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PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365022 Assertion :
If refractive index of one medium is equal to refractive index of second medium, then beam does not bend at all.
Reason :
The bending of light does not depend on refractive indices of media.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

Explanation:

Here, bending means deviation in original path. $μ_{2} = \frac{Sin i}{Sin r}$ (where subscripts 1 and 2 are for two media) If refractive index of one medium is equal to refractive index of the second medium, then the beam does not bend at all. $Sin i = Sin r \Rightarrow i = r$ bending of light depends on the refractive indices of the media. So correct option is (3).

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365023 If $_{j} μ_{i}$ represents refractive index medium $i$ w.r.to medium $j$ . Then the product $_{2} μ_{1} \times_{3} μ_{2} \times_{4} μ_{3}$ is equal to

1

_{3} μ_{1}

2

_{3} μ_{2}

3

\frac{1}{_{1} μ_{4}}

4

_{4} μ_{2}

Explanation:

$\frac{μ_{1}}{μ_{2}} \times \frac{μ_{2}}{μ_{3}} \times \frac{μ_{3}}{μ_{4}} = \frac{μ_{1}}{μ_{4}} =_{4} μ_{1} = \frac{1}{_{1} μ_{4}}$

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365024 If $ε_{0}$ and $μ_{0}$ are the permittivity and permeability of free space and $ε$ and $μ$ are the corresponding quantities for a medium, then refractive index of the medium is

1

\sqrt{\frac{μ ε}{μ_{0} ε_{0}}}

2 insufficient information

3

\sqrt{\frac{μ_{0} ε_{0}}{μ ε}}

4 1

Explanation:

Refractive index of the medium is
$n = \frac{c (s p e e d o f l i g h t i n v a c c u m)}{v (s p e e d o f l i g h t i n m e d i u m)}$
But $c = \frac{1}{\sqrt{μ_{0} ε_{0}}}$ and $v = \frac{1}{\sqrt{μ ε}}$
$∴ n = \frac{\frac{1}{\sqrt{μ_{0} ε_{0}}}}{\frac{1}{\sqrt{μ ε}}} = \sqrt{\frac{μ ε}{μ_{0} ε_{0}}}$

KCET - 2015

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365025 A light wave has a frequency of $4 \times 10^{14} H z$ and a wavelength of $5 \times 10^{- 7} m$ in a medium. The refractive index of the medium is

1 1.5

2 1.33

3 1.0

4 0.66

Explanation:

Speed of light in medium $= v λ$
$= 4 \times 10^{14} \times 5 \times 10^{- 7} = 20 \times 10^{7} m s^{- 1}$
$μ = \frac{Speed of light in vacuum}{Speed of light in medium} = \frac{3 \times 10^{8}}{20 \times 10^{7}}$
$= 1 .5$ .
So correct option is (1)

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365022 Assertion :
If refractive index of one medium is equal to refractive index of second medium, then beam does not bend at all.
Reason :
The bending of light does not depend on refractive indices of media.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

Explanation:

Here, bending means deviation in original path. $μ_{2} = \frac{Sin i}{Sin r}$ (where subscripts 1 and 2 are for two media) If refractive index of one medium is equal to refractive index of the second medium, then the beam does not bend at all. $Sin i = Sin r \Rightarrow i = r$ bending of light depends on the refractive indices of the media. So correct option is (3).

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365023 If $_{j} μ_{i}$ represents refractive index medium $i$ w.r.to medium $j$ . Then the product $_{2} μ_{1} \times_{3} μ_{2} \times_{4} μ_{3}$ is equal to

1

_{3} μ_{1}

2

_{3} μ_{2}

3

\frac{1}{_{1} μ_{4}}

4

_{4} μ_{2}

Explanation:

$\frac{μ_{1}}{μ_{2}} \times \frac{μ_{2}}{μ_{3}} \times \frac{μ_{3}}{μ_{4}} = \frac{μ_{1}}{μ_{4}} =_{4} μ_{1} = \frac{1}{_{1} μ_{4}}$

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365024 If $ε_{0}$ and $μ_{0}$ are the permittivity and permeability of free space and $ε$ and $μ$ are the corresponding quantities for a medium, then refractive index of the medium is

1

\sqrt{\frac{μ ε}{μ_{0} ε_{0}}}

2 insufficient information

3

\sqrt{\frac{μ_{0} ε_{0}}{μ ε}}

4 1

Explanation:

Refractive index of the medium is
$n = \frac{c (s p e e d o f l i g h t i n v a c c u m)}{v (s p e e d o f l i g h t i n m e d i u m)}$
But $c = \frac{1}{\sqrt{μ_{0} ε_{0}}}$ and $v = \frac{1}{\sqrt{μ ε}}$
$∴ n = \frac{\frac{1}{\sqrt{μ_{0} ε_{0}}}}{\frac{1}{\sqrt{μ ε}}} = \sqrt{\frac{μ ε}{μ_{0} ε_{0}}}$

KCET - 2015

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365025 A light wave has a frequency of $4 \times 10^{14} H z$ and a wavelength of $5 \times 10^{- 7} m$ in a medium. The refractive index of the medium is

1 1.5

2 1.33

3 1.0

4 0.66

Explanation:

Speed of light in medium $= v λ$
$= 4 \times 10^{14} \times 5 \times 10^{- 7} = 20 \times 10^{7} m s^{- 1}$
$μ = \frac{Speed of light in vacuum}{Speed of light in medium} = \frac{3 \times 10^{8}}{20 \times 10^{7}}$
$= 1 .5$ .
So correct option is (1)

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365022 Assertion :
If refractive index of one medium is equal to refractive index of second medium, then beam does not bend at all.
Reason :
The bending of light does not depend on refractive indices of media.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

Explanation:

Here, bending means deviation in original path. $μ_{2} = \frac{Sin i}{Sin r}$ (where subscripts 1 and 2 are for two media) If refractive index of one medium is equal to refractive index of the second medium, then the beam does not bend at all. $Sin i = Sin r \Rightarrow i = r$ bending of light depends on the refractive indices of the media. So correct option is (3).

