324204
\({\rm{\;}}{{\rm{N}}_{\rm{2}}}\) gas will not be evolved upon reaction of \({\rm{HN}}{{\rm{O}}_{\rm{2}}}\) with which of the following amines?
1 \(1^{\circ}\)
2 \(2^{\circ}\)
3 \(3^{\circ}\)
4 Both (b) and (c)
Explanation:
Only \(1^{\circ}\) amines evolve nitrogen when reacts with nitrous acid \({\text{HN}}{{\text{O}}_{\text{2}}}\)
CHXII13:AMINES
324205
Which among the following reagents is used to distinguish primary, secondary and tertiary amines according to solubility in alkaline medium?
1 Benzenesulphonyl chloride
2 Iodoform
3 Ethylene glycol
4 Acetyl chloride
Explanation:
Benzenesulphonyl chloride \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{Cl}\right)\), (Hinsberg reagent) is used to distinguish primary, secondary and tertiary amines. The reaction of benzenesulphonyl chloride with primary amine yields \(\mathrm{N}\)-alkylbenzene sulphonamide which is soluble in alkali. \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{Cl}+\mathrm{RNH}_{2} \rightarrow \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{NHR}\) (Soluble in alkali due to presence of acidic hydrogen atom attached to nitrogen atom. With secondary amine, it yields N, N dialkylbenzene sulphonamide which is insoluble in alkali. \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{Cl}+\mathrm{R}_{2} \mathrm{NH} \rightarrow \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{NR}_{2}\) (Insoluble in alkali due to absence hydrogen atom attached to nitrogen atom. Tertiary amines do not react with benzenesulphonyl chloride. \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{Cl},+\mathrm{R}_{3} \mathrm{~N} \rightarrow\) No reaction.
MHTCET - 2022
CHXII13:AMINES
324206
An organic compound \(X\) reacts with nitrous acid to form N-methyl-N-nitrosoethanamine. The compound \(\mathrm{X}\) is
1 ethanamine
2 N-methylethanamine
3 N,N-dimethylethanamine
4 dimethylamine
Explanation:
Secondary amines react with nitrous acid to form nitroso derivative. The compound \(\mathrm{X}\) is N-methylethanamine.
CHXII13:AMINES
324207
An amine on reaction with \(\mathrm{HNO}_{2}\) evolved \(\mathrm{N}_{2}\). The amine on exhaustive methylation with \(\mathrm{CH}_{3} \mathrm{I}\) formed a quaternary salt containing \(59.07 \%\) iodine. The molecular mass of amine is ____.
1 127
2 135
3 215
4 230
Explanation:
Evolution of \(\mathrm{N}_{2}\) with \(\mathrm{HNO}_{2}\), suggests that \(1^{\circ}\) amine \(59.07 \mathrm{gm}\) of (I) is present in \(100\,\,{\rm{gm}}\) of compound \(127\,\,{\rm{gm}}\) of \(\mathrm{I}(1 \mathrm{~mol})\) is present in \(\dfrac{100 \times 127}{59.07}=215\) Molecular mass \(=215\)
CHXII13:AMINES
324208
The amine, which reacts with p-toluenesulphonyl chloride to give a clear solution, which on acidification gives insoluble compound is
\(1^{\circ}, 2^{\circ}\) and \(3^{\circ}\) amines can be distinguished from each other by \(\mathrm{p}\)-toluenesulphonyl chloride (Hinsberg reagent) \(1^{\circ}\) amine on sulphonation gives a product, which is insoluble in acid. \(2^{\circ}\) amine on sulphonation gives same product but is soluble in acid. \(3^{\circ}\) amine does not undergo this reaction.
324204
\({\rm{\;}}{{\rm{N}}_{\rm{2}}}\) gas will not be evolved upon reaction of \({\rm{HN}}{{\rm{O}}_{\rm{2}}}\) with which of the following amines?
1 \(1^{\circ}\)
2 \(2^{\circ}\)
3 \(3^{\circ}\)
4 Both (b) and (c)
Explanation:
Only \(1^{\circ}\) amines evolve nitrogen when reacts with nitrous acid \({\text{HN}}{{\text{O}}_{\text{2}}}\)
CHXII13:AMINES
324205
Which among the following reagents is used to distinguish primary, secondary and tertiary amines according to solubility in alkaline medium?
