Explanation:
\(\mathop {Be}\limits_{92}^{234} \to \mathop Y\limits_{88}^{218} + x\mathop \alpha \limits_2^4 + y\mathop \beta \limits_{ - 1}^o \)
By balancing the proton and mass numbers on both sides.
\(92 = 88 + 2x - y\,\,\,\,\,(1)\)
\(234 = 218 + 4x\,\,\,\,\,\,\,(2)\)
From eq’s (1) & (2)
\(x = 4\& y = 4\)