Capacitors with Dielectric
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359194 A parallel plate air filled capacitor of capacitance ' \(C\) ' has plate area ' \(A\) ' and the distance between the plates ' \(d\) '. When a metal sheet of thickness \(\left(\dfrac{d}{2}\right)\) and of the same area ' \(A\) ' is introduced between the plates, its capacitance becomes ' \(C_{2}\) '. The ratio \(C_{2}: C_{1}\) is

1 \(2: 1\)
2 \(3: 2\)
3 \(4: 1\)
4 \(3: 1\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359195 In absence of dielectric medium, capacity of a parallel plate capacitor is \({C_{0}}\). A sheet of dielectric constant \({k}\) and thickness of one third of the plate separation is inserted between the plates. If new capacity is \({C}\), then:

1 \({\dfrac{C}{C_{0}}=\dfrac{3 k}{2 k+1}}\)
2 \({\dfrac{C}{C_{0}}=\dfrac{2 k}{3 k+1}}\)
3 \({\dfrac{C}{C_{0}}=\dfrac{3 k+1}{2 k} \quad}\)
4 \({\dfrac{C}{C_{0}}=\dfrac{2 k+1}{3 k}}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359196 If a slab of insulating material \(4 \times {10^{ - 3}}m\) thick is introduced between the plates of a parallel plate capacitor, the separation between the plates has to be increased by \(3.5 \times {10^{ - 3}}m\) to restore the capacity to original value. The dielectric constant of the material will be

1 \(6\)
2 \(8\)
3 \(10\)
4 \(12\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359197 Assertion :
A parallel plate capacitor is connected across battery through a key. A dielectric slab of dielectric constant \(K\) is introduced between the plates. The energy which is stored becomes \(K\) times.
Reason :
The surface density of charge on the plate remains constant or unchanged.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Both Assertion and Reason are incorrect.
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359198 Two parallel plate air capacitor of same capacity \(C\) are connected in series to a battery of emf \(E\). Then one of the capacitors is completely filled with dielectric material of constant \(K\). The change in the effective capacity of the series combination is

1 \(\frac{C}{2}\left[ {\frac{{K - 1}}{{K + 1}}} \right]\)
2 \(\frac{2}{C}\left[ {\frac{{K - 1}}{{K + 1}}} \right]\)
3 \(\frac{C}{2}\left[ {\frac{{K + 1}}{{K - 1}}} \right]\)
4 \(\frac{C}{2}{\left[ {\frac{{K - 1}}{{K + 1}}} \right]^2}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359194 A parallel plate air filled capacitor of capacitance ' \(C\) ' has plate area ' \(A\) ' and the distance between the plates ' \(d\) '. When a metal sheet of thickness \(\left(\dfrac{d}{2}\right)\) and of the same area ' \(A\) ' is introduced between the plates, its capacitance becomes ' \(C_{2}\) '. The ratio \(C_{2}: C_{1}\) is

1 \(2: 1\)
2 \(3: 2\)
3 \(4: 1\)
4 \(3: 1\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359195 In absence of dielectric medium, capacity of a parallel plate capacitor is \({C_{0}}\). A sheet of dielectric constant \({k}\) and thickness of one third of the plate separation is inserted between the plates. If new capacity is \({C}\), then:

1 \({\dfrac{C}{C_{0}}=\dfrac{3 k}{2 k+1}}\)
2 \({\dfrac{C}{C_{0}}=\dfrac{2 k}{3 k+1}}\)
3 \({\dfrac{C}{C_{0}}=\dfrac{3 k+1}{2 k} \quad}\)
4 \({\dfrac{C}{C_{0}}=\dfrac{2 k+1}{3 k}}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359196 If a slab of insulating material \(4 \times {10^{ - 3}}m\) thick is introduced between the plates of a parallel plate capacitor, the separation between the plates has to be increased by \(3.5 \times {10^{ - 3}}m\) to restore the capacity to original value. The dielectric constant of the material will be