1 Benzenesulphonyl chloride
2 Iodoform
3 Ethylene glycol
4 Acetyl chloride
Explanation:
Benzenesulphonyl chloride \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{Cl}\right)\), (Hinsberg reagent) is used to distinguish primary, secondary and tertiary amines. The reaction of benzenesulphonyl chloride with primary amine yields \(\mathrm{N}\)-alkylbenzene sulphonamide which is soluble in alkali. \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{Cl}+\mathrm{RNH}_{2} \rightarrow \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{NHR}\) (Soluble in alkali due to presence of acidic hydrogen atom attached to nitrogen atom. With secondary amine, it yields N, N dialkylbenzene sulphonamide which is insoluble in alkali. \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{Cl}+\mathrm{R}_{2} \mathrm{NH} \rightarrow \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{NR}_{2}\) (Insoluble in alkali due to absence hydrogen atom attached to nitrogen atom. Tertiary amines do not react with benzenesulphonyl chloride. \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{Cl},+\mathrm{R}_{3} \mathrm{~N} \rightarrow\) No reaction.
MHTCET - 2022
CHXII13:AMINES
324206
An organic compound \(X\) reacts with nitrous acid to form N-methyl-N-nitrosoethanamine. The compound \(\mathrm{X}\) is
1 ethanamine
2 N-methylethanamine
3 N,N-dimethylethanamine
4 dimethylamine
Explanation:
Secondary amines react with nitrous acid to form nitroso derivative. The compound \(\mathrm{X}\) is N-methylethanamine.
CHXII13:AMINES
324207
An amine on reaction with \(\mathrm{HNO}_{2}\) evolved \(\mathrm{N}_{2}\). The amine on exhaustive methylation with \(\mathrm{CH}_{3} \mathrm{I}\) formed a quaternary salt containing \(59.07 \%\) iodine. The molecular mass of amine is ____.
1 127
2 135
3 215
4 230
Explanation:
Evolution of \(\mathrm{N}_{2}\) with \(\mathrm{HNO}_{2}\), suggests that \(1^{\circ}\) amine \(59.07 \mathrm{gm}\) of (I) is present in \(100\,\,{\rm{gm}}\) of compound \(127\,\,{\rm{gm}}\) of \(\mathrm{I}(1 \mathrm{~mol})\) is present in \(\dfrac{100 \times 127}{59.07}=215\) Molecular mass \(=215\)
CHXII13:AMINES
324208
The amine, which reacts with p-toluenesulphonyl chloride to give a clear solution, which on acidification gives insoluble compound is
\(1^{\circ}, 2^{\circ}\) and \(3^{\circ}\) amines can be distinguished from each other by \(\mathrm{p}\)-toluenesulphonyl chloride (Hinsberg reagent) \(1^{\circ}\) amine on sulphonation gives a product, which is insoluble in acid. \(2^{\circ}\) amine on sulphonation gives same product but is soluble in acid. \(3^{\circ}\) amine does not undergo this reaction.
324204
\({\rm{\;}}{{\rm{N}}_{\rm{2}}}\) gas will not be evolved upon reaction of \({\rm{HN}}{{\rm{O}}_{\rm{2}}}\) with which of the following amines?
1 \(1^{\circ}\)
2 \(2^{\circ}\)
3 \(3^{\circ}\)
4 Both (b) and (c)
Explanation:
Only \(1^{\circ}\) amines evolve nitrogen when reacts with nitrous acid \({\text{HN}}{{\text{O}}_{\text{2}}}\)
CHXII13:AMINES
324205
Which among the following reagents is used to distinguish primary, secondary and tertiary amines according to solubility in alkaline medium?
1 Benzenesulphonyl chloride
2 Iodoform
3 Ethylene glycol
4 Acetyl chloride
Explanation:
Benzenesulphonyl chloride \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{Cl}\right)\), (Hinsberg reagent) is used to distinguish primary, secondary and tertiary amines. The reaction of benzenesulphonyl chloride with primary amine yields \(\mathrm{N}\)-alkylbenzene sulphonamide which is soluble in alkali. \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{Cl}+\mathrm{RNH}_{2} \rightarrow \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{NHR}\) (Soluble in alkali due to presence of acidic hydrogen atom attached to nitrogen atom. With secondary amine, it yields N, N dialkylbenzene sulphonamide which is insoluble in alkali. \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{Cl}+\mathrm{R}_{2} \mathrm{NH} \rightarrow \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{NR}_{2}\) (Insoluble in alkali due to absence hydrogen atom attached to nitrogen atom. Tertiary amines do not react with benzenesulphonyl chloride. \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{Cl},+\mathrm{R}_{3} \mathrm{~N} \rightarrow\) No reaction.
