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CHXII09:COORDINATION COMPOUNDS

322243 What is the number of unpaired electrons of nickel observed in ${[Ni (CN)_{4}]}^{2 -}$ ?

1 zero

2 2

3 6

4 4

Explanation:

${CN}^{-}$ is strong field ligand, so $e^{-}$ pair up (Low spin complex)
supporting img

Hence the number of unpaired electrons in $Ni$ in ${[Ni (CN)_{4}]}^{2 -}$ is zero.

MHTCET - 2022

CHXII09:COORDINATION COMPOUNDS

322244 Match Column I and II:
Column I
Column II
A
Tetrahedral
P
${[Ni(CN)_{4}]}^{2 -}$
B
Octahedral
Q
${[Ag {(N H_{3})}_{2}]}^{+}$
C
Square planar
R
$[Fe {(CO)}_{5}]$
D
Trigonal bipyramidal
S
${[Cr {(en)}_{2} C l_{2}]}^{+}$
E
Linear
T
${[NiC l_{4}]}^{2 -}$

1

A - T, B - S, C - R, D - Q, E - P

2

A - S, B - R, C - Q, D - T, E - P

3

A - T, B - S, C - P, D - R, E - Q

4

A - T, B - S, C - Q, D - R, E - P

Explanation:

${[Ni (CN)_{4}]}^{2 -} - {dsp}^{2}$ - square planar
${[Ag {({NH}_{3})}_{2}]}^{+}$ - sp - linear
$[Fe (CO)_{5}] - {dsp}^{3}$ - trigonal bipyramidal
${[Cr (en)_{2} {Cl}_{2}]}^{+} - d^{2} {sp}^{3}$ - octahedral
${[{NiCl}_{4}]}^{2 -} - {sp}^{3} -$ tetrahedral

CHXII09:COORDINATION COMPOUNDS

322245 Arrange the following in order of decreasing number of unpaired electrons?
A. ${[Fe {(H_{2} O)}_{6}]}^{2 +}$
B. ${[Fe (CN)_{6}]}^{- 3}$
C. ${[Fe (CN)_{6}]}^{4 -}$
D. ${[Fe {(H_{2} O)}_{6}]}^{3 +}$

1 D, A, B, C

2 A, B, C, D

3 C, B, A, D

4 B, C, A, D

Explanation:

(A) ${[Fe {(H_{2} O)}_{6}]}^{2 +}, 3 d^{6}$
$t_{2} g^{4} {eg}^{2}$ (weak field ligand) (4 unpaired ${\bar{e}}^{-})$
(B) ${[Fe (CN)_{6}]}^{3 -}, 3 d^{5}$ (strong field ligand)
$t_{2} \overset{5}{g} (1$ unpaired $\overset{―}{e})$
(C) ${[Fe (CN)_{6}]}^{4 -}, 3 d^{6}$ (strong field ligand)
$t_{2} g^{6} {eg}^{0}$ (zero unpaired ${\bar{e}}^{-}$ )
(D) ${[Fe {(H_{2} O)}_{6}]}^{3 +}, 3 d^{5}$ (weak field ligand)
$t_{2} \overset{3}{g} {eg}_{g}$ (5 unpaired $\overset{―}{e}$ )

CHXII09:COORDINATION COMPOUNDS

322246 $d s p^{2}$ -hybridisation is found in

1

{[Co {({NH}_{3})}_{2}]}^{2 +}

2

{[{NiCl}_{4}]}^{2 -}

3

{[Co {({NH}_{3})}_{6}]}^{3 +}

4

{[{PtCl}_{4}]}^{2 -}

Explanation:

${[{PtCl}_{4}]}^{2 -}$ involves $ds p^{2}$ hybridisation.

CHXII09:COORDINATION COMPOUNDS

322243 What is the number of unpaired electrons of nickel observed in ${[Ni (CN)_{4}]}^{2 -}$ ?

1 zero

2 2

3 6

4 4

Explanation:

${CN}^{-}$ is strong field ligand, so $e^{-}$ pair up (Low spin complex)
supporting img

Hence the number of unpaired electrons in $Ni$ in ${[Ni (CN)_{4}]}^{2 -}$ is zero.

MHTCET - 2022

CHXII09:COORDINATION COMPOUNDS

322244 Match Column I and II:
Column I
Column II
A
Tetrahedral
P
${[Ni(CN)_{4}]}^{2 -}$
B
Octahedral
Q
${[Ag {(N H_{3})}_{2}]}^{+}$
C
Square planar
R
$[Fe {(CO)}_{5}]$
D
Trigonal bipyramidal
S
${[Cr {(en)}_{2} C l_{2}]}^{+}$
E
Linear
T
${[NiC l_{4}]}^{2 -}$

1

A - T, B - S, C - R, D - Q, E - P

2

A - S, B - R, C - Q, D - T, E - P

3

A - T, B - S, C - P, D - R, E - Q

4

A - T, B - S, C - Q, D - R, E - P

Explanation:

${[Ni (CN)_{4}]}^{2 -} - {dsp}^{2}$ - square planar
${[Ag {({NH}_{3})}_{2}]}^{+}$ - sp - linear
$[Fe (CO)_{5}] - {dsp}^{3}$ - trigonal bipyramidal
${[Cr (en)_{2} {Cl}_{2}]}^{+} - d^{2} {sp}^{3}$ - octahedral
${[{NiCl}_{4}]}^{2 -} - {sp}^{3} -$ tetrahedral

CHXII09:COORDINATION COMPOUNDS

322245 Arrange the following in order of decreasing number of unpaired electrons?
A. ${[Fe {(H_{2} O)}_{6}]}^{2 +}$
B. ${[Fe (CN)_{6}]}^{- 3}$
C. ${[Fe (CN)_{6}]}^{4 -}$
D. ${[Fe {(H_{2} O)}_{6}]}^{3 +}$

1 D, A, B, C

2 A, B, C, D

3 C, B, A, D

4 B, C, A, D

Explanation:

(A) ${[Fe {(H_{2} O)}_{6}]}^{2 +}, 3 d^{6}$
$t_{2} g^{4} {eg}^{2}$ (weak field ligand) (4 unpaired ${\bar{e}}^{-})$
(B) ${[Fe (CN)_{6}]}^{3 -}, 3 d^{5}$ (strong field ligand)
$t_{2} \overset{5}{g} (1$ unpaired $\overset{―}{e})$
(C) ${[Fe (CN)_{6}]}^{4 -}, 3 d^{6}$ (strong field ligand)
$t_{2} g^{6} {eg}^{0}$ (zero unpaired ${\bar{e}}^{-}$ )
(D) ${[Fe {(H_{2} O)}_{6}]}^{3 +}, 3 d^{5}$ (weak field ligand)
$t_{2} \overset{3}{g} {eg}_{g}$ (5 unpaired $\overset{―}{e}$ )

CHXII09:COORDINATION COMPOUNDS

322246 $d s p^{2}$ -hybridisation is found in

1

{[Co {({NH}_{3})}_{2}]}^{2 +}

2

{[{NiCl}_{4}]}^{2 -}

3

{[Co {({NH}_{3})}_{6}]}^{3 +}

4

{[{PtCl}_{4}]}^{2 -}

Explanation:

${[{PtCl}_{4}]}^{2 -}$ involves $ds p^{2}$ hybridisation.

CHXII09:COORDINATION COMPOUNDS

322243 What is the number of unpaired electrons of nickel observed in ${[Ni (CN)_{4}]}^{2 -}$ ?

1 zero

2 2

3 6

4 4

Explanation:

${CN}^{-}$ is strong field ligand, so $e^{-}$ pair up (Low spin complex)
supporting img

Hence the number of unpaired electrons in $Ni$ in ${[Ni (CN)_{4}]}^{2 -}$ is zero.

MHTCET - 2022

CHXII09:COORDINATION COMPOUNDS

322244 Match Column I and II:
Column I
Column II
A
Tetrahedral
P
${[Ni(CN)_{4}]}^{2 -}$
B
Octahedral
Q
${[Ag {(N H_{3})}_{2}]}^{+}$
C
Square planar
R
$[Fe {(CO)}_{5}]$
D
Trigonal bipyramidal
S
${[Cr {(en)}_{2} C l_{2}]}^{+}$
E
Linear
T
${[NiC l_{4}]}^{2 -}$

1

A - T, B - S, C - R, D - Q, E - P

2

A - S, B - R, C - Q, D - T, E - P

3

A - T, B - S, C - P, D - R, E - Q

4

A - T, B - S, C - Q, D - R, E - P

Explanation:

${[Ni (CN)_{4}]}^{2 -} - {dsp}^{2}$ - square planar
${[Ag {({NH}_{3})}_{2}]}^{+}$ - sp - linear
$[Fe (CO)_{5}] - {dsp}^{3}$ - trigonal bipyramidal
${[Cr (en)_{2} {Cl}_{2}]}^{+} - d^{2} {sp}^{3}$ - octahedral
${[{NiCl}_{4}]}^{2 -} - {sp}^{3} -$ tetrahedral

CHXII09:COORDINATION COMPOUNDS

322245 Arrange the following in order of decreasing number of unpaired electrons?
A. ${[Fe {(H_{2} O)}_{6}]}^{2 +}$
B. ${[Fe (CN)_{6}]}^{- 3}$
C. ${[Fe (CN)_{6}]}^{4 -}$
D. ${[Fe {(H_{2} O)}_{6}]}^{3 +}$

1 D, A, B, C

2 A, B, C, D

3 C, B, A, D

4 B, C, A, D

Explanation:

