Relation between Field and Potential
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PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359563 An electric field is expressed as \(\overrightarrow E = 2\widehat i + 3\widehat j\). Find the potential difference \(({V_A} - {V_B})\) between two points \(A\) and \(B\) whose position vectors are given by \({r_A} = \widehat i + 2\widehat j\) and \({r_B} = 2\widehat i + \widehat j + 3\widehat k\)

1 \( - 1\,V\)
2 \(1\,V\)
3 \(2\,V\)
4 \(3\,V\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359564 A uniform electric field of magnitude \(E\) and directed along positive \(x\)-axis exists in a certain region of space. At \(x = 0\) the electric potential \(V\) is zero, then the potential at \(x = + {x_0}\) is

1 \( - \frac{E}{{{x_0}}}\)
2 \( - E\,{x_0}\)
3 \({\rm{Zero}}\)
4 \(\frac{E}{{{x_0}}}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359565 In the figure shown, the electric field intensity at \(r = 1m,r = 6m,r = 9m,\) in \(V{m^{ - 1}}\) is
supporting img

1 \( + 5,1.67, - 5\)
2 \( - 5,0 + 5\)
3 \( - 5, - 1.67, + 5\)
4 \(0,1.67,0\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359566 Electric potential at any point is \(V = - 5x + 3y + \sqrt {15} \,z,\) then the magnitude of the electric field is :

1 \(4\sqrt 2 \)
2 \(3\sqrt 2 \)
3 \(7\)
4 \(5\sqrt 2 \)
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PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359563 An electric field is expressed as \(\overrightarrow E = 2\widehat i + 3\widehat j\). Find the potential difference \(({V_A} - {V_B})\) between two points \(A\) and \(B\) whose position vectors are given by \({r_A} = \widehat i + 2\widehat j\) and \({r_B} = 2\widehat i + \widehat j + 3\widehat k\)

1 \( - 1\,V\)
2 \(1\,V\)
3 \(2\,V\)
4 \(3\,V\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359564 A uniform electric field of magnitude \(E\) and directed along positive \(x\)-axis exists in a certain region of space. At \(x = 0\) the electric potential \(V\) is zero, then the potential at \(x = + {x_0}\) is

1 \( - \frac{E}{{{x_0}}}\)
2 \( - E\,{x_0}\)
3 \({\rm{Zero}}\)
4 \(\frac{E}{{{x_0}}}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359565 In the figure shown, the electric field intensity at \(r = 1m,r = 6m,r = 9m,\) in \(V{m^{ - 1}}\) is
supporting img

1 \( + 5,1.67, - 5\)
2 \( - 5,0 + 5\)
3 \( - 5, - 1.67, + 5\)
4 \(0,1.67,0\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359566 Electric potential at any point is \(V = - 5x + 3y + \sqrt {15} \,z,\) then the magnitude of the electric field is :

1 \(4\sqrt 2 \)
2 \(3\sqrt 2 \)
3 \(7\)
4 \(5\sqrt 2 \)
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PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359563 An electric field is expressed as \(\overrightarrow E = 2\widehat i + 3\widehat j\). Find the potential difference \(({V_A} - {V_B})\) between two points \(A\) and \(B\) whose position vectors are given by \({r_A} = \widehat i + 2\widehat j\) and \({r_B} = 2\widehat i + \widehat j + 3\widehat k\)

1 \( - 1\,V\)
2 \(1\,V\)
3 \(2\,V\)
4 \(3\,V\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359564 A uniform electric field of magnitude \(E\) and directed along positive \(x\)-axis exists in a certain region of space. At \(x = 0\) the electric potential \(V\) is zero, then the potential at \(x = + {x_0}\) is

1 \( - \frac{E}{{{x_0}}}\)
2 \( - E\,{x_0}\)
3 \({\rm{Zero}}\)
4 \(\frac{E}{{{x_0}}}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359565 In the figure shown, the electric field intensity at \(r = 1m,r = 6m,r = 9m,\) in \(V{m^{ - 1}}\) is
supporting img

1 \( + 5,1.67, - 5\)
2 \( - 5,0 + 5\)
3 \( - 5, - 1.67, + 5\)
4 \(0,1.67,0\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359566 Electric potential at any point is \(V = - 5x + 3y + \sqrt {15} \,z,\) then the magnitude of the electric field is :

1 \(4\sqrt 2 \)
2 \(3\sqrt 2 \)
3 \(7\)
4 \(5\sqrt 2 \)
For More Updates join with Us
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359563 An electric field is expressed as \(\overrightarrow E = 2\widehat i + 3\widehat j\). Find the potential difference \(({V_A} - {V_B})\) between two points \(A\) and \(B\) whose position vectors are given by \({r_A} = \widehat i + 2\widehat j\) and \({r_B} = 2\widehat i + \widehat j + 3\widehat k\)

1 \( - 1\,V\)
2 \(1\,V\)
3 \(2\,V\)
4 \(3\,V\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359564 A uniform electric field of magnitude \(E\) and directed along positive \(x\)-axis exists in a certain region of space. At \(x = 0\) the electric potential \(V\) is zero, then the potential at \(x = + {x_0}\) is

1 \( - \frac{E}{{{x_0}}}\)
2 \( - E\,{x_0}\)
3 \({\rm{Zero}}\)
4 \(\frac{E}{{{x_0}}}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359565 In the figure shown, the electric field intensity at \(r = 1m,r = 6m,r = 9m,\) in \(V{m^{ - 1}}\) is
supporting img

1 \( + 5,1.67, - 5\)
2 \( - 5,0 + 5\)
3 \( - 5, - 1.67, + 5\)
4 \(0,1.67,0\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359566 Electric potential at any point is \(V = - 5x + 3y + \sqrt {15} \,z,\) then the magnitude of the electric field is :

1 \(4\sqrt 2 \)
2 \(3\sqrt 2 \)
3 \(7\)
4 \(5\sqrt 2 \)