363151
The elevator shown in fig. is descending with an acceleration of \(6\,m/{s^2}\). The mass of block \(A\) is 1\(kg\). The force between \(A\) and \(B\) is :
1 \(4\,N\)
2 \(2\,N\)
3 \(1\,N\)
4 \({\mathop{\rm zero}\nolimits} \)
Explanation:
Let \(N\) be the normal force between \(A\) and \(B\). The Newton's \({2^{nd}}\) law w.r.to lift frame on block \(A\) is \(N - mg + ma = m\left( 0 \right)\) \( \Rightarrow N = m\left( {g - a} \right)\) \( = 1\left( {10 - 6} \right) = 4N\)
PHXI05:LAWS OF MOTION
363152
Two wooden blocks are moving on a smooth horizontal surface such that the mass \(m\) remains stationary with respect to block of mass \(M\) as shown in the figure. The magnitude of force \(P\) is:
1 \((M + m)g\tan \beta \)
2 \(g\tan \beta \)
3 \(mg\cos \beta \)
4 \((M + m)g\,{\rm{coses}}\,\beta \)
Explanation:
The acceleration with which the system should move so that the block does not move w.r. to the wedge is \(g\tan \beta \). The required force is \(F = (M + m)g\tan \beta \)
PHXI05:LAWS OF MOTION
363153
A pseudo force
1 Is a pseudo vector
2 Acts on the observer
3 Has no reaction force
4 \( - m\overrightarrow a \), where \(a = \) acceleration of the object of mass \(m\).
Explanation:
Conceptual Question
PHXI05:LAWS OF MOTION
363154
A person is standing in an elevator. In which situation he finds his weight less than actual weight?
1 The elevator moves upward with constant acceleration
2 The elevator moves downward with constant acceleration
3 The elevator moves upward with uniform velocity
4 The elevator moves downward with uniform velocity
Explanation:
When the elevator moves downward with an acceleration then pseudo force acts upward. Which will reduce the weight of the person.
363151
The elevator shown in fig. is descending with an acceleration of \(6\,m/{s^2}\). The mass of block \(A\) is 1\(kg\). The force between \(A\) and \(B\) is :
1 \(4\,N\)
2 \(2\,N\)
3 \(1\,N\)
4 \({\mathop{\rm zero}\nolimits} \)
Explanation:
Let \(N\) be the normal force between \(A\) and \(B\). The Newton's \({2^{nd}}\) law w.r.to lift frame on block \(A\) is \(N - mg + ma = m\left( 0 \right)\) \( \Rightarrow N = m\left( {g - a} \right)\) \( = 1\left( {10 - 6} \right) = 4N\)
PHXI05:LAWS OF MOTION
363152
Two wooden blocks are moving on a smooth horizontal surface such that the mass \(m\) remains stationary with respect to block of mass \(M\) as shown in the figure. The magnitude of force \(P\) is:
1 \((M + m)g\tan \beta \)
2 \(g\tan \beta \)
3 \(mg\cos \beta \)
4 \((M + m)g\,{\rm{coses}}\,\beta \)
Explanation:
The acceleration with which the system should move so that the block does not move w.r. to the wedge is \(g\tan \beta \). The required force is \(F = (M + m)g\tan \beta \)
PHXI05:LAWS OF MOTION
363153
A pseudo force
1 Is a pseudo vector
2 Acts on the observer
3 Has no reaction force
4 \( - m\overrightarrow a \), where \(a = \) acceleration of the object of mass \(m\).
Explanation:
Conceptual Question
PHXI05:LAWS OF MOTION
363154
A person is standing in an elevator. In which situation he finds his weight less than actual weight?
1 The elevator moves upward with constant acceleration
2 The elevator moves downward with constant acceleration
3 The elevator moves upward with uniform velocity
4 The elevator moves downward with uniform velocity
Explanation:
When the elevator moves downward with an acceleration then pseudo force acts upward. Which will reduce the weight of the person.
