Kinematics of Circular Motion
PHXI04:MOTION IN A PLANE

361835 A particle moving with a constant speed of \({9 {~km} / {h}}\) on a circle reaches from end \({A}\) to the diametrically opposite end \({B}\) in time \({2 s}\). The average acceleration from \({A}\) to \({B}\) is
supporting img

1 \({9 {~km} / {h}^{2}}\)
2 \({18 {~km} / {s}^{2}}\)
3 \({5 {~km} / {h}^{2}}\)
4 \({2.5 {~m} / {s}^{2}}\)
PHXI04:MOTION IN A PLANE

361836 A particle is moving in a circle of radius \(R\) with constant speed \(v\), if radius is doubled then its centripetal force to keep the same speed should be

1 Doubled
2 Halved
3 Quadrupled
4 Unchanged
PHXI04:MOTION IN A PLANE

361837 A particle is moving with constant speed \({v}\) in \({x-y}\) plane, as shown in the figure. The magnitude of its angular velocity about point \({O}\) is
supporting img

1 \({\dfrac{v}{\sqrt{a^{2}+b^{2}}}}\)
2 \({\dfrac{v}{b}}\)
3 \({\dfrac{v b}{\left(a^{2}+b^{2}\right)}}\)
4 \({\dfrac{v}{a}}\)
PHXI04:MOTION IN A PLANE

361838 The angle turned by a body undergoing circular motion depends on time as \(\theta = {\theta _0} + {\theta _1}t + {\theta _2}{t^2}.\) Then the angular acceleration of the body is

1 \({\theta _1}\)
2 \({\theta _2}\)
3 \(2{\theta _1}\)
4 \(2{\theta _2}\)
PHXI04:MOTION IN A PLANE

361839 A point \(P\) moves in counter-clockwise direction on a circular path as shown in the figure. The movement of \('P'\) is such that it sweeps out a length \(s=t^{3}+5\), where \(s\) is in metres and \(t\) is in seconds. The radius of the path is \(27\;m.\) The acceleration of ' \(P\) ' when \(t = 3\;s\) is
(Take \(\sqrt{13}=3.6\) )
supporting img

1 \(42.2\,\,m/{s^2}\)
2 \(51.4\,\,m/{s^2}\)
3 \(63.1\,\,m/{s^2}\)
4 \(32.4\,\,m/{s^2}\)
PHXI04:MOTION IN A PLANE

361835 A particle moving with a constant speed of \({9 {~km} / {h}}\) on a circle reaches from end \({A}\) to the diametrically opposite end \({B}\) in time \({2 s}\). The average acceleration from \({A}\) to \({B}\) is
supporting img

1 \({9 {~km} / {h}^{2}}\)
2 \({18 {~km} / {s}^{2}}\)
3 \({5 {~km} / {h}^{2}}\)
4 \({2.5 {~m} / {s}^{2}}\)
PHXI04:MOTION IN A PLANE

361836 A particle is moving in a circle of radius \(R\) with constant speed \(v\), if radius is doubled then its centripetal force to keep the same speed should be

1 Doubled
2 Halved
3 Quadrupled
4 Unchanged
PHXI04:MOTION IN A PLANE

361837 A particle is moving with constant speed \({v}\) in \({x-y}\) plane, as shown in the figure. The magnitude of its angular velocity about point \({O}\) is
supporting img

1 \({\dfrac{v}{\sqrt{a^{2}+b^{2}}}}\)
2 \({\dfrac{v}{b}}\)
3 \({\dfrac{v b}{\left(a^{2}+b^{2}\right)}}\)
4 \({\dfrac{v}{a}}\)
PHXI04:MOTION IN A PLANE

361838 The angle turned by a body undergoing circular motion depends on time as \(\theta = {\theta _0} + {\theta _1}t + {\theta _2}{t^2}.\) Then the angular acceleration of the body is

1 \({\theta _1}\)
2 \({\theta _2}\)
3 \(2{\theta _1}\)
4 \(2{\theta _2}\)
PHXI04:MOTION IN A PLANE

361839 A point \(P\) moves in counter-clockwise direction on a circular path as shown in the figure. The movement of \('P'\) is such that it sweeps out a length \(s=t^{3}+5\), where \(s\) is in metres and \(t\) is in seconds. The radius of the path is \(27\;m.\) The acceleration of ' \(P\) ' when \(t = 3\;s\) is
(Take \(\sqrt{13}=3.6\) )
supporting img

1 \(42.2\,\,m/{s^2}\)
2 \(51.4\,\,m/{s^2}\)
3 \(63.1\,\,m/{s^2}\)
4 \(32.4\,\,m/{s^2}\)
PHXI04:MOTION IN A PLANE

361835 A particle moving with a constant speed of \({9 {~km} / {h}}\) on a circle reaches from end \({A}\) to the diametrically opposite end \({B}\) in time \({2 s}\). The average acceleration from \({A}\) to \({B}\) is
supporting img

1 \({9 {~km} / {h}^{2}}\)
2 \({18 {~km} / {s}^{2}}\)
3 \({5 {~km} / {h}^{2}}\)
4 \({2.5 {~m} / {s}^{2}}\)
PHXI04:MOTION IN A PLANE

361836 A particle is moving in a circle of radius \(R\) with constant speed \(v\), if radius is doubled then its centripetal force to keep the same speed should be

1 Doubled
2 Halved
3 Quadrupled
4 Unchanged
PHXI04:MOTION IN A PLANE

361837 A particle is moving with constant speed \({v}\) in \({x-y}\) plane, as shown in the figure. The magnitude of its angular velocity about point \({O}\) is
supporting img

