363915
In a radio active decay, an element \(_Z{X^A}\) emits four \(\alpha \) particles, three \(\beta \) particles and eight gamma photons. The atomic number and mass number of the resulting final nucleus are
1 \(Z - 11,A - 16\)
2 \(Z - 5,A - 13\)
3 \(Z - 5,A - 16\)
4 \(Z - 8,A - 13\)
Explanation:
Emission of \(\alpha \) particle decreases the atomic number and mass number by 2 and 4 respectively. Emission of \({\beta ^ - }\) particle increases the atomic number by 1 while the mass number remains unchanged. After emission of \(\gamma \) particle both the atomic number and the mass number remain unchanged \(\therefore \) After the emission of four \(\alpha \) particles, three \({\beta ^ - }\) particles and eight \(\gamma \) photons: Decrease in atomic number \( = 4 \times 2 - 3 \times 1 = 5\) Decrease in mass number \( = 4 \times 4 - 0 = 16\) Thus, the atomic number and mass number of resulting final nucleus are \((Z - 5)\) and \((A - 16)\) respectively. \(\therefore \) The resulting final nucleus is \(_{Z - 5}{Y^{A - 16}}\)
PHXII13:NUCLEI
363916
A radioactive decay can form an isotope of the original nucleus with the emission of particles
1 One \(\alpha \) and two \(\beta \)
2 Four \(\alpha \) and one \(\beta \)
3 One \(\alpha \) and four \(\beta \)
4 One \(\alpha \) and one \(\beta \)
Explanation:
As the emission of an alpha particle decreases the atomic number and mass number by 2 and 4 respectively while the emission of a beta particle increases the atomic number by 1 but mass number remains the same.So, the emission of one alpha particle and two beta particles from the nucleus can form an isotope of the original nucleus. It may be represented as \(_Z{X^A}{\xrightarrow{\alpha }_{Z - 2}}{Y^{A - 4}}{\xrightarrow{{2{\beta ^ - }}}_z}{X^{A - 4}}\)
KCET - 2015
PHXII13:NUCLEI
363917
Assertion : It is very easy to detect neutrino in nature. Reason : It has high affinity to interact with matter.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Neutrinos have a very weak interaction with matter, making their detection difficult. So correct option is (4).
363915
In a radio active decay, an element \(_Z{X^A}\) emits four \(\alpha \) particles, three \(\beta \) particles and eight gamma photons. The atomic number and mass number of the resulting final nucleus are
1 \(Z - 11,A - 16\)
2 \(Z - 5,A - 13\)
3 \(Z - 5,A - 16\)
4 \(Z - 8,A - 13\)
Explanation:
Emission of \(\alpha \) particle decreases the atomic number and mass number by 2 and 4 respectively. Emission of \({\beta ^ - }\) particle increases the atomic number by 1 while the mass number remains unchanged. After emission of \(\gamma \) particle both the atomic number and the mass number remain unchanged \(\therefore \) After the emission of four \(\alpha \) particles, three \({\beta ^ - }\) particles and eight \(\gamma \) photons: Decrease in atomic number \( = 4 \times 2 - 3 \times 1 = 5\) Decrease in mass number \( = 4 \times 4 - 0 = 16\) Thus, the atomic number and mass number of resulting final nucleus are \((Z - 5)\) and \((A - 16)\) respectively. \(\therefore \) The resulting final nucleus is \(_{Z - 5}{Y^{A - 16}}\)
PHXII13:NUCLEI
363916
A radioactive decay can form an isotope of the original nucleus with the emission of particles
1 One \(\alpha \) and two \(\beta \)
2 Four \(\alpha \) and one \(\beta \)
3 One \(\alpha \) and four \(\beta \)
4 One \(\alpha \) and one \(\beta \)
Explanation:
As the emission of an alpha particle decreases the atomic number and mass number by 2 and 4 respectively while the emission of a beta particle increases the atomic number by 1 but mass number remains the same.So, the emission of one alpha particle and two beta particles from the nucleus can form an isotope of the original nucleus. It may be represented as \(_Z{X^A}{\xrightarrow{\alpha }_{Z - 2}}{Y^{A - 4}}{\xrightarrow{{2{\beta ^ - }}}_z}{X^{A - 4}}\)
KCET - 2015
PHXII13:NUCLEI
363917
Assertion : It is very easy to detect neutrino in nature. Reason : It has high affinity to interact with matter.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Neutrinos have a very weak interaction with matter, making their detection difficult. So correct option is (4).