MHTCET - 2022
CHXII13:AMINES
324206
An organic compound \(X\) reacts with nitrous acid to form N-methyl-N-nitrosoethanamine. The compound \(\mathrm{X}\) is
1 ethanamine
2 N-methylethanamine
3 N,N-dimethylethanamine
4 dimethylamine
Explanation:
Secondary amines react with nitrous acid to form nitroso derivative. The compound \(\mathrm{X}\) is N-methylethanamine.
CHXII13:AMINES
324207
An amine on reaction with \(\mathrm{HNO}_{2}\) evolved \(\mathrm{N}_{2}\). The amine on exhaustive methylation with \(\mathrm{CH}_{3} \mathrm{I}\) formed a quaternary salt containing \(59.07 \%\) iodine. The molecular mass of amine is ____.
1 127
2 135
3 215
4 230
Explanation:
Evolution of \(\mathrm{N}_{2}\) with \(\mathrm{HNO}_{2}\), suggests that \(1^{\circ}\) amine \(59.07 \mathrm{gm}\) of (I) is present in \(100\,\,{\rm{gm}}\) of compound \(127\,\,{\rm{gm}}\) of \(\mathrm{I}(1 \mathrm{~mol})\) is present in \(\dfrac{100 \times 127}{59.07}=215\) Molecular mass \(=215\)
CHXII13:AMINES
324208
The amine, which reacts with p-toluenesulphonyl chloride to give a clear solution, which on acidification gives insoluble compound is
\(1^{\circ}, 2^{\circ}\) and \(3^{\circ}\) amines can be distinguished from each other by \(\mathrm{p}\)-toluenesulphonyl chloride (Hinsberg reagent) \(1^{\circ}\) amine on sulphonation gives a product, which is insoluble in acid. \(2^{\circ}\) amine on sulphonation gives same product but is soluble in acid. \(3^{\circ}\) amine does not undergo this reaction.
NEET Test Series from KOTA - 10 Papers In MS WORD
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CHXII13:AMINES
324204
\({\rm{\;}}{{\rm{N}}_{\rm{2}}}\) gas will not be evolved upon reaction of \({\rm{HN}}{{\rm{O}}_{\rm{2}}}\) with which of the following amines?
1 \(1^{\circ}\)
2 \(2^{\circ}\)
3 \(3^{\circ}\)
4 Both (b) and (c)
Explanation:
Only \(1^{\circ}\) amines evolve nitrogen when reacts with nitrous acid \({\text{HN}}{{\text{O}}_{\text{2}}}\)
CHXII13:AMINES
324205
Which among the following reagents is used to distinguish primary, secondary and tertiary amines according to solubility in alkaline medium?
1 Benzenesulphonyl chloride
2 Iodoform
3 Ethylene glycol
4 Acetyl chloride
Explanation:
Benzenesulphonyl chloride \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{Cl}\right)\), (Hinsberg reagent) is used to distinguish primary, secondary and tertiary amines. The reaction of benzenesulphonyl chloride with primary amine yields \(\mathrm{N}\)-alkylbenzene sulphonamide which is soluble in alkali. \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{Cl}+\mathrm{RNH}_{2} \rightarrow \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{NHR}\) (Soluble in alkali due to presence of acidic hydrogen atom attached to nitrogen atom. With secondary amine, it yields N, N dialkylbenzene sulphonamide which is insoluble in alkali. \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{Cl}+\mathrm{R}_{2} \mathrm{NH} \rightarrow \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{NR}_{2}\) (Insoluble in alkali due to absence hydrogen atom attached to nitrogen atom. Tertiary amines do not react with benzenesulphonyl chloride. \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{Cl},+\mathrm{R}_{3} \mathrm{~N} \rightarrow\) No reaction.
MHTCET - 2022
CHXII13:AMINES
324206
An organic compound \(X\) reacts with nitrous acid to form N-methyl-N-nitrosoethanamine. The compound \(\mathrm{X}\) is
1 ethanamine
2 N-methylethanamine
3 N,N-dimethylethanamine
4 dimethylamine
Explanation:
Secondary amines react with nitrous acid to form nitroso derivative. The compound \(\mathrm{X}\) is N-methylethanamine.
CHXII13:AMINES
324207
An amine on reaction with \(\mathrm{HNO}_{2}\) evolved \(\mathrm{N}_{2}\). The amine on exhaustive methylation with \(\mathrm{CH}_{3} \mathrm{I}\) formed a quaternary salt containing \(59.07 \%\) iodine. The molecular mass of amine is ____.