(A) ${[Fe {(H_{2} O)}_{6}]}^{2 +}, 3 d^{6}$
$t_{2} g^{4} {eg}^{2}$ (weak field ligand) (4 unpaired ${\bar{e}}^{-})$
(B) ${[Fe (CN)_{6}]}^{3 -}, 3 d^{5}$ (strong field ligand)
$t_{2} \overset{5}{g} (1$ unpaired $\overset{―}{e})$
(C) ${[Fe (CN)_{6}]}^{4 -}, 3 d^{6}$ (strong field ligand)
$t_{2} g^{6} {eg}^{0}$ (zero unpaired ${\bar{e}}^{-}$ )
(D) ${[Fe {(H_{2} O)}_{6}]}^{3 +}, 3 d^{5}$ (weak field ligand)
$t_{2} \overset{3}{g} {eg}_{g}$ (5 unpaired $\overset{―}{e}$ )

CHXII09:COORDINATION COMPOUNDS

322246 $d s p^{2}$ -hybridisation is found in

1

{[Co {({NH}_{3})}_{2}]}^{2 +}

2

{[{NiCl}_{4}]}^{2 -}

3

{[Co {({NH}_{3})}_{6}]}^{3 +}

4

{[{PtCl}_{4}]}^{2 -}

Explanation:

${[{PtCl}_{4}]}^{2 -}$ involves $ds p^{2}$ hybridisation.

CHXII09:COORDINATION COMPOUNDS

322243 What is the number of unpaired electrons of nickel observed in ${[Ni (CN)_{4}]}^{2 -}$ ?

1 zero

2 2

3 6

4 4

Explanation:

${CN}^{-}$ is strong field ligand, so $e^{-}$ pair up (Low spin complex)
supporting img

Hence the number of unpaired electrons in $Ni$ in ${[Ni (CN)_{4}]}^{2 -}$ is zero.

MHTCET - 2022

CHXII09:COORDINATION COMPOUNDS

322244 Match Column I and II:
Column I
Column II
A
Tetrahedral
P
${[Ni(CN)_{4}]}^{2 -}$
B
Octahedral
Q
${[Ag {(N H_{3})}_{2}]}^{+}$
C
Square planar
R
$[Fe {(CO)}_{5}]$
D
Trigonal bipyramidal
S
${[Cr {(en)}_{2} C l_{2}]}^{+}$
E
Linear
T
${[NiC l_{4}]}^{2 -}$

1

A - T, B - S, C - R, D - Q, E - P

2

A - S, B - R, C - Q, D - T, E - P

3

A - T, B - S, C - P, D - R, E - Q

4

A - T, B - S, C - Q, D - R, E - P

Explanation:

${[Ni (CN)_{4}]}^{2 -} - {dsp}^{2}$ - square planar
${[Ag {({NH}_{3})}_{2}]}^{+}$ - sp - linear
$[Fe (CO)_{5}] - {dsp}^{3}$ - trigonal bipyramidal
${[Cr (en)_{2} {Cl}_{2}]}^{+} - d^{2} {sp}^{3}$ - octahedral
${[{NiCl}_{4}]}^{2 -} - {sp}^{3} -$ tetrahedral

CHXII09:COORDINATION COMPOUNDS

322245 Arrange the following in order of decreasing number of unpaired electrons?
A. ${[Fe {(H_{2} O)}_{6}]}^{2 +}$
B. ${[Fe (CN)_{6}]}^{- 3}$
C. ${[Fe (CN)_{6}]}^{4 -}$
D. ${[Fe {(H_{2} O)}_{6}]}^{3 +}$

1 D, A, B, C

2 A, B, C, D

3 C, B, A, D

4 B, C, A, D

Explanation:

(A) ${[Fe {(H_{2} O)}_{6}]}^{2 +}, 3 d^{6}$
$t_{2} g^{4} {eg}^{2}$ (weak field ligand) (4 unpaired ${\bar{e}}^{-})$
(B) ${[Fe (CN)_{6}]}^{3 -}, 3 d^{5}$ (strong field ligand)
$t_{2} \overset{5}{g} (1$ unpaired $\overset{―}{e})$
(C) ${[Fe (CN)_{6}]}^{4 -}, 3 d^{6}$ (strong field ligand)
$t_{2} g^{6} {eg}^{0}$ (zero unpaired ${\bar{e}}^{-}$ )
(D) ${[Fe {(H_{2} O)}_{6}]}^{3 +}, 3 d^{5}$ (weak field ligand)
$t_{2} \overset{3}{g} {eg}_{g}$ (5 unpaired $\overset{―}{e}$ )

CHXII09:COORDINATION COMPOUNDS

322246 $d s p^{2}$ -hybridisation is found in

1

{[Co {({NH}_{3})}_{2}]}^{2 +}

2

{[{NiCl}_{4}]}^{2 -}

3

{[Co {({NH}_{3})}_{6}]}^{3 +}

4

{[{PtCl}_{4}]}^{2 -}

Explanation:

${[{PtCl}_{4}]}^{2 -}$ involves $ds p^{2}$ hybridisation.

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