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PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365005 Assertion :
Higher is the refractive index of a medium or denser the medium, lesser is the velocity of light in that medium.
Reason :
Refractive index is inversely proportional to velocity.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

Explanation:

$μ = \frac{c}{v} \propto \frac{1}{v}$
$(∵ c =$ constant $)$
High value of $μ$ is for 'denser' medium. So correct option is (1).

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365006 Glass has refractive index $μ$ with respect to air and the critical angle for a ray of light going from glass to air is $θ$ . If a ray of light is incident from air on the glass with angle of incidence , corresponding angle of refraction is

1

\sin^{- 1} (μ)

2

\sin^{- 1} (\frac{1}{μ^{2}})

3

\sin^{- 1} (\frac{1}{\sqrt{μ}})

4

\sin^{- 1} (\frac{1}{μ})

Explanation:

Refractive index of glass with respect to air = $μ$
Critical angle = $θ$
$∴ μ = \frac{1}{\sin θ}$ (1)
When a ray of light incident from air on the glass with angle of incidence $θ$ . If $r$ be the angle of refraction, then by Snell’s law
$μ = \frac{\sin θ}{\sin r}$
$\Rightarrow \sin r = \frac{\sin θ}{μ} = \frac{1 / μ}{μ} [f r o m e q . (1)]$
$\Rightarrow \sin r = \frac{1}{μ^{2}}$
$r = \sin^{- 1} (\frac{1}{μ^{2}})$

MHTCET - 2019

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365007 A short pulse of white light is incident from air to glass slab at normal incidence. After travelling through the slab, the first colour to emerge is :-

1 Green

2 Blue

3 Red

4 Violet

Explanation:

We know that
$μ_{V i o l e t} > μ_{Re d} \Rightarrow v_{Re d} > v_{V i o l e t}$
$\sin 60^{\circ} = μ \sin r_{1}$
So red colour comes first

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365008 You are given four sources of light each one providing a light of a single colour-red, blue, green and yellow. Suppose the angle of refraction for a beam of yellow light corresponding to a particular angle of incidence at the interface of two media is $90^{\circ}$ . Which of the following statements is correct if the source of yellow light replaced with that of other lights without changing the angle of incidence?

1 The beam of red light would bend towards normal while it gets refracted through the second medium.

2 The beam of red light would undergo total internal reflection.

3 The beam of green light would bend away from the normal as it gets refracted through the second medium.

4 The beam of blue light would undergo total internal reflection.

NCERT EXEMPLAR

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365005 Assertion :
Higher is the refractive index of a medium or denser the medium, lesser is the velocity of light in that medium.
Reason :
Refractive index is inversely proportional to velocity.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

Explanation:

$μ = \frac{c}{v} \propto \frac{1}{v}$
$(∵ c =$ constant $)$
High value of $μ$ is for 'denser' medium. So correct option is (1).

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365006 Glass has refractive index $μ$ with respect to air and the critical angle for a ray of light going from glass to air is $θ$ . If a ray of light is incident from air on the glass with angle of incidence , corresponding angle of refraction is

1

\sin^{- 1} (μ)

2

\sin^{- 1} (\frac{1}{μ^{2}})

3

\sin^{- 1} (\frac{1}{\sqrt{μ}})

4

\sin^{- 1} (\frac{1}{μ})

Explanation:

Refractive index of glass with respect to air = $μ$
Critical angle = $θ$
$∴ μ = \frac{1}{\sin θ}$ (1)
When a ray of light incident from air on the glass with angle of incidence $θ$ . If $r$ be the angle of refraction, then by Snell’s law
$μ = \frac{\sin θ}{\sin r}$
$\Rightarrow \sin r = \frac{\sin θ}{μ} = \frac{1 / μ}{μ} [f r o m e q . (1)]$
$\Rightarrow \sin r = \frac{1}{μ^{2}}$
$r = \sin^{- 1} (\frac{1}{μ^{2}})$

MHTCET - 2019

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365007 A short pulse of white light is incident from air to glass slab at normal incidence. After travelling through the slab, the first colour to emerge is :-

1 Green

2 Blue

3 Red

4 Violet

Explanation:

We know that
$μ_{V i o l e t} > μ_{Re d} \Rightarrow v_{Re d} > v_{V i o l e t}$
$\sin 60^{\circ} = μ \sin r_{1}$
So red colour comes first

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365008 You are given four sources of light each one providing a light of a single colour-red, blue, green and yellow. Suppose the angle of refraction for a beam of yellow light corresponding to a particular angle of incidence at the interface of two media is $90^{\circ}$ . Which of the following statements is correct if the source of yellow light replaced with that of other lights without changing the angle of incidence?

