323793 \(X\) is sodium salt of an acid. When it is heated with soda lime gives ethane. The acid is

323794 Which of the following compounds undergoes readily decarboxylation on warming?

323795 Which of the following reduces carboxylic acid directly to primary alcohols?

323796 In the reaction,
\({\text{C}}{{\text{H}}_{\text{3}}}{\text{COOH}}\xrightarrow{{{\text{LiAl}}{{\text{H}}_{\text{4}}}}}{\text{A}}\xrightarrow{{{\text{PC}}{{\text{l}}_{\text{5}}}}}{\text{B}}\xrightarrow{{{\text{alc}}{\text{.KOH}}}}{\text{C}}\)
The product \(\mathrm{C}\) is

323793 \(X\) is sodium salt of an acid. When it is heated with soda lime gives ethane. The acid is

323794 Which of the following compounds undergoes readily decarboxylation on warming?

323795 Which of the following reduces carboxylic acid directly to primary alcohols?

323796 In the reaction,
\({\text{C}}{{\text{H}}_{\text{3}}}{\text{COOH}}\xrightarrow{{{\text{LiAl}}{{\text{H}}_{\text{4}}}}}{\text{A}}\xrightarrow{{{\text{PC}}{{\text{l}}_{\text{5}}}}}{\text{B}}\xrightarrow{{{\text{alc}}{\text{.KOH}}}}{\text{C}}\)
The product \(\mathrm{C}\) is

323793 \(X\) is sodium salt of an acid. When it is heated with soda lime gives ethane. The acid is

323794 Which of the following compounds undergoes readily decarboxylation on warming?

323795 Which of the following reduces carboxylic acid directly to primary alcohols?

323796 In the reaction,
\({\text{C}}{{\text{H}}_{\text{3}}}{\text{COOH}}\xrightarrow{{{\text{LiAl}}{{\text{H}}_{\text{4}}}}}{\text{A}}\xrightarrow{{{\text{PC}}{{\text{l}}_{\text{5}}}}}{\text{B}}\xrightarrow{{{\text{alc}}{\text{.KOH}}}}{\text{C}}\)
The product \(\mathrm{C}\) is

323793 \(X\) is sodium salt of an acid. When it is heated with soda lime gives ethane. The acid is

323794 Which of the following compounds undergoes readily decarboxylation on warming?

323795 Which of the following reduces carboxylic acid directly to primary alcohols?

323796 In the reaction,
\({\text{C}}{{\text{H}}_{\text{3}}}{\text{COOH}}\xrightarrow{{{\text{LiAl}}{{\text{H}}_{\text{4}}}}}{\text{A}}\xrightarrow{{{\text{PC}}{{\text{l}}_{\text{5}}}}}{\text{B}}\xrightarrow{{{\text{alc}}{\text{.KOH}}}}{\text{C}}\)
The product \(\mathrm{C}\) is