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CHXII09:COORDINATION COMPOUNDS

322260 In Wilkinson's catalyst, the hybridization of central metal ion and its shape are respectively:

1

s p^{3} d

, trigonal bipyramidal

2

d^{2} s p^{3}

, octahedral

3

ds p^{2}

, square planar

4

s p^{3}

, tetrahedral

Explanation:

Wilkinson catalyst
$[RhCl {({PPh}_{3})}_{3}]$

JEE - 2018

CHXII09:COORDINATION COMPOUNDS

322261 Which of the following statements are true about ${[{CoF}_{6}]}^{3 -}$ ion?
(I) The complex has octahedral geometry.
(II) Coordination number of Co is 3 and oxidation state is +6 .
(III) The complex is ${sp}^{3} d^{2}$ hybridised
(IV) It is a high spin complex

1 I, II and IV

2 I, III and IV

3 II and IV

4 II, III and IV

KCET - 2024

CHXII09:COORDINATION COMPOUNDS

322262 The spin only magnetic moment of ${[{MnBr}_{4}]}^{2 -}$ is $5.9 BM$ . The geometry of this complex ion is

1 Tetrahedral

2 Octahedral

3 Trigonal pyramidal

4 Square planar

Explanation:

Since, the coordination number of ${Mn}^{2 +}$ ion in the complex ion is 4 , it will have either tetrahedral ( ${sp}^{3}$ - hybridisation) or square planar ( ${dsp}^{2}$ - hybridisation) geometry. But the fact that the magnetic moment of the complex ion is 5.9BM suggests that it should have tetrahedral geometry rather than square planar because of the presence of five unpaired electrons in the d- orbitals.

AIIMS - 2018

CHXII09:COORDINATION COMPOUNDS

322263 Which of the following is correct for the Zeise's salt?

1 The complex ion is square planar.

2 The central metal ion, platinum is in +II oxidation state.

3

H_{2} C = {CH}_{2}

molecule is perpendicular to the

{PtCl}_{3}

plane

4 All of these are correct statements

Explanation:

In Zeise's salt structure, ethylene molecule occupies the fourth coordination site of the square planar complex. $C = C$ bond is perpendicular to the platinum ligand plane.
supporting img
Here ' $Pt$ ' is in +2 oxidation state and the complex is square planar.

CHXII09:COORDINATION COMPOUNDS

322260 In Wilkinson's catalyst, the hybridization of central metal ion and its shape are respectively:

1

s p^{3} d

, trigonal bipyramidal

2

d^{2} s p^{3}

, octahedral

3

ds p^{2}

, square planar

4

s p^{3}

, tetrahedral

Explanation:

Wilkinson catalyst
$[RhCl {({PPh}_{3})}_{3}]$

JEE - 2018

CHXII09:COORDINATION COMPOUNDS

322261 Which of the following statements are true about ${[{CoF}_{6}]}^{3 -}$ ion?
(I) The complex has octahedral geometry.
(II) Coordination number of Co is 3 and oxidation state is +6 .
(III) The complex is ${sp}^{3} d^{2}$ hybridised
(IV) It is a high spin complex

1 I, II and IV

2 I, III and IV

3 II and IV

4 II, III and IV

KCET - 2024

CHXII09:COORDINATION COMPOUNDS

322262 The spin only magnetic moment of ${[{MnBr}_{4}]}^{2 -}$ is $5.9 BM$ . The geometry of this complex ion is

1 Tetrahedral

2 Octahedral

3 Trigonal pyramidal

4 Square planar

Explanation:

Since, the coordination number of ${Mn}^{2 +}$ ion in the complex ion is 4 , it will have either tetrahedral ( ${sp}^{3}$ - hybridisation) or square planar ( ${dsp}^{2}$ - hybridisation) geometry. But the fact that the magnetic moment of the complex ion is 5.9BM suggests that it should have tetrahedral geometry rather than square planar because of the presence of five unpaired electrons in the d- orbitals.

AIIMS - 2018

CHXII09:COORDINATION COMPOUNDS

322263 Which of the following is correct for the Zeise's salt?

1 The complex ion is square planar.

2 The central metal ion, platinum is in +II oxidation state.

3

H_{2} C = {CH}_{2}

molecule is perpendicular to the

{PtCl}_{3}

plane

4 All of these are correct statements

Explanation:

In Zeise's salt structure, ethylene molecule occupies the fourth coordination site of the square planar complex. $C = C$ bond is perpendicular to the platinum ligand plane.
supporting img
Here ' $Pt$ ' is in +2 oxidation state and the complex is square planar.

CHXII09:COORDINATION COMPOUNDS

322260 In Wilkinson's catalyst, the hybridization of central metal ion and its shape are respectively:

1

s p^{3} d

, trigonal bipyramidal

2

d^{2} s p^{3}

, octahedral

3

ds p^{2}

, square planar

4

s p^{3}

, tetrahedral

Explanation:

Wilkinson catalyst
$[RhCl {({PPh}_{3})}_{3}]$

JEE - 2018

CHXII09:COORDINATION COMPOUNDS

322261 Which of the following statements are true about ${[{CoF}_{6}]}^{3 -}$ ion?
(I) The complex has octahedral geometry.
(II) Coordination number of Co is 3 and oxidation state is +6 .
(III) The complex is ${sp}^{3} d^{2}$ hybridised
(IV) It is a high spin complex

1 I, II and IV

2 I, III and IV

3 II and IV

4 II, III and IV

KCET - 2024

CHXII09:COORDINATION COMPOUNDS

322262 The spin only magnetic moment of ${[{MnBr}_{4}]}^{2 -}$ is $5.9 BM$ . The geometry of this complex ion is

1 Tetrahedral

2 Octahedral

3 Trigonal pyramidal

4 Square planar

Explanation:

Since, the coordination number of ${Mn}^{2 +}$ ion in the complex ion is 4 , it will have either tetrahedral ( ${sp}^{3}$ - hybridisation) or square planar ( ${dsp}^{2}$ - hybridisation) geometry. But the fact that the magnetic moment of the complex ion is 5.9BM suggests that it should have tetrahedral geometry rather than square planar because of the presence of five unpaired electrons in the d- orbitals.

AIIMS - 2018

CHXII09:COORDINATION COMPOUNDS

322263 Which of the following is correct for the Zeise's salt?

1 The complex ion is square planar.

2 The central metal ion, platinum is in +II oxidation state.

3

H_{2} C = {CH}_{2}

molecule is perpendicular to the

{PtCl}_{3}

plane

4 All of these are correct statements

Explanation:

In Zeise's salt structure, ethylene molecule occupies the fourth coordination site of the square planar complex. $C = C$ bond is perpendicular to the platinum ligand plane.
supporting img
Here ' $Pt$ ' is in +2 oxidation state and the complex is square planar.

CHXII09:COORDINATION COMPOUNDS

322260 In Wilkinson's catalyst, the hybridization of central metal ion and its shape are respectively:

1

s p^{3} d

, trigonal bipyramidal

2

d^{2} s p^{3}

, octahedral

3

ds p^{2}

, square planar

4

s p^{3}

, tetrahedral

Explanation:

Wilkinson catalyst
$[RhCl {({PPh}_{3})}_{3}]$

JEE - 2018

CHXII09:COORDINATION COMPOUNDS

322261 Which of the following statements are true about ${[{CoF}_{6}]}^{3 -}$ ion?
(I) The complex has octahedral geometry.
(II) Coordination number of Co is 3 and oxidation state is +6 .
(III) The complex is ${sp}^{3} d^{2}$ hybridised
(IV) It is a high spin complex

1 I, II and IV

2 I, III and IV

3 II and IV

4 II, III and IV

KCET - 2024

CHXII09:COORDINATION COMPOUNDS

322262 The spin only magnetic moment of ${[{MnBr}_{4}]}^{2 -}$ is $5.9 BM$ . The geometry of this complex ion is

1 Tetrahedral

2 Octahedral

3 Trigonal pyramidal

4 Square planar

Explanation:

Since, the coordination number of ${Mn}^{2 +}$ ion in the complex ion is 4 , it will have either tetrahedral ( ${sp}^{3}$ - hybridisation) or square planar ( ${dsp}^{2}$ - hybridisation) geometry. But the fact that the magnetic moment of the complex ion is 5.9BM suggests that it should have tetrahedral geometry rather than square planar because of the presence of five unpaired electrons in the d- orbitals.

AIIMS - 2018

CHXII09:COORDINATION COMPOUNDS

322263 Which of the following is correct for the Zeise's salt?

1 The complex ion is square planar.

2 The central metal ion, platinum is in +II oxidation state.

3

H_{2} C = {CH}_{2}

molecule is perpendicular to the

{PtCl}_{3}

plane

4 All of these are correct statements

Explanation:

In Zeise's salt structure, ethylene molecule occupies the fourth coordination site of the square planar complex. $C = C$ bond is perpendicular to the platinum ligand plane.
supporting img
Here ' $Pt$ ' is in +2 oxidation state and the complex is square planar.