367282
Find the dimensions of \(\frac{a}{b}\) in the equation \(P = \frac{{a - {t^2}}}{{bx}}\) where \(P\) is pressure, \(x\) is distance and \(t\) is time.
367283
Assertion : The equation \(y=x+t\) cannot be true, where \(x, y\) are distance and \(t\) is time. Reason : Quantities with different dimensions cannot be added.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
The given equation \((y=x+t)\) cannot be true, because time cannot be added to distance. So correct option is (1)
PHXI02:UNITS AND MEASUREMENTS
367284
Let Force \(F = A\sin (Ct) + B\cos (Dx)\), where \(x\) and \(t\) are displacment and time respectively,. The dimension of \(\frac{C}{D}\) are same as dimension of
1 Angular velocity
2 Velocity
3 Angular momentum
4 Velocity gradient
Explanation:
Given Force \(F = A\sin (Ct) + B\,\cos (Dx)\) Here, (\(Ct\) ) and (\(Dx\)) are dimensionless as they represent angles \(\therefore \left[ C \right] = \frac{1}{{\left[ t \right]}} = \left[ {{T^{ - 1}}} \right]\) and \(\left[ D \right] = \frac{1}{{\left[ x \right]}} = \left[ {{L^{ - 1}}} \right]\) Dimension of \(\frac{{\left[ C \right]}}{{\left[ D \right]}} = \frac{{\left[ {{T^{ - 1}}} \right]}}{{\left[ {{L^{ - 1}}} \right]}} = \left[ {L{T^{ - 1}}} \right]\) This is same as the dimension of velocity
367282
Find the dimensions of \(\frac{a}{b}\) in the equation \(P = \frac{{a - {t^2}}}{{bx}}\) where \(P\) is pressure, \(x\) is distance and \(t\) is time.
367283
Assertion : The equation \(y=x+t\) cannot be true, where \(x, y\) are distance and \(t\) is time. Reason : Quantities with different dimensions cannot be added.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
The given equation \((y=x+t)\) cannot be true, because time cannot be added to distance. So correct option is (1)
PHXI02:UNITS AND MEASUREMENTS
367284
Let Force \(F = A\sin (Ct) + B\cos (Dx)\), where \(x\) and \(t\) are displacment and time respectively,. The dimension of \(\frac{C}{D}\) are same as dimension of
1 Angular velocity
2 Velocity
3 Angular momentum
4 Velocity gradient
Explanation:
Given Force \(F = A\sin (Ct) + B\,\cos (Dx)\) Here, (\(Ct\) ) and (\(Dx\)) are dimensionless as they represent angles \(\therefore \left[ C \right] = \frac{1}{{\left[ t \right]}} = \left[ {{T^{ - 1}}} \right]\) and \(\left[ D \right] = \frac{1}{{\left[ x \right]}} = \left[ {{L^{ - 1}}} \right]\) Dimension of \(\frac{{\left[ C \right]}}{{\left[ D \right]}} = \frac{{\left[ {{T^{ - 1}}} \right]}}{{\left[ {{L^{ - 1}}} \right]}} = \left[ {L{T^{ - 1}}} \right]\) This is same as the dimension of velocity
367282
Find the dimensions of \(\frac{a}{b}\) in the equation \(P = \frac{{a - {t^2}}}{{bx}}\) where \(P\) is pressure, \(x\) is distance and \(t\) is time.
