NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
365022
Assertion : If refractive index of one medium is equal to refractive index of second medium, then beam does not bend at all. Reason : The bending of light does not depend on refractive indices of media.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Here, bending means deviation in original path. \(\mu_{2}=\dfrac{\operatorname{Sin} i}{\operatorname{Sin} r}\) (where subscripts 1 and 2 are for two media) If refractive index of one medium is equal to refractive index of the second medium, then the beam does not bend at all. \(\operatorname{Sin} i=\operatorname{Sin} r \Rightarrow i=r\) bending of light depends on the refractive indices of the media. So correct option is (3).
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
365023
If \(_j{{\bf{\mu }}_i}\) represents refractive index medium \(i\) w.r.to medium \(j\). Then the product \(_2{\mu _1} \times {\;_3}{\mu _2} \times {\;_4}{\mu _3}\) is equal to
365024
If \({\varepsilon _0}\) and \({\mu _0}\) are the permittivity and permeability of free space and \(\varepsilon \) and \(\mu \) are the corresponding quantities for a medium, then refractive index of the medium is
Refractive index of the medium is \(n = \frac{{c\left( {speed\,of\,light\,in\,vaccum} \right)}}{{v\left( {speed\,of\,light\,in\,medium} \right)}}\) But \(c = \frac{1}{{\sqrt {{\mu _0}{\varepsilon _0}} }}\) and \(v = \frac{1}{{\sqrt {\mu \varepsilon } }}\) \(\therefore n = \frac{{\frac{1}{{\sqrt {{\mu _0}{\varepsilon _0}} }}}}{{\frac{1}{{\sqrt {\mu \varepsilon } }}}} = \sqrt {\frac{{\mu \varepsilon }}{{{\mu _0}{\varepsilon _0}}}} \)
KCET - 2015
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
365025
A light wave has a frequency of \({4 \times 10^{14} {~Hz}}\) and a wavelength of \({5 \times 10^{-7} {~m}}\) in a medium. The refractive index of the medium is
1 1.5
2 1.33
3 1.0
4 0.66
Explanation:
Speed of light in medium \({=v \lambda}\) \({=4 \times 10^{14} \times 5 \times 10^{-7}=20 \times 10^{7} {~m} {~s}^{-1}}\) \(\mu = \frac{{{\text{ Speed of light in vacuum }}}}{{{\text{ Speed of light in medium }}}} = \frac{{3 \times {{10}^8}}}{{20 \times {{10}^7}}}\) \({\text{ = 1}}{\text{.5}}\). So correct option is (1)
365022
Assertion : If refractive index of one medium is equal to refractive index of second medium, then beam does not bend at all. Reason : The bending of light does not depend on refractive indices of media.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Here, bending means deviation in original path. \(\mu_{2}=\dfrac{\operatorname{Sin} i}{\operatorname{Sin} r}\) (where subscripts 1 and 2 are for two media) If refractive index of one medium is equal to refractive index of the second medium, then the beam does not bend at all. \(\operatorname{Sin} i=\operatorname{Sin} r \Rightarrow i=r\) bending of light depends on the refractive indices of the media. So correct option is (3).
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
365023
If \(_j{{\bf{\mu }}_i}\) represents refractive index medium \(i\) w.r.to medium \(j\). Then the product \(_2{\mu _1} \times {\;_3}{\mu _2} \times {\;_4}{\mu _3}\) is equal to
365024
If \({\varepsilon _0}\) and \({\mu _0}\) are the permittivity and permeability of free space and \(\varepsilon \) and \(\mu \) are the corresponding quantities for a medium, then refractive index of the medium is
Refractive index of the medium is \(n = \frac{{c\left( {speed\,of\,light\,in\,vaccum} \right)}}{{v\left( {speed\,of\,light\,in\,medium} \right)}}\) But \(c = \frac{1}{{\sqrt {{\mu _0}{\varepsilon _0}} }}\) and \(v = \frac{1}{{\sqrt {\mu \varepsilon } }}\) \(\therefore n = \frac{{\frac{1}{{\sqrt {{\mu _0}{\varepsilon _0}} }}}}{{\frac{1}{{\sqrt {\mu \varepsilon } }}}} = \sqrt {\frac{{\mu \varepsilon }}{{{\mu _0}{\varepsilon _0}}}} \)
KCET - 2015
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
365025
A light wave has a frequency of \({4 \times 10^{14} {~Hz}}\) and a wavelength of \({5 \times 10^{-7} {~m}}\) in a medium. The refractive index of the medium is
1 1.5
2 1.33
3 1.0
4 0.66
Explanation:
Speed of light in medium \({=v \lambda}\) \({=4 \times 10^{14} \times 5 \times 10^{-7}=20 \times 10^{7} {~m} {~s}^{-1}}\) \(\mu = \frac{{{\text{ Speed of light in vacuum }}}}{{{\text{ Speed of light in medium }}}} = \frac{{3 \times {{10}^8}}}{{20 \times {{10}^7}}}\) \({\text{ = 1}}{\text{.5}}\). So correct option is (1)
365022
Assertion : If refractive index of one medium is equal to refractive index of second medium, then beam does not bend at all. Reason : The bending of light does not depend on refractive indices of media.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Here, bending means deviation in original path. \(\mu_{2}=\dfrac{\operatorname{Sin} i}{\operatorname{Sin} r}\) (where subscripts 1 and 2 are for two media) If refractive index of one medium is equal to refractive index of the second medium, then the beam does not bend at all. \(\operatorname{Sin} i=\operatorname{Sin} r \Rightarrow i=r\) bending of light depends on the refractive indices of the media. So correct option is (3).
