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CHXII13:AMINES

324204 $N_{2}$ gas will not be evolved upon reaction of $H N O_{2}$ with which of the following amines?

1

1^{\circ}

2

2^{\circ}

3

3^{\circ}

4 Both (b) and (c)

Explanation:

Only $1^{\circ}$ amines evolve nitrogen when reacts with nitrous acid $HN O_{2}$
supporting img

CHXII13:AMINES

324205 Which among the following reagents is used to distinguish primary, secondary and tertiary amines according to solubility in alkaline medium?

1 Benzenesulphonyl chloride

2 Iodoform

3 Ethylene glycol

4 Acetyl chloride

Explanation:

Benzenesulphonyl chloride $(C_{6} H_{5} {SO}_{2} Cl)$ , (Hinsberg reagent) is used to distinguish primary, secondary and tertiary amines.
The reaction of benzenesulphonyl chloride with primary amine yields $N$ -alkylbenzene sulphonamide which is soluble in alkali.
$C_{6} H_{5} {SO}_{2} Cl + {RNH}_{2} \to C_{6} H_{5} {SO}_{2} NHR$
(Soluble in alkali due to presence of acidic hydrogen atom attached to nitrogen atom.
With secondary amine, it yields N, N dialkylbenzene sulphonamide which is insoluble in alkali.
$C_{6} H_{5} {SO}_{2} Cl + R_{2} NH \to C_{6} H_{5} {SO}_{2} {NR}_{2}$
(Insoluble in alkali due to absence hydrogen atom attached to nitrogen atom.
Tertiary amines do not react with benzenesulphonyl chloride.
$C_{6} H_{5} {SO}_{2} Cl, + R_{3} N \to$ No reaction.

MHTCET - 2022

CHXII13:AMINES

324206 An organic compound $X$ reacts with nitrous acid to form N-methyl-N-nitrosoethanamine. The compound $X$ is

1 ethanamine

2 N-methylethanamine

3 N,N-dimethylethanamine

4 dimethylamine

Explanation:

Secondary amines react with nitrous acid to form nitroso derivative. The compound $X$ is N-methylethanamine.

CHXII13:AMINES

324207 An amine on reaction with ${HNO}_{2}$ evolved $N_{2}$ . The amine on exhaustive methylation with ${CH}_{3} I$ formed a quaternary salt containing $59.07 %$ iodine. The molecular mass of amine is ____.

1 127

2 135

3 215

4 230

Explanation:

Evolution of $N_{2}$ with ${HNO}_{2}$ , suggests that $1^{\circ}$ amine $59.07 gm$ of (I) is present in $100 g m$ of compound
$127 g m$ of $I (1 mol)$ is present in $\frac{100 \times 127}{59.07} = 215$
Molecular mass $= 215$

CHXII13:AMINES

324208 The amine, which reacts with p-toluenesulphonyl chloride to give a clear solution, which on acidification gives insoluble compound is

1

C_{2} H_{5} {NH}_{2}

2

{(C_{2} H_{5})}_{2} NH

3

{(C_{2} H_{5})}_{3} N

4

{CH}_{3} {NHC}_{2} H_{5}

Explanation:

$1^{\circ}, 2^{\circ}$ and $3^{\circ}$ amines can be distinguished from each other by $p$ -toluenesulphonyl chloride (Hinsberg reagent)
$1^{\circ}$ amine on sulphonation gives a product, which is insoluble in acid.
$2^{\circ}$ amine on sulphonation gives same product but is soluble in acid.
$3^{\circ}$ amine does not undergo this reaction.
supporting img

MHTCET - 2017

CHXII13:AMINES

324204 $N_{2}$ gas will not be evolved upon reaction of $H N O_{2}$ with which of the following amines?

1

1^{\circ}

2

2^{\circ}

3

3^{\circ}

4 Both (b) and (c)

Explanation:

Only $1^{\circ}$ amines evolve nitrogen when reacts with nitrous acid $HN O_{2}$
supporting img

CHXII13:AMINES

324205 Which among the following reagents is used to distinguish primary, secondary and tertiary amines according to solubility in alkaline medium?

