371410
Assertion : The efficiency of a Carnot engine cannot be \(100 \%\). Reason : This is because 'Sink of heat' cannot be maintained at \(0 \mathrm{~K}\).
1 Both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
The efficiency of a Carnot engine cannot be \(100 \%\) because it depends on the temperature difference between the source and the sink, and maintaining the sink at absolute zero temperature is not possible. So correct option is (1).
PHXI12:THERMODYNAMICS
371411
The temperature-entropy diagram of reversible engine cycle is given in the figure. Its efficiency is
1 \(1 / 2\)
2 \(1 / 4\)
3 \(1 / 3\)
4 \(2 / 3\)
Explanation:
According to the figure, Heat energy from \(A\) to \(B\), \(Q_{1}=T_{0} S_{0}+\dfrac{1}{2} T_{0} S_{0}=\dfrac{3}{2} T_{0} S_{0}\) Heat, energy from \(B\) to \(C\), \(Q_{2}=T_{0}\left(2 S_{0}-S_{0}\right)=T_{0} S_{0}\) Heat energy from \(C\) to \(A\) \(\begin{aligned}& Q_{3}=0 \\& \Rightarrow \eta=\dfrac{W}{Q_{1}}=\dfrac{Q_{1}-Q_{2}}{Q_{1}} \\& \quad=1-\dfrac{Q_{2}}{Q_{1}}=1-\dfrac{2}{3}=\dfrac{1}{3}\end{aligned}\)
AIIMS - 2009
PHXI12:THERMODYNAMICS
371412
A Carnot engine has efficiency \(40 \%\) (sink at \(27^\circ C\) ). To increase efficiency to \(50 \%\), the temperature of the source has to be increased by
371410
Assertion : The efficiency of a Carnot engine cannot be \(100 \%\). Reason : This is because 'Sink of heat' cannot be maintained at \(0 \mathrm{~K}\).
1 Both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
The efficiency of a Carnot engine cannot be \(100 \%\) because it depends on the temperature difference between the source and the sink, and maintaining the sink at absolute zero temperature is not possible. So correct option is (1).
PHXI12:THERMODYNAMICS
371411
The temperature-entropy diagram of reversible engine cycle is given in the figure. Its efficiency is
1 \(1 / 2\)
2 \(1 / 4\)
3 \(1 / 3\)
4 \(2 / 3\)
Explanation:
According to the figure, Heat energy from \(A\) to \(B\), \(Q_{1}=T_{0} S_{0}+\dfrac{1}{2} T_{0} S_{0}=\dfrac{3}{2} T_{0} S_{0}\) Heat, energy from \(B\) to \(C\), \(Q_{2}=T_{0}\left(2 S_{0}-S_{0}\right)=T_{0} S_{0}\) Heat energy from \(C\) to \(A\) \(\begin{aligned}& Q_{3}=0 \\& \Rightarrow \eta=\dfrac{W}{Q_{1}}=\dfrac{Q_{1}-Q_{2}}{Q_{1}} \\& \quad=1-\dfrac{Q_{2}}{Q_{1}}=1-\dfrac{2}{3}=\dfrac{1}{3}\end{aligned}\)
AIIMS - 2009
PHXI12:THERMODYNAMICS
371412
A Carnot engine has efficiency \(40 \%\) (sink at \(27^\circ C\) ). To increase efficiency to \(50 \%\), the temperature of the source has to be increased by
NEET Test Series from KOTA - 10 Papers In MS WORD
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PHXI12:THERMODYNAMICS
371410
Assertion : The efficiency of a Carnot engine cannot be \(100 \%\). Reason : This is because 'Sink of heat' cannot be maintained at \(0 \mathrm{~K}\).
1 Both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
The efficiency of a Carnot engine cannot be \(100 \%\) because it depends on the temperature difference between the source and the sink, and maintaining the sink at absolute zero temperature is not possible. So correct option is (1).
PHXI12:THERMODYNAMICS
371411
The temperature-entropy diagram of reversible engine cycle is given in the figure. Its efficiency is
1 \(1 / 2\)
2 \(1 / 4\)
3 \(1 / 3\)
4 \(2 / 3\)
Explanation:
According to the figure, Heat energy from \(A\) to \(B\), \(Q_{1}=T_{0} S_{0}+\dfrac{1}{2} T_{0} S_{0}=\dfrac{3}{2} T_{0} S_{0}\) Heat, energy from \(B\) to \(C\), \(Q_{2}=T_{0}\left(2 S_{0}-S_{0}\right)=T_{0} S_{0}\) Heat energy from \(C\) to \(A\) \(\begin{aligned}& Q_{3}=0 \\& \Rightarrow \eta=\dfrac{W}{Q_{1}}=\dfrac{Q_{1}-Q_{2}}{Q_{1}} \\& \quad=1-\dfrac{Q_{2}}{Q_{1}}=1-\dfrac{2}{3}=\dfrac{1}{3}\end{aligned}\)
AIIMS - 2009
PHXI12:THERMODYNAMICS
371412
A Carnot engine has efficiency \(40 \%\) (sink at \(27^\circ C\) ). To increase efficiency to \(50 \%\), the temperature of the source has to be increased by
371410
Assertion : The efficiency of a Carnot engine cannot be \(100 \%\). Reason : This is because 'Sink of heat' cannot be maintained at \(0 \mathrm{~K}\).
1 Both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
The efficiency of a Carnot engine cannot be \(100 \%\) because it depends on the temperature difference between the source and the sink, and maintaining the sink at absolute zero temperature is not possible. So correct option is (1).
PHXI12:THERMODYNAMICS
371411
The temperature-entropy diagram of reversible engine cycle is given in the figure. Its efficiency is
1 \(1 / 2\)
2 \(1 / 4\)
3 \(1 / 3\)
4 \(2 / 3\)
Explanation:
According to the figure, Heat energy from \(A\) to \(B\), \(Q_{1}=T_{0} S_{0}+\dfrac{1}{2} T_{0} S_{0}=\dfrac{3}{2} T_{0} S_{0}\) Heat, energy from \(B\) to \(C\), \(Q_{2}=T_{0}\left(2 S_{0}-S_{0}\right)=T_{0} S_{0}\) Heat energy from \(C\) to \(A\) \(\begin{aligned}& Q_{3}=0 \\& \Rightarrow \eta=\dfrac{W}{Q_{1}}=\dfrac{Q_{1}-Q_{2}}{Q_{1}} \\& \quad=1-\dfrac{Q_{2}}{Q_{1}}=1-\dfrac{2}{3}=\dfrac{1}{3}\end{aligned}\)
AIIMS - 2009
PHXI12:THERMODYNAMICS
371412
A Carnot engine has efficiency \(40 \%\) (sink at \(27^\circ C\) ). To increase efficiency to \(50 \%\), the temperature of the source has to be increased by
