363918
Assertion : The ionising power of \(\beta\) -particle is less compared to \(\alpha\) -particles but their penetrating power is more. Reason : The mass of \(\beta\) -particle is less than the mass of \(\alpha\) -particle.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
\(\alpha\)-particles are more charged than \(\beta . \beta\) particles, having significantly higher velocities compared to \(\alpha\)-particles, spend limited time in the vicinity of medium atoms. \(\Rightarrow\) Assertion is true. However, this also means that their energy loss occurs gradually, allowing them to penetrate the medium to a substantial depth. Reason is a separate fact. So correct option is (2)
PHXII13:NUCLEI
363919
A nucleus \({ }_{Z}^{A} X\) emits an \(\alpha\)-particle. The resultant nucleus emits a \(\beta^{+}\)-particle. The respective atomic and mass number of final nucleus will be
1 \(Z - 3,A - 4\)
2 \(Z-1, A-4\)
3 \(Z-2, A-4\)
4 \(Z, A-2\)
Explanation:
\({ }_{Z}^{A} X \rightarrow{ }_{2}^{4} \mathrm{He}+{ }_{Z-2}^{A-4} Y\) \({ }_{Z-2}^{A-4} Y \rightarrow e^{+}+{ }_{Z-3}^{A-4} Y^{\prime}\) During \(\beta^{+}\)emission. \({ }_{1} p^{1} \rightarrow{ }_{0} n^{1}+\beta^{+}\) The proton changes into neutron. So, charge number decreases by \(1\) but mass number remains unchanged.
PHXII13:NUCLEI
363920
When a neutron disintegrates to give a \({\beta ^ - }\) particle,
1 A neutrino alone is emitted
2 A proton and neutrino are emitted
3 A proton alone is emitted
4 A proton and an antineutrino are emitted
Explanation:
In \({\beta ^ - }\) decay, a neutron disintegrates into a proton, an electron, and an anti-neutrino as shown: \(\mathop n\limits_{neutron} \to \mathop p\limits_{proton} + \mathop {{e^ - }}\limits_{electron} + \mathop {\overline v }\limits_{antineutrino} \)
KCET - 2010
PHXII13:NUCLEI
363921
Assertion : Radioactive nuclei emits \(\beta\) particles. Reason : Electron exist inside the nucleus.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Radioactive nuclei can emit \(\beta\)-particles, which are electrons \(\left(\beta^{-}\right)\)or positrons \(\left(\beta^{+}\right)\), as part of the process of radioactive decay. Electrons do not exist inside the nucleus of an atom. Electrons are negatively charged subatomic particles that orbit the nucleus in electron shells or energy levels, but they are not found within the nucleus. The nucleus primarily contains protons and neutrons. So option (3) is correct.
AIIMS - 2018
PHXII13:NUCLEI
363922
On the bombardment of neutron with boron, \({\alpha}\)-particle is emitted. The product nuclei formed is
1 \({{ }_{4}^{9} {Be}}\)
2 \({{ }_{6}^{12} {C}}\)
3 \({{ }_{3}^{6} {Li}}\)
4 \({{ }_{3}^{7} {Li}}\)
Explanation:
\({{ }_{0}^{1} n+{ }_{5}^{10} {~B} \longrightarrow{ }_{3}^{7} {Li}+{ }_{2}^{4} {He}}\). So correct option is (4)
363918
Assertion : The ionising power of \(\beta\) -particle is less compared to \(\alpha\) -particles but their penetrating power is more. Reason : The mass of \(\beta\) -particle is less than the mass of \(\alpha\) -particle.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
\(\alpha\)-particles are more charged than \(\beta . \beta\) particles, having significantly higher velocities compared to \(\alpha\)-particles, spend limited time in the vicinity of medium atoms. \(\Rightarrow\) Assertion is true. However, this also means that their energy loss occurs gradually, allowing them to penetrate the medium to a substantial depth. Reason is a separate fact. So correct option is (2)
PHXII13:NUCLEI
363919
A nucleus \({ }_{Z}^{A} X\) emits an \(\alpha\)-particle. The resultant nucleus emits a \(\beta^{+}\)-particle. The respective atomic and mass number of final nucleus will be
1 \(Z - 3,A - 4\)
2 \(Z-1, A-4\)
3 \(Z-2, A-4\)
4 \(Z, A-2\)
Explanation:
\({ }_{Z}^{A} X \rightarrow{ }_{2}^{4} \mathrm{He}+{ }_{Z-2}^{A-4} Y\) \({ }_{Z-2}^{A-4} Y \rightarrow e^{+}+{ }_{Z-3}^{A-4} Y^{\prime}\) During \(\beta^{+}\)emission. \({ }_{1} p^{1} \rightarrow{ }_{0} n^{1}+\beta^{+}\) The proton changes into neutron. So, charge number decreases by \(1\) but mass number remains unchanged.
