NEET Test Series from KOTA - 10 Papers In MS WORD
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CHXII08:THE D- & F-BLOCK ELEMENTS
321406
All the \({\rm{3d}}\)-series elements are good reducing agents except
1 scandium
2 titanium
3 copper
4 zinc
Explanation:
Copper has a SRP of \(\mathrm{+0.34 \mathrm{~V}}\). As such, it is not a good reducing agent.
CHXII08:THE D- & F-BLOCK ELEMENTS
321407
Pure conc. \(\mathrm{HNO}_{3}\) makes iron passive as the surface is covered with protective layer of
1 \(\mathrm{Fe}_{2} \mathrm{O}_{3}\)
2 \(\mathrm{FeO}\)
3 \(\mathrm{Fe}_{3} \mathrm{O}_{4}\)
4 \(\mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{3}\)
Explanation:
The passivity of iron is due to the formation of a thin insoluble and invisible iron film on surface which prevents its further reactions. The film is due to the formation of \(\mathrm{Fe}_{3} \mathrm{O}_{4}\).
CHXII08:THE D- & F-BLOCK ELEMENTS
321408
Assertion : On adding \(\mathrm{KI}\) to blue \(\mathrm{CuSO}_{4}\) solution, the colour changes to dark brown. Reason : This is due to the formation of \(\mathrm{CuO}\).
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
The dark brown colour is due to the evolution of iodine. \(2 \mathrm{CuSO}_{4}+4 \mathrm{KI} \rightarrow 2 \mathrm{CuI}+2 \mathrm{~K}_{2} \mathrm{SO}_{4}+\underset{\text { (dark brown) }}{\mathrm{I}_{2}}\) So option (3) is correct.
CHXII08:THE D- & F-BLOCK ELEMENTS
321409
Reactivity of transition elements decreases almost regularly from \(\mathrm{\mathrm{Sc}}\) to \(\mathrm{\mathrm{Cu}}\) because
1 Regular increase in Electronegativity
2 Regular increase in Ionisation enthalphy
3 Regular increase in size
4 All the above
Explanation:
It is due to regular increase in ionisation enthalpy.
321406
All the \({\rm{3d}}\)-series elements are good reducing agents except
1 scandium
2 titanium
3 copper
4 zinc
Explanation:
Copper has a SRP of \(\mathrm{+0.34 \mathrm{~V}}\). As such, it is not a good reducing agent.
CHXII08:THE D- & F-BLOCK ELEMENTS
321407
Pure conc. \(\mathrm{HNO}_{3}\) makes iron passive as the surface is covered with protective layer of
1 \(\mathrm{Fe}_{2} \mathrm{O}_{3}\)
2 \(\mathrm{FeO}\)
3 \(\mathrm{Fe}_{3} \mathrm{O}_{4}\)
4 \(\mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{3}\)
Explanation:
The passivity of iron is due to the formation of a thin insoluble and invisible iron film on surface which prevents its further reactions. The film is due to the formation of \(\mathrm{Fe}_{3} \mathrm{O}_{4}\).
CHXII08:THE D- & F-BLOCK ELEMENTS
321408
Assertion : On adding \(\mathrm{KI}\) to blue \(\mathrm{CuSO}_{4}\) solution, the colour changes to dark brown. Reason : This is due to the formation of \(\mathrm{CuO}\).
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
The dark brown colour is due to the evolution of iodine. \(2 \mathrm{CuSO}_{4}+4 \mathrm{KI} \rightarrow 2 \mathrm{CuI}+2 \mathrm{~K}_{2} \mathrm{SO}_{4}+\underset{\text { (dark brown) }}{\mathrm{I}_{2}}\) So option (3) is correct.
CHXII08:THE D- & F-BLOCK ELEMENTS
321409
Reactivity of transition elements decreases almost regularly from \(\mathrm{\mathrm{Sc}}\) to \(\mathrm{\mathrm{Cu}}\) because
1 Regular increase in Electronegativity
2 Regular increase in Ionisation enthalphy
3 Regular increase in size
4 All the above
Explanation:
It is due to regular increase in ionisation enthalpy.
