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PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS

365211 Name the logic gate equivalent to the diagram given
supporting img

1 NAND

2 NOR

3 AND

4 OR

Explanation:

Truth table for the given circuit is
supporting img
Circuit is closed when neither $A$ nor $B$ is closed. Current flows for $A = 0, B = 0$ when either or both of $A$ and $B$ is closed, current flows through the switch. So, it is NOR Gate.

JEE - 2023

PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS

365212 The Boolean expression for the gate circuit shown below is
supporting img

1

A + \overset{―}{A} = 1

2

A + 1 = 1

3

A + A = A

4

A + 0 = A

Explanation:

The input of OR gate is $A & \bar{A}$
$Y = A + \bar{A} = 1$

PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS

365213 In the following circuit the output $Y$ becomes zero for the inputs
supporting img

1

A = 1, B = 0, C = 0

2

A = 0, B = 1, C = 1

3

A = 0, B = 0, C = 0

4

A = 1, B = 1, C = 0

Explanation:

Here
$Y = \overset{―}{(A . B) . \overset{―}{C}} = (\overset{―}{A . B}) + C = \overset{―}{A} + \overset{―}{B} + C$
$Y = 0$ if $A = 1, B = 1$ and $C = 0$

PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS

365214 Following circuit will act as
supporting img

1 NOR gate

2 NAND gate

3 AND gate

4 OR gate

Explanation:

The truth table for the circuit is as
supporting img
The $Y$ -output is of NOR gate.

PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS

365211 Name the logic gate equivalent to the diagram given
supporting img

1 NAND

2 NOR

3 AND

4 OR

Explanation:

Truth table for the given circuit is
supporting img
Circuit is closed when neither $A$ nor $B$ is closed. Current flows for $A = 0, B = 0$ when either or both of $A$ and $B$ is closed, current flows through the switch. So, it is NOR Gate.

JEE - 2023

PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS

365212 The Boolean expression for the gate circuit shown below is
supporting img

1

A + \overset{―}{A} = 1

2

A + 1 = 1

3

A + A = A

4

A + 0 = A

Explanation:

The input of OR gate is $A & \bar{A}$
$Y = A + \bar{A} = 1$

PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS

365213 In the following circuit the output $Y$ becomes zero for the inputs
supporting img

1

A = 1, B = 0, C = 0

2

A = 0, B = 1, C = 1

3

A = 0, B = 0, C = 0

4

A = 1, B = 1, C = 0

Explanation:

Here
$Y = \overset{―}{(A . B) . \overset{―}{C}} = (\overset{―}{A . B}) + C = \overset{―}{A} + \overset{―}{B} + C$
$Y = 0$ if $A = 1, B = 1$ and $C = 0$

PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS

365214 Following circuit will act as
supporting img

1 NOR gate

2 NAND gate

3 AND gate

4 OR gate

Explanation:

The truth table for the circuit is as
supporting img
The $Y$ -output is of NOR gate.

PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS

365211 Name the logic gate equivalent to the diagram given
supporting img

1 NAND

2 NOR

3 AND

4 OR

Explanation:

Truth table for the given circuit is
supporting img
Circuit is closed when neither $A$ nor $B$ is closed. Current flows for $A = 0, B = 0$ when either or both of $A$ and $B$ is closed, current flows through the switch. So, it is NOR Gate.

JEE - 2023

PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS

365212 The Boolean expression for the gate circuit shown below is
supporting img

1

A + \overset{―}{A} = 1

2

A + 1 = 1

3

A + A = A

4

A + 0 = A

Explanation:

The input of OR gate is $A & \bar{A}$
$Y = A + \bar{A} = 1$

PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS

365213 In the following circuit the output $Y$ becomes zero for the inputs
supporting img

1

A = 1, B = 0, C = 0

2

A = 0, B = 1, C = 1

3

A = 0, B = 0, C = 0

4

A = 1, B = 1, C = 0

Explanation:

Here
$Y = \overset{―}{(A . B) . \overset{―}{C}} = (\overset{―}{A . B}) + C = \overset{―}{A} + \overset{―}{B} + C$
$Y = 0$ if $A = 1, B = 1$ and $C = 0$

PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS

365214 Following circuit will act as
supporting img

1 NOR gate

2 NAND gate

3 AND gate

4 OR gate

Explanation:

The truth table for the circuit is as
supporting img
The $Y$ -output is of NOR gate.

PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS

365211 Name the logic gate equivalent to the diagram given
supporting img

1 NAND

2 NOR

3 AND

4 OR

Explanation:

Truth table for the given circuit is
supporting img
Circuit is closed when neither $A$ nor $B$ is closed. Current flows for $A = 0, B = 0$ when either or both of $A$ and $B$ is closed, current flows through the switch. So, it is NOR Gate.

JEE - 2023

PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS

365212 The Boolean expression for the gate circuit shown below is
supporting img

1

A + \overset{―}{A} = 1

2

A + 1 = 1

3

A + A = A

4

A + 0 = A

Explanation:

The input of OR gate is $A & \bar{A}$
$Y = A + \bar{A} = 1$

PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS

365213 In the following circuit the output $Y$ becomes zero for the inputs
supporting img

1

A = 1, B = 0, C = 0

2

A = 0, B = 1, C = 1

3

A = 0, B = 0, C = 0

4

A = 1, B = 1, C = 0

Explanation:

Here
$Y = \overset{―}{(A . B) . \overset{―}{C}} = (\overset{―}{A . B}) + C = \overset{―}{A} + \overset{―}{B} + C$
$Y = 0$ if $A = 1, B = 1$ and $C = 0$

PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS

365214 Following circuit will act as
supporting img

1 NOR gate

2 NAND gate

3 AND gate

4 OR gate

Explanation:

The truth table for the circuit is as
supporting img
The $Y$ -output is of NOR gate.