PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365211
Name the logic gate equivalent to the diagram given
1 NAND
2 NOR
3 AND
4 OR
Explanation:
Truth table for the given circuit is Circuit is closed when neither \(A\) nor \(B\) is closed. Current flows for \(A=0, B=0\) when either or both of \(A\) and \(B\) is closed, current flows through the switch. So, it is NOR Gate.
JEE - 2023
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365212
The Boolean expression for the gate circuit shown below is
1 \(A + \overline A = 1\)
2 \(A + 1 = 1\)
3 \(A + A = A\)
4 \(A + 0 = A\)
Explanation:
The input of OR gate is \(A\,\,\& \,\,\bar A\) \(Y = A + \bar A = 1\)
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365213
In the following circuit the output \(Y\) becomes zero for the inputs
1 \(A = 1,B = 0,C = 0\)
2 \(A = 0,B = 1,C = 1\)
3 \(A = 0,B = 0,C = 0\)
4 \(A = 1,B = 1,C = 0\)
Explanation:
Here \(Y = \overline {\left( {A.B} \right).\overline C } = \left( {\overline {A.B} } \right) + C = \overline A + \overline B + C\) \(Y = 0\) if \(A = 1,\,\,B = 1\) and \(C = 0\)
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365214
Following circuit will act as
1 NOR gate
2 NAND gate
3 AND gate
4 OR gate
Explanation:
The truth table for the circuit is as The \(Y\)-output is of NOR gate.
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365211
Name the logic gate equivalent to the diagram given
1 NAND
2 NOR
3 AND
4 OR
Explanation:
Truth table for the given circuit is Circuit is closed when neither \(A\) nor \(B\) is closed. Current flows for \(A=0, B=0\) when either or both of \(A\) and \(B\) is closed, current flows through the switch. So, it is NOR Gate.
JEE - 2023
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365212
The Boolean expression for the gate circuit shown below is
1 \(A + \overline A = 1\)
2 \(A + 1 = 1\)
3 \(A + A = A\)
4 \(A + 0 = A\)
Explanation:
The input of OR gate is \(A\,\,\& \,\,\bar A\) \(Y = A + \bar A = 1\)
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365213
In the following circuit the output \(Y\) becomes zero for the inputs
1 \(A = 1,B = 0,C = 0\)
2 \(A = 0,B = 1,C = 1\)
3 \(A = 0,B = 0,C = 0\)
4 \(A = 1,B = 1,C = 0\)
Explanation:
Here \(Y = \overline {\left( {A.B} \right).\overline C } = \left( {\overline {A.B} } \right) + C = \overline A + \overline B + C\) \(Y = 0\) if \(A = 1,\,\,B = 1\) and \(C = 0\)
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365214
Following circuit will act as
1 NOR gate
2 NAND gate
3 AND gate
4 OR gate
Explanation:
The truth table for the circuit is as The \(Y\)-output is of NOR gate.
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365211
Name the logic gate equivalent to the diagram given
1 NAND
2 NOR
3 AND
4 OR
Explanation:
Truth table for the given circuit is Circuit is closed when neither \(A\) nor \(B\) is closed. Current flows for \(A=0, B=0\) when either or both of \(A\) and \(B\) is closed, current flows through the switch. So, it is NOR Gate.
JEE - 2023
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365212
The Boolean expression for the gate circuit shown below is
1 \(A + \overline A = 1\)
2 \(A + 1 = 1\)
3 \(A + A = A\)
4 \(A + 0 = A\)
Explanation:
The input of OR gate is \(A\,\,\& \,\,\bar A\) \(Y = A + \bar A = 1\)
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365213
In the following circuit the output \(Y\) becomes zero for the inputs
1 \(A = 1,B = 0,C = 0\)
2 \(A = 0,B = 1,C = 1\)
3 \(A = 0,B = 0,C = 0\)
4 \(A = 1,B = 1,C = 0\)
Explanation:
Here \(Y = \overline {\left( {A.B} \right).\overline C } = \left( {\overline {A.B} } \right) + C = \overline A + \overline B + C\) \(Y = 0\) if \(A = 1,\,\,B = 1\) and \(C = 0\)
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365214
Following circuit will act as
1 NOR gate
2 NAND gate
3 AND gate
4 OR gate
Explanation:
The truth table for the circuit is as The \(Y\)-output is of NOR gate.
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365211
Name the logic gate equivalent to the diagram given
1 NAND
2 NOR
3 AND
4 OR
Explanation:
Truth table for the given circuit is Circuit is closed when neither \(A\) nor \(B\) is closed. Current flows for \(A=0, B=0\) when either or both of \(A\) and \(B\) is closed, current flows through the switch. So, it is NOR Gate.
JEE - 2023
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365212
The Boolean expression for the gate circuit shown below is
1 \(A + \overline A = 1\)
2 \(A + 1 = 1\)
3 \(A + A = A\)
4 \(A + 0 = A\)
Explanation:
The input of OR gate is \(A\,\,\& \,\,\bar A\) \(Y = A + \bar A = 1\)
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365213
In the following circuit the output \(Y\) becomes zero for the inputs
1 \(A = 1,B = 0,C = 0\)
2 \(A = 0,B = 1,C = 1\)
3 \(A = 0,B = 0,C = 0\)
4 \(A = 1,B = 1,C = 0\)
Explanation:
Here \(Y = \overline {\left( {A.B} \right).\overline C } = \left( {\overline {A.B} } \right) + C = \overline A + \overline B + C\) \(Y = 0\) if \(A = 1,\,\,B = 1\) and \(C = 0\)
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365214
Following circuit will act as
1 NOR gate
2 NAND gate
3 AND gate
4 OR gate
Explanation:
The truth table for the circuit is as The \(Y\)-output is of NOR gate.
