Capacitors with Dielectric
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359199 A parallel plate condenser with a dielectric of dielectric constant \({k}\) between the plates has a capacity \({C}\) and is charged to a potential \({V}\) volts. The dielectric slab is slowly removed from between the plates and then re-inserted. The net work done by the system in this process is

1 \({\dfrac{1}{2}(k-1) C V^{2}}\)
2 \({C V^{2}(k-1) / K}\)
3 \({(k-1) C V^{2}}\)
4 zero
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359200 Assertion :
The plates of a parallel plate capacitor are connected to a battery. Charge on the plates increases on introducing a dielectric slab between the plates.
Reason :
Capacity increases on introducing dielectric slab and hence more charge is drawn from the battery.

1 Both assertion and reason are correct and reason is the correct explanation of assertion.
2 Both assertion and reason are correct but reason is not the correct explanation of assertion.
3 Assertion is correct but reason is incorrect.
4 Assertion is incorrect but reason is correct.
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359201 A parallel plate air capacitor has capacitance ‘\(C\)’ farad, potential ‘\(V\)’ volt and energy ‘\(E\)’ joule. When the gap between the plates is completely filled with dielectric

1 Both \(V\) and \(E\) increase
2 Both \(V\) and \(E\) decrease
3 \(V\) increase, \(E\) increase
4 \(V\) increase, \(E\) decrease
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359202 A slab of copper of thickness \(d / 2\) is introduced between the plates of a parallel plate capacitor where \(d\) is the separation between its two plates. If the capacitance of the capacitor without copper slab is \(C\) and with copper slab is \(C^{\prime}\) then \(\dfrac{C^{\prime}}{C}\) is:

1 \(\sqrt{2}\)
2 2
3 1
4 \(\dfrac{1}{\sqrt{2}}\)
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PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359199 A parallel plate condenser with a dielectric of dielectric constant \({k}\) between the plates has a capacity \({C}\) and is charged to a potential \({V}\) volts. The dielectric slab is slowly removed from between the plates and then re-inserted. The net work done by the system in this process is

1 \({\dfrac{1}{2}(k-1) C V^{2}}\)
2 \({C V^{2}(k-1) / K}\)
3 \({(k-1) C V^{2}}\)
4 zero
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359200 Assertion :
The plates of a parallel plate capacitor are connected to a battery. Charge on the plates increases on introducing a dielectric slab between the plates.
Reason :
Capacity increases on introducing dielectric slab and hence more charge is drawn from the battery.

1 Both assertion and reason are correct and reason is the correct explanation of assertion.
2 Both assertion and reason are correct but reason is not the correct explanation of assertion.
3 Assertion is correct but reason is incorrect.
4 Assertion is incorrect but reason is correct.
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359201 A parallel plate air capacitor has capacitance ‘\(C\)’ farad, potential ‘\(V\)’ volt and energy ‘\(E\)’ joule. When the gap between the plates is completely filled with dielectric

1 Both \(V\) and \(E\) increase
2 Both \(V\) and \(E\) decrease
3 \(V\) increase, \(E\) increase
4 \(V\) increase, \(E\) decrease
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359202 A slab of copper of thickness \(d / 2\) is introduced between the plates of a parallel plate capacitor where \(d\) is the separation between its two plates. If the capacitance of the capacitor without copper slab is \(C\) and with copper slab is \(C^{\prime}\) then \(\dfrac{C^{\prime}}{C}\) is:

1 \(\sqrt{2}\)
2 2
3 1
4 \(\dfrac{1}{\sqrt{2}}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359199 A parallel plate condenser with a dielectric of dielectric constant \({k}\) between the plates has a capacity \({C}\) and is charged to a potential \({V}\) volts. The dielectric slab is slowly removed from between the plates and then re-inserted. The net work done by the system in this process is

1 \({\dfrac{1}{2}(k-1) C V^{2}}\)
2 \({C V^{2}(k-1) / K}\)
3 \({(k-1) C V^{2}}\)
4 zero
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359200 Assertion :
The plates of a parallel plate capacitor are connected to a battery. Charge on the plates increases on introducing a dielectric slab between the plates.
Reason :
Capacity increases on introducing dielectric slab and hence more charge is drawn from the battery.

1 Both assertion and reason are correct and reason is the correct explanation of assertion.
2 Both assertion and reason are correct but reason is not the correct explanation of assertion.
3 Assertion is correct but reason is incorrect.
4 Assertion is incorrect but reason is correct.
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359201 A parallel plate air capacitor has capacitance ‘\(C\)’ farad, potential ‘\(V\)’ volt and energy ‘\(E\)’ joule. When the gap between the plates is completely filled with dielectric

1 Both \(V\) and \(E\) increase
2 Both \(V\) and \(E\) decrease
3 \(V\) increase, \(E\) increase
4 \(V\) increase, \(E\) decrease
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359202 A slab of copper of thickness \(d / 2\) is introduced between the plates of a parallel plate capacitor where \(d\) is the separation between its two plates. If the capacitance of the capacitor without copper slab is \(C\) and with copper slab is \(C^{\prime}\) then \(\dfrac{C^{\prime}}{C}\) is:

1 \(\sqrt{2}\)
2 2
3 1
4 \(\dfrac{1}{\sqrt{2}}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359199 A parallel plate condenser with a dielectric of dielectric constant \({k}\) between the plates has a capacity \({C}\) and is charged to a potential \({V}\) volts. The dielectric slab is slowly removed from between the plates and then re-inserted. The net work done by the system in this process is

1 \({\dfrac{1}{2}(k-1) C V^{2}}\)
2 \({C V^{2}(k-1) / K}\)
3 \({(k-1) C V^{2}}\)
4 zero
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359200 Assertion :
The plates of a parallel plate capacitor are connected to a battery. Charge on the plates increases on introducing a dielectric slab between the plates.
Reason :
Capacity increases on introducing dielectric slab and hence more charge is drawn from the battery.

1 Both assertion and reason are correct and reason is the correct explanation of assertion.
2 Both assertion and reason are correct but reason is not the correct explanation of assertion.
3 Assertion is correct but reason is incorrect.
4 Assertion is incorrect but reason is correct.
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359201 A parallel plate air capacitor has capacitance ‘\(C\)’ farad, potential ‘\(V\)’ volt and energy ‘\(E\)’ joule. When the gap between the plates is completely filled with dielectric

1 Both \(V\) and \(E\) increase
2 Both \(V\) and \(E\) decrease
3 \(V\) increase, \(E\) increase
4 \(V\) increase, \(E\) decrease
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359202 A slab of copper of thickness \(d / 2\) is introduced between the plates of a parallel plate capacitor where \(d\) is the separation between its two plates. If the capacitance of the capacitor without copper slab is \(C\) and with copper slab is \(C^{\prime}\) then \(\dfrac{C^{\prime}}{C}\) is:

1 \(\sqrt{2}\)
2 2
3 1
4 \(\dfrac{1}{\sqrt{2}}\)