320485 Inversion of a sugar follows first order rate equation which can be followed by noting the change in rotation of the plane of polarisation of light in the polarimeter. If \({{\rm{r}}_\infty }\,\,{\rm{and}}\,\,{{\rm{r}}_{\rm{0}}}\) are the rotations at \({\rm{t = }}\infty {\rm{,}}\,{\rm{t = t}}\,\,{\rm{and}}\,\,{\rm{t = 0}}\) then, first order reaction can be written as

320486 Consider the reaction, \({\text{2A + B}} \to \) Products When concentration of \({\text{B}}\) alone was doubled, the half-life did not change. When the concentration of \({\text{A}}\) alone was doubled, the rate increased by two times. The unit of rate constant for this reaction is:

320487 If concentration of reactant 'A' is increased by 10 times the rate of reaction becomes 100 times. What is the order of reaction, if rate law is, rate \(=\mathrm{k}[\mathrm{A}]^{\mathrm{x}}\) ?

320488 The rate constant of reaction \({\rm{2A + B}} \to {\rm{C}}\) is \({\rm{2}}{\rm{.57 \times 1}}{{\rm{0}}^{{\rm{ - 5}}}}{\rm{\;L\;mol}}{{\rm{e}}^{{\rm{ - 1}}}}{\rm{se}}{{\rm{c}}^{{\rm{ - 1}}}}\) after \({\rm{10}}\,{\rm{sec}}\),
\({\rm{2}}{\rm{.65 \times 1}}{{\rm{0}}^{{\rm{ - 5}}}}\,\,{\rm{L}}\,\,{\rm{mol}}{{\rm{e}}^{{\rm{ - 1}}}}\,{\rm{se}}{{\rm{c}}^{{\rm{ - 1}}}}\) after 20 sec and \({\rm{2}}{\rm{.55 \times 1}}{{\rm{0}}^{{\rm{ - 5}}}}{\rm{L}}\,{\rm{mol}}{{\rm{e}}^{{\rm{ - 1}}}}{\rm{se}}{{\rm{c}}^{{\rm{ - 1}}}}{\rm{after}}{\mkern 1mu} {\mkern 1mu} {\rm{30}}{\mkern 1mu} {\mkern 1mu} {\rm{sec}}\).
The order of the reaction is:

320485 Inversion of a sugar follows first order rate equation which can be followed by noting the change in rotation of the plane of polarisation of light in the polarimeter. If \({{\rm{r}}_\infty }\,\,{\rm{and}}\,\,{{\rm{r}}_{\rm{0}}}\) are the rotations at \({\rm{t = }}\infty {\rm{,}}\,{\rm{t = t}}\,\,{\rm{and}}\,\,{\rm{t = 0}}\) then, first order reaction can be written as

320486 Consider the reaction, \({\text{2A + B}} \to \) Products When concentration of \({\text{B}}\) alone was doubled, the half-life did not change. When the concentration of \({\text{A}}\) alone was doubled, the rate increased by two times. The unit of rate constant for this reaction is:

320487 If concentration of reactant 'A' is increased by 10 times the rate of reaction becomes 100 times. What is the order of reaction, if rate law is, rate \(=\mathrm{k}[\mathrm{A}]^{\mathrm{x}}\) ?

320488 The rate constant of reaction \({\rm{2A + B}} \to {\rm{C}}\) is \({\rm{2}}{\rm{.57 \times 1}}{{\rm{0}}^{{\rm{ - 5}}}}{\rm{\;L\;mol}}{{\rm{e}}^{{\rm{ - 1}}}}{\rm{se}}{{\rm{c}}^{{\rm{ - 1}}}}\) after \({\rm{10}}\,{\rm{sec}}\),
\({\rm{2}}{\rm{.65 \times 1}}{{\rm{0}}^{{\rm{ - 5}}}}\,\,{\rm{L}}\,\,{\rm{mol}}{{\rm{e}}^{{\rm{ - 1}}}}\,{\rm{se}}{{\rm{c}}^{{\rm{ - 1}}}}\) after 20 sec and \({\rm{2}}{\rm{.55 \times 1}}{{\rm{0}}^{{\rm{ - 5}}}}{\rm{L}}\,{\rm{mol}}{{\rm{e}}^{{\rm{ - 1}}}}{\rm{se}}{{\rm{c}}^{{\rm{ - 1}}}}{\rm{after}}{\mkern 1mu} {\mkern 1mu} {\rm{30}}{\mkern 1mu} {\mkern 1mu} {\rm{sec}}\).
The order of the reaction is:

320485 Inversion of a sugar follows first order rate equation which can be followed by noting the change in rotation of the plane of polarisation of light in the polarimeter. If \({{\rm{r}}_\infty }\,\,{\rm{and}}\,\,{{\rm{r}}_{\rm{0}}}\) are the rotations at \({\rm{t = }}\infty {\rm{,}}\,{\rm{t = t}}\,\,{\rm{and}}\,\,{\rm{t = 0}}\) then, first order reaction can be written as

320486 Consider the reaction, \({\text{2A + B}} \to \) Products When concentration of \({\text{B}}\) alone was doubled, the half-life did not change. When the concentration of \({\text{A}}\) alone was doubled, the rate increased by two times. The unit of rate constant for this reaction is:

320487 If concentration of reactant 'A' is increased by 10 times the rate of reaction becomes 100 times. What is the order of reaction, if rate law is, rate \(=\mathrm{k}[\mathrm{A}]^{\mathrm{x}}\) ?

320488 The rate constant of reaction \({\rm{2A + B}} \to {\rm{C}}\) is \({\rm{2}}{\rm{.57 \times 1}}{{\rm{0}}^{{\rm{ - 5}}}}{\rm{\;L\;mol}}{{\rm{e}}^{{\rm{ - 1}}}}{\rm{se}}{{\rm{c}}^{{\rm{ - 1}}}}\) after \({\rm{10}}\,{\rm{sec}}\),
\({\rm{2}}{\rm{.65 \times 1}}{{\rm{0}}^{{\rm{ - 5}}}}\,\,{\rm{L}}\,\,{\rm{mol}}{{\rm{e}}^{{\rm{ - 1}}}}\,{\rm{se}}{{\rm{c}}^{{\rm{ - 1}}}}\) after 20 sec and \({\rm{2}}{\rm{.55 \times 1}}{{\rm{0}}^{{\rm{ - 5}}}}{\rm{L}}\,{\rm{mol}}{{\rm{e}}^{{\rm{ - 1}}}}{\rm{se}}{{\rm{c}}^{{\rm{ - 1}}}}{\rm{after}}{\mkern 1mu} {\mkern 1mu} {\rm{30}}{\mkern 1mu} {\mkern 1mu} {\rm{sec}}\).
The order of the reaction is:

320485 Inversion of a sugar follows first order rate equation which can be followed by noting the change in rotation of the plane of polarisation of light in the polarimeter. If \({{\rm{r}}_\infty }\,\,{\rm{and}}\,\,{{\rm{r}}_{\rm{0}}}\) are the rotations at \({\rm{t = }}\infty {\rm{,}}\,{\rm{t = t}}\,\,{\rm{and}}\,\,{\rm{t = 0}}\) then, first order reaction can be written as

320486 Consider the reaction, \({\text{2A + B}} \to \) Products When concentration of \({\text{B}}\) alone was doubled, the half-life did not change. When the concentration of \({\text{A}}\) alone was doubled, the rate increased by two times. The unit of rate constant for this reaction is:

320487 If concentration of reactant 'A' is increased by 10 times the rate of reaction becomes 100 times. What is the order of reaction, if rate law is, rate \(=\mathrm{k}[\mathrm{A}]^{\mathrm{x}}\) ?

320488 The rate constant of reaction \({\rm{2A + B}} \to {\rm{C}}\) is \({\rm{2}}{\rm{.57 \times 1}}{{\rm{0}}^{{\rm{ - 5}}}}{\rm{\;L\;mol}}{{\rm{e}}^{{\rm{ - 1}}}}{\rm{se}}{{\rm{c}}^{{\rm{ - 1}}}}\) after \({\rm{10}}\,{\rm{sec}}\),
\({\rm{2}}{\rm{.65 \times 1}}{{\rm{0}}^{{\rm{ - 5}}}}\,\,{\rm{L}}\,\,{\rm{mol}}{{\rm{e}}^{{\rm{ - 1}}}}\,{\rm{se}}{{\rm{c}}^{{\rm{ - 1}}}}\) after 20 sec and \({\rm{2}}{\rm{.55 \times 1}}{{\rm{0}}^{{\rm{ - 5}}}}{\rm{L}}\,{\rm{mol}}{{\rm{e}}^{{\rm{ - 1}}}}{\rm{se}}{{\rm{c}}^{{\rm{ - 1}}}}{\rm{after}}{\mkern 1mu} {\mkern 1mu} {\rm{30}}{\mkern 1mu} {\mkern 1mu} {\rm{sec}}\).
The order of the reaction is: