363961
In the following equation representing \(\beta^{-}\)decay, the number of neutrons in the nucleus \(X\) is \({ }_{83}^{210} B i \rightarrow X+e^{-1}+\bar{v}\).
1 125
2 84
3 126
4 127
Explanation:
Here neutron is converted to proton. So, \(Z\) increases by 1. \(\Rightarrow Z\) of \(X=83+1=84\). \(N=A-Z=210-84=126\). Correct option is (3).
KCET - 2023
PHXII13:NUCLEI
363962
In the given nuclear reaction, how many \(\alpha \) and \(\beta \) particles are emitted \({}_{92}{X^{235}}_{82}{Y^{207}}\)?
363963
In the nuclear decay given below \({}_Z^AX \to {}_{Z + 1}^AY \to {}_{Z - 1}^{A - 4}{B^*} \to {}_{Z - 1}^{A - 4}B\) the particles emitted in the sequence are
363961
In the following equation representing \(\beta^{-}\)decay, the number of neutrons in the nucleus \(X\) is \({ }_{83}^{210} B i \rightarrow X+e^{-1}+\bar{v}\).
1 125
2 84
3 126
4 127
Explanation:
Here neutron is converted to proton. So, \(Z\) increases by 1. \(\Rightarrow Z\) of \(X=83+1=84\). \(N=A-Z=210-84=126\). Correct option is (3).
KCET - 2023
PHXII13:NUCLEI
363962
In the given nuclear reaction, how many \(\alpha \) and \(\beta \) particles are emitted \({}_{92}{X^{235}}_{82}{Y^{207}}\)?
363963
In the nuclear decay given below \({}_Z^AX \to {}_{Z + 1}^AY \to {}_{Z - 1}^{A - 4}{B^*} \to {}_{Z - 1}^{A - 4}B\) the particles emitted in the sequence are
363961
In the following equation representing \(\beta^{-}\)decay, the number of neutrons in the nucleus \(X\) is \({ }_{83}^{210} B i \rightarrow X+e^{-1}+\bar{v}\).
1 125
2 84
3 126
4 127
Explanation:
Here neutron is converted to proton. So, \(Z\) increases by 1. \(\Rightarrow Z\) of \(X=83+1=84\). \(N=A-Z=210-84=126\). Correct option is (3).
KCET - 2023
PHXII13:NUCLEI
363962
In the given nuclear reaction, how many \(\alpha \) and \(\beta \) particles are emitted \({}_{92}{X^{235}}_{82}{Y^{207}}\)?
363963
In the nuclear decay given below \({}_Z^AX \to {}_{Z + 1}^AY \to {}_{Z - 1}^{A - 4}{B^*} \to {}_{Z - 1}^{A - 4}B\) the particles emitted in the sequence are
363961
In the following equation representing \(\beta^{-}\)decay, the number of neutrons in the nucleus \(X\) is \({ }_{83}^{210} B i \rightarrow X+e^{-1}+\bar{v}\).
1 125
2 84
3 126
4 127
Explanation:
Here neutron is converted to proton. So, \(Z\) increases by 1. \(\Rightarrow Z\) of \(X=83+1=84\). \(N=A-Z=210-84=126\). Correct option is (3).
KCET - 2023
PHXII13:NUCLEI
363962
In the given nuclear reaction, how many \(\alpha \) and \(\beta \) particles are emitted \({}_{92}{X^{235}}_{82}{Y^{207}}\)?
363963
In the nuclear decay given below \({}_Z^AX \to {}_{Z + 1}^AY \to {}_{Z - 1}^{A - 4}{B^*} \to {}_{Z - 1}^{A - 4}B\) the particles emitted in the sequence are