1 The beam of red light would bend towards normal while it gets refracted through the second medium.

2 The beam of red light would undergo total internal reflection.

3 The beam of green light would bend away from the normal as it gets refracted through the second medium.

4 The beam of blue light would undergo total internal reflection.

NCERT EXEMPLAR

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365005 Assertion :
Higher is the refractive index of a medium or denser the medium, lesser is the velocity of light in that medium.
Reason :
Refractive index is inversely proportional to velocity.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

Explanation:

$μ = \frac{c}{v} \propto \frac{1}{v}$
$(∵ c =$ constant $)$
High value of $μ$ is for 'denser' medium. So correct option is (1).

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365006 Glass has refractive index $μ$ with respect to air and the critical angle for a ray of light going from glass to air is $θ$ . If a ray of light is incident from air on the glass with angle of incidence , corresponding angle of refraction is

1

\sin^{- 1} (μ)

2

\sin^{- 1} (\frac{1}{μ^{2}})

3

\sin^{- 1} (\frac{1}{\sqrt{μ}})

4

\sin^{- 1} (\frac{1}{μ})

Explanation:

Refractive index of glass with respect to air = $μ$
Critical angle = $θ$
$∴ μ = \frac{1}{\sin θ}$ (1)
When a ray of light incident from air on the glass with angle of incidence $θ$ . If $r$ be the angle of refraction, then by Snell’s law
$μ = \frac{\sin θ}{\sin r}$
$\Rightarrow \sin r = \frac{\sin θ}{μ} = \frac{1 / μ}{μ} [f r o m e q . (1)]$
$\Rightarrow \sin r = \frac{1}{μ^{2}}$
$r = \sin^{- 1} (\frac{1}{μ^{2}})$

MHTCET - 2019

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365007 A short pulse of white light is incident from air to glass slab at normal incidence. After travelling through the slab, the first colour to emerge is :-

1 Green

2 Blue

3 Red

4 Violet

Explanation:

We know that
$μ_{V i o l e t} > μ_{Re d} \Rightarrow v_{Re d} > v_{V i o l e t}$
$\sin 60^{\circ} = μ \sin r_{1}$
So red colour comes first

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365008 You are given four sources of light each one providing a light of a single colour-red, blue, green and yellow. Suppose the angle of refraction for a beam of yellow light corresponding to a particular angle of incidence at the interface of two media is $90^{\circ}$ . Which of the following statements is correct if the source of yellow light replaced with that of other lights without changing the angle of incidence?

1 The beam of red light would bend towards normal while it gets refracted through the second medium.

2 The beam of red light would undergo total internal reflection.

3 The beam of green light would bend away from the normal as it gets refracted through the second medium.

4 The beam of blue light would undergo total internal reflection.

NCERT EXEMPLAR

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365005 Assertion :
Higher is the refractive index of a medium or denser the medium, lesser is the velocity of light in that medium.
Reason :
Refractive index is inversely proportional to velocity.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

Explanation:

$μ = \frac{c}{v} \propto \frac{1}{v}$
$(∵ c =$ constant $)$
High value of $μ$ is for 'denser' medium. So correct option is (1).

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365006 Glass has refractive index $μ$ with respect to air and the critical angle for a ray of light going from glass to air is $θ$ . If a ray of light is incident from air on the glass with angle of incidence , corresponding angle of refraction is

1

\sin^{- 1} (μ)

2

\sin^{- 1} (\frac{1}{μ^{2}})

3

\sin^{- 1} (\frac{1}{\sqrt{μ}})

4

\sin^{- 1} (\frac{1}{μ})

Explanation:

Refractive index of glass with respect to air = $μ$
Critical angle = $θ$
$∴ μ = \frac{1}{\sin θ}$ (1)
When a ray of light incident from air on the glass with angle of incidence $θ$ . If $r$ be the angle of refraction, then by Snell’s law
$μ = \frac{\sin θ}{\sin r}$
$\Rightarrow \sin r = \frac{\sin θ}{μ} = \frac{1 / μ}{μ} [f r o m e q . (1)]$
$\Rightarrow \sin r = \frac{1}{μ^{2}}$
$r = \sin^{- 1} (\frac{1}{μ^{2}})$

MHTCET - 2019

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365007 A short pulse of white light is incident from air to glass slab at normal incidence. After travelling through the slab, the first colour to emerge is :-

1 Green

2 Blue

3 Red

4 Violet

Explanation:

We know that
$μ_{V i o l e t} > μ_{Re d} \Rightarrow v_{Re d} > v_{V i o l e t}$
$\sin 60^{\circ} = μ \sin r_{1}$
So red colour comes first

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365008 You are given four sources of light each one providing a light of a single colour-red, blue, green and yellow. Suppose the angle of refraction for a beam of yellow light corresponding to a particular angle of incidence at the interface of two media is $90^{\circ}$ . Which of the following statements is correct if the source of yellow light replaced with that of other lights without changing the angle of incidence?

1 The beam of red light would bend towards normal while it gets refracted through the second medium.

2 The beam of red light would undergo total internal reflection.

3 The beam of green light would bend away from the normal as it gets refracted through the second medium.

4 The beam of blue light would undergo total internal reflection.

NCERT EXEMPLAR

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