363147
The pendulum hanging from the ceiling of a railway carriage makes an angle \(30^\circ \) with the vertical when it is accelerating. The acceleration of the carriage is
1 \(\frac{{\sqrt 3 }}{2}g\)
2 \(\frac{2}{{\sqrt 3 }}g\)
3 \(g\sqrt 3 \)
4 \(\frac{g}{{\sqrt 3 }}\)
Explanation:
\(T\cos \theta = mg\) and \(T\sin \theta = ma\) From these two equations we get, \(a = g\tan \theta = g\tan 30^\circ = \frac{g}{{\sqrt 3 }}\)
PHXI05:LAWS OF MOTION
363148
A person of mass 60 \(kg\) is inside a lift of mass 940 \(kg\) and presses the button on control panel. The lift starts moving upwards with an acceleration \(1.0\,m/{s^2}.\) If \(g = \,10\,m/{s^2},\) the tension in the supporting cable is
1 \(9680\,N\)
2 \(8600\,N\)
3 \(1200\,N\)
4 \(11000\,N\)
Explanation:
Total mass \((m) = \) Mass of lift \(+\) Mass of person \( = 940 + 60 = 1000\,kg\) \(T - mg = ma\) Hence, \(T - 1000 \times 10 = 1000 \times 1\) \(T = 11000\,N\)
PHXI05:LAWS OF MOTION
363149
Reading shown in two extended spring balances, \({S_{1}}\) and \({S_{2}}\) is \(60\,kg\) and \(30\,kg\) respectively and lift is accelerating upward with acceleration \({10 {~m} / {s}^{2}}\). The mass is stationary with respect to lift. Find the mass of the block
363150
Assertion : The driver in a vehicle moving with a constant speed on a straight road is in a non inertial frame of reference. Reason : A reference in which Newton's laws of motion are applicable is non - inertial.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Both Assertion and reason are incorrect.
Explanation:
A frame (vehicle) which moving with constant speed, i.e. acceleration \(=0\) is an inertial frame of reference and Newton's laws of motion are applicable in it Hence, option (4) is correct.
363147
The pendulum hanging from the ceiling of a railway carriage makes an angle \(30^\circ \) with the vertical when it is accelerating. The acceleration of the carriage is
1 \(\frac{{\sqrt 3 }}{2}g\)
2 \(\frac{2}{{\sqrt 3 }}g\)
3 \(g\sqrt 3 \)
4 \(\frac{g}{{\sqrt 3 }}\)
Explanation:
\(T\cos \theta = mg\) and \(T\sin \theta = ma\) From these two equations we get, \(a = g\tan \theta = g\tan 30^\circ = \frac{g}{{\sqrt 3 }}\)
PHXI05:LAWS OF MOTION
363148
A person of mass 60 \(kg\) is inside a lift of mass 940 \(kg\) and presses the button on control panel. The lift starts moving upwards with an acceleration \(1.0\,m/{s^2}.\) If \(g = \,10\,m/{s^2},\) the tension in the supporting cable is
1 \(9680\,N\)
2 \(8600\,N\)
3 \(1200\,N\)
4 \(11000\,N\)
Explanation:
Total mass \((m) = \) Mass of lift \(+\) Mass of person \( = 940 + 60 = 1000\,kg\) \(T - mg = ma\) Hence, \(T - 1000 \times 10 = 1000 \times 1\) \(T = 11000\,N\)
PHXI05:LAWS OF MOTION
363149
Reading shown in two extended spring balances, \({S_{1}}\) and \({S_{2}}\) is \(60\,kg\) and \(30\,kg\) respectively and lift is accelerating upward with acceleration \({10 {~m} / {s}^{2}}\). The mass is stationary with respect to lift. Find the mass of the block
363150
Assertion : The driver in a vehicle moving with a constant speed on a straight road is in a non inertial frame of reference. Reason : A reference in which Newton's laws of motion are applicable is non - inertial.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Both Assertion and reason are incorrect.
Explanation:
A frame (vehicle) which moving with constant speed, i.e. acceleration \(=0\) is an inertial frame of reference and Newton's laws of motion are applicable in it Hence, option (4) is correct.