PHXII13:NUCLEI
363920
When a neutron disintegrates to give a \({\beta ^ - }\) particle,
1 A neutrino alone is emitted
2 A proton and neutrino are emitted
3 A proton alone is emitted
4 A proton and an antineutrino are emitted
Explanation:
In \({\beta ^ - }\) decay, a neutron disintegrates into a proton, an electron, and an anti-neutrino as shown: \(\mathop n\limits_{neutron} \to \mathop p\limits_{proton} + \mathop {{e^ - }}\limits_{electron} + \mathop {\overline v }\limits_{antineutrino} \)
KCET - 2010
PHXII13:NUCLEI
363921
Assertion : Radioactive nuclei emits \(\beta\) particles. Reason : Electron exist inside the nucleus.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Radioactive nuclei can emit \(\beta\)-particles, which are electrons \(\left(\beta^{-}\right)\)or positrons \(\left(\beta^{+}\right)\), as part of the process of radioactive decay. Electrons do not exist inside the nucleus of an atom. Electrons are negatively charged subatomic particles that orbit the nucleus in electron shells or energy levels, but they are not found within the nucleus. The nucleus primarily contains protons and neutrons. So option (3) is correct.
AIIMS - 2018
PHXII13:NUCLEI
363922
On the bombardment of neutron with boron, \({\alpha}\)-particle is emitted. The product nuclei formed is
1 \({{ }_{4}^{9} {Be}}\)
2 \({{ }_{6}^{12} {C}}\)
3 \({{ }_{3}^{6} {Li}}\)
4 \({{ }_{3}^{7} {Li}}\)
Explanation:
\({{ }_{0}^{1} n+{ }_{5}^{10} {~B} \longrightarrow{ }_{3}^{7} {Li}+{ }_{2}^{4} {He}}\). So correct option is (4)
NEET Test Series from KOTA - 10 Papers In MS WORD
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PHXII13:NUCLEI
363918
Assertion : The ionising power of \(\beta\) -particle is less compared to \(\alpha\) -particles but their penetrating power is more. Reason : The mass of \(\beta\) -particle is less than the mass of \(\alpha\) -particle.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
\(\alpha\)-particles are more charged than \(\beta . \beta\) particles, having significantly higher velocities compared to \(\alpha\)-particles, spend limited time in the vicinity of medium atoms. \(\Rightarrow\) Assertion is true. However, this also means that their energy loss occurs gradually, allowing them to penetrate the medium to a substantial depth. Reason is a separate fact. So correct option is (2)
PHXII13:NUCLEI
363919
A nucleus \({ }_{Z}^{A} X\) emits an \(\alpha\)-particle. The resultant nucleus emits a \(\beta^{+}\)-particle. The respective atomic and mass number of final nucleus will be
1 \(Z - 3,A - 4\)
2 \(Z-1, A-4\)
3 \(Z-2, A-4\)
4 \(Z, A-2\)
Explanation:
\({ }_{Z}^{A} X \rightarrow{ }_{2}^{4} \mathrm{He}+{ }_{Z-2}^{A-4} Y\) \({ }_{Z-2}^{A-4} Y \rightarrow e^{+}+{ }_{Z-3}^{A-4} Y^{\prime}\) During \(\beta^{+}\)emission. \({ }_{1} p^{1} \rightarrow{ }_{0} n^{1}+\beta^{+}\) The proton changes into neutron. So, charge number decreases by \(1\) but mass number remains unchanged.