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365023 If $_{j} μ_{i}$ represents refractive index medium $i$ w.r.to medium $j$ . Then the product $_{2} μ_{1} \times_{3} μ_{2} \times_{4} μ_{3}$ is equal to

1

_{3} μ_{1}

2

_{3} μ_{2}

3

\frac{1}{_{1} μ_{4}}

4

_{4} μ_{2}

Explanation:

$\frac{μ_{1}}{μ_{2}} \times \frac{μ_{2}}{μ_{3}} \times \frac{μ_{3}}{μ_{4}} = \frac{μ_{1}}{μ_{4}} =_{4} μ_{1} = \frac{1}{_{1} μ_{4}}$

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365024 If $ε_{0}$ and $μ_{0}$ are the permittivity and permeability of free space and $ε$ and $μ$ are the corresponding quantities for a medium, then refractive index of the medium is

1

\sqrt{\frac{μ ε}{μ_{0} ε_{0}}}

2 insufficient information

3

\sqrt{\frac{μ_{0} ε_{0}}{μ ε}}

4 1

Explanation:

Refractive index of the medium is
$n = \frac{c (s p e e d o f l i g h t i n v a c c u m)}{v (s p e e d o f l i g h t i n m e d i u m)}$
But $c = \frac{1}{\sqrt{μ_{0} ε_{0}}}$ and $v = \frac{1}{\sqrt{μ ε}}$
$∴ n = \frac{\frac{1}{\sqrt{μ_{0} ε_{0}}}}{\frac{1}{\sqrt{μ ε}}} = \sqrt{\frac{μ ε}{μ_{0} ε_{0}}}$

KCET - 2015

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365025 A light wave has a frequency of $4 \times 10^{14} H z$ and a wavelength of $5 \times 10^{- 7} m$ in a medium. The refractive index of the medium is

1 1.5

2 1.33

3 1.0

4 0.66

Explanation:

Speed of light in medium $= v λ$
$= 4 \times 10^{14} \times 5 \times 10^{- 7} = 20 \times 10^{7} m s^{- 1}$
$μ = \frac{Speed of light in vacuum}{Speed of light in medium} = \frac{3 \times 10^{8}}{20 \times 10^{7}}$
$= 1 .5$ .
So correct option is (1)

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365022 Assertion :
If refractive index of one medium is equal to refractive index of second medium, then beam does not bend at all.
Reason :
The bending of light does not depend on refractive indices of media.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

Explanation:

Here, bending means deviation in original path. $μ_{2} = \frac{Sin i}{Sin r}$ (where subscripts 1 and 2 are for two media) If refractive index of one medium is equal to refractive index of the second medium, then the beam does not bend at all. $Sin i = Sin r \Rightarrow i = r$ bending of light depends on the refractive indices of the media. So correct option is (3).

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365023 If $_{j} μ_{i}$ represents refractive index medium $i$ w.r.to medium $j$ . Then the product $_{2} μ_{1} \times_{3} μ_{2} \times_{4} μ_{3}$ is equal to

1

_{3} μ_{1}

2

_{3} μ_{2}

3

\frac{1}{_{1} μ_{4}}

4

_{4} μ_{2}

Explanation:

$\frac{μ_{1}}{μ_{2}} \times \frac{μ_{2}}{μ_{3}} \times \frac{μ_{3}}{μ_{4}} = \frac{μ_{1}}{μ_{4}} =_{4} μ_{1} = \frac{1}{_{1} μ_{4}}$

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365024 If $ε_{0}$ and $μ_{0}$ are the permittivity and permeability of free space and $ε$ and $μ$ are the corresponding quantities for a medium, then refractive index of the medium is

1

\sqrt{\frac{μ ε}{μ_{0} ε_{0}}}

2 insufficient information

3

\sqrt{\frac{μ_{0} ε_{0}}{μ ε}}

4 1

Explanation:

Refractive index of the medium is
$n = \frac{c (s p e e d o f l i g h t i n v a c c u m)}{v (s p e e d o f l i g h t i n m e d i u m)}$
But $c = \frac{1}{\sqrt{μ_{0} ε_{0}}}$ and $v = \frac{1}{\sqrt{μ ε}}$
$∴ n = \frac{\frac{1}{\sqrt{μ_{0} ε_{0}}}}{\frac{1}{\sqrt{μ ε}}} = \sqrt{\frac{μ ε}{μ_{0} ε_{0}}}$

KCET - 2015

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365025 A light wave has a frequency of $4 \times 10^{14} H z$ and a wavelength of $5 \times 10^{- 7} m$ in a medium. The refractive index of the medium is

1 1.5

2 1.33

3 1.0

4 0.66

Explanation:

Speed of light in medium $= v λ$
$= 4 \times 10^{14} \times 5 \times 10^{- 7} = 20 \times 10^{7} m s^{- 1}$
$μ = \frac{Speed of light in vacuum}{Speed of light in medium} = \frac{3 \times 10^{8}}{20 \times 10^{7}}$
$= 1 .5$ .
So correct option is (1)

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