363151
The elevator shown in fig. is descending with an acceleration of \(6\,m/{s^2}\). The mass of block \(A\) is 1\(kg\). The force between \(A\) and \(B\) is :
1 \(4\,N\)
2 \(2\,N\)
3 \(1\,N\)
4 \({\mathop{\rm zero}\nolimits} \)
Explanation:
Let \(N\) be the normal force between \(A\) and \(B\). The Newton's \({2^{nd}}\) law w.r.to lift frame on block \(A\) is \(N - mg + ma = m\left( 0 \right)\) \( \Rightarrow N = m\left( {g - a} \right)\) \( = 1\left( {10 - 6} \right) = 4N\)
PHXI05:LAWS OF MOTION
363152
Two wooden blocks are moving on a smooth horizontal surface such that the mass \(m\) remains stationary with respect to block of mass \(M\) as shown in the figure. The magnitude of force \(P\) is:
1 \((M + m)g\tan \beta \)
2 \(g\tan \beta \)
3 \(mg\cos \beta \)
4 \((M + m)g\,{\rm{coses}}\,\beta \)
Explanation:
The acceleration with which the system should move so that the block does not move w.r. to the wedge is \(g\tan \beta \). The required force is \(F = (M + m)g\tan \beta \)
PHXI05:LAWS OF MOTION
363153
A pseudo force
1 Is a pseudo vector
2 Acts on the observer
3 Has no reaction force
4 \( - m\overrightarrow a \), where \(a = \) acceleration of the object of mass \(m\).
Explanation:
Conceptual Question
PHXI05:LAWS OF MOTION
363154
A person is standing in an elevator. In which situation he finds his weight less than actual weight?
1 The elevator moves upward with constant acceleration
2 The elevator moves downward with constant acceleration
3 The elevator moves upward with uniform velocity
4 The elevator moves downward with uniform velocity
Explanation:
When the elevator moves downward with an acceleration then pseudo force acts upward. Which will reduce the weight of the person.
363151
The elevator shown in fig. is descending with an acceleration of \(6\,m/{s^2}\). The mass of block \(A\) is 1\(kg\). The force between \(A\) and \(B\) is :
1 \(4\,N\)
2 \(2\,N\)
3 \(1\,N\)
4 \({\mathop{\rm zero}\nolimits} \)
Explanation:
Let \(N\) be the normal force between \(A\) and \(B\). The Newton's \({2^{nd}}\) law w.r.to lift frame on block \(A\) is \(N - mg + ma = m\left( 0 \right)\) \( \Rightarrow N = m\left( {g - a} \right)\) \( = 1\left( {10 - 6} \right) = 4N\)
PHXI05:LAWS OF MOTION
363152
Two wooden blocks are moving on a smooth horizontal surface such that the mass \(m\) remains stationary with respect to block of mass \(M\) as shown in the figure. The magnitude of force \(P\) is:
1 \((M + m)g\tan \beta \)
2 \(g\tan \beta \)
3 \(mg\cos \beta \)
4 \((M + m)g\,{\rm{coses}}\,\beta \)
Explanation:
The acceleration with which the system should move so that the block does not move w.r. to the wedge is \(g\tan \beta \). The required force is \(F = (M + m)g\tan \beta \)
PHXI05:LAWS OF MOTION
363153
A pseudo force
1 Is a pseudo vector
2 Acts on the observer
3 Has no reaction force
4 \( - m\overrightarrow a \), where \(a = \) acceleration of the object of mass \(m\).
Explanation:
Conceptual Question
PHXI05:LAWS OF MOTION
363154
A person is standing in an elevator. In which situation he finds his weight less than actual weight?
1 The elevator moves upward with constant acceleration
2 The elevator moves downward with constant acceleration
3 The elevator moves upward with uniform velocity
4 The elevator moves downward with uniform velocity
Explanation:
When the elevator moves downward with an acceleration then pseudo force acts upward. Which will reduce the weight of the person.
