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PHXII13:NUCLEI

363905 An atom of mass number $A$ and atomic number $Z$ emits successively $a$ $γ$ -ray, a $β$ -particle, and $α$ -particle and $a$ $γ$ -ray. The mass number and the atomic number of the end product are:

1

A - 4, Z - A

2

A, Z + 1

3

A - 4, Z + 2

4

A - 4, Z - 1

Explanation:

When an atom of mass number $A$ and atomic number $Z$ emits $γ$ -rays, no change take place in atomic and mass number, but when a $β$ -particle is emitted, atomic mass number remain same, but atomic number increase by 1. When an alpha particle is emitted, atomic number is decreased by 2 and atomic mass number is decreased by 4.
$_{Z}^{A} X^{*} {\overset{γ - r a y}{\to}}_{Z}^{A} X {\overset{β - p a r t i c l e}{\to}}_{Z + 1}^{A} Y \overset{α - p a r t i c l e}{\to}$
$_{Z - 1}^{A - 4} Z^{*} {\overset{γ - r a y}{\to}}_{Z - 1}^{A - 4} Z$

PHXII13:NUCLEI

363906 Neutron decay in free space is given as follows:
$_{0} n^{1} \to_{1} P^{1} +_{- 1} e^{0} + []$
Then the parenthesis represents a

1 Antineutrino

2 Graviton

3 Photon

4 Neutrino

PHXII13:NUCLEI

363907 A nucleus of mass $214 a m u$ at rest emits an
$α$ - particle. Kinetic energy of the $α$ - particle is $6.7 M e V$ . The recoil energy of the daughter nucleus is

1

1.0 M e V

2

0.5 M e V

3

0.25 M e V

4

0.125 M e V

Explanation:

$p_{1}$ (momentum of alpha particle) $+ p_{2}$ (momentum of daughter nucleus $= 0$ (initial momentum)
$\Rightarrow p_{1} = - p_{2}$
For $α$ -particle
$\frac{p_{1}^{2}}{2 m} = 6.7 M e V$
For daughter nucleus, $E = \frac{p_{2}^{2}}{2 U}$
$\Rightarrow \frac{E}{6.7} = \frac{m}{M}$
$\Rightarrow \frac{E}{6.7} = \frac{4}{214}$
$\Rightarrow E = 0.125 M e V$

PHXII13:NUCLEI

363908 $_{82}^{290} X \overset{α}{\to} Y \overset{e^{+}}{\to} Z \overset{β^{-}}{\to} P \overset{e^{-}}{\to} Q$ In the nuclear emission stated above, the mass number and atomic number of the product $Q$ respectively, are

1 280, 81

2 286, 80

3 288, 82

4 286, 81

Explanation:

$_{82}^{290} X \overset{α}{\to}_{80}^{286} Y \overset{e^{+}}{\to}_{79}^{286} Z \overset{β^{-}}{\to}$
$_{80}^{286} P \overset{e^{-}}{\to}_{81}^{286} Q$
$A = 286$ and $Z = 81$

NEET - 2024

PHXII13:NUCLEI

363909 In the nuclear reaction $_{85} X^{297} \to Y + 4 α, Y$ is

1

_{77} Y^{281}

2

_{76} Y^{287}

3

_{77} Y^{285}

4

_{77} Y^{289}

Explanation:

$_{85} X^{297} \to_{A} Y^{B} + 4_{2} α^{4}$
By equating the atomic and mass numbers
$85 = A + 8 \Rightarrow A = 77$
$297 = B + 16 \Rightarrow B = 281$

PHXII13:NUCLEI

363905 An atom of mass number $A$ and atomic number $Z$ emits successively $a$ $γ$ -ray, a $β$ -particle, and $α$ -particle and $a$ $γ$ -ray. The mass number and the atomic number of the end product are:

1

A - 4, Z - A

2

A, Z + 1

3

A - 4, Z + 2

4

A - 4, Z - 1

Explanation:

When an atom of mass number $A$ and atomic number $Z$ emits $γ$ -rays, no change take place in atomic and mass number, but when a $β$ -particle is emitted, atomic mass number remain same, but atomic number increase by 1. When an alpha particle is emitted, atomic number is decreased by 2 and atomic mass number is decreased by 4.
$_{Z}^{A} X^{*} {\overset{γ - r a y}{\to}}_{Z}^{A} X {\overset{β - p a r t i c l e}{\to}}_{Z + 1}^{A} Y \overset{α - p a r t i c l e}{\to}$
$_{Z - 1}^{A - 4} Z^{*} {\overset{γ - r a y}{\to}}_{Z - 1}^{A - 4} Z$

