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CHXII09:COORDINATION COMPOUNDS

322281 Number of complexes from the following with even number of unpaired " $d$ " electrons is ____.
${[V {(H_{2} O)}_{6}]}^{3 +}, {[Cr {(H_{2} O)}_{6}]}^{2 +}, {[Fe {(H_{2} O)}_{6}]}^{3 +}$ , ${[Ni {(H_{2} O)}_{6}]}^{3 +}, {[Cu {(H_{2} O)}_{6}]}^{2 +}$
[Given atomic numbers : $V = 23, Cr = 24$ , $Fe = 26, Ni = 28, Cu = 29]$

1 5

2 2

3 1

4 4

Explanation:

supporting img
So, ${[V {(H_{2} O)}_{6}]}^{3 +}$ and ${[Cr {(H_{2} O)}_{6}]}^{2 +}$ have even number of unpaired electrons. So, the correct option is (2).

JEE Main - 2024

CHXII09:COORDINATION COMPOUNDS

322282 The correct statements from following are
(I) The strength of anionic ligands can be explained by crystal field theory.
(II) Valence bond theory does not give a quantitative interpretation of kinetic stability of coordination compounds.
(III) The hybridisation involved in formation of ${[Ni (CN)_{4}]}^{2 -}$ complex is ${dsp}^{2}$ .
(IV) The number of possible isomer(s) of $cis {[{PtCl}_{2} (en)_{2}]}^{2 +}$ is one.
Choose the correct answer from the options given below

1 (I), (IV)only

2 (II), (III) only

3 (II), (IV)only

4 (I), (III) only

Explanation:

The statements II and III are correct. The correct statements of I and IV are given below:
The strength of anionic ligands is not explained by crystal field theory. It is explained by ligand field theory.
cis- ${[{PtCl}_{2} (en)_{2}]}^{2 +}$ shows optical activity. So exists in two forms $(d, 1)$ .So, the correct option is (2).

JEE Main - 2024

CHXII09:COORDINATION COMPOUNDS

322283 VBT can not explain the geometry of:

1

{[Cr {({NH}_{3})}_{6}]}^{+ 3}

2

{[Co {({NH}_{3})}_{6}]}^{+ 3}

3

{[Cu {({NH}_{3})}_{4}]}^{+ 2}

.

4

{[Zn {({NH}_{3})}_{4}]}^{+ 2}

Explanation:

According to VBT, geometry of ${[Cu {({NH}_{3})}_{4}]}^{+ 2}$ is tetrahedral but its actual geometry is square planar.

CHXII09:COORDINATION COMPOUNDS

322284 The pair having the same magnetic moment is : [At. $No : Cr = 24, Mn = 25, Fe = 26, Co = 27$ ]

1

{[Cr {(H_{2} O)}_{6}]}^{2 +}

and

{[Fe {(H_{2} O)}_{6}]}^{2 +}

2

{[Mn {(H_{2} O)}_{6}]}^{2 +}

and

{[Cr {(H_{2} O)}_{6}]}^{2 +}

3

{[{CoCl}_{4}]}^{2 -}

and

{[Fe {(H_{2} O)}_{6}]}^{2 +}

4

{[Cr {(H_{2} O)}_{6}]}^{2 +}

and

{[{CoCl}_{4}]}^{2 -}

Explanation:

$C r^{2 +} \to d^{4} \to$ No. of unpaired electrons are are 4.
$F e^{2 +} \to d^{6} \to$ No of unpaired electrons are 4.
Both configurations have 4 unpaired electrons due to weak field ligands.

CHXII09:COORDINATION COMPOUNDS

322281 Number of complexes from the following with even number of unpaired " $d$ " electrons is ____.
${[V {(H_{2} O)}_{6}]}^{3 +}, {[Cr {(H_{2} O)}_{6}]}^{2 +}, {[Fe {(H_{2} O)}_{6}]}^{3 +}$ , ${[Ni {(H_{2} O)}_{6}]}^{3 +}, {[Cu {(H_{2} O)}_{6}]}^{2 +}$
[Given atomic numbers : $V = 23, Cr = 24$ , $Fe = 26, Ni = 28, Cu = 29]$

1 5

2 2

3 1

4 4

Explanation:

supporting img
So, ${[V {(H_{2} O)}_{6}]}^{3 +}$ and ${[Cr {(H_{2} O)}_{6}]}^{2 +}$ have even number of unpaired electrons. So, the correct option is (2).