PHXII13:NUCLEI
363920
When a neutron disintegrates to give a \({\beta ^ - }\) particle,
1 A neutrino alone is emitted
2 A proton and neutrino are emitted
3 A proton alone is emitted
4 A proton and an antineutrino are emitted
Explanation:
In \({\beta ^ - }\) decay, a neutron disintegrates into a proton, an electron, and an anti-neutrino as shown: \(\mathop n\limits_{neutron} \to \mathop p\limits_{proton} + \mathop {{e^ - }}\limits_{electron} + \mathop {\overline v }\limits_{antineutrino} \)
KCET - 2010
PHXII13:NUCLEI
363921
Assertion : Radioactive nuclei emits \(\beta\) particles. Reason : Electron exist inside the nucleus.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Radioactive nuclei can emit \(\beta\)-particles, which are electrons \(\left(\beta^{-}\right)\)or positrons \(\left(\beta^{+}\right)\), as part of the process of radioactive decay. Electrons do not exist inside the nucleus of an atom. Electrons are negatively charged subatomic particles that orbit the nucleus in electron shells or energy levels, but they are not found within the nucleus. The nucleus primarily contains protons and neutrons. So option (3) is correct.
AIIMS - 2018
PHXII13:NUCLEI
363922
On the bombardment of neutron with boron, \({\alpha}\)-particle is emitted. The product nuclei formed is
1 \({{ }_{4}^{9} {Be}}\)
2 \({{ }_{6}^{12} {C}}\)
3 \({{ }_{3}^{6} {Li}}\)
4 \({{ }_{3}^{7} {Li}}\)
Explanation:
\({{ }_{0}^{1} n+{ }_{5}^{10} {~B} \longrightarrow{ }_{3}^{7} {Li}+{ }_{2}^{4} {He}}\). So correct option is (4)
363918
Assertion : The ionising power of \(\beta\) -particle is less compared to \(\alpha\) -particles but their penetrating power is more. Reason : The mass of \(\beta\) -particle is less than the mass of \(\alpha\) -particle.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
\(\alpha\)-particles are more charged than \(\beta . \beta\) particles, having significantly higher velocities compared to \(\alpha\)-particles, spend limited time in the vicinity of medium atoms. \(\Rightarrow\) Assertion is true. However, this also means that their energy loss occurs gradually, allowing them to penetrate the medium to a substantial depth. Reason is a separate fact. So correct option is (2)
PHXII13:NUCLEI
363919
A nucleus \({ }_{Z}^{A} X\) emits an \(\alpha\)-particle. The resultant nucleus emits a \(\beta^{+}\)-particle. The respective atomic and mass number of final nucleus will be
1 \(Z - 3,A - 4\)
2 \(Z-1, A-4\)
3 \(Z-2, A-4\)
4 \(Z, A-2\)
Explanation:
\({ }_{Z}^{A} X \rightarrow{ }_{2}^{4} \mathrm{He}+{ }_{Z-2}^{A-4} Y\) \({ }_{Z-2}^{A-4} Y \rightarrow e^{+}+{ }_{Z-3}^{A-4} Y^{\prime}\) During \(\beta^{+}\)emission. \({ }_{1} p^{1} \rightarrow{ }_{0} n^{1}+\beta^{+}\) The proton changes into neutron. So, charge number decreases by \(1\) but mass number remains unchanged.
PHXII13:NUCLEI
363920
When a neutron disintegrates to give a \({\beta ^ - }\) particle,
1 A neutrino alone is emitted
2 A proton and neutrino are emitted
3 A proton alone is emitted
4 A proton and an antineutrino are emitted
Explanation:
In \({\beta ^ - }\) decay, a neutron disintegrates into a proton, an electron, and an anti-neutrino as shown: \(\mathop n\limits_{neutron} \to \mathop p\limits_{proton} + \mathop {{e^ - }}\limits_{electron} + \mathop {\overline v }\limits_{antineutrino} \)
KCET - 2010
PHXII13:NUCLEI
363921
Assertion : Radioactive nuclei emits \(\beta\) particles. Reason : Electron exist inside the nucleus.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Radioactive nuclei can emit \(\beta\)-particles, which are electrons \(\left(\beta^{-}\right)\)or positrons \(\left(\beta^{+}\right)\), as part of the process of radioactive decay. Electrons do not exist inside the nucleus of an atom. Electrons are negatively charged subatomic particles that orbit the nucleus in electron shells or energy levels, but they are not found within the nucleus. The nucleus primarily contains protons and neutrons. So option (3) is correct.