PHXII13:NUCLEI

363906 Neutron decay in free space is given as follows:
$_{0} n^{1} \to_{1} P^{1} +_{- 1} e^{0} + []$
Then the parenthesis represents a

1 Antineutrino

2 Graviton

3 Photon

4 Neutrino

PHXII13:NUCLEI

363907 A nucleus of mass $214 a m u$ at rest emits an
$α$ - particle. Kinetic energy of the $α$ - particle is $6.7 M e V$ . The recoil energy of the daughter nucleus is

1

1.0 M e V

2

0.5 M e V

3

0.25 M e V

4

0.125 M e V

Explanation:

$p_{1}$ (momentum of alpha particle) $+ p_{2}$ (momentum of daughter nucleus $= 0$ (initial momentum)
$\Rightarrow p_{1} = - p_{2}$
For $α$ -particle
$\frac{p_{1}^{2}}{2 m} = 6.7 M e V$
For daughter nucleus, $E = \frac{p_{2}^{2}}{2 U}$
$\Rightarrow \frac{E}{6.7} = \frac{m}{M}$
$\Rightarrow \frac{E}{6.7} = \frac{4}{214}$
$\Rightarrow E = 0.125 M e V$

PHXII13:NUCLEI

363908 $_{82}^{290} X \overset{α}{\to} Y \overset{e^{+}}{\to} Z \overset{β^{-}}{\to} P \overset{e^{-}}{\to} Q$ In the nuclear emission stated above, the mass number and atomic number of the product $Q$ respectively, are

1 280, 81

2 286, 80

3 288, 82

4 286, 81

Explanation:

$_{82}^{290} X \overset{α}{\to}_{80}^{286} Y \overset{e^{+}}{\to}_{79}^{286} Z \overset{β^{-}}{\to}$
$_{80}^{286} P \overset{e^{-}}{\to}_{81}^{286} Q$
$A = 286$ and $Z = 81$

NEET - 2024

PHXII13:NUCLEI

363909 In the nuclear reaction $_{85} X^{297} \to Y + 4 α, Y$ is

1

_{77} Y^{281}

2

_{76} Y^{287}

3

_{77} Y^{285}

4

_{77} Y^{289}

Explanation:

$_{85} X^{297} \to_{A} Y^{B} + 4_{2} α^{4}$
By equating the atomic and mass numbers
$85 = A + 8 \Rightarrow A = 77$
$297 = B + 16 \Rightarrow B = 281$

PHXII13:NUCLEI

363905 An atom of mass number $A$ and atomic number $Z$ emits successively $a$ $γ$ -ray, a $β$ -particle, and $α$ -particle and $a$ $γ$ -ray. The mass number and the atomic number of the end product are:

1

A - 4, Z - A

2

A, Z + 1

3

A - 4, Z + 2

4

A - 4, Z - 1

Explanation:

When an atom of mass number $A$ and atomic number $Z$ emits $γ$ -rays, no change take place in atomic and mass number, but when a $β$ -particle is emitted, atomic mass number remain same, but atomic number increase by 1. When an alpha particle is emitted, atomic number is decreased by 2 and atomic mass number is decreased by 4.
$_{Z}^{A} X^{*} {\overset{γ - r a y}{\to}}_{Z}^{A} X {\overset{β - p a r t i c l e}{\to}}_{Z + 1}^{A} Y \overset{α - p a r t i c l e}{\to}$
$_{Z - 1}^{A - 4} Z^{*} {\overset{γ - r a y}{\to}}_{Z - 1}^{A - 4} Z$

PHXII13:NUCLEI

363906 Neutron decay in free space is given as follows:
$_{0} n^{1} \to_{1} P^{1} +_{- 1} e^{0} + []$
Then the parenthesis represents a

1 Antineutrino

2 Graviton

3 Photon

4 Neutrino

PHXII13:NUCLEI

363907 A nucleus of mass $214 a m u$ at rest emits an
$α$ - particle. Kinetic energy of the $α$ - particle is $6.7 M e V$ . The recoil energy of the daughter nucleus is

1

1.0 M e V

2

0.5 M e V

3

0.25 M e V

4

0.125 M e V

Explanation:

$p_{1}$ (momentum of alpha particle) $+ p_{2}$ (momentum of daughter nucleus $= 0$ (initial momentum)
$\Rightarrow p_{1} = - p_{2}$
For $α$ -particle
$\frac{p_{1}^{2}}{2 m} = 6.7 M e V$
For daughter nucleus, $E = \frac{p_{2}^{2}}{2 U}$
$\Rightarrow \frac{E}{6.7} = \frac{m}{M}$
$\Rightarrow \frac{E}{6.7} = \frac{4}{214}$
$\Rightarrow E = 0.125 M e V$

PHXII13:NUCLEI

363908 $_{82}^{290} X \overset{α}{\to} Y \overset{e^{+}}{\to} Z \overset{β^{-}}{\to} P \overset{e^{-}}{\to} Q$ In the nuclear emission stated above, the mass number and atomic number of the product $Q$ respectively, are

1 280, 81

2 286, 80

3 288, 82

4 286, 81

Explanation:

$_{82}^{290} X \overset{α}{\to}_{80}^{286} Y \overset{e^{+}}{\to}_{79}^{286} Z \overset{β^{-}}{\to}$
$_{80}^{286} P \overset{e^{-}}{\to}_{81}^{286} Q$
$A = 286$ and $Z = 81$

NEET - 2024

PHXII13:NUCLEI

363909 In the nuclear reaction $_{85} X^{297} \to Y + 4 α, Y$ is

1

_{77} Y^{281}

2

_{76} Y^{287}

3

_{77} Y^{285}

4

_{77} Y^{289}

Explanation:

$_{85} X^{297} \to_{A} Y^{B} + 4_{2} α^{4}$
By equating the atomic and mass numbers
$85 = A + 8 \Rightarrow A = 77$
$297 = B + 16 \Rightarrow B = 281$

PHXII13:NUCLEI

363905 An atom of mass number $A$ and atomic number $Z$ emits successively $a$ $γ$ -ray, a $β$ -particle, and $α$ -particle and $a$ $γ$ -ray. The mass number and the atomic number of the end product are:

1

A - 4, Z - A

2

A, Z + 1

3

A - 4, Z + 2

4

A - 4, Z - 1

Explanation:

When an atom of mass number $A$ and atomic number $Z$ emits $γ$ -rays, no change take place in atomic and mass number, but when a $β$ -particle is emitted, atomic mass number remain same, but atomic number increase by 1. When an alpha particle is emitted, atomic number is decreased by 2 and atomic mass number is decreased by 4.
$_{Z}^{A} X^{*} {\overset{γ - r a y}{\to}}_{Z}^{A} X {\overset{β - p a r t i c l e}{\to}}_{Z + 1}^{A} Y \overset{α - p a r t i c l e}{\to}$
$_{Z - 1}^{A - 4} Z^{*} {\overset{γ - r a y}{\to}}_{Z - 1}^{A - 4} Z$

PHXII13:NUCLEI

363906 Neutron decay in free space is given as follows:
$_{0} n^{1} \to_{1} P^{1} +_{- 1} e^{0} + []$
Then the parenthesis represents a

1 Antineutrino

2 Graviton

3 Photon

4 Neutrino

PHXII13:NUCLEI

363907 A nucleus of mass $214 a m u$ at rest emits an
$α$ - particle. Kinetic energy of the $α$ - particle is $6.7 M e V$ . The recoil energy of the daughter nucleus is

1

1.0 M e V

2

0.5 M e V

3

0.25 M e V

4

0.125 M e V

Explanation:

$p_{1}$ (momentum of alpha particle) $+ p_{2}$ (momentum of daughter nucleus $= 0$ (initial momentum)
$\Rightarrow p_{1} = - p_{2}$
For $α$ -particle
$\frac{p_{1}^{2}}{2 m} = 6.7 M e V$
For daughter nucleus, $E = \frac{p_{2}^{2}}{2 U}$
$\Rightarrow \frac{E}{6.7} = \frac{m}{M}$
$\Rightarrow \frac{E}{6.7} = \frac{4}{214}$
$\Rightarrow E = 0.125 M e V$

PHXII13:NUCLEI

363908 $_{82}^{290} X \overset{α}{\to} Y \overset{e^{+}}{\to} Z \overset{β^{-}}{\to} P \overset{e^{-}}{\to} Q$ In the nuclear emission stated above, the mass number and atomic number of the product $Q$ respectively, are