363147
The pendulum hanging from the ceiling of a railway carriage makes an angle \(30^\circ \) with the vertical when it is accelerating. The acceleration of the carriage is
1 \(\frac{{\sqrt 3 }}{2}g\)
2 \(\frac{2}{{\sqrt 3 }}g\)
3 \(g\sqrt 3 \)
4 \(\frac{g}{{\sqrt 3 }}\)
Explanation:
\(T\cos \theta = mg\) and \(T\sin \theta = ma\) From these two equations we get, \(a = g\tan \theta = g\tan 30^\circ = \frac{g}{{\sqrt 3 }}\)
PHXI05:LAWS OF MOTION
363148
A person of mass 60 \(kg\) is inside a lift of mass 940 \(kg\) and presses the button on control panel. The lift starts moving upwards with an acceleration \(1.0\,m/{s^2}.\) If \(g = \,10\,m/{s^2},\) the tension in the supporting cable is
1 \(9680\,N\)
2 \(8600\,N\)
3 \(1200\,N\)
4 \(11000\,N\)
Explanation:
Total mass \((m) = \) Mass of lift \(+\) Mass of person \( = 940 + 60 = 1000\,kg\) \(T - mg = ma\) Hence, \(T - 1000 \times 10 = 1000 \times 1\) \(T = 11000\,N\)
PHXI05:LAWS OF MOTION
363149
Reading shown in two extended spring balances, \({S_{1}}\) and \({S_{2}}\) is \(60\,kg\) and \(30\,kg\) respectively and lift is accelerating upward with acceleration \({10 {~m} / {s}^{2}}\). The mass is stationary with respect to lift. Find the mass of the block
363150
Assertion : The driver in a vehicle moving with a constant speed on a straight road is in a non inertial frame of reference. Reason : A reference in which Newton's laws of motion are applicable is non - inertial.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Both Assertion and reason are incorrect.
Explanation:
A frame (vehicle) which moving with constant speed, i.e. acceleration \(=0\) is an inertial frame of reference and Newton's laws of motion are applicable in it Hence, option (4) is correct.
363147
The pendulum hanging from the ceiling of a railway carriage makes an angle \(30^\circ \) with the vertical when it is accelerating. The acceleration of the carriage is
1 \(\frac{{\sqrt 3 }}{2}g\)
2 \(\frac{2}{{\sqrt 3 }}g\)
3 \(g\sqrt 3 \)
4 \(\frac{g}{{\sqrt 3 }}\)
Explanation:
\(T\cos \theta = mg\) and \(T\sin \theta = ma\) From these two equations we get, \(a = g\tan \theta = g\tan 30^\circ = \frac{g}{{\sqrt 3 }}\)
PHXI05:LAWS OF MOTION
363148
A person of mass 60 \(kg\) is inside a lift of mass 940 \(kg\) and presses the button on control panel. The lift starts moving upwards with an acceleration \(1.0\,m/{s^2}.\) If \(g = \,10\,m/{s^2},\) the tension in the supporting cable is
1 \(9680\,N\)
2 \(8600\,N\)
3 \(1200\,N\)
4 \(11000\,N\)
Explanation:
Total mass \((m) = \) Mass of lift \(+\) Mass of person \( = 940 + 60 = 1000\,kg\) \(T - mg = ma\) Hence, \(T - 1000 \times 10 = 1000 \times 1\) \(T = 11000\,N\)
PHXI05:LAWS OF MOTION
363149
Reading shown in two extended spring balances, \({S_{1}}\) and \({S_{2}}\) is \(60\,kg\) and \(30\,kg\) respectively and lift is accelerating upward with acceleration \({10 {~m} / {s}^{2}}\). The mass is stationary with respect to lift. Find the mass of the block
363150
Assertion : The driver in a vehicle moving with a constant speed on a straight road is in a non inertial frame of reference. Reason : A reference in which Newton's laws of motion are applicable is non - inertial.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Both Assertion and reason are incorrect.
Explanation:
A frame (vehicle) which moving with constant speed, i.e. acceleration \(=0\) is an inertial frame of reference and Newton's laws of motion are applicable in it Hence, option (4) is correct.