JEE Main - 2024

CHXII09:COORDINATION COMPOUNDS

322282 The correct statements from following are
(I) The strength of anionic ligands can be explained by crystal field theory.
(II) Valence bond theory does not give a quantitative interpretation of kinetic stability of coordination compounds.
(III) The hybridisation involved in formation of ${[Ni (CN)_{4}]}^{2 -}$ complex is ${dsp}^{2}$ .
(IV) The number of possible isomer(s) of $cis {[{PtCl}_{2} (en)_{2}]}^{2 +}$ is one.
Choose the correct answer from the options given below

1 (I), (IV)only

2 (II), (III) only

3 (II), (IV)only

4 (I), (III) only

Explanation:

The statements II and III are correct. The correct statements of I and IV are given below:
The strength of anionic ligands is not explained by crystal field theory. It is explained by ligand field theory.
cis- ${[{PtCl}_{2} (en)_{2}]}^{2 +}$ shows optical activity. So exists in two forms $(d, 1)$ .So, the correct option is (2).

JEE Main - 2024

CHXII09:COORDINATION COMPOUNDS

322283 VBT can not explain the geometry of:

1

{[Cr {({NH}_{3})}_{6}]}^{+ 3}

2

{[Co {({NH}_{3})}_{6}]}^{+ 3}

3

{[Cu {({NH}_{3})}_{4}]}^{+ 2}

.

4

{[Zn {({NH}_{3})}_{4}]}^{+ 2}

Explanation:

According to VBT, geometry of ${[Cu {({NH}_{3})}_{4}]}^{+ 2}$ is tetrahedral but its actual geometry is square planar.

CHXII09:COORDINATION COMPOUNDS

322284 The pair having the same magnetic moment is : [At. $No : Cr = 24, Mn = 25, Fe = 26, Co = 27$ ]

1

{[Cr {(H_{2} O)}_{6}]}^{2 +}

and

{[Fe {(H_{2} O)}_{6}]}^{2 +}

2

{[Mn {(H_{2} O)}_{6}]}^{2 +}

and

{[Cr {(H_{2} O)}_{6}]}^{2 +}

3

{[{CoCl}_{4}]}^{2 -}

and

{[Fe {(H_{2} O)}_{6}]}^{2 +}

4

{[Cr {(H_{2} O)}_{6}]}^{2 +}

and

{[{CoCl}_{4}]}^{2 -}

Explanation:

$C r^{2 +} \to d^{4} \to$ No. of unpaired electrons are are 4.
$F e^{2 +} \to d^{6} \to$ No of unpaired electrons are 4.
Both configurations have 4 unpaired electrons due to weak field ligands.

CHXII09:COORDINATION COMPOUNDS

322281 Number of complexes from the following with even number of unpaired " $d$ " electrons is ____.
${[V {(H_{2} O)}_{6}]}^{3 +}, {[Cr {(H_{2} O)}_{6}]}^{2 +}, {[Fe {(H_{2} O)}_{6}]}^{3 +}$ , ${[Ni {(H_{2} O)}_{6}]}^{3 +}, {[Cu {(H_{2} O)}_{6}]}^{2 +}$
[Given atomic numbers : $V = 23, Cr = 24$ , $Fe = 26, Ni = 28, Cu = 29]$

1 5

2 2

3 1

4 4

Explanation:

supporting img
So, ${[V {(H_{2} O)}_{6}]}^{3 +}$ and ${[Cr {(H_{2} O)}_{6}]}^{2 +}$ have even number of unpaired electrons. So, the correct option is (2).

JEE Main - 2024

CHXII09:COORDINATION COMPOUNDS

322282 The correct statements from following are
(I) The strength of anionic ligands can be explained by crystal field theory.
(II) Valence bond theory does not give a quantitative interpretation of kinetic stability of coordination compounds.
(III) The hybridisation involved in formation of ${[Ni (CN)_{4}]}^{2 -}$ complex is ${dsp}^{2}$ .
(IV) The number of possible isomer(s) of $cis {[{PtCl}_{2} (en)_{2}]}^{2 +}$ is one.
Choose the correct answer from the options given below

1 (I), (IV)only

2 (II), (III) only

3 (II), (IV)only

4 (I), (III) only

Explanation:

The statements II and III are correct. The correct statements of I and IV are given below:
The strength of anionic ligands is not explained by crystal field theory. It is explained by ligand field theory.
cis- ${[{PtCl}_{2} (en)_{2}]}^{2 +}$ shows optical activity. So exists in two forms $(d, 1)$ .So, the correct option is (2).

JEE Main - 2024

CHXII09:COORDINATION COMPOUNDS

322283 VBT can not explain the geometry of:

1

{[Cr {({NH}_{3})}_{6}]}^{+ 3}

2

{[Co {({NH}_{3})}_{6}]}^{+ 3}

3

{[Cu {({NH}_{3})}_{4}]}^{+ 2}

.

