364843
An object is placed 50 \(cm\) from a screen as shown in figure.
A converging lens is moved such that line \({M N}\) is its principal axis. Sharp images are formed on the screen in two positions of lens separated by 30 \(cm\). Find the focal length of the lens
364845
Assertion :
The focal length of an equiconvex lens placed in air is equal to radius of curvature of either face. (Lens is made up of material of refractive index of 1.5.)
Reason :
The focal length will be \(\dfrac{R}{3}\) for equiconvex lens of redfractive index 1.5
364843
An object is placed 50 \(cm\) from a screen as shown in figure.
A converging lens is moved such that line \({M N}\) is its principal axis. Sharp images are formed on the screen in two positions of lens separated by 30 \(cm\). Find the focal length of the lens
364845
Assertion :
The focal length of an equiconvex lens placed in air is equal to radius of curvature of either face. (Lens is made up of material of refractive index of 1.5.)
Reason :
The focal length will be \(\dfrac{R}{3}\) for equiconvex lens of redfractive index 1.5
364843
An object is placed 50 \(cm\) from a screen as shown in figure.
A converging lens is moved such that line \({M N}\) is its principal axis. Sharp images are formed on the screen in two positions of lens separated by 30 \(cm\). Find the focal length of the lens
364845
Assertion :
The focal length of an equiconvex lens placed in air is equal to radius of curvature of either face. (Lens is made up of material of refractive index of 1.5.)
Reason :
The focal length will be \(\dfrac{R}{3}\) for equiconvex lens of redfractive index 1.5
364843
An object is placed 50 \(cm\) from a screen as shown in figure.
A converging lens is moved such that line \({M N}\) is its principal axis. Sharp images are formed on the screen in two positions of lens separated by 30 \(cm\). Find the focal length of the lens
364845
Assertion :
The focal length of an equiconvex lens placed in air is equal to radius of curvature of either face. (Lens is made up of material of refractive index of 1.5.)
Reason :
The focal length will be \(\dfrac{R}{3}\) for equiconvex lens of redfractive index 1.5