359216 A parallel plate capacitor is formed by two plates each of area $30\pi c{m}^2$ separated by 1 $mm$. A material of dielectric strength $3.6\times {10}^{7}V{m}^{-1}$ is filled between the plates. If the maximum charge that can be stored on the capacitor without causing any dielectric breakdown is $7\times {10}^{-6}C$, the value of dielectric constant of the material is :
$\left\{Use:\frac{1}{4\pi {\epsilon }_0}=9\times {10}^{9}N{m}^2{C}^{-2}\right\}$

359218 Assertion :
When a dielectric medium is filled between the plates of a condenser, its capacitance increases.
Reason :
The dielectric medium reduces the potential difference between the plates of the condenser.

359219 A slab of copper of thickness ${\displaystyle \frac{d}{2}}$ is introduced between the plates of a parallel plate capacitor where $d$ is the seperation between its two plates. If the capacitance of the capacitor without copper slab is $C$ and with copper slab is $C^{\prime }$, then ${\displaystyle \frac{C^{\prime }}{C}}$ is

359216 A parallel plate capacitor is formed by two plates each of area $30\pi c{m}^2$ separated by 1 $mm$. A material of dielectric strength $3.6\times {10}^{7}V{m}^{-1}$ is filled between the plates. If the maximum charge that can be stored on the capacitor without causing any dielectric breakdown is $7\times {10}^{-6}C$, the value of dielectric constant of the material is :
$\left\{Use:\frac{1}{4\pi {\epsilon }_0}=9\times {10}^{9}N{m}^2{C}^{-2}\right\}$

359217 The potential energy of a charged parallel plate capacitor is $U_0$. If a slab of dielectric constant $K$ is inserted between the plates, then the new potential energy will be

359218 Assertion :
When a dielectric medium is filled between the plates of a condenser, its capacitance increases.
Reason :
The dielectric medium reduces the potential difference between the plates of the condenser.

359219 A slab of copper of thickness ${\displaystyle \frac{d}{2}}$ is introduced between the plates of a parallel plate capacitor where $d$ is the seperation between its two plates. If the capacitance of the capacitor without copper slab is $C$ and with copper slab is $C^{\prime }$, then ${\displaystyle \frac{C^{\prime }}{C}}$ is

359216 A parallel plate capacitor is formed by two plates each of area $30\pi c{m}^2$ separated by 1 $mm$. A material of dielectric strength $3.6\times {10}^{7}V{m}^{-1}$ is filled between the plates. If the maximum charge that can be stored on the capacitor without causing any dielectric breakdown is $7\times {10}^{-6}C$, the value of dielectric constant of the material is :
$\left\{Use:\frac{1}{4\pi {\epsilon }_0}=9\times {10}^{9}N{m}^2{C}^{-2}\right\}$

359217 The potential energy of a charged parallel plate capacitor is $U_0$. If a slab of dielectric constant $K$ is inserted between the plates, then the new potential energy will be

359218 Assertion :
When a dielectric medium is filled between the plates of a condenser, its capacitance increases.
Reason :
The dielectric medium reduces the potential difference between the plates of the condenser.

359219 A slab of copper of thickness ${\displaystyle \frac{d}{2}}$ is introduced between the plates of a parallel plate capacitor where $d$ is the seperation between its two plates. If the capacitance of the capacitor without copper slab is $C$ and with copper slab is $C^{\prime }$, then ${\displaystyle \frac{C^{\prime }}{C}}$ is

359216 A parallel plate capacitor is formed by two plates each of area $30\pi c{m}^2$ separated by 1 $mm$. A material of dielectric strength $3.6\times {10}^{7}V{m}^{-1}$ is filled between the plates. If the maximum charge that can be stored on the capacitor without causing any dielectric breakdown is $7\times {10}^{-6}C$, the value of dielectric constant of the material is :
$\left\{Use:\frac{1}{4\pi {\epsilon }_0}=9\times {10}^{9}N{m}^2{C}^{-2}\right\}$

359217 The potential energy of a charged parallel plate capacitor is $U_0$. If a slab of dielectric constant $K$ is inserted between the plates, then the new potential energy will be

359218 Assertion :
When a dielectric medium is filled between the plates of a condenser, its capacitance increases.
Reason :
The dielectric medium reduces the potential difference between the plates of the condenser.

359219 A slab of copper of thickness ${\displaystyle \frac{d}{2}}$ is introduced between the plates of a parallel plate capacitor where $d$ is the seperation between its two plates. If the capacitance of the capacitor without copper slab is $C$ and with copper slab is $C^{\prime }$, then ${\displaystyle \frac{C^{\prime }}{C}}$ is