367481 The errors in the measurement which arise due to unpredictable fluctuations in temperature and voltage supply are:

367482 The following observations were taken for determining surface tension \(\mathrm{T}\) of water by capillary method: Diameter of capillary \((D) = 1.50 \times {10^{ - 2}}\;m,\) Rise of water \((h) = 3.00 \times {10^{ - 2}}\;m.\) Using \(g = 9.80\;m{\rm{/}}{s^2}\) and the simplified relation \(T = \frac{{rhg}}{2} \times {10^3}\;N{\rm{/}}m,\) what is the possible error in \((\% )\) surface tension?

367483 The period of oscillation of a simple pendulum in the experiment is recorded as 2.63 \(s\), 2.56 \(s\), 2.42 \(s\), 2.71 \(s\) and 2.80 \(s\) respectively. The average absolute error is:

367484 Calculate the mean percentage error in five observations, \(80.0,80.5,81.0,81.5\) and 82 .

367485 Choose the incorrect statement out of the following.

367481 The errors in the measurement which arise due to unpredictable fluctuations in temperature and voltage supply are:

367482 The following observations were taken for determining surface tension \(\mathrm{T}\) of water by capillary method: Diameter of capillary \((D) = 1.50 \times {10^{ - 2}}\;m,\) Rise of water \((h) = 3.00 \times {10^{ - 2}}\;m.\) Using \(g = 9.80\;m{\rm{/}}{s^2}\) and the simplified relation \(T = \frac{{rhg}}{2} \times {10^3}\;N{\rm{/}}m,\) what is the possible error in \((\% )\) surface tension?

367483 The period of oscillation of a simple pendulum in the experiment is recorded as 2.63 \(s\), 2.56 \(s\), 2.42 \(s\), 2.71 \(s\) and 2.80 \(s\) respectively. The average absolute error is:

367484 Calculate the mean percentage error in five observations, \(80.0,80.5,81.0,81.5\) and 82 .

367485 Choose the incorrect statement out of the following.

367481 The errors in the measurement which arise due to unpredictable fluctuations in temperature and voltage supply are:

367482 The following observations were taken for determining surface tension \(\mathrm{T}\) of water by capillary method: Diameter of capillary \((D) = 1.50 \times {10^{ - 2}}\;m,\) Rise of water \((h) = 3.00 \times {10^{ - 2}}\;m.\) Using \(g = 9.80\;m{\rm{/}}{s^2}\) and the simplified relation \(T = \frac{{rhg}}{2} \times {10^3}\;N{\rm{/}}m,\) what is the possible error in \((\% )\) surface tension?

367483 The period of oscillation of a simple pendulum in the experiment is recorded as 2.63 \(s\), 2.56 \(s\), 2.42 \(s\), 2.71 \(s\) and 2.80 \(s\) respectively. The average absolute error is:

367484 Calculate the mean percentage error in five observations, \(80.0,80.5,81.0,81.5\) and 82 .

367485 Choose the incorrect statement out of the following.

367481 The errors in the measurement which arise due to unpredictable fluctuations in temperature and voltage supply are:

367482 The following observations were taken for determining surface tension \(\mathrm{T}\) of water by capillary method: Diameter of capillary \((D) = 1.50 \times {10^{ - 2}}\;m,\) Rise of water \((h) = 3.00 \times {10^{ - 2}}\;m.\) Using \(g = 9.80\;m{\rm{/}}{s^2}\) and the simplified relation \(T = \frac{{rhg}}{2} \times {10^3}\;N{\rm{/}}m,\) what is the possible error in \((\% )\) surface tension?

367483 The period of oscillation of a simple pendulum in the experiment is recorded as 2.63 \(s\), 2.56 \(s\), 2.42 \(s\), 2.71 \(s\) and 2.80 \(s\) respectively. The average absolute error is:

367484 Calculate the mean percentage error in five observations, \(80.0,80.5,81.0,81.5\) and 82 .

367485 Choose the incorrect statement out of the following.

367481 The errors in the measurement which arise due to unpredictable fluctuations in temperature and voltage supply are:

367482 The following observations were taken for determining surface tension \(\mathrm{T}\) of water by capillary method: Diameter of capillary \((D) = 1.50 \times {10^{ - 2}}\;m,\) Rise of water \((h) = 3.00 \times {10^{ - 2}}\;m.\) Using \(g = 9.80\;m{\rm{/}}{s^2}\) and the simplified relation \(T = \frac{{rhg}}{2} \times {10^3}\;N{\rm{/}}m,\) what is the possible error in \((\% )\) surface tension?

367483 The period of oscillation of a simple pendulum in the experiment is recorded as 2.63 \(s\), 2.56 \(s\), 2.42 \(s\), 2.71 \(s\) and 2.80 \(s\) respectively. The average absolute error is:

367484 Calculate the mean percentage error in five observations, \(80.0,80.5,81.0,81.5\) and 82 .

367485 Choose the incorrect statement out of the following.