1 \({\dfrac{v}{\sqrt{a^{2}+b^{2}}}}\)
2 \({\dfrac{v}{b}}\)
3 \({\dfrac{v b}{\left(a^{2}+b^{2}\right)}}\)
4 \({\dfrac{v}{a}}\)
PHXI04:MOTION IN A PLANE

361838 The angle turned by a body undergoing circular motion depends on time as \(\theta = {\theta _0} + {\theta _1}t + {\theta _2}{t^2}.\) Then the angular acceleration of the body is

1 \({\theta _1}\)
2 \({\theta _2}\)
3 \(2{\theta _1}\)
4 \(2{\theta _2}\)
PHXI04:MOTION IN A PLANE

361839 A point \(P\) moves in counter-clockwise direction on a circular path as shown in the figure. The movement of \('P'\) is such that it sweeps out a length \(s=t^{3}+5\), where \(s\) is in metres and \(t\) is in seconds. The radius of the path is \(27\;m.\) The acceleration of ' \(P\) ' when \(t = 3\;s\) is
(Take \(\sqrt{13}=3.6\) )
supporting img

1 \(42.2\,\,m/{s^2}\)
2 \(51.4\,\,m/{s^2}\)
3 \(63.1\,\,m/{s^2}\)
4 \(32.4\,\,m/{s^2}\)
PHXI04:MOTION IN A PLANE

361835 A particle moving with a constant speed of \({9 {~km} / {h}}\) on a circle reaches from end \({A}\) to the diametrically opposite end \({B}\) in time \({2 s}\). The average acceleration from \({A}\) to \({B}\) is
supporting img

1 \({9 {~km} / {h}^{2}}\)
2 \({18 {~km} / {s}^{2}}\)
3 \({5 {~km} / {h}^{2}}\)
4 \({2.5 {~m} / {s}^{2}}\)
PHXI04:MOTION IN A PLANE

361836 A particle is moving in a circle of radius \(R\) with constant speed \(v\), if radius is doubled then its centripetal force to keep the same speed should be

1 Doubled
2 Halved
3 Quadrupled
4 Unchanged
PHXI04:MOTION IN A PLANE

361837 A particle is moving with constant speed \({v}\) in \({x-y}\) plane, as shown in the figure. The magnitude of its angular velocity about point \({O}\) is
supporting img

1 \({\dfrac{v}{\sqrt{a^{2}+b^{2}}}}\)
2 \({\dfrac{v}{b}}\)
3 \({\dfrac{v b}{\left(a^{2}+b^{2}\right)}}\)
4 \({\dfrac{v}{a}}\)
PHXI04:MOTION IN A PLANE

361838 The angle turned by a body undergoing circular motion depends on time as \(\theta = {\theta _0} + {\theta _1}t + {\theta _2}{t^2}.\) Then the angular acceleration of the body is

1 \({\theta _1}\)
2 \({\theta _2}\)
3 \(2{\theta _1}\)
4 \(2{\theta _2}\)
PHXI04:MOTION IN A PLANE

361839 A point \(P\) moves in counter-clockwise direction on a circular path as shown in the figure. The movement of \('P'\) is such that it sweeps out a length \(s=t^{3}+5\), where \(s\) is in metres and \(t\) is in seconds. The radius of the path is \(27\;m.\) The acceleration of ' \(P\) ' when \(t = 3\;s\) is
(Take \(\sqrt{13}=3.6\) )
supporting img

1 \(42.2\,\,m/{s^2}\)
2 \(51.4\,\,m/{s^2}\)
3 \(63.1\,\,m/{s^2}\)
4 \(32.4\,\,m/{s^2}\)
PHXI04:MOTION IN A PLANE

361835 A particle moving with a constant speed of \({9 {~km} / {h}}\) on a circle reaches from end \({A}\) to the diametrically opposite end \({B}\) in time \({2 s}\). The average acceleration from \({A}\) to \({B}\) is
supporting img

1 \({9 {~km} / {h}^{2}}\)
2 \({18 {~km} / {s}^{2}}\)
3 \({5 {~km} / {h}^{2}}\)
4 \({2.5 {~m} / {s}^{2}}\)
PHXI04:MOTION IN A PLANE

361836 A particle is moving in a circle of radius \(R\) with constant speed \(v\), if radius is doubled then its centripetal force to keep the same speed should be

1 Doubled
2 Halved
3 Quadrupled
4 Unchanged
PHXI04:MOTION IN A PLANE

361837 A particle is moving with constant speed \({v}\) in \({x-y}\) plane, as shown in the figure. The magnitude of its angular velocity about point \({O}\) is
supporting img

1 \({\dfrac{v}{\sqrt{a^{2}+b^{2}}}}\)
2 \({\dfrac{v}{b}}\)
3 \({\dfrac{v b}{\left(a^{2}+b^{2}\right)}}\)
4 \({\dfrac{v}{a}}\)
PHXI04:MOTION IN A PLANE

361838 The angle turned by a body undergoing circular motion depends on time as \(\theta = {\theta _0} + {\theta _1}t + {\theta _2}{t^2}.\) Then the angular acceleration of the body is

1 \({\theta _1}\)
2 \({\theta _2}\)
3 \(2{\theta _1}\)
4 \(2{\theta _2}\)
PHXI04:MOTION IN A PLANE

361839 A point \(P\) moves in counter-clockwise direction on a circular path as shown in the figure. The movement of \('P'\) is such that it sweeps out a length \(s=t^{3}+5\), where \(s\) is in metres and \(t\) is in seconds. The radius of the path is \(27\;m.\) The acceleration of ' \(P\) ' when \(t = 3\;s\) is
(Take \(\sqrt{13}=3.6\) )
supporting img

1 \(42.2\,\,m/{s^2}\)
2 \(51.4\,\,m/{s^2}\)
3 \(63.1\,\,m/{s^2}\)
4 \(32.4\,\,m/{s^2}\)