371598 The pressure \((P)\) and temperature \((T)\) relationship of an ideal gas obeys the equation \(P T^{2}=\) constant. The volume expansion coefficient of the gas will be

371599 When 2 moles of air is given 70 calorie of heat, its temperature changes from \(20^\circ C\) to \(25^\circ C\) at constant pressure. The amount of heat required to rise the temperature of air through same range \(\left( {20^\circ C} \right.\) to \(\left. {25^\circ C} \right)\) at constant volume is \(\left(\gamma=\dfrac{7}{5}\right)\)

371600 Assertion :
When a bottle of cold carbonated drink is opened, a slight fog forms around the opening.
Reason :
Adiabatic expansion of the gas causes lowering of temperature and condensation of water vapours.

371601 \(1\;c{m^3}\) of water at its boiling point absorbs \(540{\mkern 1mu} {\mkern 1mu} cal\) of heat to become steam with a volume of \(1671\;c{m^3}.\) If the atmospheric pressure \( = 1.013 \times {10^5}N{m^{ - 2}}\) and the mechanical equivalent of heat \( = 4.19\;J\,cal,\) the energy spent in this process in overcoming intermolecular forces is

371602 A sample of gas expands from volume \(V_{1}\) to \(V_{2}\). The amount of work done by the gas is greatest when the expansion is

371598 The pressure \((P)\) and temperature \((T)\) relationship of an ideal gas obeys the equation \(P T^{2}=\) constant. The volume expansion coefficient of the gas will be

371599 When 2 moles of air is given 70 calorie of heat, its temperature changes from \(20^\circ C\) to \(25^\circ C\) at constant pressure. The amount of heat required to rise the temperature of air through same range \(\left( {20^\circ C} \right.\) to \(\left. {25^\circ C} \right)\) at constant volume is \(\left(\gamma=\dfrac{7}{5}\right)\)

371600 Assertion :
When a bottle of cold carbonated drink is opened, a slight fog forms around the opening.
Reason :
Adiabatic expansion of the gas causes lowering of temperature and condensation of water vapours.

371601 \(1\;c{m^3}\) of water at its boiling point absorbs \(540{\mkern 1mu} {\mkern 1mu} cal\) of heat to become steam with a volume of \(1671\;c{m^3}.\) If the atmospheric pressure \( = 1.013 \times {10^5}N{m^{ - 2}}\) and the mechanical equivalent of heat \( = 4.19\;J\,cal,\) the energy spent in this process in overcoming intermolecular forces is

371602 A sample of gas expands from volume \(V_{1}\) to \(V_{2}\). The amount of work done by the gas is greatest when the expansion is

371598 The pressure \((P)\) and temperature \((T)\) relationship of an ideal gas obeys the equation \(P T^{2}=\) constant. The volume expansion coefficient of the gas will be

371599 When 2 moles of air is given 70 calorie of heat, its temperature changes from \(20^\circ C\) to \(25^\circ C\) at constant pressure. The amount of heat required to rise the temperature of air through same range \(\left( {20^\circ C} \right.\) to \(\left. {25^\circ C} \right)\) at constant volume is \(\left(\gamma=\dfrac{7}{5}\right)\)

371600 Assertion :
When a bottle of cold carbonated drink is opened, a slight fog forms around the opening.
Reason :
Adiabatic expansion of the gas causes lowering of temperature and condensation of water vapours.

371601 \(1\;c{m^3}\) of water at its boiling point absorbs \(540{\mkern 1mu} {\mkern 1mu} cal\) of heat to become steam with a volume of \(1671\;c{m^3}.\) If the atmospheric pressure \( = 1.013 \times {10^5}N{m^{ - 2}}\) and the mechanical equivalent of heat \( = 4.19\;J\,cal,\) the energy spent in this process in overcoming intermolecular forces is

371602 A sample of gas expands from volume \(V_{1}\) to \(V_{2}\). The amount of work done by the gas is greatest when the expansion is

371598 The pressure \((P)\) and temperature \((T)\) relationship of an ideal gas obeys the equation \(P T^{2}=\) constant. The volume expansion coefficient of the gas will be

371599 When 2 moles of air is given 70 calorie of heat, its temperature changes from \(20^\circ C\) to \(25^\circ C\) at constant pressure. The amount of heat required to rise the temperature of air through same range \(\left( {20^\circ C} \right.\) to \(\left. {25^\circ C} \right)\) at constant volume is \(\left(\gamma=\dfrac{7}{5}\right)\)

371600 Assertion :
When a bottle of cold carbonated drink is opened, a slight fog forms around the opening.
Reason :
Adiabatic expansion of the gas causes lowering of temperature and condensation of water vapours.

371601 \(1\;c{m^3}\) of water at its boiling point absorbs \(540{\mkern 1mu} {\mkern 1mu} cal\) of heat to become steam with a volume of \(1671\;c{m^3}.\) If the atmospheric pressure \( = 1.013 \times {10^5}N{m^{ - 2}}\) and the mechanical equivalent of heat \( = 4.19\;J\,cal,\) the energy spent in this process in overcoming intermolecular forces is

371602 A sample of gas expands from volume \(V_{1}\) to \(V_{2}\). The amount of work done by the gas is greatest when the expansion is

371598 The pressure \((P)\) and temperature \((T)\) relationship of an ideal gas obeys the equation \(P T^{2}=\) constant. The volume expansion coefficient of the gas will be

371599 When 2 moles of air is given 70 calorie of heat, its temperature changes from \(20^\circ C\) to \(25^\circ C\) at constant pressure. The amount of heat required to rise the temperature of air through same range \(\left( {20^\circ C} \right.\) to \(\left. {25^\circ C} \right)\) at constant volume is \(\left(\gamma=\dfrac{7}{5}\right)\)

371600 Assertion :
When a bottle of cold carbonated drink is opened, a slight fog forms around the opening.
Reason :
Adiabatic expansion of the gas causes lowering of temperature and condensation of water vapours.

371601 \(1\;c{m^3}\) of water at its boiling point absorbs \(540{\mkern 1mu} {\mkern 1mu} cal\) of heat to become steam with a volume of \(1671\;c{m^3}.\) If the atmospheric pressure \( = 1.013 \times {10^5}N{m^{ - 2}}\) and the mechanical equivalent of heat \( = 4.19\;J\,cal,\) the energy spent in this process in overcoming intermolecular forces is

371602 A sample of gas expands from volume \(V_{1}\) to \(V_{2}\). The amount of work done by the gas is greatest when the expansion is