360396
A bar magnet with a magnetic moment \(5.0\,A{m^2}\) is placed in parallel position relative to a magnetic field of \(0.4\,T.\) The amount of required work done in turning the magnet from parallel to antiparallel position relative to the field direction is
1 \(4\,J\)
2 \(2\,J\)
3 zero
4 \(1\,J\)
Explanation:
The work done in turning a magnet from position \(\theta_{1}\) to \(\theta_{2}\) in a magnetic field \(B\) is, \(W=-\Delta U=U_{i}-U_{f}\) \(\therefore W=M B\left(\cos \theta_{1}-\cos \theta_{2}\right)\) As per question, \(W=M B\left(\cos 0^{\circ}-\cos 180^{\circ}\right)\) \(W = 2MB = 2 \times 5.0 \times 0.4 = 4\,J\) So, correct option is (1).
JEE - 2023
PHXII05:MAGNETISM and MATTER
360397
A magnetic needle suspended parallel to a magnetic field requires \({\sqrt{3} J}\) of work to turn it through \({60^{\circ}}\). The torque needed to maintain the needle in this position will be
360398
A magnet of magnetic moment \(M\) is rotated through \(360^{\circ}\) in a magnetic field of field strength \(H\). The work done will be
1 2\(MH\)
2 \(2 \pi M H\)
3 \(MH\)
4 Zero
Explanation:
Work done to rotate a dipole in field \(\begin{aligned}& W=M B\left(\cos \theta_{1}-\cos \theta_{2}\right) \\& \theta_{1}=0^{\circ} \text { and } \theta_{2}=360^{\circ} \Rightarrow W=0\end{aligned}\)
PHXII05:MAGNETISM and MATTER
360399
Assertion : Magnetic dipole possesses maximum potential energy when magnetic moment and magnetic field are parallel to each other. Reason : Current loop is treated as a magnetic dipole.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
We know that, magnetic dipole possesses maximum potential energy when magnetic moment and magnetic field are anti-parallel. A current loop can be treated as a magnetic dipole. When current loop has an area, \(A\) and carries a current, \(i\) then the magnetic dipole moment is given by \(M=i A\). Option (4) is correct.
360396
A bar magnet with a magnetic moment \(5.0\,A{m^2}\) is placed in parallel position relative to a magnetic field of \(0.4\,T.\) The amount of required work done in turning the magnet from parallel to antiparallel position relative to the field direction is
1 \(4\,J\)
2 \(2\,J\)
3 zero
4 \(1\,J\)
Explanation:
The work done in turning a magnet from position \(\theta_{1}\) to \(\theta_{2}\) in a magnetic field \(B\) is, \(W=-\Delta U=U_{i}-U_{f}\) \(\therefore W=M B\left(\cos \theta_{1}-\cos \theta_{2}\right)\) As per question, \(W=M B\left(\cos 0^{\circ}-\cos 180^{\circ}\right)\) \(W = 2MB = 2 \times 5.0 \times 0.4 = 4\,J\) So, correct option is (1).
JEE - 2023
PHXII05:MAGNETISM and MATTER
360397
A magnetic needle suspended parallel to a magnetic field requires \({\sqrt{3} J}\) of work to turn it through \({60^{\circ}}\). The torque needed to maintain the needle in this position will be
360398
A magnet of magnetic moment \(M\) is rotated through \(360^{\circ}\) in a magnetic field of field strength \(H\). The work done will be
1 2\(MH\)
2 \(2 \pi M H\)
3 \(MH\)
4 Zero
Explanation:
Work done to rotate a dipole in field \(\begin{aligned}& W=M B\left(\cos \theta_{1}-\cos \theta_{2}\right) \\& \theta_{1}=0^{\circ} \text { and } \theta_{2}=360^{\circ} \Rightarrow W=0\end{aligned}\)
PHXII05:MAGNETISM and MATTER
360399
Assertion : Magnetic dipole possesses maximum potential energy when magnetic moment and magnetic field are parallel to each other. Reason : Current loop is treated as a magnetic dipole.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
We know that, magnetic dipole possesses maximum potential energy when magnetic moment and magnetic field are anti-parallel. A current loop can be treated as a magnetic dipole. When current loop has an area, \(A\) and carries a current, \(i\) then the magnetic dipole moment is given by \(M=i A\). Option (4) is correct.
