathrm{qVB} \sin 90^{\circ}$ $\mathrm{F}=\mathrm{qVB}$ Thus, speed will not be changed only direction will be changed.
CBSE AIPMT 2003
Moving Charges & Magnetism
153354
A uniform electric field and a uniform magnetic field are acting along the same direction in a certain region. If an electron is projected in the region such that its velocity is pointed along the direction of fields, then the electron
1 Speed will decrease
2 Speed will increase
3 will turn towards left of direction of motion
4 Will turn towards right of direction of motion
Explanation:
A From question, the electric field and magnetic field are acting along the same direction. $\mathrm{F}_{\mathrm{m}}=0$ Thus, the speed of electron will decrease.
AIPMT-2011
Moving Charges & Magnetism
153360
An electron moving in a circular orbit of radius $r$ makes $n$ rotations per second. The magnetic field produced at the centre has magnitude
1 $\frac{\mu_{0} \mathrm{ne}}{2 \pi \mathrm{r}}$
2 Zero
3 $\frac{\mu_{0} n^{2} \mathrm{e}}{\mathrm{r}}$
4 $\frac{\mu_{0} \mathrm{ne}}{2 \mathrm{r}}$
Explanation:
D Current due to the electron (e) rotation, $\mathrm{I}=$ ne Magnetic field at center of circular coil is $\vec{B}=\frac{\mu_{o} I}{2 r}$ $\vec{B}=\frac{\mu_{o} n e}{2 r}$
AIPMT-2015
Moving Charges & Magnetism
153371
A bar magnet is placed inside a uniform magnetic field. What does it experience?
1 A force
2 A torque
3 Both a force and a torque
4 Neither a force nor a torque
Explanation:
B A bar magnet placed inside a uniform magnetic field experience a torque. In a uniform magnetic field the two poles of the bar magnet experience equal and opposite forces. The force at one end nullifies the force at the other end. Hence, the bar magnet experience only the torque due to uniform magnetic field and thus the net force is zero. If bar magnet is placed in a non uniform magnetic field then it will experiences both torque as well as force.
1 Ampere's law is : f $\overrightarrow{\mathrm{B}} \cdot \mathrm{d} \overrightarrow{\mathrm{S}}=\mu_{\mathrm{o}} \mathrm{i}_{\text {enc }}$
2 Faraday's law is : $\mathrm{e}=-\mathrm{e}_{\mathrm{o}} \frac{\mathrm{d} \phi_{\mathrm{B}}}{\mathrm{dt}}$
3 Biot-Savart law is : $\mathrm{d} \overrightarrow{\mathrm{B}}=\frac{\mu_{\mathrm{o}} \mathrm{i}}{4 \pi} \frac{\mathrm{d} \overrightarrow{\mathrm{s}} \times \overrightarrow{\mathrm{r}}}{\mathrm{r}^{3}}$
4 Gauss's law is : $\varepsilon_{\mathrm{o}} f \overrightarrow{\mathrm{E}} \cdot \mathrm{d} \overrightarrow{\mathrm{A}}=\mathrm{q}$
Explanation:
B Faraday's law basic law of electromagnetism which help us predict how a magnetic field would interact with an electric circuit to produce an electromotive force (EMF) $\mathrm{e}=-\mathrm{N} \frac{\mathrm{d} \phi}{\mathrm{dt}}$ Where -ve sign indicates the direction of induced emf.
AMU-2007
Moving Charges & Magnetism
153351
A charged particle moves through a magnetic field in a direction perpendicular to it. Then, the
1 acceleration remains unchanged
2 velocity remains unchanged
3 speed of the particle remains uncahnged
4 direction of the particle remains unchanged
Explanation:
C Given, $\theta=90^{\circ}$ $\mathrm{F}=\mathrm{qVB} \sin \theta$ $\mathrm{F}=\mathrm{qVB} \sin 90^{\circ}$ $\mathrm{F}=\mathrm{qVB}$ Thus, speed will not be changed only direction will be changed.
CBSE AIPMT 2003
Moving Charges & Magnetism
153354
A uniform electric field and a uniform magnetic field are acting along the same direction in a certain region. If an electron is projected in the region such that its velocity is pointed along the direction of fields, then the electron
1 Speed will decrease
2 Speed will increase
3 will turn towards left of direction of motion
4 Will turn towards right of direction of motion
Explanation:
A From question, the electric field and magnetic field are acting along the same direction. $\mathrm{F}_{\mathrm{m}}=0$ Thus, the speed of electron will decrease.