1 Benzenesulphonyl chloride

2 Iodoform

3 Ethylene glycol

4 Acetyl chloride

Explanation:

Benzenesulphonyl chloride $(C_{6} H_{5} {SO}_{2} Cl)$ , (Hinsberg reagent) is used to distinguish primary, secondary and tertiary amines.
The reaction of benzenesulphonyl chloride with primary amine yields $N$ -alkylbenzene sulphonamide which is soluble in alkali.
$C_{6} H_{5} {SO}_{2} Cl + {RNH}_{2} \to C_{6} H_{5} {SO}_{2} NHR$
(Soluble in alkali due to presence of acidic hydrogen atom attached to nitrogen atom.
With secondary amine, it yields N, N dialkylbenzene sulphonamide which is insoluble in alkali.
$C_{6} H_{5} {SO}_{2} Cl + R_{2} NH \to C_{6} H_{5} {SO}_{2} {NR}_{2}$
(Insoluble in alkali due to absence hydrogen atom attached to nitrogen atom.
Tertiary amines do not react with benzenesulphonyl chloride.
$C_{6} H_{5} {SO}_{2} Cl, + R_{3} N \to$ No reaction.

MHTCET - 2022

CHXII13:AMINES

324206 An organic compound $X$ reacts with nitrous acid to form N-methyl-N-nitrosoethanamine. The compound $X$ is

1 ethanamine

2 N-methylethanamine

3 N,N-dimethylethanamine

4 dimethylamine

Explanation:

Secondary amines react with nitrous acid to form nitroso derivative. The compound $X$ is N-methylethanamine.

CHXII13:AMINES

324207 An amine on reaction with ${HNO}_{2}$ evolved $N_{2}$ . The amine on exhaustive methylation with ${CH}_{3} I$ formed a quaternary salt containing $59.07 %$ iodine. The molecular mass of amine is ____.

1 127

2 135

3 215

4 230

Explanation:

Evolution of $N_{2}$ with ${HNO}_{2}$ , suggests that $1^{\circ}$ amine $59.07 gm$ of (I) is present in $100 g m$ of compound
$127 g m$ of $I (1 mol)$ is present in $\frac{100 \times 127}{59.07} = 215$
Molecular mass $= 215$

CHXII13:AMINES

324208 The amine, which reacts with p-toluenesulphonyl chloride to give a clear solution, which on acidification gives insoluble compound is

1

C_{2} H_{5} {NH}_{2}

2

{(C_{2} H_{5})}_{2} NH

3

{(C_{2} H_{5})}_{3} N

4

{CH}_{3} {NHC}_{2} H_{5}

Explanation:

$1^{\circ}, 2^{\circ}$ and $3^{\circ}$ amines can be distinguished from each other by $p$ -toluenesulphonyl chloride (Hinsberg reagent)
$1^{\circ}$ amine on sulphonation gives a product, which is insoluble in acid.
$2^{\circ}$ amine on sulphonation gives same product but is soluble in acid.
$3^{\circ}$ amine does not undergo this reaction.
supporting img

MHTCET - 2017

CHXII13:AMINES

324204 $N_{2}$ gas will not be evolved upon reaction of $H N O_{2}$ with which of the following amines?

1

1^{\circ}

2

2^{\circ}

3

3^{\circ}

4 Both (b) and (c)

Explanation:

Only $1^{\circ}$ amines evolve nitrogen when reacts with nitrous acid $HN O_{2}$
supporting img

CHXII13:AMINES

324205 Which among the following reagents is used to distinguish primary, secondary and tertiary amines according to solubility in alkaline medium?

1 Benzenesulphonyl chloride

2 Iodoform

3 Ethylene glycol

4 Acetyl chloride

Explanation:

Benzenesulphonyl chloride $(C_{6} H_{5} {SO}_{2} Cl)$ , (Hinsberg reagent) is used to distinguish primary, secondary and tertiary amines.
The reaction of benzenesulphonyl chloride with primary amine yields $N$ -alkylbenzene sulphonamide which is soluble in alkali.
$C_{6} H_{5} {SO}_{2} Cl + {RNH}_{2} \to C_{6} H_{5} {SO}_{2} NHR$
(Soluble in alkali due to presence of acidic hydrogen atom attached to nitrogen atom.
With secondary amine, it yields N, N dialkylbenzene sulphonamide which is insoluble in alkali.
$C_{6} H_{5} {SO}_{2} Cl + R_{2} NH \to C_{6} H_{5} {SO}_{2} {NR}_{2}$
(Insoluble in alkali due to absence hydrogen atom attached to nitrogen atom.
Tertiary amines do not react with benzenesulphonyl chloride.
$C_{6} H_{5} {SO}_{2} Cl, + R_{3} N \to$ No reaction.

