Explanation:
\(\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\rm{Ti}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\rm{V}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\rm{Cr}}\)
\({{\rm{E}}^{\rm{^\circ }}}\left( {{{\rm{M}}^{{\rm{3 + }}}}{\rm{/}}{{\rm{M}}^{{\rm{2 + }}}}} \right)\quad - {\rm{0}}.{\rm{37}}\quad - {\rm{0}}.{\rm{26}}\quad - {\rm{0}}.{\rm{41}}\)
\({\rm{(in}}\,{\rm{volts)}}\)
The above \({\mathrm{\mathrm{E}^{\circ}}}\) values indicate that \({\mathrm{\mathrm{Ti}^{2+}, \mathrm{V}^{2+}}}\) and \({\mathrm{\mathrm{Cr}^{2+}}}\) ions are strong reducing agents and can liberate hydrogen from a dilute acid. So, the correct option is (3).