AIPMT-2011
Moving Charges & Magnetism
153360
An electron moving in a circular orbit of radius $r$ makes $n$ rotations per second. The magnetic field produced at the centre has magnitude
1 $\frac{\mu_{0} \mathrm{ne}}{2 \pi \mathrm{r}}$
2 Zero
3 $\frac{\mu_{0} n^{2} \mathrm{e}}{\mathrm{r}}$
4 $\frac{\mu_{0} \mathrm{ne}}{2 \mathrm{r}}$
Explanation:
D Current due to the electron (e) rotation, $\mathrm{I}=$ ne Magnetic field at center of circular coil is $\vec{B}=\frac{\mu_{o} I}{2 r}$ $\vec{B}=\frac{\mu_{o} n e}{2 r}$
AIPMT-2015
Moving Charges & Magnetism
153371
A bar magnet is placed inside a uniform magnetic field. What does it experience?
1 A force
2 A torque
3 Both a force and a torque
4 Neither a force nor a torque
Explanation:
B A bar magnet placed inside a uniform magnetic field experience a torque. In a uniform magnetic field the two poles of the bar magnet experience equal and opposite forces. The force at one end nullifies the force at the other end. Hence, the bar magnet experience only the torque due to uniform magnetic field and thus the net force is zero. If bar magnet is placed in a non uniform magnetic field then it will experiences both torque as well as force.
1 Ampere's law is : f $\overrightarrow{\mathrm{B}} \cdot \mathrm{d} \overrightarrow{\mathrm{S}}=\mu_{\mathrm{o}} \mathrm{i}_{\text {enc }}$
2 Faraday's law is : $\mathrm{e}=-\mathrm{e}_{\mathrm{o}} \frac{\mathrm{d} \phi_{\mathrm{B}}}{\mathrm{dt}}$
3 Biot-Savart law is : $\mathrm{d} \overrightarrow{\mathrm{B}}=\frac{\mu_{\mathrm{o}} \mathrm{i}}{4 \pi} \frac{\mathrm{d} \overrightarrow{\mathrm{s}} \times \overrightarrow{\mathrm{r}}}{\mathrm{r}^{3}}$
4 Gauss's law is : $\varepsilon_{\mathrm{o}} f \overrightarrow{\mathrm{E}} \cdot \mathrm{d} \overrightarrow{\mathrm{A}}=\mathrm{q}$
Explanation:
B Faraday's law basic law of electromagnetism which help us predict how a magnetic field would interact with an electric circuit to produce an electromotive force (EMF) $\mathrm{e}=-\mathrm{N} \frac{\mathrm{d} \phi}{\mathrm{dt}}$ Where -ve sign indicates the direction of induced emf.
AMU-2007
Moving Charges & Magnetism
153351
A charged particle moves through a magnetic field in a direction perpendicular to it. Then, the
1 acceleration remains unchanged
2 velocity remains unchanged
3 speed of the particle remains uncahnged
4 direction of the particle remains unchanged
Explanation:
C Given, $\theta=90^{\circ}$ $\mathrm{F}=\mathrm{qVB} \sin \theta$ $\mathrm{F}=\mathrm{qVB} \sin 90^{\circ}$ $\mathrm{F}=\mathrm{qVB}$ Thus, speed will not be changed only direction will be changed.
CBSE AIPMT 2003
Moving Charges & Magnetism
153354
A uniform electric field and a uniform magnetic field are acting along the same direction in a certain region. If an electron is projected in the region such that its velocity is pointed along the direction of fields, then the electron
1 Speed will decrease
2 Speed will increase
3 will turn towards left of direction of motion
4 Will turn towards right of direction of motion
Explanation:
A From question, the electric field and magnetic field are acting along the same direction. $\mathrm{F}_{\mathrm{m}}=0$ Thus, the speed of electron will decrease.
AIPMT-2011
Moving Charges & Magnetism
153360
An electron moving in a circular orbit of radius $r$ makes $n$ rotations per second. The magnetic field produced at the centre has magnitude
1 $\frac{\mu_{0} \mathrm{ne}}{2 \pi \mathrm{r}}$
2 Zero
3 $\frac{\mu_{0} n^{2} \mathrm{e}}{\mathrm{r}}$
4 $\frac{\mu_{0} \mathrm{ne}}{2 \mathrm{r}}$
Explanation:
D Current due to the electron (e) rotation, $\mathrm{I}=$ ne Magnetic field at center of circular coil is $\vec{B}=\frac{\mu_{o} I}{2 r}$ $\vec{B}=\frac{\mu_{o} n e}{2 r}$
AIPMT-2015
Moving Charges & Magnetism
153371
A bar magnet is placed inside a uniform magnetic field. What does it experience?
1 A force
2 A torque
3 Both a force and a torque
4 Neither a force nor a torque
Explanation:
B A bar magnet placed inside a uniform magnetic field experience a torque. In a uniform magnetic field the two poles of the bar magnet experience equal and opposite forces. The force at one end nullifies the force at the other end. Hence, the bar magnet experience only the torque due to uniform magnetic field and thus the net force is zero. If bar magnet is placed in a non uniform magnetic field then it will experiences both torque as well as force.