MHTCET - 2022

CHXII13:AMINES

324206 An organic compound $X$ reacts with nitrous acid to form N-methyl-N-nitrosoethanamine. The compound $X$ is

1 ethanamine

2 N-methylethanamine

3 N,N-dimethylethanamine

4 dimethylamine

Explanation:

Secondary amines react with nitrous acid to form nitroso derivative. The compound $X$ is N-methylethanamine.

CHXII13:AMINES

324207 An amine on reaction with ${HNO}_{2}$ evolved $N_{2}$ . The amine on exhaustive methylation with ${CH}_{3} I$ formed a quaternary salt containing $59.07 %$ iodine. The molecular mass of amine is ____.

1 127

2 135

3 215

4 230

Explanation:

Evolution of $N_{2}$ with ${HNO}_{2}$ , suggests that $1^{\circ}$ amine $59.07 gm$ of (I) is present in $100 g m$ of compound
$127 g m$ of $I (1 mol)$ is present in $\frac{100 \times 127}{59.07} = 215$
Molecular mass $= 215$

CHXII13:AMINES

324208 The amine, which reacts with p-toluenesulphonyl chloride to give a clear solution, which on acidification gives insoluble compound is

1

C_{2} H_{5} {NH}_{2}

2

{(C_{2} H_{5})}_{2} NH

3

{(C_{2} H_{5})}_{3} N

4

{CH}_{3} {NHC}_{2} H_{5}

Explanation:

$1^{\circ}, 2^{\circ}$ and $3^{\circ}$ amines can be distinguished from each other by $p$ -toluenesulphonyl chloride (Hinsberg reagent)
$1^{\circ}$ amine on sulphonation gives a product, which is insoluble in acid.
$2^{\circ}$ amine on sulphonation gives same product but is soluble in acid.
$3^{\circ}$ amine does not undergo this reaction.
supporting img

MHTCET - 2017

CHXII13:AMINES

324204 $N_{2}$ gas will not be evolved upon reaction of $H N O_{2}$ with which of the following amines?

1

1^{\circ}

2

2^{\circ}

3

3^{\circ}

4 Both (b) and (c)

Explanation:

Only $1^{\circ}$ amines evolve nitrogen when reacts with nitrous acid $HN O_{2}$
supporting img

CHXII13:AMINES

324205 Which among the following reagents is used to distinguish primary, secondary and tertiary amines according to solubility in alkaline medium?

1 Benzenesulphonyl chloride

2 Iodoform

3 Ethylene glycol

4 Acetyl chloride

Explanation:

Benzenesulphonyl chloride $(C_{6} H_{5} {SO}_{2} Cl)$ , (Hinsberg reagent) is used to distinguish primary, secondary and tertiary amines.
The reaction of benzenesulphonyl chloride with primary amine yields $N$ -alkylbenzene sulphonamide which is soluble in alkali.
$C_{6} H_{5} {SO}_{2} Cl + {RNH}_{2} \to C_{6} H_{5} {SO}_{2} NHR$
(Soluble in alkali due to presence of acidic hydrogen atom attached to nitrogen atom.
With secondary amine, it yields N, N dialkylbenzene sulphonamide which is insoluble in alkali.
$C_{6} H_{5} {SO}_{2} Cl + R_{2} NH \to C_{6} H_{5} {SO}_{2} {NR}_{2}$
(Insoluble in alkali due to absence hydrogen atom attached to nitrogen atom.
Tertiary amines do not react with benzenesulphonyl chloride.
$C_{6} H_{5} {SO}_{2} Cl, + R_{3} N \to$ No reaction.

MHTCET - 2022

CHXII13:AMINES

324206 An organic compound $X$ reacts with nitrous acid to form N-methyl-N-nitrosoethanamine. The compound $X$ is

1 ethanamine

2 N-methylethanamine

3 N,N-dimethylethanamine

4 dimethylamine

Explanation:

Secondary amines react with nitrous acid to form nitroso derivative. The compound $X$ is N-methylethanamine.

CHXII13:AMINES

324207 An amine on reaction with ${HNO}_{2}$ evolved $N_{2}$ . The amine on exhaustive methylation with ${CH}_{3} I$ formed a quaternary salt containing $59.07 %$ iodine. The molecular mass of amine is ____.