1 \(6\)
2 \(8\)
3 \(10\)
4 \(12\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359197 Assertion :
A parallel plate capacitor is connected across battery through a key. A dielectric slab of dielectric constant \(K\) is introduced between the plates. The energy which is stored becomes \(K\) times.
Reason :
The surface density of charge on the plate remains constant or unchanged.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Both Assertion and Reason are incorrect.
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359198 Two parallel plate air capacitor of same capacity \(C\) are connected in series to a battery of emf \(E\). Then one of the capacitors is completely filled with dielectric material of constant \(K\). The change in the effective capacity of the series combination is

1 \(\frac{C}{2}\left[ {\frac{{K - 1}}{{K + 1}}} \right]\)
2 \(\frac{2}{C}\left[ {\frac{{K - 1}}{{K + 1}}} \right]\)
3 \(\frac{C}{2}\left[ {\frac{{K + 1}}{{K - 1}}} \right]\)
4 \(\frac{C}{2}{\left[ {\frac{{K - 1}}{{K + 1}}} \right]^2}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359194 A parallel plate air filled capacitor of capacitance ' \(C\) ' has plate area ' \(A\) ' and the distance between the plates ' \(d\) '. When a metal sheet of thickness \(\left(\dfrac{d}{2}\right)\) and of the same area ' \(A\) ' is introduced between the plates, its capacitance becomes ' \(C_{2}\) '. The ratio \(C_{2}: C_{1}\) is

1 \(2: 1\)
2 \(3: 2\)
3 \(4: 1\)
4 \(3: 1\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359195 In absence of dielectric medium, capacity of a parallel plate capacitor is \({C_{0}}\). A sheet of dielectric constant \({k}\) and thickness of one third of the plate separation is inserted between the plates. If new capacity is \({C}\), then:

1 \({\dfrac{C}{C_{0}}=\dfrac{3 k}{2 k+1}}\)
2 \({\dfrac{C}{C_{0}}=\dfrac{2 k}{3 k+1}}\)
3 \({\dfrac{C}{C_{0}}=\dfrac{3 k+1}{2 k} \quad}\)
4 \({\dfrac{C}{C_{0}}=\dfrac{2 k+1}{3 k}}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359196 If a slab of insulating material \(4 \times {10^{ - 3}}m\) thick is introduced between the plates of a parallel plate capacitor, the separation between the plates has to be increased by \(3.5 \times {10^{ - 3}}m\) to restore the capacity to original value. The dielectric constant of the material will be

1 \(6\)
2 \(8\)
3 \(10\)
4 \(12\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359197 Assertion :
A parallel plate capacitor is connected across battery through a key. A dielectric slab of dielectric constant \(K\) is introduced between the plates. The energy which is stored becomes \(K\) times.
Reason :
The surface density of charge on the plate remains constant or unchanged.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Both Assertion and Reason are incorrect.
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359198 Two parallel plate air capacitor of same capacity \(C\) are connected in series to a battery of emf \(E\). Then one of the capacitors is completely filled with dielectric material of constant \(K\). The change in the effective capacity of the series combination is

1 \(\frac{C}{2}\left[ {\frac{{K - 1}}{{K + 1}}} \right]\)
2 \(\frac{2}{C}\left[ {\frac{{K - 1}}{{K + 1}}} \right]\)
3 \(\frac{C}{2}\left[ {\frac{{K + 1}}{{K - 1}}} \right]\)
4 \(\frac{C}{2}{\left[ {\frac{{K - 1}}{{K + 1}}} \right]^2}\)
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359194 A parallel plate air filled capacitor of capacitance ' \(C\) ' has plate area ' \(A\) ' and the distance between the plates ' \(d\) '. When a metal sheet of thickness \(\left(\dfrac{d}{2}\right)\) and of the same area ' \(A\) ' is introduced between the plates, its capacitance becomes ' \(C_{2}\) '. The ratio \(C_{2}: C_{1}\) is

1 \(2: 1\)
2 \(3: 2\)
3 \(4: 1\)
4 \(3: 1\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359195 In absence of dielectric medium, capacity of a parallel plate capacitor is \({C_{0}}\). A sheet of dielectric constant \({k}\) and thickness of one third of the plate separation is inserted between the plates. If new capacity is \({C}\), then:

1 \({\dfrac{C}{C_{0}}=\dfrac{3 k}{2 k+1}}\)
2 \({\dfrac{C}{C_{0}}=\dfrac{2 k}{3 k+1}}\)
3 \({\dfrac{C}{C_{0}}=\dfrac{3 k+1}{2 k} \quad}\)
4 \({\dfrac{C}{C_{0}}=\dfrac{2 k+1}{3 k}}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359196 If a slab of insulating material \(4 \times {10^{ - 3}}m\) thick is introduced between the plates of a parallel plate capacitor, the separation between the plates has to be increased by \(3.5 \times {10^{ - 3}}m\) to restore the capacity to original value. The dielectric constant of the material will be

1 \(6\)
2 \(8\)
3 \(10\)
4 \(12\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359197 Assertion :
A parallel plate capacitor is connected across battery through a key. A dielectric slab of dielectric constant \(K\) is introduced between the plates. The energy which is stored becomes \(K\) times.
Reason :
The surface density of charge on the plate remains constant or unchanged.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Both Assertion and Reason are incorrect.
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359198 Two parallel plate air capacitor of same capacity \(C\) are connected in series to a battery of emf \(E\). Then one of the capacitors is completely filled with dielectric material of constant \(K\). The change in the effective capacity of the series combination is

1 \(\frac{C}{2}\left[ {\frac{{K - 1}}{{K + 1}}} \right]\)
2 \(\frac{2}{C}\left[ {\frac{{K - 1}}{{K + 1}}} \right]\)
3 \(\frac{C}{2}\left[ {\frac{{K + 1}}{{K - 1}}} \right]\)
4 \(\frac{C}{2}{\left[ {\frac{{K - 1}}{{K + 1}}} \right]^2}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359194 A parallel plate air filled capacitor of capacitance ' \(C\) ' has plate area ' \(A\) ' and the distance between the plates ' \(d\) '. When a metal sheet of thickness \(\left(\dfrac{d}{2}\right)\) and of the same area ' \(A\) ' is introduced between the plates, its capacitance becomes ' \(C_{2}\) '. The ratio \(C_{2}: C_{1}\) is

1 \(2: 1\)
2 \(3: 2\)
3 \(4: 1\)
4 \(3: 1\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359195 In absence of dielectric medium, capacity of a parallel plate capacitor is \({C_{0}}\). A sheet of dielectric constant \({k}\) and thickness of one third of the plate separation is inserted between the plates. If new capacity is \({C}\), then:

1 \({\dfrac{C}{C_{0}}=\dfrac{3 k}{2 k+1}}\)
2 \({\dfrac{C}{C_{0}}=\dfrac{2 k}{3 k+1}}\)
3 \({\dfrac{C}{C_{0}}=\dfrac{3 k+1}{2 k} \quad}\)
4 \({\dfrac{C}{C_{0}}=\dfrac{2 k+1}{3 k}}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359196 If a slab of insulating material \(4 \times {10^{ - 3}}m\) thick is introduced between the plates of a parallel plate capacitor, the separation between the plates has to be increased by \(3.5 \times {10^{ - 3}}m\) to restore the capacity to original value. The dielectric constant of the material will be

1 \(6\)
2 \(8\)
3 \(10\)
4 \(12\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359197 Assertion :
A parallel plate capacitor is connected across battery through a key. A dielectric slab of dielectric constant \(K\) is introduced between the plates. The energy which is stored becomes \(K\) times.
Reason :
The surface density of charge on the plate remains constant or unchanged.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Both Assertion and Reason are incorrect.
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359198 Two parallel plate air capacitor of same capacity \(C\) are connected in series to a battery of emf \(E\). Then one of the capacitors is completely filled with dielectric material of constant \(K\). The change in the effective capacity of the series combination is

1 \(\frac{C}{2}\left[ {\frac{{K - 1}}{{K + 1}}} \right]\)
2 \(\frac{2}{C}\left[ {\frac{{K - 1}}{{K + 1}}} \right]\)
3 \(\frac{C}{2}\left[ {\frac{{K + 1}}{{K - 1}}} \right]\)
4 \(\frac{C}{2}{\left[ {\frac{{K - 1}}{{K + 1}}} \right]^2}\)