367283
Assertion : The equation \(y=x+t\) cannot be true, where \(x, y\) are distance and \(t\) is time. Reason : Quantities with different dimensions cannot be added.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
The given equation \((y=x+t)\) cannot be true, because time cannot be added to distance. So correct option is (1)
PHXI02:UNITS AND MEASUREMENTS
367284
Let Force \(F = A\sin (Ct) + B\cos (Dx)\), where \(x\) and \(t\) are displacment and time respectively,. The dimension of \(\frac{C}{D}\) are same as dimension of
1 Angular velocity
2 Velocity
3 Angular momentum
4 Velocity gradient
Explanation:
Given Force \(F = A\sin (Ct) + B\,\cos (Dx)\) Here, (\(Ct\) ) and (\(Dx\)) are dimensionless as they represent angles \(\therefore \left[ C \right] = \frac{1}{{\left[ t \right]}} = \left[ {{T^{ - 1}}} \right]\) and \(\left[ D \right] = \frac{1}{{\left[ x \right]}} = \left[ {{L^{ - 1}}} \right]\) Dimension of \(\frac{{\left[ C \right]}}{{\left[ D \right]}} = \frac{{\left[ {{T^{ - 1}}} \right]}}{{\left[ {{L^{ - 1}}} \right]}} = \left[ {L{T^{ - 1}}} \right]\) This is same as the dimension of velocity
367282
Find the dimensions of \(\frac{a}{b}\) in the equation \(P = \frac{{a - {t^2}}}{{bx}}\) where \(P\) is pressure, \(x\) is distance and \(t\) is time.
367283
Assertion : The equation \(y=x+t\) cannot be true, where \(x, y\) are distance and \(t\) is time. Reason : Quantities with different dimensions cannot be added.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
The given equation \((y=x+t)\) cannot be true, because time cannot be added to distance. So correct option is (1)
PHXI02:UNITS AND MEASUREMENTS
367284
Let Force \(F = A\sin (Ct) + B\cos (Dx)\), where \(x\) and \(t\) are displacment and time respectively,. The dimension of \(\frac{C}{D}\) are same as dimension of
1 Angular velocity
2 Velocity
3 Angular momentum
4 Velocity gradient
Explanation:
Given Force \(F = A\sin (Ct) + B\,\cos (Dx)\) Here, (\(Ct\) ) and (\(Dx\)) are dimensionless as they represent angles \(\therefore \left[ C \right] = \frac{1}{{\left[ t \right]}} = \left[ {{T^{ - 1}}} \right]\) and \(\left[ D \right] = \frac{1}{{\left[ x \right]}} = \left[ {{L^{ - 1}}} \right]\) Dimension of \(\frac{{\left[ C \right]}}{{\left[ D \right]}} = \frac{{\left[ {{T^{ - 1}}} \right]}}{{\left[ {{L^{ - 1}}} \right]}} = \left[ {L{T^{ - 1}}} \right]\) This is same as the dimension of velocity
367282
Find the dimensions of \(\frac{a}{b}\) in the equation \(P = \frac{{a - {t^2}}}{{bx}}\) where \(P\) is pressure, \(x\) is distance and \(t\) is time.
367283
Assertion : The equation \(y=x+t\) cannot be true, where \(x, y\) are distance and \(t\) is time. Reason : Quantities with different dimensions cannot be added.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
The given equation \((y=x+t)\) cannot be true, because time cannot be added to distance. So correct option is (1)
PHXI02:UNITS AND MEASUREMENTS
367284
Let Force \(F = A\sin (Ct) + B\cos (Dx)\), where \(x\) and \(t\) are displacment and time respectively,. The dimension of \(\frac{C}{D}\) are same as dimension of
1 Angular velocity
2 Velocity
3 Angular momentum
4 Velocity gradient
Explanation:
Given Force \(F = A\sin (Ct) + B\,\cos (Dx)\) Here, (\(Ct\) ) and (\(Dx\)) are dimensionless as they represent angles \(\therefore \left[ C \right] = \frac{1}{{\left[ t \right]}} = \left[ {{T^{ - 1}}} \right]\) and \(\left[ D \right] = \frac{1}{{\left[ x \right]}} = \left[ {{L^{ - 1}}} \right]\) Dimension of \(\frac{{\left[ C \right]}}{{\left[ D \right]}} = \frac{{\left[ {{T^{ - 1}}} \right]}}{{\left[ {{L^{ - 1}}} \right]}} = \left[ {L{T^{ - 1}}} \right]\) This is same as the dimension of velocity