1 127
2 135
3 215
4 230
Explanation:
Evolution of \(\mathrm{N}_{2}\) with \(\mathrm{HNO}_{2}\), suggests that \(1^{\circ}\) amine \(59.07 \mathrm{gm}\) of (I) is present in \(100\,\,{\rm{gm}}\) of compound \(127\,\,{\rm{gm}}\) of \(\mathrm{I}(1 \mathrm{~mol})\) is present in \(\dfrac{100 \times 127}{59.07}=215\) Molecular mass \(=215\)
CHXII13:AMINES
324208
The amine, which reacts with p-toluenesulphonyl chloride to give a clear solution, which on acidification gives insoluble compound is
\(1^{\circ}, 2^{\circ}\) and \(3^{\circ}\) amines can be distinguished from each other by \(\mathrm{p}\)-toluenesulphonyl chloride (Hinsberg reagent) \(1^{\circ}\) amine on sulphonation gives a product, which is insoluble in acid. \(2^{\circ}\) amine on sulphonation gives same product but is soluble in acid. \(3^{\circ}\) amine does not undergo this reaction.
324204
\({\rm{\;}}{{\rm{N}}_{\rm{2}}}\) gas will not be evolved upon reaction of \({\rm{HN}}{{\rm{O}}_{\rm{2}}}\) with which of the following amines?
1 \(1^{\circ}\)
2 \(2^{\circ}\)
3 \(3^{\circ}\)
4 Both (b) and (c)
Explanation:
Only \(1^{\circ}\) amines evolve nitrogen when reacts with nitrous acid \({\text{HN}}{{\text{O}}_{\text{2}}}\)
CHXII13:AMINES
324205
Which among the following reagents is used to distinguish primary, secondary and tertiary amines according to solubility in alkaline medium?
1 Benzenesulphonyl chloride
2 Iodoform
3 Ethylene glycol
4 Acetyl chloride
Explanation:
Benzenesulphonyl chloride \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{Cl}\right)\), (Hinsberg reagent) is used to distinguish primary, secondary and tertiary amines. The reaction of benzenesulphonyl chloride with primary amine yields \(\mathrm{N}\)-alkylbenzene sulphonamide which is soluble in alkali. \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{Cl}+\mathrm{RNH}_{2} \rightarrow \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{NHR}\) (Soluble in alkali due to presence of acidic hydrogen atom attached to nitrogen atom. With secondary amine, it yields N, N dialkylbenzene sulphonamide which is insoluble in alkali. \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{Cl}+\mathrm{R}_{2} \mathrm{NH} \rightarrow \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{NR}_{2}\) (Insoluble in alkali due to absence hydrogen atom attached to nitrogen atom. Tertiary amines do not react with benzenesulphonyl chloride. \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{Cl},+\mathrm{R}_{3} \mathrm{~N} \rightarrow\) No reaction.
MHTCET - 2022
CHXII13:AMINES
324206
An organic compound \(X\) reacts with nitrous acid to form N-methyl-N-nitrosoethanamine. The compound \(\mathrm{X}\) is
1 ethanamine
2 N-methylethanamine
3 N,N-dimethylethanamine
4 dimethylamine
Explanation:
Secondary amines react with nitrous acid to form nitroso derivative. The compound \(\mathrm{X}\) is N-methylethanamine.
CHXII13:AMINES
324207
An amine on reaction with \(\mathrm{HNO}_{2}\) evolved \(\mathrm{N}_{2}\). The amine on exhaustive methylation with \(\mathrm{CH}_{3} \mathrm{I}\) formed a quaternary salt containing \(59.07 \%\) iodine. The molecular mass of amine is ____.
1 127
2 135
3 215
4 230
Explanation:
Evolution of \(\mathrm{N}_{2}\) with \(\mathrm{HNO}_{2}\), suggests that \(1^{\circ}\) amine \(59.07 \mathrm{gm}\) of (I) is present in \(100\,\,{\rm{gm}}\) of compound \(127\,\,{\rm{gm}}\) of \(\mathrm{I}(1 \mathrm{~mol})\) is present in \(\dfrac{100 \times 127}{59.07}=215\) Molecular mass \(=215\)
CHXII13:AMINES
324208
The amine, which reacts with p-toluenesulphonyl chloride to give a clear solution, which on acidification gives insoluble compound is
\(1^{\circ}, 2^{\circ}\) and \(3^{\circ}\) amines can be distinguished from each other by \(\mathrm{p}\)-toluenesulphonyl chloride (Hinsberg reagent) \(1^{\circ}\) amine on sulphonation gives a product, which is insoluble in acid. \(2^{\circ}\) amine on sulphonation gives same product but is soluble in acid. \(3^{\circ}\) amine does not undergo this reaction.
