364838
A parallel beam of light is incident on a converging lens parallel to its principal axis. As one moves away from the lens on the other side of the principal axis, the intensity of light
1 First decreases and then increases
2 Continuously increases
3 Continuously decreases
4 First increases and then decreases
Explanation:
The parallel beam, after refracting through lens, first converges to a point at the focus and then diverges. Hence the intensity of light first increases and then decreases.
KCET - 2009
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364839
When a lens of refractive index \({n_1}\) is placed in a liquid of refractive index \({n_2}\), the lens look to be disappeared, if
1 \({n_1} = 3{n_2}/4\)
2 \({n_1} = {n_2}/2\)
3 \({n_1} = 5{n_2}/4\)
4 \({n_1} = {n_2}\)
Explanation:
Conceptual Question
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364840
A double convex thin lens made of glass ( \(\mu=1.5)\) has both radii of curvature of magnitude \(20\;cm\). Incident light rays parallel to the axis of the lens will converge at a distance \(L\) such that:
364841
A convex lens of glass is immersed in water compared to its power in air, its power in water will
1 Increase
2 Decrease
3 Not change
4 Decrease for red light increase for violet light
Explanation:
In air medium \({P_1} = \frac{1}{{{f_1}}} = ({\mu _g} - 1)\left( {\frac{1}{{{R_1}}} - \frac{1}{{{R_2}}}} \right)\) In water medium \({P_2} = \frac{1}{{{f_2}}} = \left( {\frac{{{\mu _g}}}{{{\mu _w}}} - 1} \right)\left( {\frac{1}{{{R_1}}} - \frac{1}{{{R_2}}}} \right)\) In water medium power of the lens decreases
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PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364838
A parallel beam of light is incident on a converging lens parallel to its principal axis. As one moves away from the lens on the other side of the principal axis, the intensity of light
1 First decreases and then increases
2 Continuously increases
3 Continuously decreases
4 First increases and then decreases
Explanation:
The parallel beam, after refracting through lens, first converges to a point at the focus and then diverges. Hence the intensity of light first increases and then decreases.
KCET - 2009
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364839
When a lens of refractive index \({n_1}\) is placed in a liquid of refractive index \({n_2}\), the lens look to be disappeared, if
1 \({n_1} = 3{n_2}/4\)
2 \({n_1} = {n_2}/2\)
3 \({n_1} = 5{n_2}/4\)
4 \({n_1} = {n_2}\)
Explanation:
Conceptual Question
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364840
A double convex thin lens made of glass ( \(\mu=1.5)\) has both radii of curvature of magnitude \(20\;cm\). Incident light rays parallel to the axis of the lens will converge at a distance \(L\) such that:
364841
A convex lens of glass is immersed in water compared to its power in air, its power in water will
1 Increase
2 Decrease
3 Not change
4 Decrease for red light increase for violet light
Explanation:
In air medium \({P_1} = \frac{1}{{{f_1}}} = ({\mu _g} - 1)\left( {\frac{1}{{{R_1}}} - \frac{1}{{{R_2}}}} \right)\) In water medium \({P_2} = \frac{1}{{{f_2}}} = \left( {\frac{{{\mu _g}}}{{{\mu _w}}} - 1} \right)\left( {\frac{1}{{{R_1}}} - \frac{1}{{{R_2}}}} \right)\) In water medium power of the lens decreases
364838
A parallel beam of light is incident on a converging lens parallel to its principal axis. As one moves away from the lens on the other side of the principal axis, the intensity of light
1 First decreases and then increases
2 Continuously increases
3 Continuously decreases
4 First increases and then decreases
Explanation:
The parallel beam, after refracting through lens, first converges to a point at the focus and then diverges. Hence the intensity of light first increases and then decreases.
KCET - 2009
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364839
When a lens of refractive index \({n_1}\) is placed in a liquid of refractive index \({n_2}\), the lens look to be disappeared, if
1 \({n_1} = 3{n_2}/4\)
2 \({n_1} = {n_2}/2\)
3 \({n_1} = 5{n_2}/4\)
4 \({n_1} = {n_2}\)
Explanation:
Conceptual Question
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364840
A double convex thin lens made of glass ( \(\mu=1.5)\) has both radii of curvature of magnitude \(20\;cm\). Incident light rays parallel to the axis of the lens will converge at a distance \(L\) such that:
364841
A convex lens of glass is immersed in water compared to its power in air, its power in water will
1 Increase
2 Decrease
3 Not change
4 Decrease for red light increase for violet light
Explanation:
In air medium \({P_1} = \frac{1}{{{f_1}}} = ({\mu _g} - 1)\left( {\frac{1}{{{R_1}}} - \frac{1}{{{R_2}}}} \right)\) In water medium \({P_2} = \frac{1}{{{f_2}}} = \left( {\frac{{{\mu _g}}}{{{\mu _w}}} - 1} \right)\left( {\frac{1}{{{R_1}}} - \frac{1}{{{R_2}}}} \right)\) In water medium power of the lens decreases
364838
A parallel beam of light is incident on a converging lens parallel to its principal axis. As one moves away from the lens on the other side of the principal axis, the intensity of light
1 First decreases and then increases
2 Continuously increases
3 Continuously decreases
4 First increases and then decreases
Explanation:
The parallel beam, after refracting through lens, first converges to a point at the focus and then diverges. Hence the intensity of light first increases and then decreases.
KCET - 2009
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364839
When a lens of refractive index \({n_1}\) is placed in a liquid of refractive index \({n_2}\), the lens look to be disappeared, if
1 \({n_1} = 3{n_2}/4\)
2 \({n_1} = {n_2}/2\)
3 \({n_1} = 5{n_2}/4\)
4 \({n_1} = {n_2}\)
Explanation:
Conceptual Question
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364840
A double convex thin lens made of glass ( \(\mu=1.5)\) has both radii of curvature of magnitude \(20\;cm\). Incident light rays parallel to the axis of the lens will converge at a distance \(L\) such that:
364841
A convex lens of glass is immersed in water compared to its power in air, its power in water will
1 Increase
2 Decrease
3 Not change
4 Decrease for red light increase for violet light
Explanation:
In air medium \({P_1} = \frac{1}{{{f_1}}} = ({\mu _g} - 1)\left( {\frac{1}{{{R_1}}} - \frac{1}{{{R_2}}}} \right)\) In water medium \({P_2} = \frac{1}{{{f_2}}} = \left( {\frac{{{\mu _g}}}{{{\mu _w}}} - 1} \right)\left( {\frac{1}{{{R_1}}} - \frac{1}{{{R_2}}}} \right)\) In water medium power of the lens decreases