360396
A bar magnet with a magnetic moment \(5.0\,A{m^2}\) is placed in parallel position relative to a magnetic field of \(0.4\,T.\) The amount of required work done in turning the magnet from parallel to antiparallel position relative to the field direction is
1 \(4\,J\)
2 \(2\,J\)
3 zero
4 \(1\,J\)
Explanation:
The work done in turning a magnet from position \(\theta_{1}\) to \(\theta_{2}\) in a magnetic field \(B\) is, \(W=-\Delta U=U_{i}-U_{f}\) \(\therefore W=M B\left(\cos \theta_{1}-\cos \theta_{2}\right)\) As per question, \(W=M B\left(\cos 0^{\circ}-\cos 180^{\circ}\right)\) \(W = 2MB = 2 \times 5.0 \times 0.4 = 4\,J\) So, correct option is (1).
JEE - 2023
PHXII05:MAGNETISM and MATTER
360397
A magnetic needle suspended parallel to a magnetic field requires \({\sqrt{3} J}\) of work to turn it through \({60^{\circ}}\). The torque needed to maintain the needle in this position will be
360398
A magnet of magnetic moment \(M\) is rotated through \(360^{\circ}\) in a magnetic field of field strength \(H\). The work done will be
1 2\(MH\)
2 \(2 \pi M H\)
3 \(MH\)
4 Zero
Explanation:
Work done to rotate a dipole in field \(\begin{aligned}& W=M B\left(\cos \theta_{1}-\cos \theta_{2}\right) \\& \theta_{1}=0^{\circ} \text { and } \theta_{2}=360^{\circ} \Rightarrow W=0\end{aligned}\)
PHXII05:MAGNETISM and MATTER
360399
Assertion : Magnetic dipole possesses maximum potential energy when magnetic moment and magnetic field are parallel to each other. Reason : Current loop is treated as a magnetic dipole.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
We know that, magnetic dipole possesses maximum potential energy when magnetic moment and magnetic field are anti-parallel. A current loop can be treated as a magnetic dipole. When current loop has an area, \(A\) and carries a current, \(i\) then the magnetic dipole moment is given by \(M=i A\). Option (4) is correct.
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PHXII05:MAGNETISM and MATTER
360396
A bar magnet with a magnetic moment \(5.0\,A{m^2}\) is placed in parallel position relative to a magnetic field of \(0.4\,T.\) The amount of required work done in turning the magnet from parallel to antiparallel position relative to the field direction is
1 \(4\,J\)
2 \(2\,J\)
3 zero
4 \(1\,J\)
Explanation:
The work done in turning a magnet from position \(\theta_{1}\) to \(\theta_{2}\) in a magnetic field \(B\) is, \(W=-\Delta U=U_{i}-U_{f}\) \(\therefore W=M B\left(\cos \theta_{1}-\cos \theta_{2}\right)\) As per question, \(W=M B\left(\cos 0^{\circ}-\cos 180^{\circ}\right)\) \(W = 2MB = 2 \times 5.0 \times 0.4 = 4\,J\) So, correct option is (1).
JEE - 2023
PHXII05:MAGNETISM and MATTER
360397
A magnetic needle suspended parallel to a magnetic field requires \({\sqrt{3} J}\) of work to turn it through \({60^{\circ}}\). The torque needed to maintain the needle in this position will be
360398
A magnet of magnetic moment \(M\) is rotated through \(360^{\circ}\) in a magnetic field of field strength \(H\). The work done will be
1 2\(MH\)
2 \(2 \pi M H\)
3 \(MH\)
4 Zero
Explanation:
Work done to rotate a dipole in field \(\begin{aligned}& W=M B\left(\cos \theta_{1}-\cos \theta_{2}\right) \\& \theta_{1}=0^{\circ} \text { and } \theta_{2}=360^{\circ} \Rightarrow W=0\end{aligned}\)
PHXII05:MAGNETISM and MATTER
360399
Assertion : Magnetic dipole possesses maximum potential energy when magnetic moment and magnetic field are parallel to each other. Reason : Current loop is treated as a magnetic dipole.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
We know that, magnetic dipole possesses maximum potential energy when magnetic moment and magnetic field are anti-parallel. A current loop can be treated as a magnetic dipole. When current loop has an area, \(A\) and carries a current, \(i\) then the magnetic dipole moment is given by \(M=i A\). Option (4) is correct.
