Capacitors with Dielectric
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359216 A parallel plate capacitor is formed by two plates each of area \(30\pi c{m^2}\) separated by 1 \(mm\). A material of dielectric strength \(3.6 \times {10^7}\,V{m^{ - 1}}\) is filled between the plates. If the maximum charge that can be stored on the capacitor without causing any dielectric breakdown is \(7 \times {10^{ - 6}}C\), the value of dielectric constant of the material is :
\(\left\{ {Use:\frac{1}{{4\pi {\varepsilon _0}}} = 9 \times {{10}^9}N{m^2}{C^{ - 2}}} \right\}\)

1 1.66
2 1.75
3 2.25
4 2.33
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359217 The potential energy of a charged parallel plate capacitor is \(U_{0}\). If a slab of dielectric constant \(K\) is inserted between the plates, then the new potential energy will be

1 \(\dfrac{U_{0}}{K}\)
2 \({U_0}K\)
3 \({{\text{ }}\frac{{{U_0}}}{{{K^2}}}}\)
4 \(U_0^2\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359218 Assertion :
When a dielectric medium is filled between the plates of a condenser, its capacitance increases.
Reason :
The dielectric medium reduces the potential difference between the plates of the condenser.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359219 A slab of copper of thickness \({\dfrac{d}{2}}\) is introduced between the plates of a parallel plate capacitor where \({d}\) is the seperation between its two plates. If the capacitance of the capacitor without copper slab is \({C}\) and with copper slab is \({C^{\prime}}\), then \({\dfrac{C^{\prime}}{C}}\) is

1 \({\sqrt{2}}\)
2 2
3 1
4 \({\dfrac{1}{\sqrt{2}}}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359216 A parallel plate capacitor is formed by two plates each of area \(30\pi c{m^2}\) separated by 1 \(mm\). A material of dielectric strength \(3.6 \times {10^7}\,V{m^{ - 1}}\) is filled between the plates. If the maximum charge that can be stored on the capacitor without causing any dielectric breakdown is \(7 \times {10^{ - 6}}C\), the value of dielectric constant of the material is :
\(\left\{ {Use:\frac{1}{{4\pi {\varepsilon _0}}} = 9 \times {{10}^9}N{m^2}{C^{ - 2}}} \right\}\)

1 1.66
2 1.75
3 2.25
4 2.33
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359217 The potential energy of a charged parallel plate capacitor is \(U_{0}\). If a slab of dielectric constant \(K\) is inserted between the plates, then the new potential energy will be

1 \(\dfrac{U_{0}}{K}\)
2 \({U_0}K\)
3 \({{\text{ }}\frac{{{U_0}}}{{{K^2}}}}\)
4 \(U_0^2\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359218 Assertion :
When a dielectric medium is filled between the plates of a condenser, its capacitance increases.
Reason :
The dielectric medium reduces the potential difference between the plates of the condenser.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359219 A slab of copper of thickness \({\dfrac{d}{2}}\) is introduced between the plates of a parallel plate capacitor where \({d}\) is the seperation between its two plates. If the capacitance of the capacitor without copper slab is \({C}\) and with copper slab is \({C^{\prime}}\), then \({\dfrac{C^{\prime}}{C}}\) is

1 \({\sqrt{2}}\)
2 2
3 1
4 \({\dfrac{1}{\sqrt{2}}}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359216 A parallel plate capacitor is formed by two plates each of area \(30\pi c{m^2}\) separated by 1 \(mm\). A material of dielectric strength \(3.6 \times {10^7}\,V{m^{ - 1}}\) is filled between the plates. If the maximum charge that can be stored on the capacitor without causing any dielectric breakdown is \(7 \times {10^{ - 6}}C\), the value of dielectric constant of the material is :
\(\left\{ {Use:\frac{1}{{4\pi {\varepsilon _0}}} = 9 \times {{10}^9}N{m^2}{C^{ - 2}}} \right\}\)

1 1.66
2 1.75
3 2.25
4 2.33
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359217 The potential energy of a charged parallel plate capacitor is \(U_{0}\). If a slab of dielectric constant \(K\) is inserted between the plates, then the new potential energy will be

1 \(\dfrac{U_{0}}{K}\)
2 \({U_0}K\)
3 \({{\text{ }}\frac{{{U_0}}}{{{K^2}}}}\)
4 \(U_0^2\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359218 Assertion :
When a dielectric medium is filled between the plates of a condenser, its capacitance increases.
Reason :
The dielectric medium reduces the potential difference between the plates of the condenser.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359219 A slab of copper of thickness \({\dfrac{d}{2}}\) is introduced between the plates of a parallel plate capacitor where \({d}\) is the seperation between its two plates. If the capacitance of the capacitor without copper slab is \({C}\) and with copper slab is \({C^{\prime}}\), then \({\dfrac{C^{\prime}}{C}}\) is

1 \({\sqrt{2}}\)
2 2
3 1
4 \({\dfrac{1}{\sqrt{2}}}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359216 A parallel plate capacitor is formed by two plates each of area \(30\pi c{m^2}\) separated by 1 \(mm\). A material of dielectric strength \(3.6 \times {10^7}\,V{m^{ - 1}}\) is filled between the plates. If the maximum charge that can be stored on the capacitor without causing any dielectric breakdown is \(7 \times {10^{ - 6}}C\), the value of dielectric constant of the material is :
\(\left\{ {Use:\frac{1}{{4\pi {\varepsilon _0}}} = 9 \times {{10}^9}N{m^2}{C^{ - 2}}} \right\}\)

1 1.66
2 1.75
3 2.25
4 2.33
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359217 The potential energy of a charged parallel plate capacitor is \(U_{0}\). If a slab of dielectric constant \(K\) is inserted between the plates, then the new potential energy will be

1 \(\dfrac{U_{0}}{K}\)
2 \({U_0}K\)
3 \({{\text{ }}\frac{{{U_0}}}{{{K^2}}}}\)
4 \(U_0^2\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359218 Assertion :
When a dielectric medium is filled between the plates of a condenser, its capacitance increases.
Reason :
The dielectric medium reduces the potential difference between the plates of the condenser.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359219 A slab of copper of thickness \({\dfrac{d}{2}}\) is introduced between the plates of a parallel plate capacitor where \({d}\) is the seperation between its two plates. If the capacitance of the capacitor without copper slab is \({C}\) and with copper slab is \({C^{\prime}}\), then \({\dfrac{C^{\prime}}{C}}\) is

1 \({\sqrt{2}}\)
2 2
3 1
4 \({\dfrac{1}{\sqrt{2}}}\)