363915
In a radio active decay, an element \(_Z{X^A}\) emits four \(\alpha \) particles, three \(\beta \) particles and eight gamma photons. The atomic number and mass number of the resulting final nucleus are
1 \(Z - 11,A - 16\)
2 \(Z - 5,A - 13\)
3 \(Z - 5,A - 16\)
4 \(Z - 8,A - 13\)
Explanation:
Emission of \(\alpha \) particle decreases the atomic number and mass number by 2 and 4 respectively. Emission of \({\beta ^ - }\) particle increases the atomic number by 1 while the mass number remains unchanged. After emission of \(\gamma \) particle both the atomic number and the mass number remain unchanged \(\therefore \) After the emission of four \(\alpha \) particles, three \({\beta ^ - }\) particles and eight \(\gamma \) photons: Decrease in atomic number \( = 4 \times 2 - 3 \times 1 = 5\) Decrease in mass number \( = 4 \times 4 - 0 = 16\) Thus, the atomic number and mass number of resulting final nucleus are \((Z - 5)\) and \((A - 16)\) respectively. \(\therefore \) The resulting final nucleus is \(_{Z - 5}{Y^{A - 16}}\)
PHXII13:NUCLEI
363916
A radioactive decay can form an isotope of the original nucleus with the emission of particles
1 One \(\alpha \) and two \(\beta \)
2 Four \(\alpha \) and one \(\beta \)
3 One \(\alpha \) and four \(\beta \)
4 One \(\alpha \) and one \(\beta \)
Explanation:
As the emission of an alpha particle decreases the atomic number and mass number by 2 and 4 respectively while the emission of a beta particle increases the atomic number by 1 but mass number remains the same.So, the emission of one alpha particle and two beta particles from the nucleus can form an isotope of the original nucleus. It may be represented as \(_Z{X^A}{\xrightarrow{\alpha }_{Z - 2}}{Y^{A - 4}}{\xrightarrow{{2{\beta ^ - }}}_z}{X^{A - 4}}\)
KCET - 2015
PHXII13:NUCLEI
363917
Assertion : It is very easy to detect neutrino in nature. Reason : It has high affinity to interact with matter.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Neutrinos have a very weak interaction with matter, making their detection difficult. So correct option is (4).
363915
In a radio active decay, an element \(_Z{X^A}\) emits four \(\alpha \) particles, three \(\beta \) particles and eight gamma photons. The atomic number and mass number of the resulting final nucleus are
1 \(Z - 11,A - 16\)
2 \(Z - 5,A - 13\)
3 \(Z - 5,A - 16\)
4 \(Z - 8,A - 13\)
Explanation:
Emission of \(\alpha \) particle decreases the atomic number and mass number by 2 and 4 respectively. Emission of \({\beta ^ - }\) particle increases the atomic number by 1 while the mass number remains unchanged. After emission of \(\gamma \) particle both the atomic number and the mass number remain unchanged \(\therefore \) After the emission of four \(\alpha \) particles, three \({\beta ^ - }\) particles and eight \(\gamma \) photons: Decrease in atomic number \( = 4 \times 2 - 3 \times 1 = 5\) Decrease in mass number \( = 4 \times 4 - 0 = 16\) Thus, the atomic number and mass number of resulting final nucleus are \((Z - 5)\) and \((A - 16)\) respectively. \(\therefore \) The resulting final nucleus is \(_{Z - 5}{Y^{A - 16}}\)
PHXII13:NUCLEI
363916
A radioactive decay can form an isotope of the original nucleus with the emission of particles
1 One \(\alpha \) and two \(\beta \)
2 Four \(\alpha \) and one \(\beta \)
3 One \(\alpha \) and four \(\beta \)
4 One \(\alpha \) and one \(\beta \)
Explanation:
As the emission of an alpha particle decreases the atomic number and mass number by 2 and 4 respectively while the emission of a beta particle increases the atomic number by 1 but mass number remains the same.So, the emission of one alpha particle and two beta particles from the nucleus can form an isotope of the original nucleus. It may be represented as \(_Z{X^A}{\xrightarrow{\alpha }_{Z - 2}}{Y^{A - 4}}{\xrightarrow{{2{\beta ^ - }}}_z}{X^{A - 4}}\)
KCET - 2015
PHXII13:NUCLEI
363917
Assertion : It is very easy to detect neutrino in nature. Reason : It has high affinity to interact with matter.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Neutrinos have a very weak interaction with matter, making their detection difficult. So correct option is (4).