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
365023
If \(_j{{\bf{\mu }}_i}\) represents refractive index medium \(i\) w.r.to medium \(j\). Then the product \(_2{\mu _1} \times {\;_3}{\mu _2} \times {\;_4}{\mu _3}\) is equal to
365024
If \({\varepsilon _0}\) and \({\mu _0}\) are the permittivity and permeability of free space and \(\varepsilon \) and \(\mu \) are the corresponding quantities for a medium, then refractive index of the medium is
Refractive index of the medium is \(n = \frac{{c\left( {speed\,of\,light\,in\,vaccum} \right)}}{{v\left( {speed\,of\,light\,in\,medium} \right)}}\) But \(c = \frac{1}{{\sqrt {{\mu _0}{\varepsilon _0}} }}\) and \(v = \frac{1}{{\sqrt {\mu \varepsilon } }}\) \(\therefore n = \frac{{\frac{1}{{\sqrt {{\mu _0}{\varepsilon _0}} }}}}{{\frac{1}{{\sqrt {\mu \varepsilon } }}}} = \sqrt {\frac{{\mu \varepsilon }}{{{\mu _0}{\varepsilon _0}}}} \)
KCET - 2015
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
365025
A light wave has a frequency of \({4 \times 10^{14} {~Hz}}\) and a wavelength of \({5 \times 10^{-7} {~m}}\) in a medium. The refractive index of the medium is
1 1.5
2 1.33
3 1.0
4 0.66
Explanation:
Speed of light in medium \({=v \lambda}\) \({=4 \times 10^{14} \times 5 \times 10^{-7}=20 \times 10^{7} {~m} {~s}^{-1}}\) \(\mu = \frac{{{\text{ Speed of light in vacuum }}}}{{{\text{ Speed of light in medium }}}} = \frac{{3 \times {{10}^8}}}{{20 \times {{10}^7}}}\) \({\text{ = 1}}{\text{.5}}\). So correct option is (1)
365022
Assertion : If refractive index of one medium is equal to refractive index of second medium, then beam does not bend at all. Reason : The bending of light does not depend on refractive indices of media.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Here, bending means deviation in original path. \(\mu_{2}=\dfrac{\operatorname{Sin} i}{\operatorname{Sin} r}\) (where subscripts 1 and 2 are for two media) If refractive index of one medium is equal to refractive index of the second medium, then the beam does not bend at all. \(\operatorname{Sin} i=\operatorname{Sin} r \Rightarrow i=r\) bending of light depends on the refractive indices of the media. So correct option is (3).
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
365023
If \(_j{{\bf{\mu }}_i}\) represents refractive index medium \(i\) w.r.to medium \(j\). Then the product \(_2{\mu _1} \times {\;_3}{\mu _2} \times {\;_4}{\mu _3}\) is equal to
365024
If \({\varepsilon _0}\) and \({\mu _0}\) are the permittivity and permeability of free space and \(\varepsilon \) and \(\mu \) are the corresponding quantities for a medium, then refractive index of the medium is
Refractive index of the medium is \(n = \frac{{c\left( {speed\,of\,light\,in\,vaccum} \right)}}{{v\left( {speed\,of\,light\,in\,medium} \right)}}\) But \(c = \frac{1}{{\sqrt {{\mu _0}{\varepsilon _0}} }}\) and \(v = \frac{1}{{\sqrt {\mu \varepsilon } }}\) \(\therefore n = \frac{{\frac{1}{{\sqrt {{\mu _0}{\varepsilon _0}} }}}}{{\frac{1}{{\sqrt {\mu \varepsilon } }}}} = \sqrt {\frac{{\mu \varepsilon }}{{{\mu _0}{\varepsilon _0}}}} \)
KCET - 2015
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
365025
A light wave has a frequency of \({4 \times 10^{14} {~Hz}}\) and a wavelength of \({5 \times 10^{-7} {~m}}\) in a medium. The refractive index of the medium is
1 1.5
2 1.33
3 1.0
4 0.66
Explanation:
Speed of light in medium \({=v \lambda}\) \({=4 \times 10^{14} \times 5 \times 10^{-7}=20 \times 10^{7} {~m} {~s}^{-1}}\) \(\mu = \frac{{{\text{ Speed of light in vacuum }}}}{{{\text{ Speed of light in medium }}}} = \frac{{3 \times {{10}^8}}}{{20 \times {{10}^7}}}\) \({\text{ = 1}}{\text{.5}}\). So correct option is (1)