1 127

2 135

3 215

4 230

Explanation:

Evolution of $N_{2}$ with ${HNO}_{2}$ , suggests that $1^{\circ}$ amine $59.07 gm$ of (I) is present in $100 g m$ of compound
$127 g m$ of $I (1 mol)$ is present in $\frac{100 \times 127}{59.07} = 215$
Molecular mass $= 215$

CHXII13:AMINES

324208 The amine, which reacts with p-toluenesulphonyl chloride to give a clear solution, which on acidification gives insoluble compound is

1

C_{2} H_{5} {NH}_{2}

2

{(C_{2} H_{5})}_{2} NH

3

{(C_{2} H_{5})}_{3} N

4

{CH}_{3} {NHC}_{2} H_{5}

Explanation:

$1^{\circ}, 2^{\circ}$ and $3^{\circ}$ amines can be distinguished from each other by $p$ -toluenesulphonyl chloride (Hinsberg reagent)
$1^{\circ}$ amine on sulphonation gives a product, which is insoluble in acid.
$2^{\circ}$ amine on sulphonation gives same product but is soluble in acid.
$3^{\circ}$ amine does not undergo this reaction.
supporting img

MHTCET - 2017

CHXII13:AMINES

324204 $N_{2}$ gas will not be evolved upon reaction of $H N O_{2}$ with which of the following amines?

1

1^{\circ}

2

2^{\circ}

3

3^{\circ}

4 Both (b) and (c)

Explanation:

Only $1^{\circ}$ amines evolve nitrogen when reacts with nitrous acid $HN O_{2}$
supporting img

CHXII13:AMINES

324205 Which among the following reagents is used to distinguish primary, secondary and tertiary amines according to solubility in alkaline medium?

1 Benzenesulphonyl chloride

2 Iodoform

3 Ethylene glycol

4 Acetyl chloride

Explanation:

Benzenesulphonyl chloride $(C_{6} H_{5} {SO}_{2} Cl)$ , (Hinsberg reagent) is used to distinguish primary, secondary and tertiary amines.
The reaction of benzenesulphonyl chloride with primary amine yields $N$ -alkylbenzene sulphonamide which is soluble in alkali.
$C_{6} H_{5} {SO}_{2} Cl + {RNH}_{2} \to C_{6} H_{5} {SO}_{2} NHR$
(Soluble in alkali due to presence of acidic hydrogen atom attached to nitrogen atom.
With secondary amine, it yields N, N dialkylbenzene sulphonamide which is insoluble in alkali.
$C_{6} H_{5} {SO}_{2} Cl + R_{2} NH \to C_{6} H_{5} {SO}_{2} {NR}_{2}$
(Insoluble in alkali due to absence hydrogen atom attached to nitrogen atom.
Tertiary amines do not react with benzenesulphonyl chloride.
$C_{6} H_{5} {SO}_{2} Cl, + R_{3} N \to$ No reaction.

MHTCET - 2022

CHXII13:AMINES

324206 An organic compound $X$ reacts with nitrous acid to form N-methyl-N-nitrosoethanamine. The compound $X$ is

1 ethanamine

2 N-methylethanamine

3 N,N-dimethylethanamine

4 dimethylamine

Explanation:

Secondary amines react with nitrous acid to form nitroso derivative. The compound $X$ is N-methylethanamine.

CHXII13:AMINES

324207 An amine on reaction with ${HNO}_{2}$ evolved $N_{2}$ . The amine on exhaustive methylation with ${CH}_{3} I$ formed a quaternary salt containing $59.07 %$ iodine. The molecular mass of amine is ____.

1 127

2 135

3 215

4 230

Explanation:

Evolution of $N_{2}$ with ${HNO}_{2}$ , suggests that $1^{\circ}$ amine $59.07 gm$ of (I) is present in $100 g m$ of compound
$127 g m$ of $I (1 mol)$ is present in $\frac{100 \times 127}{59.07} = 215$
Molecular mass $= 215$

CHXII13:AMINES

324208 The amine, which reacts with p-toluenesulphonyl chloride to give a clear solution, which on acidification gives insoluble compound is

1

C_{2} H_{5} {NH}_{2}

2

{(C_{2} H_{5})}_{2} NH

3

{(C_{2} H_{5})}_{3} N

4

{CH}_{3} {NHC}_{2} H_{5}

Explanation:

$1^{\circ}, 2^{\circ}$ and $3^{\circ}$ amines can be distinguished from each other by $p$ -toluenesulphonyl chloride (Hinsberg reagent)
$1^{\circ}$ amine on sulphonation gives a product, which is insoluble in acid.
$2^{\circ}$ amine on sulphonation gives same product but is soluble in acid.
$3^{\circ}$ amine does not undergo this reaction.
supporting img

MHTCET - 2017