321406
All the \({\rm{3d}}\)-series elements are good reducing agents except
1 scandium
2 titanium
3 copper
4 zinc
Explanation:
Copper has a SRP of \(\mathrm{+0.34 \mathrm{~V}}\). As such, it is not a good reducing agent.
CHXII08:THE D- & F-BLOCK ELEMENTS
321407
Pure conc. \(\mathrm{HNO}_{3}\) makes iron passive as the surface is covered with protective layer of
1 \(\mathrm{Fe}_{2} \mathrm{O}_{3}\)
2 \(\mathrm{FeO}\)
3 \(\mathrm{Fe}_{3} \mathrm{O}_{4}\)
4 \(\mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{3}\)
Explanation:
The passivity of iron is due to the formation of a thin insoluble and invisible iron film on surface which prevents its further reactions. The film is due to the formation of \(\mathrm{Fe}_{3} \mathrm{O}_{4}\).
CHXII08:THE D- & F-BLOCK ELEMENTS
321408
Assertion : On adding \(\mathrm{KI}\) to blue \(\mathrm{CuSO}_{4}\) solution, the colour changes to dark brown. Reason : This is due to the formation of \(\mathrm{CuO}\).
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
The dark brown colour is due to the evolution of iodine. \(2 \mathrm{CuSO}_{4}+4 \mathrm{KI} \rightarrow 2 \mathrm{CuI}+2 \mathrm{~K}_{2} \mathrm{SO}_{4}+\underset{\text { (dark brown) }}{\mathrm{I}_{2}}\) So option (3) is correct.
CHXII08:THE D- & F-BLOCK ELEMENTS
321409
Reactivity of transition elements decreases almost regularly from \(\mathrm{\mathrm{Sc}}\) to \(\mathrm{\mathrm{Cu}}\) because
1 Regular increase in Electronegativity
2 Regular increase in Ionisation enthalphy
3 Regular increase in size
4 All the above
Explanation:
It is due to regular increase in ionisation enthalpy.
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
CHXII08:THE D- & F-BLOCK ELEMENTS
321406
All the \({\rm{3d}}\)-series elements are good reducing agents except
1 scandium
2 titanium
3 copper
4 zinc
Explanation:
Copper has a SRP of \(\mathrm{+0.34 \mathrm{~V}}\). As such, it is not a good reducing agent.
CHXII08:THE D- & F-BLOCK ELEMENTS
321407
Pure conc. \(\mathrm{HNO}_{3}\) makes iron passive as the surface is covered with protective layer of
1 \(\mathrm{Fe}_{2} \mathrm{O}_{3}\)
2 \(\mathrm{FeO}\)
3 \(\mathrm{Fe}_{3} \mathrm{O}_{4}\)
4 \(\mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{3}\)
Explanation:
The passivity of iron is due to the formation of a thin insoluble and invisible iron film on surface which prevents its further reactions. The film is due to the formation of \(\mathrm{Fe}_{3} \mathrm{O}_{4}\).
CHXII08:THE D- & F-BLOCK ELEMENTS
321408
Assertion : On adding \(\mathrm{KI}\) to blue \(\mathrm{CuSO}_{4}\) solution, the colour changes to dark brown. Reason : This is due to the formation of \(\mathrm{CuO}\).
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
The dark brown colour is due to the evolution of iodine. \(2 \mathrm{CuSO}_{4}+4 \mathrm{KI} \rightarrow 2 \mathrm{CuI}+2 \mathrm{~K}_{2} \mathrm{SO}_{4}+\underset{\text { (dark brown) }}{\mathrm{I}_{2}}\) So option (3) is correct.
CHXII08:THE D- & F-BLOCK ELEMENTS
321409
Reactivity of transition elements decreases almost regularly from \(\mathrm{\mathrm{Sc}}\) to \(\mathrm{\mathrm{Cu}}\) because
1 Regular increase in Electronegativity
2 Regular increase in Ionisation enthalphy
3 Regular increase in size
4 All the above
Explanation:
It is due to regular increase in ionisation enthalpy.