1 280, 81

2 286, 80

3 288, 82

4 286, 81

Explanation:

$_{82}^{290} X \overset{α}{\to}_{80}^{286} Y \overset{e^{+}}{\to}_{79}^{286} Z \overset{β^{-}}{\to}$
$_{80}^{286} P \overset{e^{-}}{\to}_{81}^{286} Q$
$A = 286$ and $Z = 81$

NEET - 2024

PHXII13:NUCLEI

363909 In the nuclear reaction $_{85} X^{297} \to Y + 4 α, Y$ is

1

_{77} Y^{281}

2

_{76} Y^{287}

3

_{77} Y^{285}

4

_{77} Y^{289}

Explanation:

$_{85} X^{297} \to_{A} Y^{B} + 4_{2} α^{4}$
By equating the atomic and mass numbers
$85 = A + 8 \Rightarrow A = 77$
$297 = B + 16 \Rightarrow B = 281$

PHXII13:NUCLEI

363905 An atom of mass number $A$ and atomic number $Z$ emits successively $a$ $γ$ -ray, a $β$ -particle, and $α$ -particle and $a$ $γ$ -ray. The mass number and the atomic number of the end product are:

1

A - 4, Z - A

2

A, Z + 1

3

A - 4, Z + 2

4

A - 4, Z - 1

Explanation:

When an atom of mass number $A$ and atomic number $Z$ emits $γ$ -rays, no change take place in atomic and mass number, but when a $β$ -particle is emitted, atomic mass number remain same, but atomic number increase by 1. When an alpha particle is emitted, atomic number is decreased by 2 and atomic mass number is decreased by 4.
$_{Z}^{A} X^{*} {\overset{γ - r a y}{\to}}_{Z}^{A} X {\overset{β - p a r t i c l e}{\to}}_{Z + 1}^{A} Y \overset{α - p a r t i c l e}{\to}$
$_{Z - 1}^{A - 4} Z^{*} {\overset{γ - r a y}{\to}}_{Z - 1}^{A - 4} Z$

PHXII13:NUCLEI

363906 Neutron decay in free space is given as follows:
$_{0} n^{1} \to_{1} P^{1} +_{- 1} e^{0} + []$
Then the parenthesis represents a

1 Antineutrino

2 Graviton

3 Photon

4 Neutrino

PHXII13:NUCLEI

363907 A nucleus of mass $214 a m u$ at rest emits an
$α$ - particle. Kinetic energy of the $α$ - particle is $6.7 M e V$ . The recoil energy of the daughter nucleus is

1

1.0 M e V

2

0.5 M e V

3

0.25 M e V

4

0.125 M e V

Explanation:

$p_{1}$ (momentum of alpha particle) $+ p_{2}$ (momentum of daughter nucleus $= 0$ (initial momentum)
$\Rightarrow p_{1} = - p_{2}$
For $α$ -particle
$\frac{p_{1}^{2}}{2 m} = 6.7 M e V$
For daughter nucleus, $E = \frac{p_{2}^{2}}{2 U}$
$\Rightarrow \frac{E}{6.7} = \frac{m}{M}$
$\Rightarrow \frac{E}{6.7} = \frac{4}{214}$
$\Rightarrow E = 0.125 M e V$

PHXII13:NUCLEI

363908 $_{82}^{290} X \overset{α}{\to} Y \overset{e^{+}}{\to} Z \overset{β^{-}}{\to} P \overset{e^{-}}{\to} Q$ In the nuclear emission stated above, the mass number and atomic number of the product $Q$ respectively, are

1 280, 81

2 286, 80

3 288, 82

4 286, 81

Explanation:

$_{82}^{290} X \overset{α}{\to}_{80}^{286} Y \overset{e^{+}}{\to}_{79}^{286} Z \overset{β^{-}}{\to}$
$_{80}^{286} P \overset{e^{-}}{\to}_{81}^{286} Q$
$A = 286$ and $Z = 81$

NEET - 2024

PHXII13:NUCLEI

363909 In the nuclear reaction $_{85} X^{297} \to Y + 4 α, Y$ is

1

_{77} Y^{281}

2

_{76} Y^{287}

3

_{77} Y^{285}

4

_{77} Y^{289}

Explanation:

$_{85} X^{297} \to_{A} Y^{B} + 4_{2} α^{4}$
By equating the atomic and mass numbers
$85 = A + 8 \Rightarrow A = 77$
$297 = B + 16 \Rightarrow B = 281$

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