AIIMS - 2018
PHXII13:NUCLEI
363922
On the bombardment of neutron with boron, \({\alpha}\)-particle is emitted. The product nuclei formed is
1 \({{ }_{4}^{9} {Be}}\)
2 \({{ }_{6}^{12} {C}}\)
3 \({{ }_{3}^{6} {Li}}\)
4 \({{ }_{3}^{7} {Li}}\)
Explanation:
\({{ }_{0}^{1} n+{ }_{5}^{10} {~B} \longrightarrow{ }_{3}^{7} {Li}+{ }_{2}^{4} {He}}\). So correct option is (4)
363918
Assertion : The ionising power of \(\beta\) -particle is less compared to \(\alpha\) -particles but their penetrating power is more. Reason : The mass of \(\beta\) -particle is less than the mass of \(\alpha\) -particle.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
\(\alpha\)-particles are more charged than \(\beta . \beta\) particles, having significantly higher velocities compared to \(\alpha\)-particles, spend limited time in the vicinity of medium atoms. \(\Rightarrow\) Assertion is true. However, this also means that their energy loss occurs gradually, allowing them to penetrate the medium to a substantial depth. Reason is a separate fact. So correct option is (2)
PHXII13:NUCLEI
363919
A nucleus \({ }_{Z}^{A} X\) emits an \(\alpha\)-particle. The resultant nucleus emits a \(\beta^{+}\)-particle. The respective atomic and mass number of final nucleus will be
1 \(Z - 3,A - 4\)
2 \(Z-1, A-4\)
3 \(Z-2, A-4\)
4 \(Z, A-2\)
Explanation:
\({ }_{Z}^{A} X \rightarrow{ }_{2}^{4} \mathrm{He}+{ }_{Z-2}^{A-4} Y\) \({ }_{Z-2}^{A-4} Y \rightarrow e^{+}+{ }_{Z-3}^{A-4} Y^{\prime}\) During \(\beta^{+}\)emission. \({ }_{1} p^{1} \rightarrow{ }_{0} n^{1}+\beta^{+}\) The proton changes into neutron. So, charge number decreases by \(1\) but mass number remains unchanged.
PHXII13:NUCLEI
363920
When a neutron disintegrates to give a \({\beta ^ - }\) particle,
1 A neutrino alone is emitted
2 A proton and neutrino are emitted
3 A proton alone is emitted
4 A proton and an antineutrino are emitted
Explanation:
In \({\beta ^ - }\) decay, a neutron disintegrates into a proton, an electron, and an anti-neutrino as shown: \(\mathop n\limits_{neutron} \to \mathop p\limits_{proton} + \mathop {{e^ - }}\limits_{electron} + \mathop {\overline v }\limits_{antineutrino} \)
KCET - 2010
PHXII13:NUCLEI
363921
Assertion : Radioactive nuclei emits \(\beta\) particles. Reason : Electron exist inside the nucleus.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Radioactive nuclei can emit \(\beta\)-particles, which are electrons \(\left(\beta^{-}\right)\)or positrons \(\left(\beta^{+}\right)\), as part of the process of radioactive decay. Electrons do not exist inside the nucleus of an atom. Electrons are negatively charged subatomic particles that orbit the nucleus in electron shells or energy levels, but they are not found within the nucleus. The nucleus primarily contains protons and neutrons. So option (3) is correct.
AIIMS - 2018
PHXII13:NUCLEI
363922
On the bombardment of neutron with boron, \({\alpha}\)-particle is emitted. The product nuclei formed is
1 \({{ }_{4}^{9} {Be}}\)
2 \({{ }_{6}^{12} {C}}\)
3 \({{ }_{3}^{6} {Li}}\)
4 \({{ }_{3}^{7} {Li}}\)
Explanation:
\({{ }_{0}^{1} n+{ }_{5}^{10} {~B} \longrightarrow{ }_{3}^{7} {Li}+{ }_{2}^{4} {He}}\). So correct option is (4)