367477
Assertion : The watches having hour hand, minute hand and second hand have least count as \(1\;s\). Reason : Least count is the maximum measurement that can be measured accurately by an instrument.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
The least count of a watch with hour, minute, and second hand is 1 second. Least count is actually the smallest possible measurement that can be made by the instrument. So, the assertion is true, but the reason is false. So correct option is (3)
PHXI02:UNITS AND MEASUREMENTS
367478
The length, breadth, and thickness of a strip are \({(10.0 \pm 0.1) {cm},(1.00 \pm 0.01) {cm}}\), and \({(0.100 \pm}\) \({0.001) {cm}}\) respectively. The most probable error in its volume will be
367479
For a cubical block, error in measurement of sides is \( \pm 1\% \) and error in measurement of mass is \( \pm 2\% \), then maximum possible error in density is:
367480
A physical quantity \(Q\) is found to depend on quantities \(a, b, c\) by the relation \(Q=\dfrac{a^{4} b^{3}}{c^{2}}\). The percentage error in \(a, b\) and \(c\) are \(3 \%, 4 \%\) and \(5 \%\) respectively. Then, the percentage error in \(Q\) is
1 \(14 \%\)
2 \(43 \%\)
3 \(34 \%\)
4 \(66 \%\)
Explanation:
Given : \(Q=\dfrac{a^{4} b^{3}}{c^{2}} ; a \rightarrow 3 \%, b \rightarrow 4 \%, c \rightarrow 5 \%\) So, using error analysis, we can calculate the error as \(\dfrac{\Delta Q}{Q} \times 100 \%=\dfrac{4 \Delta a}{a} \times 100 \%+\dfrac{3 \Delta b}{b} \times 100 \%+\) \(\dfrac{2 \Delta c}{c} \times 100 \%\) \(=4 \times 3+3 \times 4+2 \times 5=34 \%\)
367477
Assertion : The watches having hour hand, minute hand and second hand have least count as \(1\;s\). Reason : Least count is the maximum measurement that can be measured accurately by an instrument.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
The least count of a watch with hour, minute, and second hand is 1 second. Least count is actually the smallest possible measurement that can be made by the instrument. So, the assertion is true, but the reason is false. So correct option is (3)
PHXI02:UNITS AND MEASUREMENTS
367478
The length, breadth, and thickness of a strip are \({(10.0 \pm 0.1) {cm},(1.00 \pm 0.01) {cm}}\), and \({(0.100 \pm}\) \({0.001) {cm}}\) respectively. The most probable error in its volume will be
367479
For a cubical block, error in measurement of sides is \( \pm 1\% \) and error in measurement of mass is \( \pm 2\% \), then maximum possible error in density is:
367480
A physical quantity \(Q\) is found to depend on quantities \(a, b, c\) by the relation \(Q=\dfrac{a^{4} b^{3}}{c^{2}}\). The percentage error in \(a, b\) and \(c\) are \(3 \%, 4 \%\) and \(5 \%\) respectively. Then, the percentage error in \(Q\) is
1 \(14 \%\)
2 \(43 \%\)
3 \(34 \%\)
4 \(66 \%\)
Explanation:
Given : \(Q=\dfrac{a^{4} b^{3}}{c^{2}} ; a \rightarrow 3 \%, b \rightarrow 4 \%, c \rightarrow 5 \%\) So, using error analysis, we can calculate the error as \(\dfrac{\Delta Q}{Q} \times 100 \%=\dfrac{4 \Delta a}{a} \times 100 \%+\dfrac{3 \Delta b}{b} \times 100 \%+\) \(\dfrac{2 \Delta c}{c} \times 100 \%\) \(=4 \times 3+3 \times 4+2 \times 5=34 \%\)
367477
Assertion : The watches having hour hand, minute hand and second hand have least count as \(1\;s\). Reason : Least count is the maximum measurement that can be measured accurately by an instrument.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
The least count of a watch with hour, minute, and second hand is 1 second. Least count is actually the smallest possible measurement that can be made by the instrument. So, the assertion is true, but the reason is false. So correct option is (3)
PHXI02:UNITS AND MEASUREMENTS
367478
The length, breadth, and thickness of a strip are \({(10.0 \pm 0.1) {cm},(1.00 \pm 0.01) {cm}}\), and \({(0.100 \pm}\) \({0.001) {cm}}\) respectively. The most probable error in its volume will be
367479
For a cubical block, error in measurement of sides is \( \pm 1\% \) and error in measurement of mass is \( \pm 2\% \), then maximum possible error in density is:
367480
A physical quantity \(Q\) is found to depend on quantities \(a, b, c\) by the relation \(Q=\dfrac{a^{4} b^{3}}{c^{2}}\). The percentage error in \(a, b\) and \(c\) are \(3 \%, 4 \%\) and \(5 \%\) respectively. Then, the percentage error in \(Q\) is
1 \(14 \%\)
2 \(43 \%\)
3 \(34 \%\)
4 \(66 \%\)
Explanation:
Given : \(Q=\dfrac{a^{4} b^{3}}{c^{2}} ; a \rightarrow 3 \%, b \rightarrow 4 \%, c \rightarrow 5 \%\) So, using error analysis, we can calculate the error as \(\dfrac{\Delta Q}{Q} \times 100 \%=\dfrac{4 \Delta a}{a} \times 100 \%+\dfrac{3 \Delta b}{b} \times 100 \%+\) \(\dfrac{2 \Delta c}{c} \times 100 \%\) \(=4 \times 3+3 \times 4+2 \times 5=34 \%\)
367477
Assertion : The watches having hour hand, minute hand and second hand have least count as \(1\;s\). Reason : Least count is the maximum measurement that can be measured accurately by an instrument.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
The least count of a watch with hour, minute, and second hand is 1 second. Least count is actually the smallest possible measurement that can be made by the instrument. So, the assertion is true, but the reason is false. So correct option is (3)
PHXI02:UNITS AND MEASUREMENTS
367478
The length, breadth, and thickness of a strip are \({(10.0 \pm 0.1) {cm},(1.00 \pm 0.01) {cm}}\), and \({(0.100 \pm}\) \({0.001) {cm}}\) respectively. The most probable error in its volume will be
367479
For a cubical block, error in measurement of sides is \( \pm 1\% \) and error in measurement of mass is \( \pm 2\% \), then maximum possible error in density is:
367480
A physical quantity \(Q\) is found to depend on quantities \(a, b, c\) by the relation \(Q=\dfrac{a^{4} b^{3}}{c^{2}}\). The percentage error in \(a, b\) and \(c\) are \(3 \%, 4 \%\) and \(5 \%\) respectively. Then, the percentage error in \(Q\) is
1 \(14 \%\)
2 \(43 \%\)
3 \(34 \%\)
4 \(66 \%\)
Explanation:
Given : \(Q=\dfrac{a^{4} b^{3}}{c^{2}} ; a \rightarrow 3 \%, b \rightarrow 4 \%, c \rightarrow 5 \%\) So, using error analysis, we can calculate the error as \(\dfrac{\Delta Q}{Q} \times 100 \%=\dfrac{4 \Delta a}{a} \times 100 \%+\dfrac{3 \Delta b}{b} \times 100 \%+\) \(\dfrac{2 \Delta c}{c} \times 100 \%\) \(=4 \times 3+3 \times 4+2 \times 5=34 \%\)