4

{[Zn {({NH}_{3})}_{4}]}^{+ 2}

Explanation:

According to VBT, geometry of ${[Cu {({NH}_{3})}_{4}]}^{+ 2}$ is tetrahedral but its actual geometry is square planar.

CHXII09:COORDINATION COMPOUNDS

322284 The pair having the same magnetic moment is : [At. $No : Cr = 24, Mn = 25, Fe = 26, Co = 27$ ]

1

{[Cr {(H_{2} O)}_{6}]}^{2 +}

and

{[Fe {(H_{2} O)}_{6}]}^{2 +}

2

{[Mn {(H_{2} O)}_{6}]}^{2 +}

and

{[Cr {(H_{2} O)}_{6}]}^{2 +}

3

{[{CoCl}_{4}]}^{2 -}

and

{[Fe {(H_{2} O)}_{6}]}^{2 +}

4

{[Cr {(H_{2} O)}_{6}]}^{2 +}

and

{[{CoCl}_{4}]}^{2 -}

Explanation:

$C r^{2 +} \to d^{4} \to$ No. of unpaired electrons are are 4.
$F e^{2 +} \to d^{6} \to$ No of unpaired electrons are 4.
Both configurations have 4 unpaired electrons due to weak field ligands.

CHXII09:COORDINATION COMPOUNDS

322281 Number of complexes from the following with even number of unpaired " $d$ " electrons is ____.
${[V {(H_{2} O)}_{6}]}^{3 +}, {[Cr {(H_{2} O)}_{6}]}^{2 +}, {[Fe {(H_{2} O)}_{6}]}^{3 +}$ , ${[Ni {(H_{2} O)}_{6}]}^{3 +}, {[Cu {(H_{2} O)}_{6}]}^{2 +}$
[Given atomic numbers : $V = 23, Cr = 24$ , $Fe = 26, Ni = 28, Cu = 29]$

1 5

2 2

3 1

4 4

Explanation:

supporting img
So, ${[V {(H_{2} O)}_{6}]}^{3 +}$ and ${[Cr {(H_{2} O)}_{6}]}^{2 +}$ have even number of unpaired electrons. So, the correct option is (2).

JEE Main - 2024

CHXII09:COORDINATION COMPOUNDS

322282 The correct statements from following are
(I) The strength of anionic ligands can be explained by crystal field theory.
(II) Valence bond theory does not give a quantitative interpretation of kinetic stability of coordination compounds.
(III) The hybridisation involved in formation of ${[Ni (CN)_{4}]}^{2 -}$ complex is ${dsp}^{2}$ .
(IV) The number of possible isomer(s) of $cis {[{PtCl}_{2} (en)_{2}]}^{2 +}$ is one.
Choose the correct answer from the options given below

1 (I), (IV)only

2 (II), (III) only

3 (II), (IV)only

4 (I), (III) only

Explanation:

The statements II and III are correct. The correct statements of I and IV are given below:
The strength of anionic ligands is not explained by crystal field theory. It is explained by ligand field theory.
cis- ${[{PtCl}_{2} (en)_{2}]}^{2 +}$ shows optical activity. So exists in two forms $(d, 1)$ .So, the correct option is (2).

JEE Main - 2024

CHXII09:COORDINATION COMPOUNDS

322283 VBT can not explain the geometry of:

1

{[Cr {({NH}_{3})}_{6}]}^{+ 3}

2

{[Co {({NH}_{3})}_{6}]}^{+ 3}

3

{[Cu {({NH}_{3})}_{4}]}^{+ 2}

.

4

{[Zn {({NH}_{3})}_{4}]}^{+ 2}

Explanation:

According to VBT, geometry of ${[Cu {({NH}_{3})}_{4}]}^{+ 2}$ is tetrahedral but its actual geometry is square planar.

CHXII09:COORDINATION COMPOUNDS

322284 The pair having the same magnetic moment is : [At. $No : Cr = 24, Mn = 25, Fe = 26, Co = 27$ ]

1

{[Cr {(H_{2} O)}_{6}]}^{2 +}

and

{[Fe {(H_{2} O)}_{6}]}^{2 +}

2

{[Mn {(H_{2} O)}_{6}]}^{2 +}

and

{[Cr {(H_{2} O)}_{6}]}^{2 +}

3

{[{CoCl}_{4}]}^{2 -}

and

{[Fe {(H_{2} O)}_{6}]}^{2 +}

4

{[Cr {(H_{2} O)}_{6}]}^{2 +}

and

{[{CoCl}_{4}]}^{2 -}

Explanation:

$C r^{2 +} \to d^{4} \to$ No. of unpaired electrons are are 4.
$F e^{2 +} \to d^{6} \to$ No of unpaired electrons are 4.
Both configurations have 4 unpaired electrons due to weak field ligands.

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