Capacitors with Dielectric
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PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359173 A parallel plate condenser with oil between the plates (dielectric constant of oil \(K =\) 2) has a capacitance \(C\). If the oil is removed, then capacitance of the capacitor becomes

1 \(2C\)
2 \(\frac{C}{2}\)
3 \(\sqrt 2 C\)
4 \(\frac{C}{{\sqrt 2 }}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359174 A capacitor connected to a 10 \(V\) battery collects a charge of \(20\mu C\) with air as dielectric and \(100\mu C\) with a given oil as dielectric. The dielectric constant of the oil is

1 \(1.5\)
2 \(2.0\)
3 \(5\)
4 \(3.0\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359175 A capacitor has air as dielectric medium and two conducting plates of area \(12\;c{m^2}\) and they are \(0.6\,cm\) apart. When a slab of dielectric constant \((K)\) having same area and thickness is inserted between the plates, one of the conducting plates has to be moved by \(0.2\,cm\) to keep the capacitance same as in previous case. The dielectric constant of the slab is (Given \({\varepsilon _0} = 8.834 \times {10^{ - 12}}\;F/m)\)

1 1.50
2 1
3 0.66
4 1.33
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359176 The capacity of a parallel plate condenser is \(5\,\mu F\) without dielectric. Dielectric of constant 3 is used to fill half the distance between the plates, the new capacitance in \(\mu F\) is

1 \(10\)
2 \(5\)
3 \(15\)
4 \(7.5\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359173 A parallel plate condenser with oil between the plates (dielectric constant of oil \(K =\) 2) has a capacitance \(C\). If the oil is removed, then capacitance of the capacitor becomes

1 \(2C\)
2 \(\frac{C}{2}\)
3 \(\sqrt 2 C\)
4 \(\frac{C}{{\sqrt 2 }}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359174 A capacitor connected to a 10 \(V\) battery collects a charge of \(20\mu C\) with air as dielectric and \(100\mu C\) with a given oil as dielectric. The dielectric constant of the oil is

1 \(1.5\)
2 \(2.0\)
3 \(5\)
4 \(3.0\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359175 A capacitor has air as dielectric medium and two conducting plates of area \(12\;c{m^2}\) and they are \(0.6\,cm\) apart. When a slab of dielectric constant \((K)\) having same area and thickness is inserted between the plates, one of the conducting plates has to be moved by \(0.2\,cm\) to keep the capacitance same as in previous case. The dielectric constant of the slab is (Given \({\varepsilon _0} = 8.834 \times {10^{ - 12}}\;F/m)\)

1 1.50
2 1
3 0.66
4 1.33
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359176 The capacity of a parallel plate condenser is \(5\,\mu F\) without dielectric. Dielectric of constant 3 is used to fill half the distance between the plates, the new capacitance in \(\mu F\) is

1 \(10\)
2 \(5\)
3 \(15\)
4 \(7.5\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359173 A parallel plate condenser with oil between the plates (dielectric constant of oil \(K =\) 2) has a capacitance \(C\). If the oil is removed, then capacitance of the capacitor becomes

1 \(2C\)
2 \(\frac{C}{2}\)
3 \(\sqrt 2 C\)
4 \(\frac{C}{{\sqrt 2 }}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359174 A capacitor connected to a 10 \(V\) battery collects a charge of \(20\mu C\) with air as dielectric and \(100\mu C\) with a given oil as dielectric. The dielectric constant of the oil is

1 \(1.5\)
2 \(2.0\)
3 \(5\)
4 \(3.0\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359175 A capacitor has air as dielectric medium and two conducting plates of area \(12\;c{m^2}\) and they are \(0.6\,cm\) apart. When a slab of dielectric constant \((K)\) having same area and thickness is inserted between the plates, one of the conducting plates has to be moved by \(0.2\,cm\) to keep the capacitance same as in previous case. The dielectric constant of the slab is (Given \({\varepsilon _0} = 8.834 \times {10^{ - 12}}\;F/m)\)

1 1.50
2 1
3 0.66
4 1.33
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359176 The capacity of a parallel plate condenser is \(5\,\mu F\) without dielectric. Dielectric of constant 3 is used to fill half the distance between the plates, the new capacitance in \(\mu F\) is

1 \(10\)
2 \(5\)
3 \(15\)
4 \(7.5\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359173 A parallel plate condenser with oil between the plates (dielectric constant of oil \(K =\) 2) has a capacitance \(C\). If the oil is removed, then capacitance of the capacitor becomes

1 \(2C\)
2 \(\frac{C}{2}\)
3 \(\sqrt 2 C\)
4 \(\frac{C}{{\sqrt 2 }}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359174 A capacitor connected to a 10 \(V\) battery collects a charge of \(20\mu C\) with air as dielectric and \(100\mu C\) with a given oil as dielectric. The dielectric constant of the oil is

1 \(1.5\)
2 \(2.0\)
3 \(5\)
4 \(3.0\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359175 A capacitor has air as dielectric medium and two conducting plates of area \(12\;c{m^2}\) and they are \(0.6\,cm\) apart. When a slab of dielectric constant \((K)\) having same area and thickness is inserted between the plates, one of the conducting plates has to be moved by \(0.2\,cm\) to keep the capacitance same as in previous case. The dielectric constant of the slab is (Given \({\varepsilon _0} = 8.834 \times {10^{ - 12}}\;F/m)\)

1 1.50
2 1
3 0.66
4 1.33
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359176 The capacity of a parallel plate condenser is \(5\,\mu F\) without dielectric. Dielectric of constant 3 is used to fill half the distance between the plates, the new capacitance in \(\mu F\) is

1 \(10\)
2 \(5\)
3 \(15\)
4 \(7.5\)